Mercurial, pulling a single branch - mercurial

I have two Mercurial repos C1 and C2 which both derived from the same parent P some time ago but have since had separate lines of development. In addition, in C2, there is a named branch B2 which happened since the diversion. I want to pull only branch B2 into C1, which I can easily do with hg pull C2 --branch B2.
Now B2 branches off of some points in the default branch of the C2 repo. So those default changesets from C2 get pulled over into C1 even though I am only trying to pull branch B2. (I can understand that since they are ancestors of the B2 changesets).
After the above pull, I will have two heads on the default branch of C1, the original head and the head composed of those default changesets that got pulled over as a result of pulling B2 over. I want to leave the default branch of C1 unchanged, otherwise I have two heads, keep getting told that updates "cross branches" and telling me I have to merge. (I will be pulling new default branch things into C1 from other external repos going forward).
How can I do the above so that I do not have two heads on default?

Thinking about the problem, am I right in thinking you have something like this?
# 4[tip]:1 439255c536ee 2013-01-25 10:42 +0000 rob
| More changes on original default branch
|
| o 3 379f384c1d73 2013-01-25 10:41 +0000 rob
| | Changes on named branch B2
| /
| o 2:0 d225da266931 2013-01-25 10:40 +0000 rob
| | Changes on cloned default
| |
o | 1 7088660d3ba6 2013-01-25 10:41 +0000 rob
|/ Changes on original default branch
|
o 0 a02a921256b3 2013-01-25 10:39 +0000 rob
Project Start
The problem you're describing is that while you want to keep the B2 branch, you don't want the two heads on default:
$ hg heads default --style=compact
4[tip]:1 439255c536ee 2013-01-25 10:42 +0000 rob
More changes on original default branch
2:0 d225da266931 2013-01-25 10:40 +0000 rob
Changes on cloned default
I can see two possibilities to "fix" this. One is simply to close the "cloned" default branch (at least in your repo):
$ hg update 2
$ hg commit -m "Closing cloned default" --close-branch
$ hg heads default --style=compact
4[tip]:1 439255c536ee 2013-01-25 10:42 +0000 rob
More changes on original default branch
This would mean that if you issue an hg update default, it shouldn't be ambiguous, which I guess is part of the problem.
An alternative would be to do a "null merge" from the other default branch:
$ hg update
$ hg -y merge --tool=internal:fail 2
$ hg revert --all --rev .
$ hg resolve -a -m
$ hg commit -m "Merged cloned default"
The main difference in these approaches is that using the --close-branch option, you can still see the extra head when you use hg heads -c... it is still a head, but it simply has a flag set in the metadata to say it's closed. You can still update to the closed branch, and even commit changes to it. Doing a merge you won't see the head at all, as it will not longer be a head.
Both of these methods mean that you can still pull changes to the B2 branch - however, if in the repo you're pulling from they make changes on default and merge those into B2 (often used when bugfixing, etc), you will hit the same problem later on, and have to repeat the above.
I hope that makes sense. Of course, if you later push to another repo, you will push the closed/merged changesets too. It would be wise to clone your repo and try these approaches locally to check if that's what you actually want.

Related

What is the rebase command used in hg pull --rebase

Typically, in HG my workflow is to exclusively use:
hg pull --rebase
If I wanted to run this in two commands, how would I do it?
hg pull
hg rebase <probably with some options?>
What hg pull --rebase does is to indeed first do a hg pull and then hg rebase with default arguments on top of that (you can look at the code in rebase.py in the Mercurial distribution in function pullrebase()), but only if any new revisions were pulled in. If no rebasing is necessary, hg pull --rebase will update to the new branch tip instead. So, hg pull && hg rebase is approximately correct, but doesn't quite capture some corner cases (no new revisions, no rebase necessary).
By default, hg rebase will use the parent of the working directory as the base revision of the rebase and the most recent revision of the current branch (i.e. usually what you just pulled in) as the destination. In short, it's equivalent to hg rebase -b . -d 'last(branch(.))'.
What does "base revision" mean in this context? It means that Mercurial will go and look for the least common ancestor of the base revision and the destination. Then it will rebase everything up to, but not including that least common ancestor on top of the destination. I.e., specifying the base revision allows you to pick pretty much any revision on the branch [1] that you want to rebase and let Mercurial figure out which revisions belong to that branch.
Note that because the rebase is based on the parent of the current working directory, this means that if your current checkout is not what you have been working on, then hg pull --rebase may surprise you by actually trying to rebase a different branch (it will usually fail, because those revisions are generally part of the public phase, but it's something you need to be aware of if you're working with so-called non-publishing repositories and don't use named branches).
[1] Branch in this context refers to an anonymous or topological branch, not a named branch. See hg help glossary for further details.
If you want to rebase by hand (bad idea in common), you have to
Read hg help rebase before
Understand usable for you options of rebase (at least -s and -d)
Use these options
Let's see at toy-repos:
Repo A
A>hg log -T "{rev} {desc}\n"
1 A2
0 A1
with 2 changesets A1 and A2 was cloned to repos B and C (B for pull --rebase A, C for clean pull A)
and two additional changesets was added to A and B+C after clone in order to test your use-case (diverged history)
A>hg log -T "{rev} {desc}\n"
3 A2++
2 A2+
1 A2
0 A1
B>hg log -T "{rev} {desc}\n"
3 B2
2 B1
1 A2
0 A1
C state is identical to B
B>hg pull --rebase
...
B>hg log -T "{rev} {desc}\n" -G
# 5 B2
|
o 4 B1
|
o 3 A2++
|
o 2 A2+
|
o 1 A2
|
o 0 A1
I.e. result of rebased pull is "linear history with local changes on top of remote changes", compared to just pull from C
C>hg log -T "{rev} {desc}\n" -G
# 5 A2++
|
o 4 A2+
|
| o 3 B2
| |
| o 2 B1
|/
o 1 A2
|
o 0 A1
or, in GUI
and in order to get B from C, you have to rebase 2 (-s 2) to new parent 5 (-d 5), but short hg rebase -b 2 will work also and will have the same effect

Hg backout, then take the changes and store on a branch

Here is what I am trying to do. I have a commit to the default branch that I need off default. We build for production from default and this commit is not ready. So I have used hg backout to undo the changes from the default branch. Now I have created a new branch to store the changes. But when I attempt to transplant or graft the changes onto the branch I get told that I cannot graft in changes from an ancestor. This makes sense, but I need to pull changes from an ancestor, how do I do this.
I have tried
hg diff -c 8c13fc133926 > new_branch.diff
hg import new_branch.diff
but this Fails with no explanation. Any pointers?
EDIT
It seems I'm a little hard to follow, so I will try and clarify.
o Default with only ready changes
|
| o Not ready changes (new commit on a branch)
| |
|/
o Hg backout commit Undoing not ready changes from default
|
o Lots of other commits and merges to default
|
o ...
|
o Not ready changes (original commit)
The graph above shows where I need to get to.
I have done this by using hg diff -c 6877 | patch -p1 where 6877 is the revision of the commit that needs to be moved off of default.
But I think I am doing this wrong.
Make your new branch off of the revision BEFORE you made the "not ready changes" commit. I will call that revision 123:
hg up 123
hg branch NewBranch
hg ci -m "branching for NewBranch"
Now you can do your GRAFT, with no concerns about ancestors.
Tying up loose ends:
It seems that you'll already have another head on NewBranch, the one you said you created. You can merge with that or just close it. You can see the heads with:
hg heads NewBranch
I will call that unwanted head revision 456. And I would close it like this:
hg up 456
hg ci --close-branch -m "It was all just a dream... a terrible, terrible dream."
Which reminds me: you could have used the same technique (closing an unwanted branch head) instead of hg backout! Then you could have done the steps above ... except you'd be able to do a neat-and-tidy REBASE ("leaving no witnesses", like they say in the movies) instead of cherry-picking with GRAFT, and leaving behind the wreckage on the default branch!
I personally avoid grafting as much as possible, and your commit is already in the history. You seem to be using the correct commands, but it is hard to understand your issue, more information is needed.
How about creating your new branch from the commit that you wanted to backout?
o NewBranch: head, creation of the branch
|
|
o | default: head, Backed-out changeset
| |
|/
o default: commit (not ready)
|
|
o default: initial state
|
Another idea, if you don't care about grafting, simply start your new branch from the initial state, and transplant the commit; it won't be considered an ancestor anymore.
o NewBranch: head, grafted commit
|
/|
| o NewBranch: creation
| |
| |
o | | default: Backed-out changeset
| | |
|/ |
o / default: commit (not ready)
| /
|/
o default: initial state
|

How to bring latest changes in a mercurial feature branch (workflow)?

Given a branch called 'main'. As a developer wanting to work on a new feature, I create 'f1' and do several commits, pushing regularly to our central repo. While working on the feature, I need to get the changes form 'main' in my branch.
I know I can hg merge main to get the changes in 'f1'. But when I later integrate in 'main' then the history will be full of references to that temporary branch. Are there ways to make my branch work less visible after the fact?
To make branch less visible in history you should use bookmarks. Let's see both cases, with a named branch or with a bookmark.
With new branch named 'f1' from 'main':
$ hg update main
$ hg branch f1
...
$ hg glog --template "{rev} {branch} {bookmarks} {desc}\n"
# 5 main Hacking main.
|
| o 4 f1 Hacking f1.
| |
| o 3 f1 Hacking f1.
|/
o 2 main Hacking main.
|
o 1 main Hacking main.
|
o 0 default
With new bookmark named 'f1' from 'main':
$ hg update main
$ hg bookmark f1
...
$ hg glog --template "{rev} {branch} {bookmarks} {desc}\n"
# 5 main Hacking main.
|
| o 4 main f1 Hacking f1.
| |
| o 3 main Hacking f1.
|/
o 2 main Hacking main.
|
o 1 main Hacking main.
|
o 0 default
In the bookmark case the 'f1' feature can be removed from history with hg bookmarks --delete f1 (from Mercurial 2.3 new bookmarks are pulled by default WhatsNew) and there are two paths in the 'main' branch.
First of all, why do you worry about that the main branch would contain the history of the f1 branch after merging the latter to the former, if the f1 branch is already in the central repo??? The f1 branch is not temporary/disposable/invisible any more once it's pushed into the central repo, it's very visible to everyone who can access the central repo.
The answer to your question is: No way unless f1 is a by-cloning branch. All suggestions of using bookmark and/or anonymous branch are false.

mercurial - see changes on the branch ignoring all the merge commits

I have a branch that was developed for a long period of time. During the development default branch was merged into that branch several times. I would like now to review all the changes done on that branch ignoring merges, to decide whether it is safe to merge it to default.
I tried
hg diff -r "branch('myBranch') - merge()"
but it still shows changes introduced by merges. Also tried following this How to show the diff specific to a named branch in mercurial but
hg diff -r "branch('myBranch') - branch('default')"
still bring changes introduced by merges.
You have to read about revsets syntax
Your case
hg log -r "branch('myBranch') and ! merge()"
The problem with your commands is that when you perform a hg diff and pass it several changesets, you actually perform a diff between those changesets, hence you will see the merge result.
If you want to see just the changes made by the changesets then you could use export:
$ hg export -r "branch('mybranch') and not merge()"
// lists the changes made by each changeset
For easier reviewing, you can output these to files with names based on the revision/changeset id:
$ hg export -r "branch('mybranch') and not merge()" -o "%H.patch"
... creates a file for each non-merge changeset in mybranch, and outputs it to a file with the name "40-digit changeset id.patch". If you'd prefer the revision number (only useful for your local repository as revision id's are local), use "%R.patch".
The following uses the log command but with the --patch parameter it can show the modified lines as well:
hg log --branch my-branch --no-merges --patch
Short form:
hg log -Mpb my-branch
That is a very good question, which I am trying to find good answer for a long time, and yet not found a good one. OK, one thing which 100% works is this:
hg status # make sure that you don't have local changes
hg up <target_branch>
hg merge <your branch>
hg diff > merge.diff
hg up -C # this one cleans the merge
I use this workflow all the time, but it does not satisfy me fully because it requires to switch branches (when I actually might not want to do actual merge right at this exact moment, I am just checking whats there)
I've been searching for ages for a good solution here, but so far there are none found. Tried those:
hg diff -r "branch('.') and ! merge()" # this page
hg diff -r "default:branch('.') and not merge()"
hg diff -r "parents(branch(.)):branch('.') and not merge()"
This problem also discussed in:
Mercurial: how can I see only the changes introduced by a merge?
which has good answer as: "so if you can define it unambiguously you might convince one of us Mercurial contributors that read SO to implement it."
Try:
hg diff -r"ancestor(default,my_branch)" -rmy_branch
If you haven't done any merges to the branch, then "ancestor" will pick up the original branch point. If you've done merges, then "ancestor" will pick up the latest merge point.
For example, on the graph below you'll get the diff between 520 and 519:
# 521 (default)
|
| o 520 (my_branch)
|/|
o | 519
| |
o | 518
| |
o | 517
| |
| o 516
| |
| o 515
| |
| o 514
|/
o 513
On the simpler graph below you'll get a diff between 516 and 513:
# 517 (default)
|
| o 516 (my_branch)
| |
| o 515
| |
| o 514
|/
o 513
Per Matt Mackall what you probably want is:
hg diff -r mainbranchrev -r mywork
He writes:
You may be under the impression that "a changeset is a delta" or
similar, and that this means that Mercurial can magically chain together
a bunch of non-contiguous deltas to construct a bigger delta that's just
your changes.
In fact, Mercurial is much simpler than that. A changeset is actually a
snapshot: a complete set of complete files representing the state of the
project at the time of commit. And a diff is simply the difference
between these two snapshots. So when you do:
hg stat --rev '3408::3575 and user(mdiamond) and not merge()'
..status simply uses the first and last changesets of the resulting set
to do its calculation.
When you do incremental merges on your development branch, you're
inextricably tangling your work with mainline development, and Mercurial
is not nearly smart enough to untangle it in the way you're asking. Your
best bet is to compare the head of your work with the head of the main
branch:
hg diff -r mainbranchrev -r mywork
..which will show all your work plus whatever merge fixups you had to
do.

Mercurial: how can I see only the changes introduced by a merge?

I'm trying to get in the habit of doing code reviews, but merges have been making the process difficult because I don't know how to ask Mercurial to "show only changes introduced by the merge which were not present in either of its parents."
Or, slightly more formally (thanks to Steve Losh):
Show me every hunk in the merge that wasn't present in either of its parents, and show me every hunk present in either of its parents that isn't also present in 3.
For example, assume I have a repository with two files, a and b. If "a" is changed in revision 1, "b" is changed in revision 2 (which is on a separate branch) and these two changes are merged in revision 3, I'll get a history which looks like this:
# changeset: 3
|\ summary: Merged.
| |
| o changeset: 2
| | summary: Changing b
| |
o | changeset: 1
|/ summary: Changing a
|
o changeset: 0
summary: Adding a and b
But if I ask to see the changes introduced by revision 3, hg di -c 3, Mercurial will show me the same thing as if I asked to see the changes introduced in revision 1, hg di -c 1:
$ hg di -c 3
--- a/a
+++ b/a
## -1,1 +1,1 ##
-a
+Change to a
$ hg di -c 1
--- a/a
+++ b/a
## -1,1 +1,1 ##
-a
+Change to a
But, obviously, this isn't very helpful - instead, I would like to be told that no new changes were introduced by revision 3 (or, if there was a conflict during the merge, I would like to see only the resolution to that conflict). Something like:
$ hg di -c 3
$
So, how can I do this?
ps: I know that I can reduce the number of merges in my repository using rebaseā€¦ But that's not my problem - my problem is figuring out what was changed with a merge.
The short answer: you can't do this with any stock Mercurial command.
Running hg diff -c 3 will show you the changes between 3 and its first parent -- i.e. the changeset you were at when you ran hg merge.
This makes sense when you think of branches as more than just simple changesets. When you run hg up 1 && hg merge 2 you're telling Mercurial: "Merge changeset 2 into changeset 1".
It's more obvious if you're using named branches. Say changeset 2 in your example was on a named branch called rewrite-ui. When you run hg update 1 && hg merge rewrite-ui you're effectively saying: "Merge all the changes in the rewrite-ui branch into the current branch." When you later run hg diff -c on this changeset it's showing you everything that was introduced to the default branch (or whatever branch 1 happens to be on) by the merge, which makes sense.
From your question, though, it looks like you're looking for a way to say:
Show me every hunk in this changeset that wasn't present in either of its parents, and show me every hunk present in either of its parents that isn't also present in 3.
This isn't a simple thing to calculate (I'm not even sure I got the description right just now). I can definitely see how it would be useful, though, so if you can define it unambiguously you might convince one of us Mercurial contributors that read SO to implement it.
In order to do code reviews you really want to see just the changes in the project that you are reviewing. To that end we use a new branch for each story and use pull requests to spotlight the changes, having merged all changes into the story branch before creating the pull request. We host our code on bitbucket and the review / pull request tools are really very good, offering a side by side diff.
Pull requests with side-by-side diffs