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I have table - config.
Schema:
config_name | config_value
And I would like to update multiple records in one query. I try like that:
UPDATE config
SET t1.config_value = 'value'
, t2.config_value = 'value2'
WHERE t1.config_name = 'name1'
AND t2.config_name = 'name2';
but that query is wrong :(
Can you help me?
Try either multi-table update syntax
UPDATE config t1 JOIN config t2
ON t1.config_name = 'name1' AND t2.config_name = 'name2'
SET t1.config_value = 'value',
t2.config_value = 'value2';
Here is a SQLFiddle demo
or conditional update
UPDATE config
SET config_value = CASE config_name
WHEN 'name1' THEN 'value'
WHEN 'name2' THEN 'value2'
ELSE config_value
END
WHERE config_name IN('name1', 'name2');
Here is a SQLFiddle demo
You can accomplish it with INSERT as below:
INSERT INTO mytable (id, a, b, c)
VALUES (1, 'a1', 'b1', 'c1'),
(2, 'a2', 'b2', 'c2'),
(3, 'a3', 'b3', 'c3'),
(4, 'a4', 'b4', 'c4'),
(5, 'a5', 'b5', 'c5'),
(6, 'a6', 'b6', 'c6')
ON DUPLICATE KEY UPDATE id=VALUES(id),
a=VALUES(a),
b=VALUES(b),
c=VALUES(c);
This insert new values into table, but if primary key is duplicated (already inserted into table) that values you specify would be updated and same record would not be inserted second time.
in my case I have to update the records which are more than 1000, for this instead of hitting the update query each time I preferred this,
UPDATE mst_users
SET base_id = CASE user_id
WHEN 78 THEN 999
WHEN 77 THEN 88
ELSE base_id END WHERE user_id IN(78, 77)
78,77 are the user Ids and for those user id I need to update the base_id 999 and 88 respectively.This works for me.
instead of this
UPDATE staff SET salary = 1200 WHERE name = 'Bob';
UPDATE staff SET salary = 1200 WHERE name = 'Jane';
UPDATE staff SET salary = 1200 WHERE name = 'Frank';
UPDATE staff SET salary = 1200 WHERE name = 'Susan';
UPDATE staff SET salary = 1200 WHERE name = 'John';
you can use
UPDATE staff SET salary = 1200 WHERE name IN ('Bob', 'Frank', 'John');
maybe for someone it will be useful
for Postgresql 9.5 works as a charm
INSERT INTO tabelname(id, col2, col3, col4)
VALUES
(1, 1, 1, 'text for col4'),
(DEFAULT,1,4,'another text for col4')
ON CONFLICT (id) DO UPDATE SET
col2 = EXCLUDED.col2,
col3 = EXCLUDED.col3,
col4 = EXCLUDED.col4
this SQL updates existing record and inserts if new one (2 in 1)
Camille's solution worked. Turned it into a basic PHP function, which writes up the SQL statement. Hope this helps someone else.
function _bulk_sql_update_query($table, $array)
{
/*
* Example:
INSERT INTO mytable (id, a, b, c)
VALUES (1, 'a1', 'b1', 'c1'),
(2, 'a2', 'b2', 'c2'),
(3, 'a3', 'b3', 'c3'),
(4, 'a4', 'b4', 'c4'),
(5, 'a5', 'b5', 'c5'),
(6, 'a6', 'b6', 'c6')
ON DUPLICATE KEY UPDATE id=VALUES(id),
a=VALUES(a),
b=VALUES(b),
c=VALUES(c);
*/
$sql = "";
$columns = array_keys($array[0]);
$columns_as_string = implode(', ', $columns);
$sql .= "
INSERT INTO $table
(" . $columns_as_string . ")
VALUES ";
$len = count($array);
foreach ($array as $index => $values) {
$sql .= '("';
$sql .= implode('", "', $array[$index]) . "\"";
$sql .= ')';
$sql .= ($index == $len - 1) ? "" : ", \n";
}
$sql .= "\nON DUPLICATE KEY UPDATE \n";
$len = count($columns);
foreach ($columns as $index => $column) {
$sql .= "$column=VALUES($column)";
$sql .= ($index == $len - 1) ? "" : ", \n";
}
$sql .= ";";
return $sql;
}
Execute the code below to update n number of rows, where Parent ID is the id you want to get the data from and Child ids are the ids u need to be updated so it's just u need to add the parent id and child ids to update all the rows u need using a small script.
