I have query like this:
SELECT DATE,REGION,COUNT(*)
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION,DATE DESC
and the result is
What is the right query to display like this capture below
Could somebody help me?
This type of query is known as a PIVOT. Unfortunately, MySQL doesn't have a PIVOT function, so you will need to replicate the function using a CASE statement and an aggregate function.
If you know the number of columns to transform, then you can hard-code the values:
select region,
SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
from ALL_ID_DATA
group by region;
select region,
COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
from ALL_ID_DATA
group by region;
See SQL Fiddle with Demo.
Then adding this to your existing query, it would be:
SELECT REGION,
SUM(CASE WHEN date = '2012-09-24' THEN 1 END) as `2012-09-24`,
SUM(CASE WHEN date = '2012-09-30' THEN 1 END) as `2012-09-30`,
SUM(CASE WHEN date = '2012-10-01' THEN 1 END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION
OR
SELECT REGION,
COUNT(CASE WHEN date = '2012-09-24' THEN 1 ELSE null END) as `2012-09-24`,
COUNT(CASE WHEN date = '2012-09-30' THEN 1 ELSE null END) as `2012-09-30`,
COUNT(CASE WHEN date = '2012-10-01' THEN 1 ELSE null END) as `2012-10-01`
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION='inbound'
AND REASON_1 = 'complaint'
GROUP BY REGION
Now if you have an unknown number of dates to transform into columns, then you can use prepared statements and your query would be similar to this (See SQL Fiddle with Demo):
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(case when date = ''',
date,
''' then 1 else 0 end) AS ''',
Date(date), ''''
)
) INTO #sql
FROM ALL_ID_DATA;
select #sql;
SET #sql = CONCAT('SELECT region, ', #sql, '
FROM ALL_ID_DATA
GROUP BY region');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
Then placing your original query in the prepared statement the final query would be:
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(case when date = ''',
date,
''' then 1 else 0 end) AS ''',
Date(date), ''''
)
) INTO #sql
FROM ALL_ID_DATA;
select #sql;
SET #sql = CONCAT('SELECT region, ', #sql, '
FROM ALL_ID_DATA
WHERE DATE in (SUBDATE(CURDATE(),1),SUBDATE(CURDATE(),2),SUBDATE(CURDATE(),8))
AND DIRECTION=''inbound''
AND REASON_1 = ''complaint''');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
I think you are looking for this :
http://www.artfulsoftware.com/infotree/queries.php#78
Related
I have the following SQL code:
select distinct members_main.membership_type,
payment_method,sum(amount_paid)
from members_main, members_payments
where members_main.contact_id=members_payments.contact_id
group by members_main.membership_type,payment_method
That returns the following:
I want to be able to return the results in the following table grid format:
Does anyone know if or how I can do this within MySQL?
Thanks,
John
Depending on data complexity either go with bluefeet's way or if the payment_method amount is dynamic then it sounds like you need a pivot table. Try looking at this.
MySQL does not have a pivot function but you can use a CASE expression and an aggregate function to turn the rows into columns:
select m.membership_type,
sum(case when p.payment_method = 'Cash' then amount_paid else 0 end) Cash,
sum(case when p.payment_method = 'Credit Card' then amount_paid else 0 end) CreditCard,
sum(case when p.payment_method = 'Paypal' then amount_paid else 0 end) Paypal
from members_main m
inner join members_payments p
on m.contact_id=p.contact_id
group by m.membership_type;
If you are going to have an unknown number of payment_method's, then you will want to look at using a prepared statement to generate dynamic SQL:
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'sum(CASE WHEN p.payment_method = ',
payment_method,
' THEN amount_paid else 0 END) AS `',
payment_method, '`'
)
) INTO #sql
FROM members_payments ;
SET #sql
= CONCAT('SELECT m.membership_type, ', #sql, '
from members_main m
inner join members_payments p
on m.contact_id=p.contact_id
group by m.membership_type');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
I have a database (MySQL 5.5) similar to this:
ID Name Page Visited Date
1 Tim Page A 11-2-2000
1 Tim Page B 11-3-2000
1 Tim Page B 11-3-2000
2 Jeff Page C 11-5-2000
2 Jeff Page A 11-11-2000
I want to build a query (trying to at the moment), where the results would be similar to this:
ID Name Page A Visits Page B Visits Page C Visits
1 Tim 1 2 0
I assume that I need to run the following query against a subset (my question is how do I do this with essentially 3 counts)?:
SELECT * From database.mytable GROUP BY ID HAVING COUNT(*) >=1
SELECT ID, Name,
SUM(CASE WHEN `Page Visited` = 'Page A' THEN 1 ELSE 0 END) `Page A Visit`,
SUM(CASE WHEN `Page Visited` = 'Page B' THEN 1 ELSE 0 END) `Page B Visit`,
SUM(CASE WHEN `Page Visited` = 'Page C' THEN 1 ELSE 0 END) `Page C Visit`
FROM tableName
GROUP BY ID, Name
SQLFiddle Demo
if you have unknown number of page, you can also PreparedStatement
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(CASE WHEN `Page Visited` =''',
`Page Visited`,
''' then 1 ELSE 0 end) AS ',
CONCAT('`',`Page Visited`, ' Visits`')
)
) INTO #sql
FROM TableName;
SET #sql = CONCAT('SELECT ID, Name, ', #sql, '
FROM tableName
GROUP BY ID, Name');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SQLFiddle Demo
I have the following table:
----------------------------------------------
|ID|Vote_Item_ID|User_ID|Country_code| Vote|
|01| 105102151|user1 | CA| like|
|02| 105102151|user2 | CA|dislike|
|03| 105102151|user3 | UK|dislike|
|04| 105102151|user4 | UK| like|
|05| 105102151|user5 | UK| like|
----------------------------------------------
What I need to do is create an SQL statement that creates an array which totals the likes and dislikes for each country...The script I am using this with has 175 countries, so would this be an inefficient way to about it?
