Sending field parameters to SSRS action link - reporting-services

I was trying to pass field parameters to Action Link in SSRS like,
http://mysite.aspx?id="+Fields!ID.Value
but it is saying as, Input String was not in a correct format. When i tried with the format
as http://mysite.aspx?id=10(10 is static not dynamic). It is not showing any error.
Please tell me what i can do, as i'm struck up with this issue.
Thanks in Advance,
Raghava.

right click the field you want to make hyperlink and select TextBox Properties, and then go to Action tab in the popup that appears.
and choose Go To Url option and click on expression and set the below given expression.
="http://mysite.aspx?id=" & Fields!ID.Value
it should work.

Related

Textbox with reference to dropdown returns nothing

I have cmbCountry on a form as an unbound dropdown. The dropdown works as expected. I have setup a textbox called txtCM_ID on the same form, in which I want to display the ID that was selected in the dropdown.
When I enter the record source for the textbox as =Forms![frm_ClientModel]!cmbCountry.Column(0) access automatically changes it to read =[Forms]![frm_ClientModel]![cmbCountry].[column](0)
My version returns the correct information when i test it in the VBE Immediate window. The code that access produces returns the below when run in the Immediate window:
runtime error 450: Wrong number of arguments or invalid property
assignment
The frustrating thing is, that regardless of where or how i enter the code in the control source, access changes it to its version. When the form is opened the txtCM_ID simply remains blank.
I have also tried to go around this problem by changing my reference to the following: Forms("frm_ClientModel").Controls("cmbCountry").column(0)
While this version (also tested and ok in VBE) doesn't produce an error, it too returns nothing in the text box.
What am I missing / doing wrong / overlooking?
Use just
=[cmbCountry]
To access the value of cmbCountry from other control.
I was not able to specifically determine why this happened, but ended up solving the issue by using the OnClick Event of the Dropdown and writing the needed info into the Textbox via VBA with this:
Private Sub cmbCountry_AfterUpdate()
Me.txt_CMID = Forms("frm_ClientModel").Controls("cmbCountry").Column(0)
End Sub
If anyone else finds an answer as to why form controls did not work properly I would be interested in hearing from you.

MS Access VBA display Listbox Count to Textbox

This is not working.
Me.Textbox = Me.ListBox.ListCount
It say;
What code should I put into it?
When I load the Form, it should display the count of the ListBox's items on the textbox.
The TextBox and ListBox are not the names of the variables, but oh the classes. When you instantiate an object of Textbox (or ListBox), VB gives it the name TexBox1 (or ListBox1). You can change this name in the properties window. I suppose what you have now are TextBox1 and ListBox1.
Me.Textbox1 = Me.ListBox1.ListCount
There is nothing wrong with the syntax of your code. So the first thing that should be looked at is the names of your listbox and textbox. By default ms-access calls them list and text followed by a number. To find the assigned name go to their property and then the other tab and name of the control is at the top of the list.
Also make sure that you are running the code from the form's onload event. You may try the forms oncurrent event to see if it makes ant difence

How to show only "filled in" fields on an Access report

I have created a report for Microsoft access and am trying to add fields to a report only if then have been clicked on our filled out. The only way I can think of doing this is writing a code or an if-then statement in access. I have very little experience with writing code and am not sure where to begin. I'm looking for something like "If a checkbox is selected then add it to the report".
Thank you.
Instead of trying to dynamically add controls to a report you could include all of the fields on the report and then simply hide the controls that correspond to empty fields. For example, if you have a text field named [SpecialRequirements] and your report contains a bound text box named [txtSpecialRequirements] then in the On Format event handler of the report's Detail band you could use
Me.txtSpecialRequirements.Visible = (Not IsNull([SpecialRequirements]))
which is just a shorthand way of saying
If IsNull([SpecialRequirements]) Then
Me.txtSpecialRequirements.Visible = False
Else
Me.txtSpecialRequirements.Visible = True
End If
This should get you started - its a basic if structure:
If Me!myCheckBox = True Then
'Write to the report
Else
'Do something else
End If
Also check out the Microsoft Developer Network here for information on the If...Then..Else statement
This is really old, but I had the same issue above, but found a easy solution.
Go to Design view in your "report"
Make your Yes/No boxes not visible
Go to the Design tab in your tool bar
Click on the Controls and click on the Check box and place them over your Yes/No box
Delete the label it gives with the check box
Save and look at your report
Only the YES will appear as a checked box.

Hyperlink control in Access App

I've created a hyperlink control on a form page in an Access 2013 App hosted in SharePoint 2013, and want the text to display the same text ("Print Timesheet") while the actual link itself varies based on the value of a field in the record. This is so that I can link to a separate application using a query string with the individual record ID, which gets the data directly from the azure database and formats it in order to be printed out.
I've tried a macro expression to create the link address that runs "on current" and sets the value of the hyperlink, and also tried a computed column in the table to create the link which I pass to the hyperlink control value. I've set the "Default Display Text" on the hyperlink control to "Print Timesheet" in both cases.
The problem I have is that whichever way I try it, changing the value on the fly like this overrides the default display text of the hyperlink so that it displays the address itself rather than the text I want to display.
Is there any way round this?
Thanks,
Duncan
I am not sure if you got your answers. I was randomly looking on internet and found your query.
I thought the thread Troubles with Hyperlink control in Access Web App forms may have your answer.
LILizEidsness replied on August 21, 2014See post history
.....
If you have to build a url field dynamically, the basic syntax is
displaytext#url#
so, in my dynamic field....
=Concat("Click here#/relative/path/on/my/sharepointsite/allitems.aspx&ID=",[ID],"#")
....
You could use a label on the form to represent the link. Have the Label.Caption property set to "Print Timesheet" and use the On Current event to set the Label.HyperlinkAddress property to whatever the address from the recordsource is.

hyperlink doesn’t work in Access form

I have an Access form in which I am unsuccessful in formatting the record to be in hyperlink format.
The form is in datasheet-view format, which contains records with a link to a website. The form’s datasource is a select-query. The hyperlink is created with the following expression, which concantenates text and data, in order create a web link :
"#http://www.ups.com/WebTracking/processInputRequest?sort_by=status&tracknums_displayed=1&TypeOfInquiryNumber=T&loc=en_us&InquiryNumber1=" & [T].[tracking_number] & "&track.x=0&track.y=0#"
I tried setting the property-sheet format field to “hyperlink” , but it automatically changes to “hy"perli"n\k”, in both the query-design view, and form-design-view.
please advise what I need to do in order to have the form output the records in hyperlink format, so I can just click on the website link and it will open up in a web browser
thanks very much in advance,
Nathaniel, Access 2007
You can use the IsHyperlink property for the textbox (format tab) , once again, these are a nuisance to edit. If you create a form based on a table with a hyperlink field, the control created for the hyperlink field will be set up as a link.
More on IsHyperlink: http://msdn.microsoft.com/en-us/library/aa196153(office.11).aspx
Paste something like this into the textbox to see it working:
clickme#http://www.ups.com/WebTracking/processInputRequest?sort_by=status&tracknums_displayed=1&TypeOfInquiryNumber=T&loc=en_us&InquiryNumber1=123456&track.x=0&track.y=0#