I have created 3 tables named complete_shifts,incomplete_shifts and incomplete_shift_register. All three tables include 2 columns called employee_no and date. I want to get count of distinct values in employee_no column from all three tables on a specified date.
Ex: if I specify "date = 2013-06-13" then count shuld be 3. (employee no : 0008,0019,0035)
complete_shifts
shift_id | date | employee_no | sign_in_at | sign_out_at
1 |2013-06-13| 0008 | 7:05 | 16:05
2 |2013-06-13| 0008 | 7:10 | 16:05
3 |2013-06-14| 0025 | 7:11 | 16:10
incomplete_shifts
shift_id | date | employee_no | sign_in_at |sign_out_at
1 | 2013-06-13| 0019 | 7:08 |
incomplete_shift_register
shift_id | date |employee_no | sign_in_at
1 | 2013-06-13| 0008 | 7:08
2 | 2013-06-13| 0035 | 7:09
3 | 2013-06-14| 0060 | 7:11
i don't know how to write the SQL syntax for above situation... plezzz help me..
thank you.
How about something like
SELECT COUNT(DISTINCT employee_no) cnt_employee_no
FROM (
SELECT employee_no
FROM complete_shifts
WHERE date = '2013-06-13'
UNION
SELECT employee_no
FROM incomplete_shifts
WHERE date = '2013-06-13'
UNION
SELECT employee_no
FROM incomplete_shift_register
WHERE date = '2013-06-13'
)
Using
UNION Syntax
UNION is used to combine the result from multiple SELECT statements
into a single result set.
and
COUNT(DISTINCT expr,[expr...])
Returns a count of the number of rows with different non-NULL expr
values.
SELECT count(*) from
(
SELECT 1 from complete_shifts WHERE date="2013-06-13"
UNION ALL
SELECT 1 from incomplete_shifts WHERE date="2013-06-13"
UNION ALL
SELECT 1 from incomplete_shift_register WHERE date="2013-06-13"
)t
Just UNION the tables together and COUNT. The UNION will remove duplicates, so a simple COUNT will do the trick - a COUNT DISTINCT won't be needed. This will work if you want the count only; if you want other values the query gets slightly more involved:
SELECT COUNT(*) FROM (
SELECT employee_no
FROM complete_shifts
WHERE date = '2013-06-13'
UNION SELECT employee_no
FROM incomplete_shifts
WHERE date = '2013-06-13'
UNION SELECT employee_no
FROM incomplete_shift_register
WHERE date = '2013-06-13'
) AllShifts
Related
I want to count the total numbers of row in SQL database.
"tableA" :
id | date |
---+------------+
1 | 2019-09-03 |
2 | 2019-09-03 |
3 | 2019-09-04 |
4 | 2019-09-05 |
I want to execute it as new column name "total" that should have like this :
total
-----
3
because they are 3 different dates.
I know that the result must use 2 query like this:
SELECT date
FROM tableA
GROUP BY date AS total;
SELECT COUNT(total)
FROM tableA;
How to combine 2 queries like that or there is another way?
Use count(distinct date)
SELECT COUNT(distinct date) FROM tableA
select count( distinct date) as total from tableA;
I am getting number of visits every day for generating a chart. Even when there are zero records, I want to get the record with count 0.
I am planning to create a table which will contain every day, and when fetching - data will join with this table and get count of the records from visit table. Is there any other way to do the same in mySQL?
Visit Table with Sample Data
Date | ........
----------------------
01/11/2014 | --------
03/11/2014 | --------
I want results even for 02/11/2014 with count 0. If I group by date - I will get count only when records exists on a particular date.
I'll try to read in between lines of your question... Sort of game where I write the question and the answer :-/
You have a table (my_stats) holding two fields, one is the date (my_date) the other is a integer (my_counter).
By some mean, you will need a table holding a list of all dates you want to use in your output.
This could be done with a temp table... (but not all hosting solution will allow you this) the other is to build it up on the fly, using a view or a stored procedure.
Then you will LEFT JOIN this table/view/stored procedure/etc... to your table my_visits based on the date field.
This will output you all dates, and when there won't be a match in mour my_visits you'll have a NULL value. ( IFNULL(my_visits.my_counter, 0) will give you a 0 (zero) when there is no matching value.
inspiration:
Get a list of dates between two dates +
How to get list of dates between two dates in mysql select query and a nice solution here that needs no loops, procedures, or temp tables generate days from date range
Based on that last link, here we go...
