In my laravel project I am inserting multiple records at time with modelname::insert method. Now I want to get last inserted id of it.I read somewhere when you insert multiple records with single insert method and try to get the last_record_id it will gives you the first id of the last inserted query bunch. But my first question is how to get last record id with following code .If I am able to get first id of the bunch .I ll make other ids for other record by my own using incremental variable.
Code to insert multiple record
if(!empty($req->contract_name) && count($req->contract_name)>0)
{
for($i=0; $i<count($req->contract_name); $i++)
{
$contract_arr[$i]['client_id'] = $this->id;
$contract_arr[$i]['contract_name'] = $req->contract_name[$i];
$contract_arr[$i]['contract_code'] = $req->contract_code[$i];
$contract_arr[$i]['contract_type'] = $req->contract_type[$i];
$contract_arr[$i]['contract_ext_period'] = $req->contract_ext_period[$i];
$contract_arr[$i]['contract_email'] = $req->contract_email[$i];
$contract_arr[$i]['created_at'] = \Carbon\Carbon::now();
$contract_arr[$i]['updated_at'] = \Carbon\Carbon::now();
$contract_arr[$i]['created_by'] = Auth::user()->id;
$contract_arr[$i]['updated_by'] = Auth::user()->id;
if($req->startdate[$i] != ''){
$contract_arr[$i]['startdate'] = date('Y-m-d',strtotime($req->startdate[$i]));
}
if($req->enddate[$i] != ''){
$contract_arr[$i]['enddate'] = date('Y-m-d',strtotime($req->enddate[$i]));
}
}
if(!empty($contract_arr)){
Contract::insert($contract_arr);
}
}
You should be able to call it like this
$lastId = Contract::insert($contract_arr)->lastInsertId();
If i see right, you're using a Model. Direct inserting only shows an success boolean. Try this instead:
Contract::create($contract_arr)->getKey()
Related
I need to save data from an order table from one database to another through Laravel. I created a function in my controller like this:
public function getMarketplace()
{
$orderoc = OrderOC::orderBy('oc_order.date_added', 'desc')
->join('oc_order_product', 'oc_order_product.order_id', 'oc_order.order_id')
->join('oc_order_history', 'oc_order_history.order_id', 'oc_order.order_id')
->where('oc_order_history.order_status_id', '=', '17')
->get();
foreach($orderoc as $oc){
$ordererp = new Order;
$ordererp->erp_createdid = $oc->created_id;
$ordererp->erp_marketplaceid = 1;
$ordererp->erp_site = rand(1,100000000);
$ordererp->erp_payment_method = $oc->payment_method;
$ordererp->erp_orderdate = $oc->date_added;
$ordererp->erp_orderaprove = $oc->date_added;
$ordererp->erp_billingid = 1;
$ordererp->erp_shippingid = 1;
$ordererp->erp_marketplace = 'Comércio Urbano';
$ordererp->erp_orderquantity = $oc->quantity;
$ordererp->erp_erro = '';
$ordererp->erp_product_ok = 1;
$ordererp->erp_compraId = null;
$ordererp->save();
if(strlen($oc->created_id) == 0){
$oc->created_id = rand(1,10000000);
$oc->save();
}
$orderprod = new OrderProduct;
$orderprod->erp_productid = $oc->product_id;
$orderprod->erp_createdid = $oc->created_id;
$orderprod->erp_model = $oc->model;
$orderprod->erp_quantity = $oc->quantity;
}
}
One table is from my ERP and the other is responsible for receiving OpenCart purchases, but every time I run, the same product appears more than once in my order table.
(It is possible to see through the purchase date, since created_id is created in the controller function)
Does anyone know how to tell me why data is duplicated when inserted inside a foreach? This is not the first time, if you tell me a more robust way of doing the job, I'm grateful. Any suggestion? Thank you in advance!
One possiblity is you put unique validation on a table that receive the data
I am trying to create a directory and having an issue calling the "listing image" in the results. The issue is that only some listings will have images, otherwise if they do not, I want them to use the default-image I have set up. When I try and add in the 'image' table to my query, it returns ONLY the results that have an image available (leaving out the other listings that do not have an image).
Here is my code:
public function search($neighborhood = null, $biz_filter = null) {
$neighborhood = $this->uri->segment(3);
$biz_filter = $this->uri->segment(4);
// SELECT
$this->db->select('*');
// MAIN TABLE TO GRAB DATA
$this->db->from('biz');
// TABLES TO JOIN
$this->db->join('city', 'city.city_id = biz.biz_cityID');
$this->db->join('zip', 'zip.zip_id = biz.biz_zipID', 'zip.zip_cityID = city.city_id');
$this->db->join('state', 'state.state_id = city.city_stateID');
$this->db->join('neighborhood', 'neighborhood.neighborhood_id = biz.biz_neighborhoodID');
$this->db->join('biz_filter', 'biz_filter.bizfilter_bizID = biz.biz_id');
$this->db->join('biz_category', 'biz_category.bizcategory_id = biz_filter.bizfilter_bizcategoryID');
if ($neighborhood != "-" AND $biz_filter != "-") {
$this->db->where('biz_category.bizcategory_slug', $biz_filter);
$this->db->where('neighborhood.neighborhood_slug', $neighborhood);
} elseif ($neighborhood != "-" AND $biz_filter == "-") {
$this->db->where('neighborhood.neighborhood_slug', $neighborhood);
} elseif ($neighborhood == "-" AND $biz_filter != "-") {
$this->db->where('biz_category.bizcategory_slug', $biz_filter);
} else {
}
// ORDER OF THE RESULTS
$this->db->group_by('biz_name asc');
// RUN QUERY
$query = $this->db->get();
// IF MORE THAN 0 ROWS ELSE DISPLAY 404 ERROR PAGE
return $query;
}
How can I add in the separate table, 'image' that holds the logo images ('image.image_file'). The 'image' table and 'biz' table are connected through the business ID i pass through each table (image.biz_id = biz.biz_id).
