How do i combine the two mysql queries below to a single query?
SELECT R12NC, COUNT(*) AS `count1` FROM alink where Option_a = 1 GROUP BY R12NC
SELECT R12NC, COUNT(*) AS `count2` FROM alink where Option_x = 1 GROUP BY R12NC
Two ways. If you want just two columns, use a UNION
SELECT R12NC, COUNT(*) AS `count1` FROM alink where Option_a = 1 GROUP BY R12NC
UNION
SELECT R12NC, COUNT(*) AS `count2` FROM alink where Option_x = 1 GROUP BY R12NC
If you want 3 columns then something like:
SELECT R12NC, SUM(CASE WHEN Option_a = 1 THEN 1 ELSE 0 END) as `count1`,
SUM(CASE WHEN Option_x = 1 THEN 1 ELSE 0 END) as `count2`
FROM alink
GROUP BY R12NC
By using the case statement, nested in an aggregation function:
SELECT R12NC,
sum(case when Option_a = 1 then 1 else 0 end) as `count1`,
sum(case when Option_x = 1 then 1 else 0 end) as `count2`
FROM alink
GROUP BY R12NC
Related
We have a table with data from different nodes and one of the column will have status report as "compliant or non-compliant", sample data as below
I want to filter the table in such a way that if any of the checks on a node shows non compliant, it should be flagged as non-compliant and rest as compliant. Using below query i am able to do it
SELECT COUNT(*) AS total_nodes,
SUM(fully_compliant = 0) AS Non_compliant_nodes,
SUM(fully_compliant = 1) AS compliant_nodes
FROM (
SELECT Node, CASE WHEN SUM(Status = 'Compliant') = COUNT(*) THEN 1 ELSE 0 END AS fully_compliant
FROM your_table GROUP BY Node
)
Now, i want to group and split the result by dept as below, how can i achieve this
I think you're looking for this:
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
sum(case when 'Non-Compliant' then 1 else 0 end) as non_compliant_chk
from your_table
group by dept,
node
) v
group by dept;
With few modifications to what Brian suggested, I am able to get the desired result
select dept,
count(*) as total_nodes,
sum(case when non_compliant_chk = 0 then 1 else 0 end) as compliant_nodes,
sum(case when non_compliant_chk > 0 then 1 else 0 end) as non_compliant_nodes
from (
select dept,
node,
COUNT(CASE WHEN Compliance-Status = 'Non-Compliant' THEN 1 END) 'non_compliant_chk'
from table WHERE DOR >= DATE(NOW()) - INTERVAL 7 DAY
group by Dept,
Node
) v
group by Dept;
i have a query like below
select project_task_id,
status_id,
sum(case when StatusID=1 then 1 else 0 end) as task_id=1,
sum(case whenStatusID=2 then 1 else 0 end) as task_id=2,
sum(case when StatusID=3 then 1 else 0 end) as task_id=3,
sum(case when StatusID=4 then 1 else 0 end) as task_id=4,
sum(case when StatusID=5 then 1 else 0 end) as task_id=5,
sum(case when StatusID=6 then 1 else 0 end) as task_id=6,
sum(case when StatusID=7 then 1 else 0 end) as task_id=7,
from"Projects".work_unit_status
group by project_task_id,status_id;
I'm getting the below attached output:
https://i.stack.imgur.com/1wfD1.png
and I want to get the below expected output:
https://i.stack.imgur.com/Zql9z.png
include zero's if the status_id is blank
please any one help on this
Try this: use the addition of all sum column
select project_task_id,status_id,
isnull(sum(case when StatusID=1 then 1 else 0 end),0)+
isnull(sum(case whenStatusID=2 then 1 else 0 end),0) +
isnullsum(case when StatusID=3 then 1 else 0 end),0) +
isnullsum(case when StatusID=4 then 1 else 0 end),0)+
isnullsum(case when StatusID=5 then 1 else 0 end),0) +
isnullsum(case when StatusID=6 then 1 else 0 end),0) +
isnullsum(case when StatusID=7 then 1 else 0 end),0) as count_status
from"Projects".work_unit_status group by project_task_id,status_id
use in with your case
with t1 as (
select project_task_id,
status_id,
sum(case when StatusID in (1,2,3,4,5,6,7) then 1 else 0)
as sum_s
from "Projects".work_unit_status
group by project_task_id,status_id
) ,
t2 as
(
select * from (
select 1 as statusid
union
select 2
union
select 3
union
select 4
union
select 5
union
select 6
union
select 7 ) t
) select t1.project_task_id,
t2.statusid,
case when t1.sum_s>0 or not null
then sum_s else 0 end as total
t2 full join t1 on t2.statusid=t1.status_id
Without knowing the exact table structure I assumed that status_id and statusId refer to the same column. (If they are different columns, we need to use StatusId in the COUNT.)