UPDATE [Table]
SET column1 = (SELECT column1 FROM Table WHERE IDColumn = [PArent ID]),
column2 = (SELECT column2 FROM Table WHERE IDColumn = [PArent ID]),
column3 = (SELECT column3 FROM Table WHERE IDColumn = [PArent ID]),
column4 = (SELECT column4 FROM Table WHERE IDColumn = [PArent ID]),
WHERE IDColumn IN ([List of child Ids])
Execute the below code if you want to update all record in all columns:
update config set column1='value',column2='value'...columnN='value';
and if you want to update all columns of a particular row then execute below code:
update config set column1='value',column2='value'...columnN='value' where column1='value'
Assuming you have the list of values to update in an Excel spreadsheet with config_value in column A1 and config_name in B1 you can easily write up the query there using an Excel formula like
=CONCAT("UPDATE config SET config_value = ","'",A1,"'", " WHERE config_name = ","'",B1,"'")
INSERT INTO tablename
(name, salary)
VALUES
('Bob', 1125),
('Jane', 1200),
('Frank', 1100),
('Susan', 1175),
('John', 1150)
ON DUPLICATE KEY UPDATE salary = VALUES(salary);
UPDATE 2021 / MySql v8.0.20 and later
The most upvoted answer advises to use the VALUES function which is now DEPRECATED for the ON DUPLICATE KEY UPDATE syntax. With v8.0.20 you get a deprecation warning with the VALUES function:
INSERT INTO chart (id, flag)
VALUES (1, 'FLAG_1'),(2, 'FLAG_2')
ON DUPLICATE KEY UPDATE id = VALUES(id), flag = VALUES(flag);
[HY000][1287] 'VALUES function' is deprecated and will be removed in a future release. Please use an alias (INSERT INTO ... VALUES (...) AS alias) and replace VALUES(col) in the ON DUPLICATE KEY UPDATE clause with alias.col instead
Use the new alias syntax instead:
official MySQL worklog
Docs
INSERT INTO chart (id, flag)
VALUES (1, 'FLAG_1'),(2, 'FLAG_2') AS aliased
ON DUPLICATE KEY UPDATE flag=aliased.flag;
just make a transaction statement, with multiple update statement and commit. In error case, you can just rollback modification handle by starting transaction.
START TRANSACTION;
/*Multiple update statement*/
COMMIT;
(This syntax is for MySQL, for PostgreSQL, replace 'START TRANSACTION' by 'BEGIN')
Try either multi-table update syntax
Try it copy and SQL query:
CREATE TABLE #temp (id int, name varchar(50))
CREATE TABLE #temp2 (id int, name varchar(50))
INSERT INTO #temp (id, name)
VALUES (1,'abc'), (2,'xyz'), (3,'mno'), (4,'abc')
INSERT INTO #temp2 (id, name)
VALUES (2,'def'), (1,'mno1')
SELECT * FROM #temp
SELECT * FROM #temp2
UPDATE t
SET name = CASE WHEN t.id = t1.id THEN t1.name ELSE t.name END
FROM #temp t
INNER JOIN #temp2 t1 on t.id = t1.id
select * from #temp
select * from #temp2
drop table #temp
drop table #temp2
UPDATE table name SET field name = 'value' WHERE table name.primary key
If you need to update several rows at a time, the alternative is prepared statement:
database complies a query pattern you provide the first time, keep the compiled result for current connection (depends on implementation).
then you updates all the rows, by sending shortened label of the prepared function with different parameters in SQL syntax, instead of sending entire UPDATE statement several times for several updates
the database parse the shortened label of the prepared function , which is linked to the pre-compiled result, then perform the updates.
next time when you perform row updates, the database may still use the pre-compiled result and quickly complete the operations (so the first step above can be omitted since it may take time to compile).
Here is PostgreSQL example of prepare statement, many of SQL databases (e.g. MariaDB,MySQL, Oracle) also support it.
I am trying to insert records in 2 different mysql tables. Here's the situation:
Table 1: is_main that contains records of resorts with a primary key called id.
