I have a table that looks somewhat like this:
id value
1 0
1 1
1 2
1 0
1 1
2 2
2 1
2 1
2 0
3 0
3 2
3 0
Now for each id, I want to count the number of occurences of 0 and 1 and the number of occurences for that ID (the value can be any integer), so the end result should look something like this:
id n0 n1 total
1 2 2 5
2 1 2 4
3 2 0 3
I managed to get the first and last row with this statement:
SELECT id, COUNT(*) FROM mytable GROUP BY id;
But I'm sort of lost from here. Any pointers on how to achieve this without a huge statement?
With MySQL, you can use SUM(condition):
SELECT id, SUM(value=0) AS n0, SUM(value=1) AS n1, COUNT(*) AS total
FROM mytable
GROUP BY id
See it on sqlfiddle.
As #Zane commented above, the typical method is to use CASE expressions to perform the pivot.
SQL Server now has a PIVOT operator that you might see. DECODE() and IIF() were older approaches on Oracle and Access that you might still find lying around.
Related
Environment :
MySQL 5.7.x
Spring MVC
Table Data (name: TableA)
seq
level
name
order
parent_seq
1
1
name1
1
0
2
1
name2
2
0
3
2
sub1-1
1
1
4
2
sub1-2
2
1
5
2
sub2-1
1
2
6
3
third-2-1
1
5
7
3
third-1-1
1
3
Expected Result
seq
level
name
order
parent_seq
next_level
1
1
name1
1
0
2
3
2
sub1-1
1
1
3
7
3
third-1-1
1
3
2
4
2
sub1-2
2
1
1
2
1
name2
2
0
2
5
2
sub2-1
1
2
3
6
3
third-2-1
1
5
1 (last default value: 1)
Now I'm genenrating expected result with nested for statement(JAVA).
Is there any way to generate expected result only with MySQL Query?
The data stacked in random order in the table is sorted by ASC based on the level column, but check the parent_seq column so that it is sorted under the parent data. And if there are multiple data of the same level, sort by ASC based on the sort column value.
Thanks in advance!
++
EmbraceNothingButFuture's answer was great, but the query seems to work on MySQL 8. I'm using MySQL 5.7. Is there any way to use the query on MySQL 5.7?
Summary:
Use REGEXP_SUBSTR(name,"[0-9]+\-?[0-9]*") to extract the numbers and sort the datas using the numbers.
For MySQL v8 above, you can use LEAD() to generate the "next_level" column based on the "level" column
COALESCE() function for the last default value = 1
SELECT
t1.*,
COALESCE(LEAD(t1.level, 1) OVER(ORDER BY REGEXP_SUBSTR(name,"[0-9]+\-?[0-9]*")), 1) AS next_level
FROM TableA t1
ORDER BY REGEXP_SUBSTR(name,"[0-9]+\-?[0-9]*"), t1.level
See db<>fiddle
I have row and column locations of several students.
Assuming number of rows and columns are fixed (to 3x3), how can I have a query result listing all row and column combinations, with students mapped to the correct location?
For example given these students data:
Student Row Column
Paul 1 1
Chris 1 3
James 2 2
Dwayne 3 3
How to have a query output like this:
Student Row Column
Paul 1 1
NULL 1 2
Chris 1 3
NULL 2 1
James 2 2
NULL 2 3
NULL 3 1
NULL 3 2
Dwayne 3 3
Please help! Thank you very much in advance.
While using PHP, Try mysql_insert_id() for your Code.
See Example here:
http://php.net/manual/en/function.mysql-insert-id.php
Good luck.
First of all, you need to know that Mysql haven't a implicit generator of N numbers of rows, like other RDBMS have, but you can emulate this using something like this:
http://use-the-index-luke.com/blog/2011-07-30/mysql-row-generator#mysql_generator_code
Take a look for study porpuse.
