Show results from mysql query with php - mysql

Question

I have following code:
$query = "SELECT ads.*,
trafficsource.name AS trafficsource,
trafficsource.id AS trafficsourse_id,
FROM ads
JOIN trafficsource ON ads.trafficsourceId = trafficsource.id
WHERE advertiserId = '$advertiser_id'";
$mysqli = new mysqli();
$mysqli->connect('localhost', 'root', '', 'adsbase');
$result = $mysqli->query($query);
while ($row = $result->fetch_assoc()) {
echo "<h2>Traffic Sources: {$row['trafficsource']}</h2>";
}
This code show results like:
Traffic Sources: Example1
Traffic Sources: Example2
Traffic Sources: Example2
Traffic Sources: Example1
Traffic Sources: Example2
Traffic Sources: Example1
What I want and can't figure out is to show results like:
Traffic Sources: Example1, Example2
So without duplicates and also all in one line.

Answer 1

You nearly had it:
$result = $mysqli->query($query);
$trafficeSources = array();
while ($row = $result->fetch_assoc()) {
$trafficSources[] = $row['trafficsource'];
}
echo '<h2>Traffic Sources: ' . implode(', ', $trafficSources) . '</h2>';
EDIT: Query using DISTINCT
I'm assuming you only need the traffic source name, but feel free to add more columns back in if they're required. Bear in mind though that the DISTINCT applies to a distinct combination of all rows returned, so it may be possible that you could end up with duplicate traffic sources if other selected columns differ.
$query = "SELECT DISTINCT trafficsource.name AS trafficsource
FROM ads
JOIN trafficsource ON ads.trafficsourceId = trafficsource.id
WHERE advertiserId = '$advertiser_id'";

Answer 2

Try this small solution:
$trafic = array();
while ($row = $result->fetch_assoc()) {
if(!in_array($trafic)) $trafic[] = $row['trafficsource']
}
if(!empty($trafic)){
echo '<h2>Traffic Sources:' . imlode(',', $trafic) .'</h2>';
}

Answer 3

$trafficSources = array();
while ($row = $result->fetch_assoc()) {
if(!in_array($row['trafficsource'], $trafficSources) {
$trafficSources[] = $row['trafficsource'];
}
}
echo "<h2>Traffic Sources: ".implode(', ', $trafficSources)."</h2>";

Answer 4

Use Group by in 'trafficsource' in query and then in while loop concat each value of $row['trafficsource'] to other and echo it outside the while loop.