Table 2: is_features that contains a list of features that a resort can have (i.e. beach, ski, spa etc...). Each feature has got a primary key called id.
Table 3: is_i2f to connect each resort id with the feature id. This table has got 2 fields: id_i and id_f. Both fields are primary key.
I have created a form to insert a new resort, but I'm stuck here. I need a proper mysql query to insert a new resort in the is_main table and insert in is_i2f one record for each feature it has, with the id of the resort id id_i and the id of the feature id id_f.
$features = ['beach','relax','city_break','theme_park','ski','spa','views','fine_dining','golf'];
mysql_query("INSERT INTO is_main (inv_name, armchair, holiday, sipp, resort, price, rooms, inv_length, more_info)
VALUES ('$name', '$armchair', '$holiday', '$sipp', '$resort', '$price', '$rooms', '$length', '$more_info')");
$id = mysql_insert_id();
foreach($features as $feature) {
if(isset($_POST[$feature])) {
$$feature = 1;
mysql_query("INSERT INTO is_i2f (id_i, id_f) VALUES (" . $id . ", ?????????????? /missing part here????/ ); }
else {
$$feature = 0; }
}
Thanks.
Please, I'm going CrAzY!!!!!!!!!!!!!!
This may not be relevant to you, but...
Would it not make more sense to leave the link table unpopulated? You can use JOINs to then select what you need to populate the various views etc in your application
i.e. query to get 1 resort with all features:
SELECT
Id,
f.Id,
f.Name
FROM IS_MAIN m
CROSS JOIN IS_FEATURES f
WHERE m.Id = $RequiredResortId
Please find the answer on Mysql insert into 2 tables.
If you want to do multiple insert at a time you can write a SP to fulfill your needs
If I understand you correctly you could concatenate variable amount of to be inserted/selected values into one query. (This is the second query which needs an id from the first.)
//initializing variables
$id = mysql_insert_id();
$qTail = '';
$i = -1;
//standard beginning
$qHead = "INSERT INTO `is_i2f` (`id`,`feature`) VALUES ";
//loop through variable amount of variables
foreach($features] as $key => $feature) {
$i++;
//id stays the same, $feature varies
$qValues[$i] = "('{$id}', '{$feature}')";
//multiple values into one string
$qTail .= $qValues[$i] . ',';
} //end of foreach
//concatenate working query, need to remove last comma from $qTail
$q = $qHead . rtrim($qTail, ',');
Now you should have a usable insert query $q. Just echo it and see how it looks and test if it works.
Hope this was the case. If not, sorry...
How can you make one query of this two?? I will insert data into two tables.
$query = "
INSERT INTO dc_mail_users (
i_id_pk, c_user, c_passwd_md5, i_user_active_id_fk, i_user_type_id_fk
) VALUES (
%1%, %2%, %3%, %4%, %5%
)";
$query2 = "
INSERT INTO dc_mail_user_data (
i_id_ut, c_user_sex, c_user_name, c_user_surname, c_user_url
) VALUES (
%1%, %2%, %3%, %4%, %5%
)";
You cannot insert into 2 tables with one query.
You would need to use a stored procedure where you can put that inserts.
What's the purpose of this? Are you trying to insert data into two different tables from one HTML form? I don't know about stored procedures but I use a transaction in similar case like this:
$d = dbSingle::dbLink();
//set autocommit to false
mysqli_autocommit($d->getDbc(), FALSE);
$query = " INSERT INTO dc_mail_users (
i_id_pk, c_user, c_passwd_md5, i_user_active_id_fk, i_user_type_id_fk
) VALUES (
%1%, %2%, %3%, %4%, %5%
)";
$r = $d->sqlQ($query);
//get the last inserted id for the second query
$last_insert_id = $d->getInsertId();
$query2 = "
INSERT INTO dc_mail_user_data (
i_id_ut, c_user_sex, c_user_name, c_user_surname, c_user_url
) VALUES (
%{$last_insert_id}%, %2%, %3%, %4%, %5% //not sure about the syntax, sorry
)";
$r2 = $d->sqlQ($query2);
//rollback if either one of the queries failed
if (!$r || (isset($r2) && !$r2)) {
mysqli_rollback($d->getDbc());
}
else {
//commit if everything worked
mysqli_commit($d->getDbc());
//autocommit on
mysqli_autocommit($d->getDbc(), TRUE);
}
This assumes i_id_ut in the table dc_mail_user_data is the FK and the i_id_pk is an auto increment field. I have a class called dbSingle that contains the query functions and database connection. Hope it's clear enough to be used with regular mysqli functions.
You can do with trigger or stored procedures but not with simple insert query.
$query = "
INSERT INTO dc_mail_users
(i_id_pk, c_user, c_passwd_md5, i_user_active_id_fk, i_user_type_id_fk)
VALUES (%1%, %2%, %3%, %4%, %5%)
";
$query2 = "
INSERT INTO dc_mail_user_data
(c_user_sex, c_user_name, c_user_surname, c_user_url)
VALUES (%1%, %2%, %3%, %4%)";
// start query 1
$dbh = new DB_Mysql_Extended;
$dbh->prepare($query)->execute($this->i_id_pk, $this->c_user, $this->c_passwd_md5, $this->i_user_active_id_fk, $this->i_user_type_id_fk);
// start query 2
$dbh2 = new DB_Mysql_Extended;
$dbh2->prepare($query2)->execute($this->c_user_sex, $this->c_user_name, $this->c_user_surname, $this->c_user_url);
In my table I have an userID that is auto-incremented. In the same row I have an idHash. Is it possible to generate the idHash (simply an MD5 sum) from it directly with the same INSERT statement so that I don't have to SELECT the id, and then UPDATE the idHash again?
Problem is: I do not know the userID before it is being generated (auto-incremented) by MySQL.
Thanks
Frank
PS: I'm using PHP.
PPS: This question is all about a SINGLE INSERT. I know that I can use PHP or other languages to manually select the data and then update it.
I don't believe you can do it within a single INSERT statement.
What you probably could do is use an INSERT trigger, that both determines the new ID, hashes it, and then updates the record.
One solution I can recommend is using the last insert ID instead of re-querying the table. Here is a simplified example:
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "INSERT INTO users VALUES (....)";
$mysqli->query($query);
$newUserID = $mysqli->insert_id;
$query = "UPDATE users SET idHash = MD5(userID) WHERE userID = $newUserID";
$mysqli->query($query);
/* close connection */
$mysqli->close();
?>
AFAIK there's no "secure" way for doing this in the same query if you're using auto_increment.
However, if rows are never deleted in your table, you can use this little trick :
insert into mytable (col1, col2, col3, idhash)
values ('', '', '', md5(select max(id) from mytable))
I don't understand why you need to hash the id though, why not use the id directly ?
This seems to work for me:
CREATE TABLE tbl (id INT PRIMARY KEY AUTO_INCREMENT, idHash TEXT);
INSERT INTO tbl (idHash) VALUES (MD5(LAST_INSERT_ID() + 1));
SELECT *, MD5(id) FROM tbl;
Note this will only work on single-row inserts as LAST_INSERT_ID returns the insert ID of the first row inserted.
Performing MD5(column_name) on an auto_increment value does not work as the value has not been generated yet, so it is essentially calling MD5(0).
PHP snippet
<?
$tablename = "tablename";
$next_increment = 0;
$qShowStatus = "SHOW TABLE STATUS LIKE '$tablename'";
$qShowStatusResult = mysql_query($qShowStatus) or die ( "Query failed: " . mysql_error() . "<br/>" . $qShowStatus );
$row = mysql_fetch_assoc($qShowStatusResult);
$next_increment = $row['Auto_increment'];
echo "next increment number: [$next_increment]";
?>
This will get you the next auto-increment and then you can use this in your insert.
Note: This is not perfect (Your method is imperfect as you will effectively have 2 primary keys)
From: http://blog.jamiedoris.com/geek/560/
I have a MySQL question that I think must be quite easy. I need to return the LAST INSERTED ID from table1 when I run the following MySql query:
INSERT INTO table1 (title,userid) VALUES ('test',1);
INSERT INTO table2 (parentid,otherid,userid) VALUES (LAST_INSERT_ID(),4,1);
SELECT LAST_INSERT_ID();
As you can understand the current code will just return the LAST INSERT ID of table2 instead of table1, how can I get the id from table1 even if I insert into table2 between?