Anyone know how to resolve the query to work properly?
Just use
$this->db->join('image', 'image.biz_id = biz.biz_id', 'left');
To LEFT JOIN your image table. When there is no records in the table for the biz_id the image.image_file will have null values. Read here for more information.
You can use a COALESCE function to replace the "null" images with a predefined default value. Just replace your line with $this->db->select('*'); to this one:
// SELECT
$this->db->select("*, COALESCE(image.image_file, 'images/not_found.png') as my_image_file");
When you render the output make sure you use my_image_file column for the image.
On a side note: avoid using '*' in the select. Select only those columns you actually need. Selecting all columns unnecessarily increases the load on the database server resources.
I am using Zend fetch method to fetch huge number of records from database for creating reports.Since fetchAll is costly as compared to fetch i am using it.And if its the last row i need to add some additinoal logic.So my question is that is there a way to check if next record exists or not inside the while loop. I am using it like the following
//$select is the select query
$objDb = Zend_Registry::get('db');
$objAchQry = $objDb->query($select);
while($arrResult = $objAchQry->fetch()) {
//Do something
//I need to do something here if its the last record like
/*
if($last_rec)
do something
*/
}
Is there a way to check if the current one is last record or if any other record exists. I know to do it by taking count of records and incrementing a counter inside the loop.But i dont need it.Any solutions.?
"is there a way to check if next record exists" The condition on your while loop does exactly just that. The loop won't execute any more if no more rows exist to fetch.
Think of it this way:
while($arrResult = $objAchQry->fetch()) {
//Do something
}
// Now I'm just after the last record
/*
do something
*/
If you really need to do something before the last row is processed, you could modify your code to
$total_records = // get total no of rows
$counter = 0;
while($arrResult = $objAchQry->current()) {
//Do something
$counter ++;
//I need to do something here if its the last record like
if( ! $bojAchQry->next()) {
// The row currently being processed is the last one.
} else {
break;
}
}
One way - You can track with counter,
$total_records = // get total no of rows
$counter = 0;
while($arrResult = $objAchQry->fetch()) {
//Do something
$counter ++;
//I need to do something here if its the last record like
if($counter == $total_records ) // this iteration will be the last one.
//do something
}
I have a table with a column named balance.
if(mysqli_num_rows($get_bank_check_res) > 0){
$display_block = "<p>your autho code is:</p>";
$account_check = mysql_fetch_array($get_bank_check_res);
$balance= $account_check > $grand_total_safe ? (balance - $grand_total_safe) : 0;
$display_block .= "<p>your balance is: '".$balance."' </p>";
I received the warning : Undefined variable balance. Trying mysql_fetch_assoc() didn't work either.
You get a row back with mysql_fetch_array, it doesn't automagically create new variables for you. Ie your column is located here. Also, since you are using the MySQLi extension instead of mysql, it look like this:
$row = $get_bank_check_res->fetch_assoc();
$balance = $row["balance"];
then you can do you whatever math your doing using the values found inside your $row array.
I have an Array (twodimensional) and i insert it into my database.
My Code:
$yourArr = $_POST;
$action = $yourArr['action'];
$mysql = $yourArr['mysql'];
$total = $yourArr['total'];
unset( $yourArr['action'] , $yourArr['mysql'] , $yourArr['total'] );
foreach ($yourArr as $k => $v) {
list($type,$num) = explode('_item_',$k);
$items[$num][$type] = $v;
$pnr= $items[$num][pnr];
$pkt= $items[$num][pkt];
$desc= $items[$num][desc];
$qty= $items[$num][qty];
$price= $items[$num][price];
$eintragen = mysql_query("INSERT INTO rechnungspositionen (artikelnummer, menge, artikel, beschreibung,preis) VALUES ('$pnr', '$qty', '$pkt', '$desc', '$price')");
}
I get 5 inserts in the Database but only the 5th have the informations i want. The firsts are incomplete.
Can someone help me?
Sorry for my english.
check if You have sent vars from browser in array (like
input name="some_name[]" ...
also You can check, what You get at any time by putting var_dump($your_var) in any place in script.
good luck:)
You probably want to have your query and the 5 assignments above that outside of the foreach. Instead in a new loop which only executes once for every item instead of 5 times. Your indentation even suggests the same however your brackets do not.
Currently it is only assigning one value each time and executing a new query. After 5 times all the variables are assigned and the last inserted row finally has everything proper.
error_reporting(E_ALL);
$items = array();
foreach($yourArr as $k => $v) {
// check here if the variable is one you need
list($type, $num) = explode('_item_', $k);
$items[$num][$type] = $v;
}
foreach($items as $item) {
$pnr = mysql_real_escape_string($item['pnr']);
$pkt = mysql_real_escape_string($item['pkt']);
$desc = mysql_real_escape_string($item['desc']);
$qty = mysql_real_escape_string($item['qty']);
$price = mysql_real_escape_string($item['price']);
$eintragen = mysql_query("INSERT INTO rechnungspositionen (artikelnummer, menge, artikel, beschreibung,preis) VALUES ('$pnr', '$qty', '$pkt', '$desc', '$price')");
}
Switching on your error level to E_ALL would have hinted in such a direction, among else:
unquoted array-keys: if a constant of
the same name exists your script will
be unpredictable.
unescaped variables: malformed values
or even just containing a quote which
needs to be there will fail your
query or worse.
naïve exploding: not each $_POST-key
variable will contain the string
item and your list will fail, including subsequent use of $num