I have the following SQL code:
select distinct members_main.membership_type,
payment_method,sum(amount_paid)
from members_main, members_payments
where members_main.contact_id=members_payments.contact_id
group by members_main.membership_type,payment_method
That returns the following:
I want to be able to return the results in the following table grid format:
Does anyone know if or how I can do this within MySQL?
Thanks,
John
Depending on data complexity either go with bluefeet's way or if the payment_method amount is dynamic then it sounds like you need a pivot table. Try looking at this.
MySQL does not have a pivot function but you can use a CASE expression and an aggregate function to turn the rows into columns:
select m.membership_type,
sum(case when p.payment_method = 'Cash' then amount_paid else 0 end) Cash,
sum(case when p.payment_method = 'Credit Card' then amount_paid else 0 end) CreditCard,
sum(case when p.payment_method = 'Paypal' then amount_paid else 0 end) Paypal
from members_main m
inner join members_payments p
on m.contact_id=p.contact_id
group by m.membership_type;
If you are going to have an unknown number of payment_method's, then you will want to look at using a prepared statement to generate dynamic SQL:
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(CASE WHEN p.payment_method = ',
payment_method,
' THEN amount_paid else 0 END) AS `',
payment_method, '`'
)
) INTO #sql
FROM members_payments ;
SET #sql
= CONCAT('SELECT m.membership_type, ', #sql, '
from members_main m
inner join members_payments p
on m.contact_id=p.contact_id
group by m.membership_type');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
Related
I could not solve this question, any help?
Batsman_detail table has the columns ,
[Opposition (varchar), runs(int), dismissal(varchar), venue(varchar)]:
opposition column has may countries in it.
runs column has the amount of runs scored by the batsman in that match.
dimissal column has any of the following values caught/bowled/run out/not out.
venue column has the stadium name where the match is held.
Now you should write a query such that the output table must have that number of times the batsman had gone out in a type of dismissal against the countries Pakistan,Australia and Srilanka (Original table contains many countries.),
Example output format :
opposition caught bowled runout notout
Pakistan 3 5 7 9
Australia 0 4 4 1
Sri Lanka 4 2 3 4
You seem to want conditional aggregation:
select opposition,
sum(case when dismissal = 'caught' then runs else 0 end) caught,
sum(case when dismissal = 'bowled' then runs else 0 end) bowled,
sum(case when dismissal = 'run out' then runs else 0 end) run_out,
sum(case when dismissal = 'not out' then runs else 0 end) not_out
from batsman
group by opposition
This sums the runs for each value of dismissal. If you just want to count the occurences, then:
select opposition,
sum(dismissal = 'caught') caught,
sum(dismissal = 'bowled') bowled,
sum(dismissal = 'run out') run_out,
sum(dismissal = 'not out') not_out
from batsman
group by opposition
You can distinctly select all dismissal cases and then pivot dynamically as
SET #sql = NULL;
SELECT GROUP_CONCAT(
CONCAT(
'SUM(CASE WHEN dismissal =''', dismissal, ''' THEN runs ELSE 0 END ) AS ',
dismissal
)
)
INTO #sql
FROM ( SELECT DISTINCT dismissal
FROM Batsman_detail
) b;
SET #sql = CONCAT('SELECT opposition,',#sql,
' FROM Batsman_detail
GROUP BY opposition');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
Demo
I am new to SQL (mySQL) and I am trying to create a query that will populate a google chart specifically
The result should look something like this:
['group_name', 'Open_tickets_count', 'closed_tickets_count'],
['Team A', 10, 400],
['Team B', 30, 460],
['Team C', 66, 1120],
['Team D', 5, 540]
I have a tickets table that includes the following fields: id ticket_status group_name.
A few things:
In this example I only have two statuses, but the number of
statuses is actually variable
The number of teams is also variable
the actual group_names and tickets_statuses are ids to other
tables in my real table. (but I can figure out how to substitute)
I have tried everything my imagination and limited knowledge allows and got not even near to achieve this. Any help or pointers would be highly appreciated.
Thank you.
[Adding sample table structures (only relevant fields)]
Table: tickets
'id', 'int(10)'
'ticket_status_id', 'int(10)'
'ticket_group_id', 'int(10)'
Table: status
'id', 'int(10)'
'name', 'varchar(250)'
Table: groups
'id', 'int(10)'
'name', 'varchar(250)'
In order to achieve your goal you need to use conditional SUM() with GROUP BY and dynamic SQL (PREPARE, EXECUTE).
Your base script might look like this
SET #sql = '';
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(CASE WHEN t.ticket_status = ''',
id,
''' THEN 1 ELSE 0 END) `',
name, '`'
)
) INTO #sql
FROM
status;
SET #sql = CONCAT
('SELECT g.name, ', #sql, '
FROM tickets t JOIN status s
ON t.ticket_status = s.id JOIN groups g
ON t.ticket_group_id = g.id
GROUP BY t.ticket_group_id, g.name'
);
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
Here is SQLFiddle demo.
Lets go with your assumptions.
You can try something like
SELECT group_name,
SUM(CASE WHEN ts.status = 'OPEN' THEN 1 ELSE 0 END) Open_tickets_count
SUM(CASE WHEN ts.status = 'CLOSED' THEN 1 ELSE 0 END) closed_tickets_count
FROM tickets t INNER JOIN
ticket_statusses ts ON t.ticket_status = ts.id
GROUP BY group_name
You would have to add new columns for different statusses.
I have the following three queries
SELECT COUNT(*) as cached_type_a, DATE(datetime) as datetime
FROM requests
WHERE cached = 'a'
GROUP BY DAY(datetime);
SELECT COUNT(*) as cached_type_b, DATE(datetime) as datetime
FROM requests
WHERE cached = 'b'
GROUP BY DAY(datetime);
SELECT COUNT(*) as cached_type_c, DATE(datetime) as datetime
FROM requests
WHERE cached = 'c'
GROUP BY DAY(datetime);
Is it possible to combine them into a single query with 4 columns
cached_type_a, cached_type_b, cached_type_c, datetime?
If you have only three possible values of cache, you can use this,
SELECT DATE(datetime) as datetime,
SUM(CASE WHEN cached = 'a' THEN 1 ELSE 0 END) cached_a,
SUM(CASE WHEN cached = 'b' THEN 1 ELSE 0 END) cached_b,
SUM(CASE WHEN cached = 'c' THEN 1 ELSE 0 END) cached_c
FROM requests
GROUP BY DAY(datetime)
otherwise, if you have multiple number of cache, you can use Prepared Statement
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(CASE WHEN cached = ''',
cached,
''' then 1 ELSE 0 end) AS ',
CONCAT('cached_',cached)
)
) INTO #sql
FROM requests;
SET #sql = CONCAT('SELECT DATE(datetime) as datetime, ', #sql, '
FROM requests
GROUP BY DAY(datetime)');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SELECT COUNT(a.datetime) as cached_type_a,
COUNT(b.datetime) as cached_type_b,
COUNT(c.datetime) as cached_type_c,
DATE(a.datetime) as datetime
FROM requests a,
requests b,
requests c,
WHERE a.cached = 'a'
and b.cached = 'b'
and c.cached = 'c'
GROUP BY DAY(a.datetime), DAY(b.datetime), DAY(c.datetime);
i have one table with a single column having three values a,b and c.
Current snapshot of the table is
Table name:- tblTest
Values
tblColumn
a
a
a
b
b
b
b
c
c
i need to get the output exactly as
A B C
3 4 2
select sum(tblColumn = 'a') as A,
sum(tblColumn = 'b') as B,
sum(tblColumn = 'b') as C
from tblTest
SQL Fiddle Example
SELECT SUM(CASE WHEN colName = 'a' THEN 1 ELSE 0 END) as A,
SUM(CASE WHEN colName = 'b' THEN 1 ELSE 0 END) as B,
SUM(CASE WHEN colName = 'c' THEN 1 ELSE 0 END) as C
FROM tableName
another technique is by using PreparedStatement, this is very good if you have multiple unknown number group of values, eg, a,b,c,d,e,f,g,h,...
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(IF(tblColumn = ''',
tblColumn,
''', 1, 0)) AS ',
tblColumn
)
) INTO #sql
FROM
Table1;
SET #sql = CONCAT('SELECT ', #sql, ' FROM Table1');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SQLFiddle Demo
Try this
select tblColumn, Count(*) from tblTest group by tblColumn
I have query like this:
SELECT DATE,REGION,COUNT(*)
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION,DATE DESC
and the result is
What is the right query to display like this capture below
Could somebody help me?
This type of query is known as a PIVOT. Unfortunately, MySQL doesn't have a PIVOT function, so you will need to replicate the function using a CASE statement and an aggregate function.
If you know the number of columns to transform, then you can hard-code the values:
select region,
SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
from ALL_ID_DATA
group by region;
select region,
COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
from ALL_ID_DATA
group by region;
See SQL Fiddle with Demo.
Then adding this to your existing query, it would be:
SELECT REGION,
SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION
OR
SELECT REGION,
COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION
Now if you have an unknown number of dates to transform into columns, then you can use prepared statements and your query would be similar to this (See SQL Fiddle with Demo):
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(case when date = ''',
date,
''' then 1 else 0 end) AS ''',
Date(date), ''''
)
) INTO #sql
FROM ALL_ID_DATA;
select #sql;
SET #sql = CONCAT('SELECT region, ', #sql, '
FROM ALL_ID_DATA
GROUP BY region');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
Then placing your original query in the prepared statement the final query would be:
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(case when date = ''',
date,
''' then 1 else 0 end) AS ''',
Date(date), ''''
)
) INTO #sql
FROM ALL_ID_DATA;
select #sql;
SET #sql = CONCAT('SELECT region, ', #sql, '
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION=''inbound''
AND REASON_1 = ''complaint''');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
I think you are looking for this :
http://www.artfulsoftware.com/infotree/queries.php#78