Based on the expected output, you want to count the status_id and group by project_task_id. To make sure that every status is represented for every task, first, we need to create a subquery of all possible project_task_id/status_id combinations. Then we use that with the aggregate values of the original table.
select
ps.project_task_id,
ps.status_id,
count(w.status_id) as total
from (
select distinct
project_task_id,
s.status_id
from work_unit_status
cross join (select distinct status_id from work_unit_status) s
) ps
left join work_unit_status w
on ps.project_task_id = w.project_task_id and ps.status_id = w.status_id
group by
ps.project_task_id,
ps.status_id
If you really need to hardcode the statuses from 1 to 7, use the query below.
select
ps.project_task_id,
ps.status_id,
count(w.status_id) as total
from (
select distinct
project_task_id,
s.status_id
from work_unit_status
cross join (
select 1 as status_id
union select 2
union select 3
union select 4
union select 5
union select 6
union select 7
) s
) ps
left join work_unit_status w
on ps.project_task_id = w.project_task_id and ps.status_id = w.status_id
group by
ps.project_task_id,
ps.status_id
order by
ps.project_task_id,
ps.status_id
SELECT sum(case when (gender)=1 THEN 1 ELSE 0 END),
GROUP_CONCAT(sum(case when (gender)=2 THEN 1 ELSE 0 END) SEPARATOR ' ') as combine
from family_member_tbl
GROUP BY gender
NO, you can't nest grouping function like that. Rather get the sum first and then group_concat() like
select sum_1, sum_2, group_concat(sum_2) as combine
from (
SELECT gender,
sum(case when gender = 1 THEN 1 ELSE 0 END) as sum_1,
sum(case when gender = 2 THEN 1 ELSE 0 END) as sum_2
from family_member_tbl
GROUP BY gender ) xxx
group by gender;
I have two tables as below
tbl1
id qNum
1 1
2 2
3 3
tbl2
id qNum displayNum
1 1 3
2 2 1
3 2 2
4 2 4
Ideally I need a sql results to look like this
qNum display1 display2 display3 display4
1 0 0 1 0
2 1 1 0 1
3 0 0 0 0
I have tried the following sql but this was not correct
SELECT
tbl1.qNum,
CASE when tbl2.displayNum=1 then 1 else 0 end AS filter1,
CASE when tbl2.displayNum=2 then 1 else 0 end AS filter2,
CASE when tbl2.displayNum=3 then 1 else 0 end AS filter3,
CASE when tbl2.displayNum=4 then 1 else 0 end AS filter4,
CASE when tbl2.displayNum=5 then 1 else 0 end AS filter5
FROM
tbl1
Left Join tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY
tbl1.qNum
Could anyone help a little please!!
You have use MAX function to pivot the table
Try this:
SELECT tbl1.qNum,
MAX(CASE WHEN tbl2.displayNum=1 THEN 1 ELSE 0 END) AS filter1,
MAX(CASE WHEN tbl2.displayNum=2 THEN 1 ELSE 0 END) AS filter2,
MAX(CASE WHEN tbl2.displayNum=3 THEN 1 ELSE 0 END) AS filter3,
MAX(CASE WHEN tbl2.displayNum=4 THEN 1 ELSE 0 END) AS filter4,
MAX(CASE WHEN tbl2.displayNum=5 THEN 1 ELSE 0 END) AS filter5
FROM tbl1
LEFT JOIN tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY tbl1.qNum
Your query is almost correct, you're just missing an aggregate function:
SELECT
tbl1.qNum,
MAX(CASE when tbl2.displayNum=1 then 1 else 0 end) AS filter1,
MAX(CASE when tbl2.displayNum=2 then 1 else 0 end) AS filter2,
MAX(CASE when tbl2.displayNum=3 then 1 else 0 end) AS filter3,
MAX(CASE when tbl2.displayNum=4 then 1 else 0 end) AS filter4,
MAX(CASE when tbl2.displayNum=5 then 1 else 0 end) AS filter5
FROM
tbl1
Left Join tbl2 ON tbl1.qNum = tbl2.qNum
GROUP BY
tbl1.qNum
The columns you select should always be either in the group by clause or an aggregate function should be applied to them. A group by "collapses" a group of rows and if you don't have an aggregate function on a column (which is not in the group by) a random row of that group is displayed.
