I'm inserting into my pics table:
id | name
1 | dog.gif
I also want to get the id of the above insert (1) and inset that in to another table (gallery table).
Is it possible to do this in one query or would I need two?
INSERT INTO pic SET .... ;
INSERT INTO gallery SET pic_id = LAST_INSERT_ID(), ....
Since it is serial you can use select max(id) from tableName
But that's vulnerable to errors on simultaneous updates so use the method described below
From php.net clickhere
<?php
$link = mysqli_connect('localhost', 'mysql_user', 'mysql_password');
if (!$link) {
die('Could not connect: ' . mysqli::$connect_error() );
}
mysqli::select_db('mydb');
mysqli::query("INSERT INTO mytable (product) values ('kossu')");
printf("Last inserted record has id %d\n", mysqli::$insert_id());
?>
But you need to connect for every query.
Related
I have a problem regarding SQL Query. I have 3 Insert queries in my code.
the first query is with auto-increment ID.
INSERT INTO master_tbl
The second Insert will get the ID from 1st query using LAST_INSERT_ID()function.
INSERT INTO process (id_ref, process_id, hot_cold, temp)
VALUES (LAST_INSERT_ID(), '4', '-', '12')
My problem is, I have third query which needed to use the ID generated in the 1st query as its id_ref also.
When I use the LAST_INSERT_ID(), the ID it gets was the ID of the second query.
Any suggestions on how can I still get the ID in the 1st query to use on 3rd?
You can declare the variable and store the first queries id in that variable and then use it wherever you want.
After first query as you mentioned you are using the separate queries you can try using select to set the `Last insert id` into the variable and then use that variable as below,
select #valuetoUse := LAST_INSERT_ID()
Or Other way is use select the to get the value in your code and then pass that value to insert as all other values. For getting value you can directly fire select
SELECT LAST_INSERT_ID()
then in second query
INSERT INTO process (id_ref, process_id, hot_cold, temp)
VALUES (valuetoUse , '4', '-', '12')
then again in the third query
INSERT INTO thirdtable (id_ref, process_id, hot_cold, temp)
VALUES (valuetoUse , '4', '-', '12')
For more info on how to use user defined variables see here.
Functionality is same as told by #Coder of Code But with PHP
Try This
Create Connection
$conn = new mysqli($servername, $username, $password, $dbname);
First Insert into Table 1
INSERT INTO master_tbl
Then do
$sql = "SELECT MAX(id) as id from master_tbl";
$result = $conn->query($sql);
$row = $result->fetch_array(MYSQLI_NUM);
$latest_id=$row[0];
$sql = "INSERT INTO process (id_ref, process_id, hot_cold, temp)
VALUES ($latest_id,'4','-','12')";
if ($conn->query($sql) === TRUE)
{
echo "New record created successfully";
}
$sql = "INSERT INTO table3 (id_ref , columns list)
VALUES ($latest_id,other fields)";
if ($conn->query($sql) === TRUE)
{
echo "New record created successfully";
}
I am trying to insert records in 2 different mysql tables. Here's the situation:
Table 1: is_main that contains records of resorts with a primary key called id.
Table 2: is_features that contains a list of features that a resort can have (i.e. beach, ski, spa etc...). Each feature has got a primary key called id.
Table 3: is_i2f to connect each resort id with the feature id. This table has got 2 fields: id_i and id_f. Both fields are primary key.
I have created a form to insert a new resort, but I'm stuck here. I need a proper mysql query to insert a new resort in the is_main table and insert in is_i2f one record for each feature it has, with the id of the resort id id_i and the id of the feature id id_f.
$features = ['beach','relax','city_break','theme_park','ski','spa','views','fine_dining','golf'];
mysql_query("INSERT INTO is_main (inv_name, armchair, holiday, sipp, resort, price, rooms, inv_length, more_info)
VALUES ('$name', '$armchair', '$holiday', '$sipp', '$resort', '$price', '$rooms', '$length', '$more_info')");
$id = mysql_insert_id();
foreach($features as $feature) {
if(isset($_POST[$feature])) {
$$feature = 1;
mysql_query("INSERT INTO is_i2f (id_i, id_f) VALUES (" . $id . ", ?????????????? /missing part here????/ ); }
else {
$$feature = 0; }
}
Thanks.
Please, I'm going CrAzY!!!!!!!!!!!!!!
This may not be relevant to you, but...
Would it not make more sense to leave the link table unpopulated? You can use JOINs to then select what you need to populate the various views etc in your application
i.e. query to get 1 resort with all features:
SELECT
Id,
f.Id,
f.Name
FROM IS_MAIN m
CROSS JOIN IS_FEATURES f
WHERE m.Id = $RequiredResortId
Please find the answer on Mysql insert into 2 tables.
If you want to do multiple insert at a time you can write a SP to fulfill your needs
If I understand you correctly you could concatenate variable amount of to be inserted/selected values into one query. (This is the second query which needs an id from the first.)
//initializing variables
$id = mysql_insert_id();
$qTail = '';
$i = -1;
//standard beginning
$qHead = "INSERT INTO `is_i2f` (`id`,`feature`) VALUES ";
//loop through variable amount of variables
foreach($features] as $key => $feature) {
$i++;
//id stays the same, $feature varies
$qValues[$i] = "('{$id}', '{$feature}')";
//multiple values into one string
$qTail .= $qValues[$i] . ',';
} //end of foreach
//concatenate working query, need to remove last comma from $qTail
$q = $qHead . rtrim($qTail, ',');
Now you should have a usable insert query $q. Just echo it and see how it looks and test if it works.
Hope this was the case. If not, sorry...