You could store the last insert id in a variable :
INSERT INTO table1 (title,userid) VALUES ('test', 1);
SET #last_id_in_table1 = LAST_INSERT_ID();
INSERT INTO table2 (parentid,otherid,userid) VALUES (#last_id_in_table1, 4, 1);
Or get the max id from table1 (EDIT: Warning. See note in comments from Rob Starling about possible errors from race conditions when using the max id)
INSERT INTO table1 (title,userid) VALUES ('test', 1);
INSERT INTO table2 (parentid,otherid,userid) VALUES (LAST_INSERT_ID(), 4, 1);
SELECT MAX(id) FROM table1;
(Warning: as Rob Starling points out in the comments)
Since you actually stored the previous LAST_INSERT_ID() into the second table, you can get it from there:
INSERT INTO table1 (title,userid) VALUES ('test',1);
INSERT INTO table2 (parentid,otherid,userid) VALUES (LAST_INSERT_ID(),4,1);
SELECT parentid FROM table2 WHERE id = LAST_INSERT_ID();
This enables you to insert a row into 2 different tables and creates a reference to both tables too.
START TRANSACTION;
INSERT INTO accounttable(account_username)
VALUES('AnAccountName');
INSERT INTO profiletable(profile_account_id)
VALUES ((SELECT account_id FROM accounttable WHERE account_username='AnAccountName'));
SET #profile_id = LAST_INSERT_ID();
UPDATE accounttable SET `account_profile_id` = #profile_id;
COMMIT;
I had the same problem in bash and i'm doing something like this:
mysql -D "dbname" -e "insert into table1 (myvalue) values ('${foo}');"
which works fine:-) But
mysql -D "dbname" -e "insert into table1 (myvalue) values ('${foo}');set #last_insert_id = LAST_INSERT_ID();"
mysql -D "dbname" -e "insert into table2 (id_tab1) values (#last_insert_id);"
don't work. Because after the first command, the shell will be logged out from mysql and logged in again for the second command, and then the variable #last_insert_id isn't set anymore.
My solution is:
lastinsertid=$(mysql -B -N -D "dbname" -e "insert into table1 (myvalue) values ('${foo}');select LAST_INSERT_ID();")
mysql -D "dbname" -e "insert into table2 (id_tab1) values (${lastinsertid});"
Maybe someone is searching for a solution an bash :-)
We only have one person entering records, so I execute the following query immediately following the insert:
$result = $conn->query("SELECT * FROM corex ORDER BY id DESC LIMIT 1");
while ($row = $result->fetch_assoc()) {
$id = $row['id'];
}
This retrieves the last id from the database.
It would be possible to save the last_id_in_table1 variable into a php variable to use it later?
With this last_id I need to attach some records in another table with this last_id, so I need:
1) Do an INSERT and get the last_id_in_table1
INSERT into Table1(name) values ("AAA");
SET #last_id_in_table1 = LAST_INSERT_ID();
2) For any indeterminated rows in another table, UPDATING these rows with the last_id_insert generated in the insert.
$element = array(some ids)
foreach ($element as $e){
UPDATE Table2 SET column1 = #last_id_in_table1 WHERE id = $e
}
Instead of this LAST_INSERT_ID()
try to use this one
mysqli_insert_id(connection)
For no InnoDB solution: you can use a procedure
don't forgot to set the delimiter for storing the procedure with ;
CREATE PROCEDURE myproc(OUT id INT, IN otherid INT, IN title VARCHAR(255))
BEGIN
LOCK TABLES `table1` WRITE;
INSERT INTO `table1` ( `title` ) VALUES ( #title );
SET #id = LAST_INSERT_ID();
UNLOCK TABLES;
INSERT INTO `table2` ( `parentid`, `otherid`, `userid` ) VALUES (#id, #otherid, 1);
END
And you can use it...
SET #myid;
CALL myproc( #myid, 1, "my title" );
SELECT #myid;
In trigger BEFORE_INSERT this working for me:
SET #Last_Insrt_Id = (SELECT(AUTO_INCREMENT /*-1*/) /*as Last_Insert_Id*/
FROM information_schema.tables
WHERE table_name = 'tblTableName' AND table_schema = 'schSchemaName');
Or in simple select:
SELECT(AUTO_INCREMENT /*-1*/) as Last_Insert_Id
FROM information_schema.tables
WHERE table_name = 'tblTableName' AND table_schema = 'schSchemaName');
If you want, remove the comment /*-1*/ and test in other cases.
