mysql SUM CASE self join - mysql

Question

i need some help with this query
this is the actual result of my query
price received qty recieved price release qty release
10.30 10 0 0
0 0 10.30 2
0 0 10.30 1
19.20 20 0 0
0 0 19.20 5
0 0 19.20 3
0 0 19.20 1
Using this code in my query
$result = mysql_query("SELECT *,
SUM(CASE WHEN qtyreceived > 0 THEN qtyreceived END) AS qtyrec,
SUM(CASE WHEN qtyrelease > 0 THEN qtyrelease END) AS qtyrel
FROM stockledger
WHERE stockdesc= '$_POST[desc]' GROUP BY pricerelease,pricereceived ");
the results was
price received qtyreceived price release qtyrelease bal
10.30 10 10
19.20 20 20
10.30 3 -3
19.20 9 -9
and i want to view the result this way so i can get the remaining number for 2 prices
price received qtyreceived price release qtyrelease bal
10.30 10 10.30 3 7
19.20 20 19.20 9 11
thanks.....;

Answer 1

From seeing your data, I think it will be based on the prices. Right? try this one.
SELECT a.PriceReceived,
a.qtyreceived,
b.priceRelease,
b.qtyRelease,
(a.bal + b.bal) as bal
FROM stockledger a
INNER JOIN stockledger b
ON a.priceReceived = b.priceRelease
or another alternative is
SELECT a.PriceReceived,
a.qtyreceived,
b.priceRelease,
b.qtyRelease,
(a.qtyreceived - b.qtyRelease) as bal
FROM stockledger a
INNER JOIN stockledger b
ON a.priceReceived = b.priceRelease
SQLFiddle Demo