Right now I have 3 tables, the first one for users, the second for group of users and the third one for points (and other ones, if you want one I could create it for you :P).
Table users:
user_id
|
fname
|
active
Table user_groups:
id
|
group_id
|
user_id
|
active
Table user_points:
id
|
point_type
|
point_units
|
active
Each user of a group could earn points for different activities. So, I want to show the points that the users have earned for their different activities, with a grand total at the end.
Here's the query that I have so far:
SELECT
u.user_id AS `ID`,
u.fname AS `Name`,
SUM(case when up.point_type = 'Referrals' then up.point_units else 0 end) AS `Referrals`,
SUM(case when up.point_type = 'Email' then up.point_units else 0 end) AS `Email`,
SUM(case when up.point_type = 'Facebook' then up.point_units else 0 end) AS `Facebook`,
SUM(case when up.point_type = 'Twitter' then up.point_units else 0 end) AS `Twitter`,
SUM(case when up.point_type = 'Extra' then up.point_units else 0 end) AS `Extra`,
SUM(case when up.point_type = 'Discount' then up.point_units else 0 end) AS `Discount`,
SUM(case when u.user_id = up.user_id then up.point_units else 0 end) AS `Total`
FROM users AS u, user_groups AS uc, user_points AS up
WHERE u.user_id = uc.user_id
AND u.user_id = up.user_id
AND u.active = 1
AND uc.active = 1
AND up.active = 1
AND uc.group_id = up.group_id
AND uc.group_id = 65
ORDER BY u.fname;
The problem that I have is that the query only shows one user and the total sum of the points of all the users in each column.
I know that this isn't the right approach, but I don't know how to put everything into a query. Also, I'm giving this query to PHPExcel, so it could generate a nice friendly report.
Any ideas? :-)
You need a GROUP BY clause when using aggregate functions. Yours might look like:
GROUP BY u.user_id
In your query it would go here:
AND uc.group_id = 65
GROUP BY u.user_id
ORDER BY u.fname;
Related
I would like to join 3 tables.
The result is one of the field - SUM from the other table like this image, please help
You don't need to join tblwork as you can get all required fields from other 2 tables.
Following query should work:
select t1.nmstudent,
sum(case when t2.idwork = 'w001' then t2.trprice else 0 end) as w001,
sum(case when t2.idwork = 'w002' then t2.trprice else 0 end) as w002,
sum(case when t2.idwork = 'w003' then t2.trprice else 0 end) as w003,
sum(case when t2.idwork = 'w004' then t2.trprice else 0 end) as w004
from tblstudent t1
inner join tblTrans t2
on t1.idstudent = t2.idstudent
group by t1.idstudent;
Hope it helps!
I want to get results for likes by a specific user-id and all likes and dislikes of a specific page id.
My structure looks like this:
`pages`: (id, title)
`pages_likes`: (id, page_id, uid, status)
If the status is -1 it's a dislike of a specific page, if it's 1 it's a like.
So, to get all likes this is my query:
SELECT COUNT(id) FROM pages_likes WHERE status = '1'
But now I also want to get if user-id 3 for example likes this page with
SELECT COUNT(id) FROM pages_likes WHERE status = '1' AND uid='3'
How can I achieve both in one query? I guess there has to be changed something right after the SELECT statement?
If you want to do this in a single query, use conditional aggregation:
SELECT SUM(CASE WHEN uid = '3' THEN 1 ELSE 0 END) AS threeLikes,
SUM(CASE WHEN uid <> '3' THEN 1 ELSE 0 END) AS otherLikes
FROM pages_likes
WHERE status = '1'
Another option would be to use a UNION, cf. the answer given by #bernie
Update:
If you want page likes and dislikes in the same query, you can try:
SELECT SUM(CASE WHEN uid = '3' AND status = '1' THEN 1 ELSE 0 END) AS threeLikes,
SUM(CASE WHEN uid <> '3' AND status = '1' THEN 1 ELSE 0 END) AS otherLikes
SUM(CASE WHEN uid = '3' AND status = '0' THEN 1 ELSE 0 END) AS threeDislikes,
SUM(CASE WHEN uid <> '3' AND status = '0' THEN 1 ELSE 0 END) AS otherDisikes
FROM pages_likes
I think this would work:
SELECT '' user, COUNT(id) likes
FROM pages_likes
WHERE status = '1'
GROUP BY 1
UNION ALL
SELECT uid user, COUNT(id) likes
FROM pages_likes
WHERE status = '1' AND uid='3'
GROUP BY 1
I would do it this way:
SELECT COUNT(*) AS total_likes, SUM(uid=3) AS uid3_likes
FROM pages_likes
WHERE status=1 AND page_id=1234
Re your comment:
Here's an example of showing total likes, and total dislikes. It's similar to the answer from #TimBiegeleisen.
