I have one database with two tables: "music" and "agenda".
But for some reason once I have queried one table, I cannot perform a similar query on the other table. Or in any case, its variables are empty.
I'd think I could just keep the connection open and perform a second query after the first "while". Like so:
<?php
mysql_connect('localhost', 'root', 'root');
mysql_select_db('erikverwey');
$result = mysql_query("SELECT * FROM agenda ORDER BY date DESC LIMIT 0, 2") or die(mysql_error());
while($row = mysql_fetch_array($result)) {
$count++;
$date[$count] = $row['date'];
$time[$count] = $row['time'];
$place[$count] = $row['place'];
$venue[$count] = $row['venue'];
$who[$count] = $row['who'];
$concert[$count] = $row['concert'];
$urlvenue[$count] = $row['urlvenue'];
}
$result2 = mysql_query("SELECT * FROM music ORDER BY id LIMIT 0, 5") or die(mysql_error());
while($row = mysql_fetch_array($result2)) {
$count++;
$song[$count] = $row['song'];
$artist[$count] = $row['artist'];
$duration[$count] = $row['duration'];
$url[$count] = $row['url'];
}
mysql_close();
?>
But no. In this case, all the variables from the table "music" remain empty.
I've been looking for an answer, but no luck. I'm still new to MySQL, though, so apologies beforehand if this is standard stuff. Thanks!
I found the glitch. Because the counter "$count" was used a second time, it started where it left off and couldn't find any data.
Use a different counter, also in the variables (!), and all is good.
Related
I'm trying to use a variable from a row that is being selected from one table in a SELECT function targetted towards a second table. I tried doing this:
while ($row = mysqli_fetch_assoc($result)) {
$sender = $row['sender_id'];
$sql = "SELECT * FROM users WHERE user_id='$sender'";
$result = mysqli_query($conn, $sql);
while ($row2 = mysqli_fetch_assoc($result)) {
echo $row2['user_uid'];
}
}
I understand that this is not how you set a variable for each row, but I have no clue how it should be done otherwise. At the moment it only displays the username of the sender of the first notification in my inbox database, not the rest.
If anyone knows how to set a variable per row, please let me know. Thank you in advance.
getChildIds can be very slow if running it against a large set of resources, so I am trying to write a query and some code to get all the child ids faster.
However I am getting different results from getChildIds & my script.
Can anyone see why these would be yielding different results?
Method using getChildIDs:
$parentDepth = isset($scriptProperties['parentDepth']) ? $scriptProperties['parentDepth'] : 5;
$parents = explode(',', $parents);
$children = array();
foreach ($parents as $parent){
$ids = $modx->getChildIds($parent,10,array('context' => 'web'));
foreach($ids as $id){
$children[] = $id;
}
}
echo ' number of children = ' . count($children);
method using queriees & a loop:
$comma_separated = implode(",", $parents);
$sql = "SELECT `id` from modx_site_content where `parent` IN (".$comma_separated.") and published = 1 and isfolder = 0 and deleted = 0 and hidemenu = 0;";
$results = $modx->query($sql);
$mychildren = array();
while ($row = $results->fetch(PDO::FETCH_ASSOC)) {
$mychildren[] = $row['id'];
}
for($i=0; $i <= 10; $i++){
$comma_separated = implode(",", $mychildren);
$sql = "SELECT `id` from modx_site_content where `parent` IN (".$comma_separated.") and published = 1 and isfolder = 0 and deleted = 0 and hidemenu = 0;";
$results = $modx->query($sql);
while ($row = $results->fetch(PDO::FETCH_ASSOC)) {
$mychildren[] = $row['id'];
}
}
echo ' number of children = ' . count($mychildren);
The getChildIDs method takes nearly 1.5 seconds to run and gives about 1100 results
The SQL/script method runs un under 0.1 second and gives 1700 results.
Either I'm not appending the child ids to the array properly ~or~ maybe getChildIDs is filtering out some other results?
does anyone have any clues as to what could be happening here?
You can try to use built-in method of pdoFetch.
$pdo = $modx->getService('pdoFetch');
$ids = $pdo->getChildIds('modResource', 0);
print_r($ids);
It also recursive, but can be better in some situations.
Of course, you need to install pdoTools from the repository first.
Looking at the code again, the discrepancy in results is pretty obvious now. I'm appending results to the child id array, it's inserting duplicates since one parent can have many children.
the solution to avoid duplicates:
$mychildren[$row['id']] = $row['id'];
getChildIds - is recursive, so it slower by default.
I am developing a php script within the Joomla environment which queries the same table / database twice. Each time I need to know whether any matches are found.
It seemed that the best way would be to use the getNumRows(). The Joomla documentation is very specific on its use:
Miscellaneous Result Set Methods getNumRows()
getNumRows() will return the number of result rows found by the last
query and waiting to be read. To get a result from getNumRows() you
have to run it after the query and before you have retrieved any
results.
I follow this in my script. At the first query there is no problem, but the second query always throws up a warning - most likely because the getNumRows() call for the second time is after the retrieving results from the first query - which does not comply with the Joomla requirement.
Any ideas how to solve? Many thanks!