first a sample table
DROP TABLE IF EXISTS `my_stats`;
CREATE TABLE IF NOT EXISTS `my_stats` (
`my_date` date NOT NULL,
`my_counter` int(11) NOT NULL
) ENGINE=MyISAM DEFAULT CHARSET=utf8mb4;
INSERT INTO `my_stats` (`my_date`, `my_counter`) VALUES
('2017-11-01', 2),
('2017-11-02', 3),
('2017-11-03', 5),
('2017-11-05', 3),
('2017-11-07', 7);
And now a working exemple BETWEEN '2017-11-01' AND '2017-11-09'
SELECT date_range.date AS the_date,
IFNULL(my_stats.my_counter, 0) AS the_counter
FROM (
SELECT a.date
FROM (
SELECT Curdate() - INTERVAL (a.a + (10 * b.a) + (100 * c.a)) day
AS date
FROM (
SELECT 0 AS a
UNION ALL
SELECT 1
UNION ALL
SELECT 2
UNION ALL
SELECT 3
UNION ALL
SELECT 4
UNION ALL
SELECT 5
UNION ALL
SELECT 6
UNION ALL
SELECT 7
UNION ALL
SELECT 8
UNION ALL
SELECT 9
) AS a
CROSS JOIN (
SELECT 0 AS a
UNION ALL
SELECT 1
UNION ALL
SELECT 2
UNION ALL
SELECT 3
UNION ALL
SELECT 4
UNION ALL
SELECT 5
UNION ALL
SELECT 6
UNION ALL
SELECT 7
UNION ALL
SELECT 8
UNION ALL
SELECT 9
) AS b
CROSS JOIN (
SELECT 0 AS a
UNION ALL
SELECT 1
UNION ALL
SELECT 2
UNION ALL
SELECT 3
UNION ALL
SELECT 4
UNION ALL
SELECT 5
UNION ALL
SELECT 6
UNION ALL
SELECT 7
UNION ALL
SELECT 8
UNION ALL
SELECT 9
) AS c
) AS a
WHERE a.date BETWEEN '2017-11-01' AND '2017-11-09'
) AS date_range
LEFT JOIN my_stats
ON( date_range.date = my_stats.my_date )
ORDER BY the_date ASC
Output
+------------+-------------+
| the_date | the_counter |
+------------+-------------+
| 2017-11-01 | 2 |
| 2017-11-02 | 3 |
| 2017-11-03 | 5 |
| 2017-11-04 | 0 |
| 2017-11-05 | 3 |
| 2017-11-06 | 0 |
| 2017-11-07 | 7 |
| 2017-11-08 | 0 |
| 2017-11-09 | 0 |
+------------+-------------+
I have a table where one column is the date:
+----------+---------------------+
| id | date |
+----------+---------------------+
| 5 | 2012-12-10 10:12:37 |
+----------+---------------------+
| 4 | 2012-12-10 09:09:55 |
+----------+---------------------+
| 3 | 2012-12-09 21:12:35 |
+----------+---------------------+
| 2 | 2012-12-09 20:15:07 |
+----------+---------------------+
| 1 | 2012-12-09 20:01:42 |
+----------+---------------------+
What I need, is to count the rows which are for example whitin 3 hours to each other. In this example I want to join the upper row with the 2nd row, and the 3rd row with the 4th and 5th rows. So my output should be like this:
+----------+---------------------+---------+
| id | date | count |
+----------+---------------------+---------+
| 5 | 2012-12-10 10:12:37 | 2 |
+----------+---------------------+---------+
| 3 | 2012-12-09 21:12:35 | 3 |
+----------+---------------------+---------+
How could I do this?
I think you need a self-join for this:
select t.id, t.date, COUNT(t2.id)
from t left outer join
t t2
on t.date between t2.date - interval 3 hour and t2.date + interval 3 hour
group by t.id, t.date
(This is untested code so it might have a syntax error.)
If you are trying to divide everything into 3-hour intervals, you can do something like:
select max(t.date), t.id, count(*)
from (select t.*,
(date(date)*100 + floor(hour(date)/3)*3) as interval
from t
) t
group by interval
I am not sure how to do this with My SQL but i am able to build a set of queries in SQL Server 2005 which will provide the intended results. Here is the working sample, its very complex and may be overly complex but that's how i was able to get the desired result:
WITH BaseData AS
(
SELECT 5 AS ID, '2012-12-10 10:12:37' AS Date
UNION ALL
SELECT 4 AS ID, '2012-12-10 09:09:55' AS Date
UNION ALL
SELECT 3 AS ID, '2012-12-09 21:12:35' AS Date
UNION ALL
SELECT 2 AS ID, '2012-12-09 20:15:07' AS Date
UNION ALL
SELECT 1 AS ID, '2012-12-09 20:01:42' AS Date
),
BaseDataWithRowNum AS
(
SELECT ID,DATE, ROW_NUMBER() OVER (ORDER BY Date DESC) AS RowNum
FROM BaseData
),
InterRelatedDates AS
(
SELECT B1.RowNum AS RowNum1,B2.RowNum AS RowNum2
FROM BaseDataWithRowNum B1
INNER JOIN BaseDataWithRowNum B2
ON B1.Date BETWEEN B2.Date AND DATEADD(hh,3,B2.Date)
AND B1.RowNum < B2.RowNum
AND B1.ID != B2.ID
),
InterRelatedDatesWithinMultipleGroups AS
(