SELECT SUM(status=1) AS total_likes,
SUM(CASE WHEN uid=3 AND status=1 THEN 1 END) AS uid3_likes
SUM(CASE WHEN uid=3 AND status=-1 THEN 1 END) AS uid3_dislikes
FROM pages_likes
WHERE page_id=1234
I have 2 tables odds and matches :
matches : has match_id and match_date
odds : has id, timestamp, result, odd_value, user_id, match_id
I had a query that get the following information from those tables for each user:
winnings : the winning bets for each user. (when odds.result = 1)
loses : the lost bets for each user.(when odds.result != 1)
points : the points of each user.(the sum of the odds.odd_value) for each user.
bonus : for each continuous 5 winnings i want to add extra bonus to this variable. (for each user)
How to calculate bonus?
I tried to use this query and I faced a problem : (you can check it here SQL Fiddle)
the calculated bonus are not right for all the users :
first user:(winnings:13, bonus=2).
second user:(winnings:8, bonus=2)bonus here should be 1.
third user:(winnings:14, bonus=3)bonus here should be 2.
why does the query not calculate the bonus correctly?
select d.user_id,
sum(case when d.result = 1 then 1 else 0 end) as winnings,
sum(case when d.result = 2 then 1 else 0 end) as loses,
sum(case when d.result = 1 then d.odd_value else 0 end) as points,
f.bonus
FROM odds d
INNER JOIN
(
SELECT
user_id,SUM(CASE WHEN F1=5 THEN 1 ELSE 0 END) AS bonus
FROM
(
SELECT
user_id,
CASE WHEN result=1 and #counter<5 THEN #counter:=#counter+1 WHEN result=1 and #counter=5 THEN #counter:=1 ELSE #counter:=0 END AS F1
FROM odds o
cross join (SELECT #counter:=0) AS t
INNER JOIN matches mc on mc.match_id = o.match_id
WHERE MONTH(STR_TO_DATE(mc.match_date, '%Y-%m-%d')) = 2 AND
YEAR(STR_TO_DATE(mc.match_date, '%Y-%m-%d')) = 2015 AND
(YEAR(o.timestamp)=2015 AND MONTH(o.timestamp) = 02)
) Temp
group by user_id
)as f on f.user_id = d.user_id
group by d.user_id
I am not sure how your result related to matches table,
you can add back WHERE / INNER JOIN clause if you need.
Here is link to fiddle
and the last iteration according to your comments:
And here is a query:
SET #user:=0;
select d.user_id,
sum(case when d.result = 1 then 1 else 0 end) as winnings,
sum(case when d.result = 2 then 1 else 0 end) as loses,
sum(case when d.result = 1 then d.odd_value else 0 end) as points,
f.bonus
FROM odds d
INNER JOIN
(
SELECT
user_id,SUM(bonus) AS bonus
FROM
(
SELECT
user_id,
CASE WHEN result=1 and #counter<5 AND #user=user_id THEN #counter:=#counter+1
WHEN result=1 and #counter=5 AND #user=user_id THEN #counter:=1
WHEN result=1 and #user<>user_id THEN #counter:=1
ELSE
#counter:=0
END AS F1,
#user:=user_id,
CASE WHEN #counter=5 THEN 1 ELSE 0 END AS bonus
FROM odds o
ORDER BY user_id , match_id
) Temp
group by user_id
)as f on f.user_id = d.user_id
group by d.user_id
I am trying to return multiple counts and averages from multiple tables sorting by gender and am getting incorrect data. I understand that the following is incorrect, but I am unsure of how to fix it. (Edit: Problem with group by gender. See below.)