The part of my script in question reads:
$db = JFactory::getDBO();
$query = "SELECT * FROM #__art_mobiles WHERE user_agent_header='$ua'";
$db->setQuery($query);
$rowsAG = $db->getNumRows();
$replyAG = $db->loadRow();
if ($rowsAG == 0) {
//if no match check www.handsetdetection.com
//see https://www.handsetdetection.com/properties/vendormodel for current list of models in database together with headers
echo "not in local database - try external<br/>";
$prod = '';
if ($hd3->siteDetect()) {
$replyHD = $hd3->getReply();
$man = $replyHD['hd_specs']['general_vendor'];
$dev = $replyHD['hd_specs']['general_model'];
$os = $replyHD['hd_specs']['general_platform'];
echo "found in handsetdetection.com database<br/>";
//check for provisional match in local database
$query = "SELECT * FROM #__art_mobiles WHERE manufacturer='$man' AND device='$dev'";
$db->setQuery($query);
$rowsAGprov = $db->getNumRows();
$replyAGprov = $db->loadRow();
if ($rowsAGprov == 0) { **[ETC]**
I think this could be an issue with using $db->loadRow(); as getNumRows relies on an executed query.
For example you could try:
$db = JFactory::getDBO();
$query = "SELECT * FROM #__art_mobiles WHERE user_agent_header='$ua'";
$db->setQuery($query);
$replyAG = $db->query();
$rowsAG = $db->getNumRows();
And:
$query = "SELECT * FROM #__art_mobiles WHERE manufacturer='$man' AND device='$dev'";
$db->setQuery($query);
$replyAGprov = $db->query();
$rowsAGprov = $db->getNumRows();
Though I am not sure what/if the difference will be between the results returned from query and loadRow. It would be worth experimenting and seeing if this works.
Alternately, if you are only using getNumRows to see if a record exists, you could do some kind of check on your $replyAG variable instead. It again might be worth experimenting to see what loadRow returns if there are no results.
You need to add the following code before you write the the query:
$query = $db->getQuery(true);
You need to use
$db = JFactory::getDbo();
$query = $db->getQuery(true)
->select($db->qn(array('id')))
->from($db->qn('#__social_notifications'))
->where($db->qn('status') . ' = ' . $db->q(0));
$db->setQuery($query);
$db->execute();
$resultData = $db->getNumRows();
I have following code:
$query = "SELECT ads.*,
trafficsource.name AS trafficsource,
trafficsource.id AS trafficsourse_id,
FROM ads
JOIN trafficsource ON ads.trafficsourceId = trafficsource.id
WHERE advertiserId = '$advertiser_id'";
$mysqli = new mysqli();
$mysqli->connect('localhost', 'root', '', 'adsbase');
$result = $mysqli->query($query);
while ($row = $result->fetch_assoc()) {
echo "<h2>Traffic Sources: {$row['trafficsource']}</h2>";
}
This code show results like:
Traffic Sources: Example1
Traffic Sources: Example2
Traffic Sources: Example2
Traffic Sources: Example1
Traffic Sources: Example2
Traffic Sources: Example1
What I want and can't figure out is to show results like:
Traffic Sources: Example1, Example2
So without duplicates and also all in one line.
You nearly had it:
$result = $mysqli->query($query);
$trafficeSources = array();
while ($row = $result->fetch_assoc()) {
$trafficSources[] = $row['trafficsource'];
}
echo '<h2>Traffic Sources: ' . implode(', ', $trafficSources) . '</h2>';
EDIT: Query using DISTINCT
I'm assuming you only need the traffic source name, but feel free to add more columns back in if they're required. Bear in mind though that the DISTINCT applies to a distinct combination of all rows returned, so it may be possible that you could end up with duplicate traffic sources if other selected columns differ.
$query = "SELECT DISTINCT trafficsource.name AS trafficsource
FROM ads
JOIN trafficsource ON ads.trafficsourceId = trafficsource.id
WHERE advertiserId = '$advertiser_id'";
Try this small solution:
$trafic = array();
while ($row = $result->fetch_assoc()) {
if(!in_array($trafic)) $trafic[] = $row['trafficsource']
}
if(!empty($trafic)){
echo '<h2>Traffic Sources:' . imlode(',', $trafic) .'</h2>';
}
$trafficSources = array();
while ($row = $result->fetch_assoc()) {
if(!in_array($row['trafficsource'], $trafficSources) {
$trafficSources[] = $row['trafficsource'];
}
}
echo "<h2>Traffic Sources: ".implode(', ', $trafficSources)."</h2>";
Use Group by in 'trafficsource' in query and then in while loop concat each value of $row['trafficsource'] to other and echo it outside the while loop.
I have this script
$query = "SELECT id,last_name,first_name FROM users WHERE tmima_id='6'";
$result = #mysql_query($query);
while($row = mysql_fetch_array($result))
{
$i = 3;
$emp_id = $row['id'];
$cell = 'A'.$i;
$objPHPExcel->setActiveSheetIndex(0)
->setCellValue($cell, $row['last_name']. $row['first_name']);
$i++;
}
But in the .xls file it prints only one user. Why id doesnt print all of the users ? W
Thanks in advance.
I make the change you said with $sheet
$query = "SELECT id,last_name,first_name FROM users WHERE tmima_id='6'";
$result = #mysql_query($query);
while($row = mysql_fetch_array($result))
{
$i = 3;
$emp_id = $row['id'];
$cell = 'A'.$i;
$sheet->setCellValue($cell, $row['last_name']. $row['first_name']);
$i++;
}
But it still prints out only one record. And yes when i run the query in phpmyadmin it returns more than one record.
How can i print out data from mySql table.. What is going wrong ?
I am pretty sure it is because you are using a unique identifier (WHERE tmima_id='6'). It is only finding the results for that one unique identifier and displaying that. Hope this helps.
$i is being reset to row 3 every loop. Set $i=3; before the while loop, not inside it.