Here you can read about the different aggregate functions: GROUP BY (Aggregate) Functions
The MAX() function in our case here returns the greatest value (note: not the row with the greatest value. You can also have a query like this: select min(col), max(col) from whatever).
I just want to point out that in MySQL, you can simplify the expression. It doesn't need a case statement because booleans are treated as integers with values of 0 and 1:
SELECT tbl1.qNum,
MAX(tbl2.displayNum = 1) AS filter1,
MAX(tbl2.displayNum = 2) AS filter2,
MAX(tbl2.displayNum = 3) AS filter3,
MAX(tbl2.displayNum = 4) AS filter4,
MAX(tbl2.displayNum = 5) AS filter5
FROM tbl1 Left Join
tbl2
ON tbl1.qNum = tbl2.qNum
GROUP BY tbl1.qNum;
Normally, I prefer going with ANSI standard syntax. I do, however, find this easier to read than the case syntax.
Also, you may not need tbl1 for the query, if all values you are interested in are already in tbl2.
Say I have a table called votes, and a column in that table called vote_type which can either be 0 or 1. How can I fetch the COUNT of vote_type where vote_type is 1?
Right now, I can select the count of vote_type overall, but not the count of vote_type where it is 1 or 0, via this query:
SELECT COUNT(votes.vote_id) AS vote_count
FROM votes
WHERE <some condition>
ORDER BY vote_count
How can I select the total number of vote_types, the number of vote_types = 1, the number of vote_types = 0, and the total vote_value (votetypes = 1 minus votetypes = 0), and order it by the total vote_value?
EDIT: Note that 1 & 0 are not intrinsic values of a vote, but boolean expressions for a positive vote and a negative vote.
I don't know what exactly are you trying to do, but if you want to count all the votes with Vote_Type=1
try
SELECT COUNT(votes.vote_id) AS vote_count
FROM votes
WHERE votes.vote_type=1
or if you need to sum the votes
SELECT SUM(votes.vote_type) AS vote_sum
FROM votes
WHERE votes.vote_type=1
SELECT COUNT(*) TotalVotes,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) TotalVoteOne,
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteZero,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) -
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteValue
FROM votes
-- WHERE ....
-- ORDER ....
When you say order it by the total vote_value -- it actually doesn't makes sense since the total number of rows in the result is only one.
You can also wrap this in a subquery,
SELECT TotalVotes,
TotalVoteOne,
TotalVoteZero,
(TotalVoteOne - TotalVoteZero) AS TotalVoteValue
FROM
(
SELECT COUNT(*) TotalVotes,
SUM(CASE WHEN vote_type = 1 THEN 1 ELSE 0 END) TotalVoteOne,
SUM(CASE WHEN vote_type = 0 THEN 1 ELSE 0 END) TotalVoteZero
FROM tableName
-- WHERE ....
-- ORDER BY TotalVoteValue DESC
) a
Try to start with something like this:
SELECT SUM(CASE WHEN votetype = 1 then 1 else 0 end) AS vote_count_1,
SUM(CASE WHEN votetype = 0 then 1 else 0 end) AS vote_count_0
FROM votes
WHERE <some condition>
ORDER BY vote_count
Edit: Added a net_vote column, which I think is the "vote1 minus vote0" number you are after.
Select
Sum(Case v.vote_type When 1 then 1 else -1 end) as net_vote
From
Votes v
Where
<some condition>
I've removed the order by, because this is only going to return one row.
$query = "SELECT *FROM votes WHERE vote_type=1 || vote_type=0";
$result = mysql_query($query);
$row = mysql_fetch_assoc($result);
$WhereVoteIsOne=$row['vote_type'];
foreach ($WhereVoteIsOne as $votesCount) { echo $votesCount."<br/>";}