This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
Error handling in C code
I mean, I guess not all languages have exceptions so how I e.g. in C will find out more about a failure?
Return error codes from your functions, or a boolean indicating success/failure.
Related
This question already has answers here:
Why is the regex to match 1 to 10 written as [1-9]|10 and not [1-10]?
(9 answers)
Closed 7 months ago.
I am working on an exercise where we are testing form validation in an Angular template. The restrictions for the one input field are that the selection should be a number from 1-10.
My first try was below, as I was taught using pipes could separate literals.
pattern="[1|2|3|4|5|6|7|8|9|10]"
When that did not work for 10, I tried the below two lines, which still did not let me include 10, but did allow 0.
pattern="[1|2|3|4|5|6|7|8|9|(10)]"
pattern="[1|2|3|4|5|6|7|8|9|(10)]{1}"
This is my first stackoverflow question, so I think I included enough, but I will provide more information if needed.
Use this RegEx: ^([1-9]|10)$
Explanation:
^ Assert position at start of line.
( Capture group open.
[1-9] Match a single character in the range between 1 and 9.
| Equivalent to logical OR.
) Capture group close.
$ Assert position at the end of the line.
This question already has answers here:
Missing explicit interface for subroutine
(2 answers)
Procedure with assumed-shape dummy argument must have an explicit interface [duplicate]
(1 answer)
Closed 3 years ago.
I am trying to write a program in Fortran (using Plato) to calculate the median of an array without sorting them. However, I receive this error and it seems that the program doesn't enter the function at all. Can anyone please let me know what is wrong about my program?
My program is this:
!=================program median========================
program MedianVal
real,dimension(:),allocatable::arr
real::median
integer::n
print*,'please enter the number of the arrays'
read*,i
allocate(arr(i))
print*,'please enter your array:'
read*,arr
!med=median(n,arr)
!print*,'The median is:'
!print*,median(n,arr)
write(6,*)'The median is:',median(n,arr)
end program
!=================Function Median=======================
real function median(n,arr)
real,dimension(:),allocatable::arr
integer::n
!allocate(arr(i))
print*,'entered function'
n=size(arr,1)
print*,n
median=0
if(mod(n,2)==0)then
median=(arr((n-1)/2)+arr(n/2))/2
else
median=arr(n/2)
end if
end function median
Here is the error log :
Attempt to call a routine with an incorrect or missing INTERFACE
related to
argument number two, which needs to be declared as assumed-shape in both the caller and callee at address 1c008629
Within file Exercise2.exe
in MEDIAN at address fc
in MEDIANVAL in line 14, at address 371
This question already has answers here:
Can I apply must_use to a function result?
(2 answers)
Closed 4 years ago.
Does Rust have a way to declare a function, where not using its result will warn - for any types?
Something like GCC's __attribute__((warn_unused_result));?
As of 1.27, #[must_use] works for functions too.
It appears that the #[must_use] attribute is only applicable to structs, enums and unions (union is not available in stable Rust yet, though): source. I think this means you can't override it for a function.
Yes, if you don't mind wrapping said types.
The #[must_use] attribute, as answered by #ljedrz, only applies to types. However, in Rust, creating new types is painless and has not impact on performance. Therefore, just wrap your type in a MustUse<T> type, and have your function resolve this.
struct MustUse<T>(T);
Closed. This question is opinion-based. It is not currently accepting answers.
Want to improve this question? Update the question so it can be answered with facts and citations by editing this post.
Closed 9 years ago.
Improve this question
Should we use assertEquals or assertTrue for comparing primitive types specifically ints?
Is there a preference, if so why ? I'd like to know the pros and cons of each approach.
assertEquals() gives a useful default error message on failure, like "expected X but got Y", but assertTrue() can't. Use the more specific applicable method here, which is assertEquals().
assertEquals() is to test the equality of your expected value with the returning value. Whereas assertTrue() is to check for a condition. Having said that, you can also say
If you have a condition like.
String x = "abc";
String y = "abc";
assertEquals(x, y);
You can also change it to
assertTrue(x.equals(y));
It is just another way of asserting what you expect.
This question already has answers here:
Closed 12 years ago.
Possible Duplicate:
Is there a way to get a vector with the name of all functions that one could use in R?
Hi
I would like to get from R the list of functions loaded in the environment.
I know ls() that gives the list of objects loaded. But some objects are not functions.
I would like to clean my env from the functions but not from the other objects (matrices, array etc) that contain some of my result that dont want to lose.
Any idea?
See ?lsf.str
X <- lsf.str()
as.vector(X) # just for printing purposes, you can use the vector in rm()
rm(list=X)
ok, I have a proposal
rm(list=ls()[sapply(ls(), function(obj) "function"==class(eval(parse(text = obj)))[1])])
I am sure there is something more elegant.