I have a function that gets a numeric value (as Object) and returns a well formatted representation of that number. Because we can get very small numbers, in the process we use the Number object of flex. this is part of the code:
var numericValue:Number = Number(value.toString());
var fixed:String = numericValue.toFixed(precision);
This is the problem: there are situations that the numeric value is in the form of
5.684341886080802e-14
because we want to represent these numbers as 0 we use the above code. In this specific case, where precision is 0 we get an odd result
Initial Values:
value = 5.684341886080802e-14
percision = 0
Operation on values:
var numericValue:Number = Number(value.toString());
var fixed:String = numericValue.toFixed(precision);
Result:
fix = "1."
Why is this?
(BTW - on other numbers in the representataion of X.XXXXXXe-YY with percision bigger than 0 we get the correct result of 0)
This is a bug in Flash Player (FP-5141). It has been around for quite a while. The bug report says it is fixed, but it is not as of Flash Player 11.5.
Related
I had the task to code the following:
Take a list of integers and returns the value of these numbers added up, but only if they are odd.
Example input: [1,5,3,2]
Output: 9
I did the code below and it worked perfectly.
numbers = [1,5,3,2]
print(numbers)
add_up_the_odds = []
for number in numbers:
if number % 2 == 1:
add_up_the_odds.append(number)
print(add_up_the_odds)
print(sum(add_up_the_odds))
Then I tried to re-code it using function definition / return:
def add_up_the_odds(numbers):
odds = []
for number in range(1,len(numbers)):
if number % 2 == 1:
odds.append(number)
return odds
numbers = [1,5,3,2]
print (sum(odds))
But I couldn’t make it working, anybody can help with that?
Note: I'm going to assume Python 3.x
It looks like you're defining your function, but never calling it.
When the interpreter finishes going through your function definition, the function is now there for you to use - but it never actually executes until you tell it to.
Between the last two lines in your code, you need to call add_up_the_odds() on your numbers array, and assign the result to the odds variable.
i.e. odds = add_up_the_odds(numbers)
I have created an HTML web app in google script this works like a calculator, This app works fine if I add the input in descending order however if I skip the order and update in put data numbers randomly in any column then I am not getting the output properly
Example:- update the numbers in box number 4 and 5 then update in box number 1 you will find the differences in total numbers
Please refer the attached sheet for detailed script
Project Name- Project Proposal Form
$("#rTpe1").keyup(function(e){
$("#rFor1").val(this.value * $("#PerHourRate1").val());
$("#rFor3").val( Number($("#rFor1").val()) +Number($("#rFor2").val()))
});
$("#rTpe2").keyup(function(e){
$("#rFor2").val(this.value * $("#PerHourRate2").val());
$("#rFor3").val( Number($("#rFor1").val()) + Number($("#rFor2").val()))
});
$("#rTpe12").keyup(function(e){
$("#rFor12").val(this.value * $("#PerHourRate3").val());
$("#rFor3").val( Number($("#rFor1").val()) + Number($("#rFor2").val())+ Number($("#rFor12").val()))
});
$("#rTpe13").keyup(function(e){
$("#rFor13").val(this.value * $("#PerHourRate4").val());
$("#rFor3").val( Number($("#rFor1").val()) + Number($("#rFor2").val())+ Number($("#rFor12").val())+ Number($("#rFor13").val()))
});
I could be wrong, but I think that's the main culprit:
If your work your way top to bottom, the output in '#rFor3' is not affected. For example, if you enter values in the first field ('#rTpe1'), this statement
Number($("#rFor2").val()))
will evaluate to '0' because '#rFor2' probably contains an empty string at this point and Number("") will get you a zero. Because all subsequent input fields reference the results of previous calculations ('rTpe2' references 'rFor1', 'rTpe12' references both 'rFor1' and 'rFor2', etc), the sum will come out as correct.
Now consider the reverse scenario. For simplicity, let's make all your rates equal to 1. If you enter the value of '5' into 'rTpe12', the value of 'rFor3' will be
Number("") + Number("") + Number(5*1) == 5; //the first two inputs will contain empty strings at this point
The output of '#rFor3' would be 5. If you go up a step and enter the value of '2' into 'rTpe2', the value of the 'rFor3' output will change to
Number("") + Number(2*1) == 2; the first input will contain an empty string.
The code is not easy to understand, so even if this solution doesn't work for you, consider caching your DOM elements to improve performance and make your code more readable. Currently, you are using jQuery selectors to search the DOM over and over again, which is a serious performance drag. You could also store your calculated value as a variable and simply add values to it instead of recalculating on each input. For example
$('document').ready(function(){
var total = 0;
var input1 = $('#input1');
var input2 = $('#input1');
var input3 = $('#input1');
var output = $('#output');
input1.keyup(function(e){
var value = Number(this.value);
sum += value;
output.val(sum);
});
});
For some values, such as "10152116260776319", casting to number with parseFloat or Number("***") methods increments the original value by 1.
Number("10152116260776319") => 10152116260776320
Number("10202784509328139") => 10202784509328140
Is there any way to fix this? Or do I need to update all of my code to Strings.
Thanks in advance.
