I have a table with a column named balance.
if(mysqli_num_rows($get_bank_check_res) > 0){
$display_block = "<p>your autho code is:</p>";
$account_check = mysql_fetch_array($get_bank_check_res);
$balance= $account_check > $grand_total_safe ? (balance - $grand_total_safe) : 0;
$display_block .= "<p>your balance is: '".$balance."' </p>";
I received the warning : Undefined variable balance. Trying mysql_fetch_assoc() didn't work either.
You get a row back with mysql_fetch_array, it doesn't automagically create new variables for you. Ie your column is located here. Also, since you are using the MySQLi extension instead of mysql, it look like this:
$row = $get_bank_check_res->fetch_assoc();
$balance = $row["balance"];
then you can do you whatever math your doing using the values found inside your $row array.
Related
I am using MYSQL.My table contains column name as Revenue2000,Revenue2001,Revenue2002,....,Revenue 2016,Revenue 2017
Traditional way(to select all column manually):
select Revenue2005,
Revenue2006,
Revenue2007,
Revenue2008,
Revenue2009,
Revenue2010
from table_name
Desired Way:
I want to write a Dynamic select statement .There should 2 variables "start" and "end" so that i can make it dynamic.User has the option to specify the starting year and ending year and can view the desired result.
In above case, Start year =2005
End Year=2010
Yes, it's bad database design, and the best answer would be "don't do this at all, just fix your table." Unfortunately, sometimes you're stuck with something someone else made, and can't change it for whatever reason, but you still need to accomplish something (welcome to my life). I would do it like this:
Get the years from user input and convert them to integers in case someone enters something silly/naughty. Don't depend on client-side validation. Prepared statements won't help you here because these will be used as parts of column names.
$start = (int) $_POST['start'];
$end = (int) $_POST['end'];
Do a quick sanity check to make sure that the range makes sense and should work with what's in your database.
if ($start > $end
|| $start < $lowest_year_in_your_db
|| $end > $highest_year_in_your_db) {
// quit with error
}
Then you can generate a list of columns to use in your query. Here's one way with range and array_map, but you could also just build a string with a for loop.
$columns = implode(', ', array_map(function($year) {
return "Revenue$year";
}, range($start, $end)));
$sql = "SELECT $columns FROM table_name";
Theoretically, the worst thing that should be able to happen with this is that you'd get a column that didn't exist, and your query would fail.
But really, if you have any choice about it, don't do this. Normalize your database as people have stated in the comments, or find whoever keeps adding more year columns to the database and make them do it.
As already pointed out the database design is horrible. You should really normalize it, it's worth the effort.
However if that is not possible at the moment the follow code should do exactly what you need:
// Connect to DB
$mysqli = new mysqli("localhost", "USERNAME", "PASSWORD", "DATABASE");
// Get column names
$columns = $mysqli->query('SHOW COLUMNS FROM revenue')->fetch_all();
$columnNames = array_column($columns, 0);
// Extract years from column names
$years = array_map(function($columnName) {
return (int) substr($columnName, -4);
}, $columnNames);
// Get max and min year
$maxYear = max($years);
$minYear = min($years);
// Input year start and end
$start = (int) $_POST['start']; // User-input
$end = (int) $_POST['end']; // User-input
// Avoid wrong inputs
if($start > $end || $start < $minYear || $end > $maxYear) {
die('Error');
}
// Create the SQL-query
$selectColumns = [];
for ($i = $start; $i <= $end; $i++) {
$selectColumns[] = "revenue" . $i;
}
$queryString = "SELECT " . implode(", ", $selectColumns) . " FROM TABLE";
// Run the query
// ...
In my laravel project I am inserting multiple records at time with modelname::insert method. Now I want to get last inserted id of it.I read somewhere when you insert multiple records with single insert method and try to get the last_record_id it will gives you the first id of the last inserted query bunch. But my first question is how to get last record id with following code .If I am able to get first id of the bunch .I ll make other ids for other record by my own using incremental variable.
Code to insert multiple record
if(!empty($req->contract_name) && count($req->contract_name)>0)
{
for($i=0; $i<count($req->contract_name); $i++)
{
$contract_arr[$i]['client_id'] = $this->id;
$contract_arr[$i]['contract_name'] = $req->contract_name[$i];
$contract_arr[$i]['contract_code'] = $req->contract_code[$i];
$contract_arr[$i]['contract_type'] = $req->contract_type[$i];
$contract_arr[$i]['contract_ext_period'] = $req->contract_ext_period[$i];
$contract_arr[$i]['contract_email'] = $req->contract_email[$i];
$contract_arr[$i]['created_at'] = \Carbon\Carbon::now();
$contract_arr[$i]['updated_at'] = \Carbon\Carbon::now();
$contract_arr[$i]['created_by'] = Auth::user()->id;
$contract_arr[$i]['updated_by'] = Auth::user()->id;
if($req->startdate[$i] != ''){
$contract_arr[$i]['startdate'] = date('Y-m-d',strtotime($req->startdate[$i]));
}
if($req->enddate[$i] != ''){
$contract_arr[$i]['enddate'] = date('Y-m-d',strtotime($req->enddate[$i]));
}
}
if(!empty($contract_arr)){
Contract::insert($contract_arr);
}
}
You should be able to call it like this
$lastId = Contract::insert($contract_arr)->lastInsertId();
If i see right, you're using a Model. Direct inserting only shows an success boolean. Try this instead:
Contract::create($contract_arr)->getKey()
i've table with a thousand rows and i want to creating analitycs with chart display my front end php
my table structure is
and how i display this data :
by user_agent column i display operating system, browsers, and devices.
for now i still using the old algorithm with looping using for () method and parsing each rows. And it takes a long time respond and displaying the data.
anyone knows how i can display this data without take long respond in my website? any idea? with the database structure or my php script?
