Get time difference for each row in table - mysql

Question

I am working on an online time card system and have ran into a road block. What I need to do is calculate in each row the timeIn and timeOut for a date the employee might clock in and out several times a day. I have a working query to find the total for the entire day but not for each individual row. I have included the structure of the database table with some examples of what I would like to see.
+----+------------+----------+---------+------------------------------+-------------+------------+-----------+----------+
| id | employeeID | date | timeIn | jobDescription | equipType | unitNumber | unitHours | timeOut |
+----+------------+----------+---------+------------------------------+-------------+------------+-----------+----------+
| 8 | 1 | 01/15/13 | 7:00 AM | Loaded sand in Jefferson | Excavator | 345 | NULL | 9:30 PM |
| 9 | 1 | 01/15/13 | 10:00 AM | Loaded sand in Jefferson | Excavator | 345 | NULL | 12:00 PM |
| 10 | 1 | 01/16/13 | 7:00 AM | Loaded sand in Jefferson | Excavator | 345 | NULL | 5:30 PM |
| 11 | 1 | 01/17/13 | 7:00 AM | Loaded sand in Jefferson | Excavator | 345 | NULL | 5:30 PM |
| 12 | 1 | 01/18/13 | 8:00 AM | Backfill in Whispering Creek | Skid Loader | 297 | NULL | 5:30 PM |
| 13 | 1 | 01/19/13 | 8:00 AM | Backfill in Whispering Creek | Skid Loader | 297 | NULL | 3:30 PM |
| 1 | 1 | 01/20/13 | 6:00 | | Excavator | 01E | 7238 | 17:00 |
| 2 | 1 | 01/21/13 | 6:00 | Worked in Jefferson | Excavator | 01E | 7238 | 17:00 |
| 3 | 1 | 01/22/13 | 6:00 | Worked in Jefferson | Excavator | 02E | 7238 | 17:30 |
| 4 | 1 | 01/23/13 | 6:00 | Worked in Whispering Creek | Skid Loader | 32SL | 2338 | 18:30 |
| 5 | 1 | 01/24/13 | 8:00 | Worked in Hubbard | Scraper | 54C | 9638 | 11:30 |
| 6 | 1 | 01/25/13 | 8:00 | Worked in Jefferson | Dozer | 4D | 941 | 19:30 |
| 7 | 1 | 01/26/13 | 8:00 | Pushed Snow | Loader | 950H | 342 | 20:30 |
+----+------------+----------+---------+------------------------------+-------------+------------+-----------+----------+
Ok so what I would like to see is that for example the date 01/15/13 appears twice with different timeIn and timeOut values I would like to get a value back saying that in row with the id 8 there was 2:30 hours, then get another value back saying that in the row where id is 9 there was 2:00 hours. I would like to accomplish this with one query if possible.
This is my query to get the time for the entire day:
SELECT `employeeID`, SEC_TO_TIME(SUM(TIME_TO_SEC(TIMEDIFF(`timeOut`, `timeIn`)))) AS `totalTime` FROM `timeRecords` WHERE `date` = "01/15/13" AND `employeeID` = 1 GROUP BY `employeeID`;

Answer 1

If I understand you correctly you need this?
SELECT `employeeID`, TIMEDIFF(`timeOut`, `timeIn`) AS `totalTime` FROM `timeRecords`;
You can use PDO query to query your database which returns result set as array of associative array. For better performance you can use PDO prepare/execute.
<?php
function getTimeByRow($connection) {
$sql = "SELECT `employeeID`, TIMEDIFF(`timeOut`, `timeIn`) AS `totalTime` FROM `timeRecords`";
foreach ($connection->query($sql) as $row) {
print $row['employeeID'] . "\t";
print $row['totalTime'] . "\n";
}
}
?>

Answer 2

So you want to do something like this:
select employeeID, date, TIMEDIFF(timeout, timein) from timeRecords where date = x and employeeID = y