SUM of difference in values - ms-access

I need to query in MS Access the difference in value of a column to 8 and only if it is greater than 8.
So if I have a column of numbers 1-10, I want to query the sum of all the value's differences from 8. So the result of the query for the below column would be 3. (9-8)+(10-8)
SELECT Sum(([time1]-8)+([time2]-8)+([time3]-8)+([time4]-8)+([time5]-8)+([time6]-8)+([time7]-8)+([time8]-8)+([time9]-8)+([time10]-8)+([time11]-8)+([time12]-8)+([time13]-8)+([time14]-8)+([time15]-8)+([time16]-8)+([time17]-8)+([time18]-8)+([time19]-8)+([time20]-8)+([time21]-8)+([time22]-8)) AS Total
FROM tblTimeTracking
WHERE (((Month(([Day])))=Month(Now()))) AND ([time1]>8 AND[time2]>8 AND[time3]>8 AND[time4]>8 AND[time5]>8 AND[time6]>8 AND[time7]>8 AND[time8]>8 AND[time9]>8 AND[time10]>8 AND[time11]>8 AND[time12]>8 AND[time13]>8 AND[time14]>8 AND[time15]>8 AND[time16]>8 AND[time17]>8 AND[time18]>8 AND[time19]>8 AND[time20]>8 AND[time21]>8 AND[time22]) ;
Thanks,

How about:
SELECT Sum([Value]-8) As SumOfVal
FROM table
WHERE [Value]>8
Edit re complete change in original question.
It is not clear what you want
SELECT Sum(([time1]-8)+([time2]-8) ...
WHERE [time1]>8 And Time2>8 ...
Time1>8 will exclude nulls, but if that is not what you are doing, you will need to consider:
Nz([time1],0) + ...
Edit re comments
Something like:
SELECT Sum(times) FROM
(SELECT IIf(Time1>8,Time1-8,Time1) As times FROM Table
UNION ALL
SELECT IIf(Time2>8,Time2-8,Time2) As times FROM Table) As b
As b is an alias: Access SQL
UNION / UNION ALL: View a unified result from multiple queries with a union query

Related

How to get the first record of each type in sequence?

Table Data:
ID
Type
1
A
2
A
3
B
4
A
5
A
6
B
7
B
8
A
9
A
10
A
How to get only rows with IDs 1,3,4,6,8, or the first records on type-change by single query?
We were doing this in code using multiple queries and extensive processing especially for large data, is there a way to do this in a single query?
Use LAG() window function to get for every row the previous row's type and compare it to the current type.
Create a flag column that is true if the 2 types are different and use it to filter the table:
WITH cte AS (
SELECT *, type <> LAG(type, 1, '') OVER (ORDER BY id) flag
FROM tablename
)
SELECT * FROM cte WHERE flag;
I assume that the column type does not contain empty values (nulls or
empty strings).
See the demo.

How to split string with square brackets and commas to columns and rows in mysql

I want to split strings like: [[6, 10, 11, 16], [0.4444444444444445, 53.0, 7.555555555555555, 5.111111111111111]]
to output
id value
---------------------------
6 0.4444444444444445
10 53.0
11 7.555555555555555
16 5.111111111111111
Number of 'ids' in the string varies but there is always value for an 'id'.
This is possible using a stored procedure which chops up the string, creates a (temporary) table, stores the result in said table and returns the table content using a SELECT statement.
However it is unlikely that this is an efficient approach - it will be time consuming to write and execution time will not be good, creating a bottle neck if you pass it a lot of data or if is called repeatedly.
A simpler approach - and the route I would follow - is to do this in your favorite programming language and then store the result in the database.
Alternatively the output of your code could be a query with UNION which would return the desired data structure. Essentially the task is to transpose a two dimensional array and structure the output. If it is not overly large, this would be fast and efficient and could be used as a subquery if you need to combine it with other data.
To give you and idea, the output could be as follows:
SELECT 6 AS id, 0.4444444444444445 AS value
UNION ALL SELECT 10, 53.0
UNION ALL SELECT 11,7.555555555555555
UNION ALL SELECT 16, 5.111111111111111
Put to practical use:
SELECT
sub.id,
sub.value,
info.someFieldFromAnotherTable
FROM
(SELECT 6 AS id, 0.4444444444444445 AS value
UNION ALL SELECT 10, 53.0
UNION ALL SELECT 11,7.555555555555555
UNION ALL SELECT 16, 5.111111111111111
) AS sub
INNER JOIN otherInfoTable info ON info.id = sub.id