But for a first approach to resolve your problem, you can try this:
SELECT IFNULL((SELECT STUDENT FROM StudentSeatPlan B WHERE B.ROW = TB.ROW_ AND B.COLUMN = TB.COLUMN_),'') AS STUDENT,
TB.ROW_,TB.COLUMN_
FROM (
SELECT 1 ROW_,1 COLUMN_ UNION ALL
SELECT 1,2 UNION ALL
SELECT 1,3 UNION ALL
SELECT 2,1 UNION ALL
SELECT 2,2 UNION ALL
SELECT 2,3 UNION ALL
SELECT 3,1 UNION ALL
SELECT 3,2 UNION ALL
SELECT 3,3) TB
Whatever, it seems like you have a schema problem, something wrong it happens that you need generate data in this form in Mysql, maybe you prefered make it in your app if is the case.
Hello I have a problem with the function avg. I have a table like this and I would like to take the average of each row. I also have the zero in some cells and would like to avoid count them.
data rep val1 val2 val3
1 a 0 3 3
2 a 1 4 0
3 a 1 1 1
4 a 1 3 0
And I would like this result
data AVG
1 3
2 2.5
3 1
4 2
thank you
Assuming you have at least one non-zero value:
SELECT data, (val1+val2+val3)/((val1!=0) + (val2!=0) + (val3!=0)) avg
FROM **table_name**
I think divide by zero returns null see manual, depending on your db settings, so you could do:
SELECT data, COALESCE((val1+val2+val3)/((val1!=0) + (val2!=0) + (val3!=0)),0) avg
FROM **table_name**
Any null values in a row will cause each query to always return null and 0 for the row respectively.
Have a existing table of results like this;
race_id race_num racer_id place
1 0 32 2
1 1 32 3
1 2 32 1
1 3 32 6
1 0 44 2
1 1 44 2
1 2 44 2
1 3 44 2
etc...
Have lots of PHP scripts that access this table output the results in a nice format.
Now I have a case where I need to output the results for only certain race_nums.
So I have created this table races_included.
race_view race_id race_num
Day 1 1 0
Day 1 1 1
Day 2 1 2
Day 2 1 3
And can use this query to get the right results.
SELECT racer_id, place from results WHERE race_id=1
AND race_num IN
(SELECT race_num FROM races_included WHERE race_id='1' AND race_view='Day 1')
This is great but I only need this feature for a few races and to have it work in a compatible mode for the simple case show all races. I need to add alot of rows to the races_included table. Like
race_view race_id race_num
All 1 0
All 1 1
All 1 2
All 1 3
95% of my races don't use the daily feature.
So I am looking for a way to change the query so that if for race 1 there are no records in the races_included table it defaults to all races. In addition I need it to be close the same execution speed as the query without the IN clause, because this query Or variations of it are used a lot.
One way that does work is to redefine the table as races_excluded and use NOT IN. This works great but is a pain to manage the table when races are added or deleted.
Is there a simple way to use EXISTS and IN in tandem as a subquery to get the desired results? Or some other neat trick I am missing.
To clarify I have found a working but very slow solution.
SELECT * FROM race_results WHERE race_id=1
AND FIND_IN_SET(race_num, (SELECT IF((SELECT Count(*) FROM races_excluded
WHERE rid=1>0),(SELECT GROUP_CONCAT(rnum) FROM races_excluded
WHERE rid=1 AND race_view='Day 1' GROUP BY rid),race_num)))
It basically checks if any records exists for that race_id and if not return a set equal to the current race_num and if yes returns a list of included race nums.
You can do this by using or in the subquery:
SELECT racer_id, plac
from results
WHERE race_id = 1 AND
race_num IN (SELECT race_num
FROM races_included
WHERE race_id = '1' AND (race_view = 'Day 1' or raw_view = 'ANY')
);
I have a column in table A. the column name is Sequence number. The Structure of table A is numbers from 1,2,3,4.....3600.
Now on the basis of table A. I want the below output from the SQL select query for SQL server 2008.
seq no dynamic col
1 1
2 1
3 1
4 1
5 1
6 2
7 2
8 2
9 2
10 2
11 2
12 3
13 3
My Second column is getting generated at the run time.
And the business logic is that, if the seq number mod 6 = 0 then increment the value of dynamic column.
Thanks in advance
Try this:
select seqno, (seqno/6) +1 dynamiccol
from t
Fiddle Demo
Take this as pseudo code because I'm not familiar with SQL Server specifically, but it should give you somewhere to go.
SELECT
seq_no,
ROUNDDOWN(seq_no/6)+1 AS dynamic_col
FROM
my_table