I need to find rows that contain a specific number in a set of numeric values that are stored in a table. I'm using the WHERE IN() function of mysql, but I'm having problems with the proper format.
Basically I have the following query:
SELECT id,category, text
FROM ws_cat
WHERE '11' IN (category)
The category field is a VARCHAR and looks like the following:
id category
1 11
2 12,11
3 1,13,9
So I need to find the rows with id 1 and 2 in this case. Unfortunately it doesn't work and I'm guessing it's because of the missing quotes, but all the ideas of reformating with QUOTES() or just changing the format of category to something like '12','11' wouldn't work either. Both would be possible for me as long as it works...
Use the FIND_IN_SET function:
SELECT id, category, text
FROM ws_cat
WHERE FIND_IN_SET('11', category) <> 0;
Related
I'm having issue retrieving info from a DB by using this query with the lower() function:
SELECT DISTINCT "column_name" FROM "table" WHERE lower('car', 'house', 'plane'...) like '%owner%'
The query works with 1 attribute like for exmaple 'car' but when I try to use 100 I get the following error:
Error Code: 1582. Incorrect parameter count in the call to native function 'lower'
What should I change in order to be able to use and output more than a single attribute?
Thanks.
I think the query you want is something like this:
SELECT DISTINCT column_name
FROM yourTable
WHERE owner REGEXP 'car|house|plane'; -- and maybe other terms in the alternation
That is, you want to match all records where the owner column contains one of the substrings car, house, or plane.
I want SQL to show / order the results for the column name first then show results for the description column last.
Current SQL query:
SELECT * FROM products WHERE (name LIKE '%$search_query%' OR description LIKE '%$search_query%')
I tried adding order by name, description [ASC|DESC] on the end but that didn't work.
It's for optimizing the search results. If a certain word is found in description it should go last if a certain word is also found in the name column.
You can use a CASE statement in an ORDER BY to prioritize name. In the example below all results where name is matched will come first because the CASE statement will evaluate to 1 whereas all other results will evaluate to 2.
I'm not sure by your problem description what exactly you want the behavior to be, but you can certainly use this technique to create more refined cases to prioritize your results.
SELECT *
FROM products
WHERE (name LIKE '%$search_query%' OR description LIKE '%$search_query%')
ORDER BY CASE WHEN name LIKE '%$search_query%' THEN 1 ELSE 2 END
If you want the names first, the simplest order by is:
order by (name like '%$search_query%') desc
MySQL treats booleans as numbers in a numeric context, with "1" for true and "0" for false.
While this is undocumented, when results sets combined by a UNION ALL and not sorted afterwards, they stay in the order returned, as UNION ALL just adds new results to the bottom of the result set. This should work for you:
SELECT * FROM products
WHERE name LIKE '%$search_query%'
UNION ALL
SELECT * FROM products
WHERE (description LIKE '%$search_query%' AND name NOT LIKE '%$search_query%')
I apologise if the title is ambiguous.
I have a table called data and in that table is a column called barcode
The barcodes look similar to this:
TEST210001m1c8Wsa
The format of the barcode is as follows:
Job: TEST2
Auto-increment nr: 10001
Type identifier: m1
Unique ID: c8Wsa
I am trying to count the amount of barcodes in the column of the whole table that match the Job, type ID and unique ID. I am not concerned about the auto increment. I'm using the below query but it doesn't seems to work as I expect:
SELECT COUNT(*) FROM data WHERE barcode LIKE 'test2%' AND SUBSTRING('m1', LENGTH(barcode)-7,2)='m1' AND RIGHT('c8Wsa', 5)='c8Wsa'
I'm positive that I am using the SUBSTRING incorrectly because if I remove it the query returns results as expected. Could someone tell me what I'm doing wrong? I'm certain it's something small that I'm missing.
You need to specify column name for first parameter in substring() function and same for right() function also
SELECT COUNT(*) FROM data
WHERE barcode LIKE 'test2%' AND SUBSTRING(barcode, LENGTH(barcode)-6,2)='m1'
AND RIGHT(barcode , 5)='c8Wsa'
Use a sum instead like this.
Select sum(charindex, barcode, 'm1') from table where
barcode like 'Test2%' and barcode like '%c8Wsa''
That way you will effectively count all of the substrings for the barcodes filtered by your where clause.
Here is another way to do this using REGEXP:
SELECT COUNT(*)
FROM data
WHERE barcode REGEXP 'TEST2[0-9]{5}m1c8Wsa';
This assumes that the auto increment number would always be fixed at 5 digits. If it could be variable, then you may use the following pattern:
TEST2[0-9]+m1c8Wsa
id text_1 text_2
1 おはよう おはよ
2 こんにちは ちわー
3 大丈夫 さよなら
4 でんわしたい でんわしよう
I have DB same above.
I want to search with input: おはよう大丈夫？
Expect result will match: id = 1 and id = 3.
Please help me how to query search in Mysql? Thanks you.
The following SQL query will fetch your 2 ids for exact string matching
select id from TABLENAME where text_1 in ('おはよう','大丈夫');
You can also use like operator with % to fetch approximately strings id.
You might face encoding issue (文字化け）depending on your DB settings, so you might have to convert SJIS <-> UTF-8
https://dev.mysql.com/doc/refman/5.7/en/faqs-cjk.html#faq-cjk-what-cjk-avail
Last but not least, if you want to use the full string as a comparison criteria to select the rows, then you can reuse the following code:
how to compute similarity between two strings in MYSQL
select id from TABLENAME where text_1 REGEXP "おはよう大丈夫"
This question already has answers here:
MySQL query finding values in a comma separated string
(11 answers)
Closed 5 years ago.
I work with a system that used comma separated values as a one-2-many relation. It is stored in as a blob.
I try to use the MySQL IN (LIST), but only ends up with the rows where the uid is first in the list or only one in the list.
mytable
uid categories
1 24,25,26
2 25
3 22,23,25
4 25,27
run sql:
SELECT * FROM mytable WHERE 25 IN (categories)
Result:
uid categories
2 25
4 25,27
Missing (should have been selected but are not)
uid categories
1 24,25,26
3 22,23,25
Any idea why a string has to start with 25 and not just contain 25? I guess it is a string issue rather than an IN (LIST) issue
UPDATE - based on answers below:
When using th IN (LIST) on a blob, the blob is converted to an int and commas and "digits" are lost.
In stead use FIND_IN_SET(needle, haystack) that will work also on a blob containing comma separated values.
I think you are looking for FIND_IN_SET
SELECT * FROM mytable WHERE FIND_IN_SET(25,category)
This should give you your asnwer:
SELECT * FROM mytable WHERE CONCAT(',', categories, ',') LIKE '%,25,%'
But it would make more sense to create a connecting table, with each comma separated value as a new row.
What's happening is that MySQL is converting the blob to an integer (not a list of integers) for comparison. So '24,25,26' becomes the value 24. You can confirm this by running the query
SELECT CAST(categories AS signed) FROM mytable
This is not how IN (nor the blob data type) is meant to be used. Is there a reason you're not using another table for this?
Yes, it's astring issue. Your 'list' is just a string to mysql, meaning nothing.
You would have to use RegEx.
But you might think about normalizing your tables instead.