SELECT G1.RowNum1,G2.RowNum2
FROM InterRelatedDates G1
LEFT JOIN InterRelatedDates G2
ON G1.RowNum2 = G2.RowNum2
AND G1.RowNum1 != G2.RowNum1
)
SELECT BN.ID,
BN.Date,
CountExcludingOriginalGrouppingRecord +1 AS C
FROM
(
SELECT RowNum1 AS RowNum,COUNT(1) AS CountExcludingOriginalGrouppingRecord
FROM
(
-- If a row was used in only one group then it is ok. use as it is
SELECT D1.RowNum1
FROM InterRelatedDatesWithinMultipleGroups AS D1
WHERE D1.RowNum2 IS NULL
UNION ALL
-- In case a row was selected in two groups, choose the one with higher date
SELECT Min(D1.RowNum1)
FROM InterRelatedDatesWithinMultipleGroups AS D1
WHERE D1.RowNum2 IS NOT NULL
GROUP BY D1.RowNum2
) T
GROUP BY RowNum1
) T2
INNER JOIN BaseDataWithRowNum BN
ON BN.RowNum = T2.RowNum
Been searching for an answer to this for the better part of an hour without much luck. I have two regional tables laid out with the same column names and I can put out a result list for either table based on the following query (swap Table2 for Table1):
SELECT Table1.YEAR, FORMAT(COUNT(Table1.id),0) AS Total
FROM Table1
WHERE Table1.variable='Y'
GROUP BY Table1.YEAR
Ideally I'd like to get a result that gives me a total sum of the counts by year, so instead of:
| REGION 1 | | REGION 2 |
| YEAR | Total | | YEAR | Total |
| 2010 | 5 | | 2010 | 1 |
| 2009 | 2 | | 2009 | 3 |
| | | | 2008 | 4 |
I'd have:
| MERGED |
| YEAR | Total |
| 2010 | 6 |
| 2009 | 5 |
| 2008 | 4 |
I've tried a variety of JOINs and other ideas but I think I'm caught up on the SUM and COUNT issue. Any help would be appreciated, thanks!
SELECT `YEAR`, FORMAT(SUM(`count`), 0) AS `Total`
FROM (
SELECT `Table1`.`YEAR`, COUNT(*) AS `count`
WHERE `Table1`.`variable` = 'Y'
GROUP BY `Table1`.`YEAR`
UNION ALL
SELECT `Table2`.`YEAR`, COUNT(*) AS `count`
WHERE `Table2`.`variable` = 'Y'
GROUP BY `Table2`.`YEAR`
) AS `union`
GROUP BY `YEAR`
You should use an UNION:
SELECT
t.YEAR,
COUNT(*) as TOTAL
FROM (
SELECT *
FROM Table1
UNION ALL
SELECT *
FROM Table2
) t
WHERE t.variable='Y'
GROUP BY t.YEAR;
Select year, sum(counts) from (
SELECT Table1.YEAR, FORMAT(COUNT(Table1.id),0) AS Total
FROM Table1
WHERE Table1.variable='Y'
GROUP BY Table1.YEAR
UNION ALL
SELECT Table2.YEAR, FORMAT(COUNT(Table2.id),0) AS Total
FROM Table2
WHERE Table2.variable='Y'
GROUP BY Table2.YEAR ) GROUP BY year
To improve upon Shehzad's answer:
SELECT YEAR, FORMAT(SUM(counts),0) AS total FROM (
SELECT Table1.YEAR, COUNT(Table1.id) AS counts
FROM Table1
WHERE Table1.variable='Y'
GROUP BY Table1.YEAR
UNION ALL
SELECT Table2.YEAR, COUNT(Table2.id) AS counts
FROM Table2
WHERE Table2.variable='Y'
GROUP BY Table2.YEAR ) AS newTable GROUP BY YEAR
How can I count records for two columns in one table using different query criteria?
Table looks like:
user_id | date | status
------------------------------
1 | 2011-01-02 | 1
2 | 2011-01-03 | 1
3 | 2011-01-02 | 0
4 | 2011-01-03 | 1
1 | 2011-01-02 | 1
I want to count two values in one query. The first one is number of user_id group by status and the second is count of user_id group by date.
How can I do that?
You can't have different GROUP BY clauses in the same query -- each count will have to be in an independent query.
But you can return the output in a single query/resultset using subselects (subquery in the SELECT clause):
SELECT COUNT(a.user_id) AS numUsersPerStatus,
(SELECT COUNT(b.user_id)
FROM YOUR_TABLE b
GROUP BY b.date) AS numUsersPerDate
FROM YOUR_TABLE a
GROUP BY a.status
You don't.
You should use two queries. There's no advantage to doing this with a single query.
If you really want to do it you can try this:
SELECT 'date' AS grptype, date AS grp, COUNT(DISTINCT user_id) AS cnt
FROM yourtable
GROUP BY date
UNION ALL
SELECT 'status' AS grptype, status AS grp, COUNT(DISTINCT user_id) AS cnt
FROM yourtable
GROUP BY status
Result:
grptype grp cnt
date 2011-01-02 2
date 2011-01-03 2
status 0 1
status 1 3
However I would strongly advise against doing this. You want two different and unrelated result sets so you should use two separate queries.