Reorganizing mysql aggregate row into single piece rows

Consider the following mysql table:
ID WeightS AmountS WeightM AmountM WeightL AmountL Someothercolumnshere
1 6 3 10 2 18 2 ...
I need to reorganize this data into a pivot-friendly table, where each piece in the amount columns should be one result row. E.g. from the first two columns, WeightS and AmountS, the SELECT should produce 3 result rows, each having a weight of 2 kgs (=6 kgs total). So the full result table should be like this:
Weight Someothercolumnshere
2 ...
2 ...
2 ...
5 ...
5 ...
9 ...
9 ...
I don't even know if there's a SQL syntax which is able to do this kind of operation? I've never had a request like this before. Worst case scenario, I have to do it in php instead, but I think MYSQL is a lot more fun :p
I've built the schema on sqlfiddle, but I'm afraid that's all I've got.
You need a Tally table for the task like this. Create as much rows as needed in it.
Create table Tally(`N` int);
insert into Tally( `N`) values(1),(2),(3),(4),(5);
Then
(select `ID`, `WeightS`/`AmountS`, `Someothercolumnshere`
from Catches
join Tally on Catches.`AmountS` >= Tally.`N`
)
UNION ALL
(select `ID`, `WeightL`/`AmountL`, `Someothercolumnshere`
from Catches
join Tally on Catches.`AmountL` >= Tally.`N`
)
UNION ALL
(select `ID`, `WeightM`/`AmountM`, `Someothercolumnshere`
from Catches
join Tally on Catches.`AmountM` >= Tally.`N`
)

SQL stament groups rows and calculate average

I am stuck with the following issue. I have 1 table that looks like this:
field_number.. Value
````````````````````````````````
1 ......................... 1
2 ..........................1
3 ......................... 2
4 ..........................2
etc.
I want to group different fieldnumbers and have an average for the value column. So the output should be:
field_number................Value
name(1,2)...................... 1.............. ((1+1)/2)
name(3,4)...................... 2.............. ((2+2)/2)
I have checked previous questions but cannot find any question that covers this issue (I might search on the wrong keywords though). So if this has already been covered my appologies, but any help or a point to a previous answer would be appreciated.
** =============UPDATE============= **
I went through your suggestions but did not get it right. So I am trying to be more specific. I almost have the result I want apart from the fact I want to have a fixed value in one of my columns. I have the following query:
Select
Avg(wp_rg_lead_detail.value),
wp_rg_lead_detail.field_number,
From
wp_rg_lead_detail
Where
wp_rg_lead_detail.field_number In (15, 17, 24) A
UNION
Select
Avg(wp_rg_lead_detail.value),
wp_rg_lead_detail.field_number,
From
wp_rg_lead_detail
Where
wp_rg_lead_detail.field_number In (16, 108, 18)
etc.
This gives me a table with two columns
wp_rg_lead_detail.value................field_number
4.3 (average)..............................15 (first value of av calculation)
What I want is to change the field number (15 in this case) in a fixed value (text). What and how should I add this to the query?
SELECT avg(value) FROM table WHERE field_number in (1,2)
SELECT avg(value) FROM table WHERE field_number in (3,4)
If your table is really this simple, you can also get away with:
select distinct
Value,
count(Value) as '#'
from table_name
group by Value
If you acctually want to group by a range, than you can put the logic of the range in your grouping clause (see this fiddle)
select distinct
avg(Value) as average,
floor(Value),
count(Value) as '#'
from table_name
group by floor(Value)
In the fiddle I used grouping on whole integers, but you can make that as complex as you like (see, for instance, this example)
If you are actually also interested in your corresponding fields, use group_concat() like so
select
Value,
group_concat(
distinct field_number
order by Value
) as fields
from table_name tn1
group by Value
order by Value
output:
Value | fields
---------------------------------
1 | 1,2
2 | 3,4
See this fiddle implemented from this blog post
For a generalized answer.
SELECT CONCAT('name','(',GROUP_CONCAT(field_number),')') AS field_number,
AVG(Value) as Value
FROM table_name
group by table_name.`Value`
Hope this helps.

WHERE clause in SSRS expression for max function

I have for example a query with return something as it
route value
1 3
2 2
3 4
4 5
5 1
then I need to put in 2 textbox the max and the min route so in sql this would be
select top 1 route from table where value=(select max(value) from table)
I add a image done in excel, how this would be.
I believe this is so easy but I dont have idea how to get it.
I got using expression, this was extactly expression
="Route "+
Convert.ToString (
Lookup(max(fields!value.Value),fields!value.Value ,fields!route.Value,"mydataset")
)
changing max for min, for the other...
thanks everyone.
I believe the query you're looking for would be:
With Min_Max_CTE as (
Select MIN(value) as Min_Value
, MAX(value) as Max_Value
From Table
)
Select Top 1 'Min' as Type
, T.route
, T.value
From Table T
Inner Join Min_Max_CTE CTE
on T.value = CTE.Min_Value
Union All
Select Top 1 'Max' as Type
, T.route
, T.value
From Table T
Inner Join Min_Max_CTE CTE
on T.value = CTE.Max_Value
Order by Type desc --This will put the Min Route first followed by the Max Route
Then, put that query into a dataset, and then create a tablix and use the Type, route, and value fields to return the minimum route and the maximum route. It should end up being set up just like your excel section with the min and max routes above.
You can do this SSRS by using a couple of separate tables. Your example data:
And two tables in the Designer:
Since the tables only have header rows, only the first row in the table will be displayed.
To make sure we get the MAX and MIN values in the two tables, each table needs to order its Dataset appropriately, i.e. by Value by descending and ascending respectively.
MAX table:
MIN table:
Which gives your expected result: