How to sum the percent to be exactly 100.00%? - mysql

Question

I have a problem how to sum the percent to be 100.00. i try use the "Round" but the result just show 99.93. Anyone got the idea?.
SELECT Sum(percent)
FROM (SELECT state,
jantina,
bilmale,
jds,
jumall,
Round(( bilmale * 100 / ( jumall ) ), 2) PERCENT,
( jds ) * 100 / ( jumall ) AS p_jdk
FROM (SELECT Timestamp(X.createdate)
dattime
,
Upper(Date_format(X.createdate, '%d %M %Y')) AS
datenegeri,
X.state,
Upper(CASE
WHEN g.ns_fender_desc = 'male' THEN 'LELAKI'
WHEN g.ns_fender_desc = 'female' THEN 'PEREMPUAN'
ELSE g.ns_fender_desc
END) jantina
,
Sum(CASE
WHEN X.male = 1 THEN 1
WHEN X.male = 0 THEN 1
ELSE 0
END) bilmale
,
(SELECT Sum(CASE
WHEN Y.male = 1 THEN 1
WHEN Y.male = 0 THEN 1
ELSE 0
END) bilmale
FROM xyuser_userext Y
JOIN tnsstate TS
ON TS.ns_state_id = Y.state
LEFT JOIN tnsgender g
ON g.ns_gender_id = Y.male
WHERE Y.statususerext IN ( '0', '1', '2', '5' )
AND Y.state = X.state
AND Date_format(X.createdate, '%d %M %Y') =
Date_format(Y.createdate, '%d %M %Y')
GROUP BY TS.ns_state_desc,
Date_format(X.createdate, '%d %M %Y')) jds,
(SELECT Sum(CASE
WHEN Y.male = 1 THEN 1
WHEN Y.male = 0 THEN 1
ELSE 0
END) bilmale
FROM xyuser_userext Y
JOIN tnsstate TS
ON TS.ns_state_id = Y.state
LEFT JOIN tnsgender g
ON g.ns_gender_id = Y.male
WHERE Y.statususerext IN ( '0', '1', '2', '5' ))jumall
FROM xyuser_userext X
JOIN tnsstate TS
ON TS.ns_state_id = X.state
LEFT JOIN tnsgender g
ON g.ns_gender_id = X.male
WHERE X.statususerext IN ( '0', '1', '2', '5' )
GROUP BY TS.ns_state_desc,
Date_format(X.createdate, '%d %M %Y'),
X.male
ORDER BY 1 ASC) AS A) AS b

Answer 1

If you round only the result and not the individual items, it will be more accurate. Try using SELECT Round(Sum(percent), 2) and remove the Round from the percent calculation in the WHERE clause.