I'm not sure how to go about writing the Select statement, since I want the script to be reusable for many different "vote_item_id"s
I am using PDO with a MYSQL database by the way.
Thanks
SELECT Country_Code,
SUM(CASE WHEN vote = 'like' THEN 1 ELSE 0 END) `like`,
SUM(CASE WHEN vote = 'dislike' THEN 1 ELSE 0 END) dislike
FROM tableName
GROUP BY Country_Code
SQLFiddle Demo
or if you want PreparedStatement (both give the same results)
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(CASE WHEN vote = ''',
Vote,
''' then 1 Else 0 end) AS `',
Vote, '`'
)
) INTO #sql
FROM TableName;
SET #sql = CONCAT('SELECT Country_Code, ', #sql, '
FROM tableName
GROUP BY Country_Code');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SQLFiddle Demo
If you had shown your expected output, that would have been great.
Following sample is simple. So let us know what you really need beyond this. Would be happy to pitch in. :)
REFERENCE : SQLFIDDLE
CODE:
SELECT t.country_code,
sum(CASE WHEN t.vote = 'like'
THEN 1 ELSE 0 END) AS LIKES,
sum(CASE WHEN t.vote = 'dislike'
THEN 1 ELSE 0 END) AS DISLIKE
FROM tbl t
GROUP BY t.country_code
;
RESULTS:
COUNTRY_CODE LIKES DISLIKE
CA 1 1
UK 2 1
I have the following three queries
SELECT COUNT(*) as cached_type_a, DATE(datetime) as datetime
FROM requests
WHERE cached = 'a'
GROUP BY DAY(datetime);
SELECT COUNT(*) as cached_type_b, DATE(datetime) as datetime
FROM requests
WHERE cached = 'b'
GROUP BY DAY(datetime);
SELECT COUNT(*) as cached_type_c, DATE(datetime) as datetime
FROM requests
WHERE cached = 'c'
GROUP BY DAY(datetime);
Is it possible to combine them into a single query with 4 columns
cached_type_a, cached_type_b, cached_type_c, datetime?
If you have only three possible values of cache, you can use this,
SELECT DATE(datetime) as datetime,
SUM(CASE WHEN cached = 'a' THEN 1 ELSE 0 END) cached_a,
SUM(CASE WHEN cached = 'b' THEN 1 ELSE 0 END) cached_b,
SUM(CASE WHEN cached = 'c' THEN 1 ELSE 0 END) cached_c
FROM requests
GROUP BY DAY(datetime)
otherwise, if you have multiple number of cache, you can use Prepared Statement
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(CASE WHEN cached = ''',
cached,
''' then 1 ELSE 0 end) AS ',
CONCAT('cached_',cached)
)
) INTO #sql
FROM requests;
SET #sql = CONCAT('SELECT DATE(datetime) as datetime, ', #sql, '
FROM requests
GROUP BY DAY(datetime)');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SELECT COUNT(a.datetime) as cached_type_a,
COUNT(b.datetime) as cached_type_b,
COUNT(c.datetime) as cached_type_c,
DATE(a.datetime) as datetime
FROM requests a,
requests b,
requests c,
WHERE a.cached = 'a'
and b.cached = 'b'
and c.cached = 'c'
GROUP BY DAY(a.datetime), DAY(b.datetime), DAY(c.datetime);
i have one table with a single column having three values a,b and c.
Current snapshot of the table is
Table name:- tblTest
Values
tblColumn
a
a
a
b
b
b
b
c
c
i need to get the output exactly as
A B C
3 4 2
select sum(tblColumn = 'a') as A,
sum(tblColumn = 'b') as B,
sum(tblColumn = 'b') as C
from tblTest
SQL Fiddle Example
SELECT SUM(CASE WHEN colName = 'a' THEN 1 ELSE 0 END) as A,
SUM(CASE WHEN colName = 'b' THEN 1 ELSE 0 END) as B,
SUM(CASE WHEN colName = 'c' THEN 1 ELSE 0 END) as C
FROM tableName
another technique is by using PreparedStatement, this is very good if you have multiple unknown number group of values, eg, a,b,c,d,e,f,g,h,...
SET #sql = NULL;
SELECT
GROUP_CONCAT(DISTINCT
CONCAT(
'SUM(IF(tblColumn = ''',
tblColumn,
''', 1, 0)) AS ',
tblColumn
)
) INTO #sql
FROM
Table1;
SET #sql = CONCAT('SELECT ', #sql, ' FROM Table1');
PREPARE stmt FROM #sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;
SQLFiddle Demo
Try this
select tblColumn, Count(*) from tblTest group by tblColumn