Multiple options for query from select menu - mysql

Question

I have a search area which contains 3 field, one is an input field and the other two are drop down menus. Either someone enters something into the input field or they select from BOTH of the drop downs (state and city).
Input search works fine. Select menus do not.
Here is the form.
<form name="ffl_finder" method="get" action="index.php">
Enter a Zip Code to find a Firearms Dealer near you: <br />
<input name="q" type="text" id="q" size="40">
Select a State AND a City<br />
<select name="qoption2">
<option value="" selected="selected">Select . . .</option>
<?php
$sql2 = "SELECT DISTINCT state from ffl_list order by state asc";
$rs_results2 = mysql_query($sql2) or die(mysql_error());
while ($rrows2 = mysql_fetch_array($rs_results2)) {
?>
<option value="<?php echo $rrows2[state]; ?>"><?php echo $rrows2[state]; ?></option>
<?php
}
?>
</select>
<select name="qoption3">
<option value="" selected="selected">Select . . .</option>
<?php
$sql3 = "SELECT DISTINCT city from ffl_list order by city asc";
$rs_results3 = mysql_query($sql3) or die(mysql_error());
while ($rrows3 = mysql_fetch_array($rs_results3)) {
?>
<option value="<?php echo $rrows3[city]; ?>"><?php echo $rrows3[city]; ?></option>
<?php
}
?>
</select>
<input name="doSearch" type="submit" id="doSearch" value="Search">
</form>
Here is the query:
<?php if ($get['doSearch'] == 'Search') {
//$cond2 = '';
if($get['qoption2'] != '') {
$cond2 = "`state` = 'qoption2'";
}
//$cond3 = '';
if($get['qoption3'] != '') {
$cond3 = "`city` = 'qoption3'";
}
if($get['q'] == '') {
$sql = "select * from ffl_list where $cond2 and $cond3 order by state asc, city asc";
}
else {
$sql = "select * from ffl_list where `zip` = '$_REQUEST[q]' ORDER BY `id` asc";
}
$rs_results = mysql_query($sql) or die(mysql_error());
} ?>
I need the query to search both city and state and I cannot seem to get the conditions right. I know this is a lot of code but if someone could help that would be great.
Thanks,
Clint

Answer 1

<?php
while ($rrows2 = mysql_fetch_array($rs_results2))
{
?>
<option value="<?php echo $rrows2['state']; ?>"><?php echo $rrows2['state']; ?></option>
<?php
}
?>
state and citymay be cols' names of the ffl_list table, you have to use a string a key of the returned array from mysql_Fetch_array. You did wrong for $rrows2 and $rrows3
When you create your filter for the query, you set a hard string, not GETted data :
$cond2 = '';
if($_GET['qoption2'] != '') {
$cond2 = "`state` = '".$_GET['qoption2']."'";
}