The issue is not due to a problem with parseFloat or Number("***"), but a limitation of the Number type. Basically, the Number type can only hold integers properly if they're below 253 (9,007,199,254,740,992), because they're double precision floating point numbers (check out this Wikipedia page for more details: http://en.wikipedia.org/wiki/Double-precision_floating-point_format)
The problem occurs even without casting, for example
var val1:Number = 9007199254740990;
var val2:Number = 9007199254740991;
var val3:Number = 9007199254740992;
var val4:Number = 9007199254740993;
var val5:Number = 9007199254740994;
var val6:Number = 10152116260776319;
trace(val1); // 9007199254740990
trace(val2); // 9007199254740991
trace(val3); // 9007199254740992
trace(val4); // 9007199254740992
trace(val5); // 9007199254740994
trace(val6); // 10152116260776320
If you really need to store integers that large, someone's made a BigInt class that you can use: http://as3asclublib.googlecode.com/svn-history/r29/trunk/data/BigInt.as
i am just not able to read a csv file .I want to display a graph for it.
I am getting error:
TypeError: n is undefined
please help me out!!
d3.csv("example.csv", function(dataset){
var svg=d3.select("body").append("svg").attr("width",w).attr("height",h);
var xScale=d3.scale.ordinal().domain(d3.range(dataset.length)).rangeRoundBands([0,w],0.05);
var yScale=d3.scale.linear().domain([0,d3.max(dataset.value)]).range([0,h]);
svg.selectAll("rect").data(dataset).enter().append("rect").attr({x:function(d,i) {return xScale(i);}, y:function(d){
return h-yScale(d);}, width:xScale.rangeBand(),height:function(d){return yScale(d);},fill:function(d){return "rgb(0,0,"+(d.value*10)+")";}});
d3.select("svg").selectAll("text").data(dataset).enter().append("text").text(function(d) {return d.value;}).attr("x",function(d,i){
return xScale(i)+xScale.rangeBand()/2;}).attr("y",function(d){return h-yScale(d)+14;}).attr("font-family","sans-serif").attr("font-size","10px").attr
("fill","white").attr("text-anchor","middle");
d3.select("p").on("click",function(){
var numValues=dataset.length;
dataset=[];
for(var i=0;i<numValues;i++)
{var newNumber=Math.floor(Math.random()*25);
dataset.push(newNumber,newNumber);
}
yScale.domain([0,d3.max(dataset)]);
svg.selectAll("rect").data(dataset).transition().delay(function(d,i){return i/dataset.length*1000;})
.duration(500).attr("y",function(d){return h-yScale(d); }).attr("height",function(d) {return yScale(d);}).attr("fill",function(d){
return "rgb(0,0,"+(d.value*10)+")";});
svg.selectAll("text").data(dataset).transition().delay(function(d,i){return i/dataset.length*1000;}).duration(500).text(function(d){return d.value;})
.attr("x",function(d,i){return xScale(i)+xScale.rangeBand()/2;}).attr("y",function(d) {return h-yScale(d)+14;})
.attr("font-family","sans-serif").attr("font- size","10px").attr("fill","white").attr("text-anchor","middle")
;});
});
here is my csv file
names,value
john,78
brad,105
amber,103
james,2
dean,74
pat,45
matt,6
andrew,18
ashley,15
As mentioned by cuckovic there are quite a few errors in your code, not to mention that you seem to be using different styles to achieve similar things which is confusing. Anyway there are 3 fundamental things that are casuing you trouble, the first is your dataset. The value column of the csv is being read as a string. You need to convert it to a number by:
dataset.forEach(function (d,i) {
d.value = +d.value;
});
The next issue you have is the yScale where you have set the range to .range([0,h]);. This is the wrong way round for an svg viewport in which the y direction starts from top and increases towards the bottom. So you need to swap the 0 and h around in the range.
The next thing to address is the difference between d and d.value. When you bind data through the data() operator you are generally binding an array. In this case it is an array of objects. So after you have bound the data, d refers to each element of that array which in this case is an object containing a name and a value. This can be seen if you console.log your dataset. When d is passed to yScale it doesn't know what to do with it as it is not a number, what you really want to do is to pass d.value to yScale. So replace your d's with d.value.
Finally, the last part of your code starting at d3.select("p") does not seem to add anything.
I'd recommend reading Scott Murray's tutorials, particularly this one if you haven't already.
I'm preparing data for a datatable in Linq2Sql
This code highlights as a 'Possible multiple enumeration of IEnumerable' (in Resharper)
// filtered is an IEnumerable or an IQueryable
var total = filtered.Count();
var displayed = filtered
.Skip(param.iDisplayStart)
.Take(param.iDisplayLength).ToList();
And I am 100% sure Resharper is right.
How do I rewrite this to avoid the warning
To clarify, I get that I can put a ToList on the end of filtered to only do one query to the Database eg.
var filteredAndRun = filtered.ToList();
var total = filteredAndRun.Count();
var displayed = filteredAndRun
.Skip(param.iDisplayStart)
.Take(param.iDisplayLength).ToList();
but this brings back a ton more data than I want to transport over the network.
I'm expecting that I can't have my cake and eat it too. :(
It sounds like you're more concerned with multiple enumeration of IQueryable<T> rather than IEnumerable<T>.
However, in your case, it doesn't matter.
The Count call should translate to a simple and very fast SQL count query. It's only the second query that actually brings back any records.
If it is an IEnumerable<T> then the data is in memory and it'll be super fast in any case.
I'd keep your code exactly the same as it is and only worry about performance tuning when you discover you have a significant performance issue. :-)
You could also do something like
count = 0;
displayed = new List();
iDisplayStop = param.iDisplayStart + param.iDisplayLength;
foreach (element in filteredAndRun) {
++count;
if ((count < param.iDisplayStart) || (count > iDisplayStop))
continue;
displayed.Add(element);
}
That's pseudocode, obviously, and I might be off-by-one in the edge conditions, but that algorithm gets you the count with only a single iteration and you have the list of displayed items only at the end.