I want to update a table by getting the last inserted id but it is giving no results.
here is the query :
$quer = mysql_query("UPDATE date
SET d_startdate = '$start', d_enddate = '$end'
WHERE d_id = LAST_INSERT_ID() AND d_sid = $id");
d_id is the primary key and d_sid is a foreign key of another table
I have used INSERT as well as UPDATE operation on my same table and its working fine. You can change this query as per your need.
<?php
$con = mysql_connect("localhost","root","") or die("Could not connect");
mysql_selectdb("test", $con);
$query = 'INSERT INTO item (`name`) VALUES ("DELTaaaA")';
$res = mysql_query($query, $con) or die(mysql_error());
echo "<pre>";
print_r($res);
$query = 'UPDATE item set name="DELTaaaA1" WHERE id = LAST_INSERT_ID()';
$res = mysql_query($query, $con) or die(mysql_error());
print_r($res);
?>
It should return 1 1
use code like this before that
SELECT LAST_INSERT_ID() and assign this to a variable, then use that variable in your code
I don't know the normal syntax, but PDO syntax is quiet simple, you can get last inserted id by the function PDO::lastInsertId() use it as $myPDOobject->lastInsertId() . More information here : http://php.net/manual/en/pdo.lastinsertid.php
LAST_INSERT_ID gives you the id of the most recent insert.
Suppose that you added a row which has d_id=10 (d_id set by auto increment) and d_sid=20 and then another one with d_id=11 (again, auto increment) and d_sid=30.
You then want to look for the most recent insert with d_sid=20, but doing this with LAST_INSERT_ID is not possible, since LAST_INSERT_ID has value 11, and no row matches with that d_id and d_sid=20. You have to keep track by yourself of the most recent d_id for each category, most likely when you insert the new rows.
Do the INSERT
SELECT the LAST_INSERT_ID (name it L_ID)
Store the tuple <d_sid, L_ID> somewhere, so you know that for d_sid your most recent INSERT has value L_ID
UPDATE your table where the d_sid is the one you want and d_id is taken from the tuple
As a side note, mysql_* is deprecated, so you should switch to something else like mysqli or PDO.
In my table I have an userID that is auto-incremented. In the same row I have an idHash. Is it possible to generate the idHash (simply an MD5 sum) from it directly with the same INSERT statement so that I don't have to SELECT the id, and then UPDATE the idHash again?
Problem is: I do not know the userID before it is being generated (auto-incremented) by MySQL.
Thanks
Frank
PS: I'm using PHP.
PPS: This question is all about a SINGLE INSERT. I know that I can use PHP or other languages to manually select the data and then update it.
I don't believe you can do it within a single INSERT statement.
What you probably could do is use an INSERT trigger, that both determines the new ID, hashes it, and then updates the record.
One solution I can recommend is using the last insert ID instead of re-querying the table. Here is a simplified example:
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "INSERT INTO users VALUES (....)";
$mysqli->query($query);
$newUserID = $mysqli->insert_id;
$query = "UPDATE users SET idHash = MD5(userID) WHERE userID = $newUserID";
$mysqli->query($query);
/* close connection */
$mysqli->close();
?>
AFAIK there's no "secure" way for doing this in the same query if you're using auto_increment.
However, if rows are never deleted in your table, you can use this little trick :
insert into mytable (col1, col2, col3, idhash)
values ('', '', '', md5(select max(id) from mytable))
I don't understand why you need to hash the id though, why not use the id directly ?
This seems to work for me:
CREATE TABLE tbl (id INT PRIMARY KEY AUTO_INCREMENT, idHash TEXT);
INSERT INTO tbl (idHash) VALUES (MD5(LAST_INSERT_ID() + 1));
SELECT *, MD5(id) FROM tbl;
Note this will only work on single-row inserts as LAST_INSERT_ID returns the insert ID of the first row inserted.
Performing MD5(column_name) on an auto_increment value does not work as the value has not been generated yet, so it is essentially calling MD5(0).
PHP snippet
<?
$tablename = "tablename";
$next_increment = 0;
$qShowStatus = "SHOW TABLE STATUS LIKE '$tablename'";
$qShowStatusResult = mysql_query($qShowStatus) or die ( "Query failed: " . mysql_error() . "<br/>" . $qShowStatus );
$row = mysql_fetch_assoc($qShowStatusResult);
$next_increment = $row['Auto_increment'];
echo "next increment number: [$next_increment]";
?>
This will get you the next auto-increment and then you can use this in your insert.
Note: This is not perfect (Your method is imperfect as you will effectively have 2 primary keys)
From: http://blog.jamiedoris.com/geek/560/
i got two tables and my environment transaction is allowed...
Table A - ID + Name
Table B - ID + Value A+ Value B+ IDTable A
may i know how to write the query to insert value at once ? hope it can be done within single query...just performance is the highest concern.
mysql_query("BEGIN");
$result_1 = mysql_query("INSERT INTO table_a ('name') values ('Chris')");
if( ! $result_1) {
mysql_query("ROLLBACK");
die(); // or handle the error however you choose
}
$table_1_id = mysql_insert_id();
$result_2 = mysql_query("INSERT INTO table_b ('value_a', 'value_b', 'table_a_id') values ('v1', 'v2', $table_1_id)");
if( ! $result_2) {
mysql_query("ROLLBACK");
die(); // or handle the error however you choose
}
mysql_query("COMMIT");
You can't do insert on different tables with a single query.
insert into tableA (name) values ('name');
set #last = last_insert_id();
insert into tableB (valueA,valueB,idtableA) values ('valueA','valueB',#last);