Thankyou before.
Assuming you're loading all your data in a PHP script and postprocessing it in a for-loop in PHP, you should alter your database query. A GROUP BY statement might help. Of course, you need to alter your script to work with the new data. Revisiting your database structure is a good idea, too. A better approach might be not to save the whole user-agent string in one column but to use several columns.
Example before:
$data = $db->query('SELECT * FROM table');
for ($i = 0; $i <= $data->max(); i++) {
$row = $data->getRow($i);
postprocessRow($row); /* $sum += 1; */
}
Example after:
$data = $db->query('SELECT count(*) as weight, * FROM table GROUP BY user_agent');
for ($i = 0; $i <= $data->max(); i++) {
$row = $data->getRow($i);
postprocessRowWeighted($row); /* $sum += $row['weight']; */
}
I need a page that displays records from a database, sorted by their jobs. So the database holds different kind of persons with different jobs. For example, on the page "teacher" I just want to display all the teachers, not the other persons. I want to have 3 persons on a page and a button "previous" and "next" beneath it. If an user clicks the next-button I want the next 3 records to be shown. When the user reaches the last records, I need the next-button to disappear. Same goes for "previous".
What I have so far:
This piece of code creates a value named startrow.
if (!isset($_GET['startrow']) or !is_numeric($_GET['startrow'])) {
//give the value of the starting row 0 because nothing was found in URL
$startrow = 0;
//otherwise take the value from the URL
} else {
$startrow = (int)$_GET['startrow'];
}
The query I have:
$sql = mysql_query("SELECT * FROM $tbl_name WHERE jobs='teacher' LIMIT $startrow, 3")or
die(mysql_error());
$sql2 = "SELECT COUNT(*) AS TotalJobs FROM $tbl_name WHERE jobs='teacher'";
$result_count = mysql_query($sql2);
$count = mysql_fetch_array($result_count);
I created the $count for the if / else function in the next part (the part that doesn't seem to work the way I want it to):
if ($startrow < $count )
echo 'Next';
$prev = $startrow - 3;
//only print a "Previous" link if a "Next" was clicked
if ($prev >= 0)
echo 'Previous';
So the previous-button seems to work the way it should. The next doesn't. I've created the
if ($startrow < $count)
so basicly, if the value of startrow is smaller than the total number of records, it puts a next-button. But if I test this, it displays the next-button anyhow, no matter the value of startrow.
What am I missing here?
mysql_fetch_array returns an array containing the count, not the value itself. Use $count['TotalJobs'] instead.
Also, you shouldn't use the mysql extension anymore, instead use PDO or MySQLi.
Edit
You can change:
$count = mysql_fetch_array($result_count);
to
$countArr = mysql_fetch_array($result_count);
$count = $countArr['TotalJobs'];
I have an Array (twodimensional) and i insert it into my database.
My Code:
$yourArr = $_POST;
$action = $yourArr['action'];
$mysql = $yourArr['mysql'];
$total = $yourArr['total'];
unset( $yourArr['action'] , $yourArr['mysql'] , $yourArr['total'] );
foreach ($yourArr as $k => $v) {
list($type,$num) = explode('_item_',$k);
$items[$num][$type] = $v;
$pnr= $items[$num][pnr];
$pkt= $items[$num][pkt];
$desc= $items[$num][desc];
$qty= $items[$num][qty];
$price= $items[$num][price];
$eintragen = mysql_query("INSERT INTO rechnungspositionen (artikelnummer, menge, artikel, beschreibung,preis) VALUES ('$pnr', '$qty', '$pkt', '$desc', '$price')");
}
I get 5 inserts in the Database but only the 5th have the informations i want. The firsts are incomplete.
Can someone help me?
Sorry for my english.
check if You have sent vars from browser in array (like
input name="some_name[]" ...
also You can check, what You get at any time by putting var_dump($your_var) in any place in script.
good luck:)
You probably want to have your query and the 5 assignments above that outside of the foreach. Instead in a new loop which only executes once for every item instead of 5 times. Your indentation even suggests the same however your brackets do not.
Currently it is only assigning one value each time and executing a new query. After 5 times all the variables are assigned and the last inserted row finally has everything proper.
error_reporting(E_ALL);
$items = array();
foreach($yourArr as $k => $v) {
// check here if the variable is one you need
list($type, $num) = explode('_item_', $k);
$items[$num][$type] = $v;
}
foreach($items as $item) {
$pnr = mysql_real_escape_string($item['pnr']);
$pkt = mysql_real_escape_string($item['pkt']);
$desc = mysql_real_escape_string($item['desc']);
$qty = mysql_real_escape_string($item['qty']);
$price = mysql_real_escape_string($item['price']);
$eintragen = mysql_query("INSERT INTO rechnungspositionen (artikelnummer, menge, artikel, beschreibung,preis) VALUES ('$pnr', '$qty', '$pkt', '$desc', '$price')");
}
Switching on your error level to E_ALL would have hinted in such a direction, among else:
unquoted array-keys: if a constant of
the same name exists your script will
be unpredictable.
unescaped variables: malformed values
or even just containing a quote which
needs to be there will fail your
query or worse.
naïve exploding: not each $_POST-key
variable will contain the string
item and your list will fail, including subsequent use of $num