Here is the query:
SELECT c.gender AS 'Gender',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
(SELECT COUNT(DISTINCT CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) ) AS 'Open Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Avg Open',
(SELECT COUNT(DISTINCT CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) ) AS 'Click Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Avg Click',
COUNT(DISTINCT ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM ((mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id)
LEFT JOIN mailing_recipient_click mrc ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON c.cons_id = ca.cons_id)
WHERE m.mailing_id = 1
AND gender IS NOT NULL
GROUP BY c.gender;
Here is the table which would be correct if the totals in the fields were correct:
GENDER Mailing Recipient Open Total Avg Open Click Total Avg Click Donations Avg Amt
F 105 2 0.5000 2 0.5000 105 22.5000
M 98 2 0.5000 2 0.5000 98 18.8780
EDIT: Here is an example of what I am hoping to achieve. I am certain that the above values are being repeated. The below values are just examples of what I am expecting:
GENDER Mailing Recipient Open Total Avg Open Click Total Avg Click Donations Avg Amt
F 105 8 0.0761 4 0.0380 2 22.5000
M 98 2 0.0204 1 0.0102 1 18.8000
Edit:
After playing around a bit, I thought that I had discovered that the joining the cons table was what is giving me problematic returns, but the problem is with GROUP BY when using gender. To illustrate, this query (which is grouped by mailing name instead of gender) works beautifully.
select m.mailing_name AS 'mailing',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
SUM(CASE
when mrc.mailing_recipient_click_type_id = 2 THEN 1
END)
AS 'Open Total',
AVG(CASE
WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1
ELSE 0
END) AS 'Avg Open',
SUM(CASE
WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1
END)
AS 'Click Total',
AVG(CASE
WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1
ELSE 0
END) AS 'Avg Click',
COUNT(ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM
mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id
LEFT JOIN mailing_recipient_click mrc
ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON mr.cons_id = c.cons_id
WHERE m.mailing_id = 1
GROUP BY m.mailing_name;
The statement is identical with the exception of the first and last lines.
Try this:
I'm not sure what you mean by Avg Open and Avg Click.
SELECT c.gender AS 'Gender',
COUNT(DISTINCT mr.mailing_recipient_id) AS 'Mailing Recipients',
SUM(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Open Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 2 THEN 1 ELSE 0 END) AS 'Avg Open',
SUM(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Click Total',
AVG(CASE WHEN mrc.mailing_recipient_click_type_id = 1 THEN 1 ELSE 0 END) AS 'Avg Click',
COUNT(DISTINCT ca.cons_action_contribution_id) AS Donations,
AVG(ca.transaction_amt) AS 'Avg Donation Amt'
FROM mailing m
LEFT JOIN mailing_recipient mr ON m.mailing_id = mr.mailing_id
LEFT JOIN mailing_recipient_click mrc ON mr.mailing_recipient_id = mrc.mailing_recipient_id
LEFT JOIN cons_action_contribution ca ON mr.cons_id = ca.cons_id
LEFT JOIN cons c ON c.cons_id = ca.cons_id
WHERE m.mailing_id = 1
AND gender IS NOT NULL
GROUP BY c.gender;
I also think that mrc.mailing_recipient_click_type_id = 2 means open and mrc.mailing_recipient_click_type_id = 1 mean click seems strange to me. I would expect this data to be exclusive and stored in two different fields.
I am having a mysql problem I am trying to find both the most current payment value, and, for a particular month (in this query I'm using April). Link to the sqlfillde is here
(case when max(py.pay_date)and month(py.pay_date)= 4 then amount else 0 end) max_pay_april,
This is what I have but it doesn't seem to be working. The most current payment value is: (5, '2012-04-20', 90,) therefore it would be 90 I would really appreciate some help please.
How about this:
select p.name,
v.v_name,
sum(case when Month(py.pay_date) = 4 then amount end) april_amount,
max(case
when month(py.pay_date)= 4
and py.pay_date = (select max(pay_date)
from payment
where month(pay_date) =4 )
then amount else 0 end) max_pay_april,
sum(case
when Month(py.pay_date) = Month(curdate())
then amount end) current_month_amount,
sum(case
when Month(py.pay_date) = Month(curdate())-1
then amount end) previous_month_amount
from persons p
left join vehicle v
on p.id = v.person_veh
left join payment py
on p.id = py.person_id
group by p.name,
v.v_name
see SQL Fiddle with demo