For multiple use, I can write a function. It's easy.
For last and second last:
INSERT INTO `t_parent_user`(`u_id`, `p_id`) VALUES ((SELECT MAX(u_id-1) FROM user) ,(SELECT MAX(u_id) FROM user ) );
We could also use $conn->insert_id;
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
if ($conn->query($sql) === TRUE) {
$last_id = $conn->insert_id;
echo "New record created successfully. Last inserted ID is: " . $last_id;
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}
My code does not work for me. Any idea to recover the id of my last insert this is my code I am new developing and I do not know much
I GOT ERROR IN THE QUERY AND I DON'T KNOW HOW TO SEND PRINT IN THE LINE OF $ session-> msg ('s', "Product added successfully. Make cost configuration". LAST_INSERT_ID ());
ALREADY VERIFY AND IT IS CORRECT THE CONNECTION AND THE FIELDS OF THE DATABASE.
<?php
if(isset($_POST['add_producto'])){
$req_fields = array( 'nombre', 'categoria', 'proveedor');
validate_fields($req_fields);
if(empty($errors)){
$codigobarras = remove_junk($db->escape($_POST['codigobarras']));
$identificador = remove_junk($db->escape($_POST['identificador']));
$nombre = remove_junk($db->escape($_POST['nombre']));
$categoria = (int)$db->escape($_POST['categoria']);
$etiquetas = remove_junk($db->escape($_POST['etiquetas']));
$unidadmedida = remove_junk($db->escape($_POST['unidadmedida']));
$proveedor = remove_junk($db->escape($_POST['proveedor']));
$fabricante = remove_junk($db->escape($_POST['idfabricante']));
$maximo = remove_junk($db->escape($_POST['maximo']));
$minimo = remove_junk($db->escape($_POST['minimo']));
$descripcion = remove_junk($db->escape($_POST['descripcion']));
$dias_vencimiento = remove_junk($db->escape($_POST['dias_vencimiento']));
$servicio = "0";
if (isset($_POST['servicio'])){
$servicio =implode($_POST['servicio']);
}
$numeroserie = "0";
if (isset($_POST['numeroserie'])){
$numeroserie =implode($_POST['numeroserie']);
}
$ingrediente = "0";
if (isset($_POST['ingrediente'])){
$ingrediente =implode($_POST['ingrediente']);
}
$date = make_date();
$query = "INSERT INTO productos (";
$query .=" codigo_barras,identificador_producto,nombre,idcategoria,idetiquetas,unidad_medida,idproveedor,idfabricante,max_productos,min_productos,descripcion,dias_vencimiento,servicio,numero_serie,ingrediente,activo";
$query .=") VALUES (";
$query .=" '{$codigobarras}', '{$identificador}', '{$nombre}', '{$categoria}', '{$etiquetas}', '{$unidadmedida}', '{$proveedor}', '{$fabricante}', '{$maximo}', '{$minimo}', '{$descripcion}', '{$dias_vencimiento}', '{$servicio}', '{$numeroserie}', '{$ingrediente}', '1'";
$query .=");";
$query .="SELECT LAST_INSERT_ID();";
if($db->query($query)){
$session->msg('s',"Producto agregado exitosamente. Realizar configuracion de costos" . LAST_INSERT_ID());
redirect('precio_producto.php', false);
} else {
$session->msg('d',' Lo siento, registro falló.');
redirect('informacion_producto.php', false);
}
} else{
$session->msg("d", $errors);
redirect('informacion_producto.php',false);
}
}
?>
Just to add for Rodrigo post, instead of LAST_INSERT_ID() in query you can use SELECT MAX(id) FROM table1;, but you must use (),
INSERT INTO table1 (title,userid) VALUES ('test', 1)
INSERT INTO table2 (parentid,otherid,userid) VALUES ( (SELECT MAX(id) FROM table1), 4, 1)
If you need to have from mysql, after your query, the last auto-incremental id without another query, put in your code:
mysql_insert_id();