I'm trying to make a statistics page in my php script. in order to select the count from each table I need more than 30 Queries like this
SELECT COUNT(order_id) as `uncompleted_orders` FROM `orders` WHERE `order_status` != 0
and then I need to run another query like this:
SELECT COUNT(order_id) as `completed_orders` FROM `orders` WHERE `order_status` = 1
I've tried this approach, but it didn't work:
SELECT COUNT(order_id) as `uncompleted_orders` FROM `sd_orders` WHERE `order_status` != 4;
SELECT COUNT(order_id) as `completed_orders` FROM `sd_orders` WHERE `order_status` = 4;
Is there any way to creat a new temp table in MySQL contains the count for other tables?
You could try something like this:
SELECT
(
SELECT COUNT(order_id) FROM `sd_orders` WHERE `order_status` != 4
) as `uncompleted_orders`,
(
SELECT COUNT(order_id) FROM `sd_orders` WHERE `order_status` = 4
) as `completed_orders`
You will have a result set with one row and a field for each count.
Without more information it's impossible to generalise, but there are many constructs that can help you here.
First, your example is actually from one table, and not two. This means that you can do the following...
SELECT
COUNT(CASE WHEN order_status = 4 THEN order_id END) AS complete_orders,
COUNT(CASE WHEN order_status <> 4 THEN order_id END) AS incomplete_orders
FROM
sd_orders
This works because COUNT(<something>) doesn't include an NULLs in the results. And by not including an ELSE clause, anything that doesn't match returns NULL. Another way people accomplish the same result is SUM(CASE WHEN ? THEN 1 ELSE 0 END).
Second, where you do actually have multiple tables, you can combine the results in several different ways...
-- Where you want one value from each table...
--------------------------------------------------------------------------------
SELECT
(SELECT COUNT(*) FROM table1 WHERE fieldx = ?) AS value1,
(SELECT COUNT(*) FROM table2 WHERE fieldy = ?) AS value2
-- Where you want one row of values from each table...
--------------------------------------------------------------------------------
SELECT
table1_summary.value1 AS table1_value1,
table1_summary.value2 AS table1_value2,
table2_summary.value1 AS table2_value1,
table2_summary.value2 AS table2_value2
FROM
(
SELECT
COUNT(CASE WHEN fieldx = ? THEN id END) AS value1,
COUNT(CASE WHEN fieldx <> ? THEN id END) AS value2
FROM
table1
)
AS table1_summary
CROSS JOIN
(
SELECT
COUNT(CASE WHEN fieldy = ? THEN id END) AS value1,
COUNT(CASE WHEN fieldy <> ? THEN id END) AS value2
FROM
table2
)
AS table2_summary
-- Where you want many rows, but of the same fields, from each table...
--------------------------------------------------------------------------------
SELECT
*
FROM
(
SELECT
'Table1' AS source_table,
fielda AS some_grouping,
COUNT(CASE WHEN fieldx = ? THEN id END) AS value1,
COUNT(CASE WHEN fieldx <> ? THEN id END) AS value2
FROM
table1
GROUP BY
fielda
UNION ALL
SELECT
'Table2' AS source_table,
fieldb AS some_grouping,
COUNT(CASE WHEN fieldy = ? THEN id END) AS value1,
COUNT(CASE WHEN fieldy <> ? THEN id END) AS value2
FROM
table2
GROUP BY
fieldb
)
AS summary
ORDER BY
source_table,
some_grouping,
value1,
value2
As you can see, there are a lot of ways to do this. How you approach it totally depends on your data and your needs.
Related
I have a table called votes with 4 columns: id, name, choice, date.
****id****name****vote******date***
****1*****sam*******A******01-01-17
****2*****sam*******B******01-05-30
****3*****jon*******A******01-01-19
My ultimate goal is to count up all the votes, but I only want to count 1 vote per person, and specifically each person's most recent vote.
In the example above, the result should be 1 vote for A, and 1 vote for B.
Here is what I currently have:
select name,
sum(case when uniques.choice = A then 1 else 0 end) votesA,
sum(case when uniques.choice = B then 1 else 0 end) votesB
FROM (
SELECT id, name, choice, max(date)
FROM votes
GROUP BY name
) uniques;
However, this doesn't work because the subquery is indeed selecting the max date, but it's not including the correct choice that is associated with that max date.
Don't think "group by" to get the most recent vote. Think of join or some other option. Here is one way:
SELECT v.name,
SUM(v.choice = 'A') as votesA,
SUM(v.choice = 'B') as votesB
FROM votes v
WHERE v.date = (SELECT MAX(v2.date) FROM votes v2 WHERE v2.name = v.name)
GROUP BY v.name;
Here is a SQL Fiddle.
Your answer are close but need to JOIN self
Subquery get Max date by name then JOIN self.
select
sum(case when T.vote = 'A' then 1 else 0 end) votesA,
sum(case when T.vote = 'B' then 1 else 0 end) votesB
FROM (
SELECT name,Max(date) as date
FROM T
GROUP BY name
) AS T1 INNER JOIN T ON T1.date = T.date
SQLFiddle
Try this
SELECT
choice,
COUNT(1)
FROM
votes v
INNER JOIN
(
SELECT
id,
max(date)
FROM
votes
GROUP BY
name
) tmp ON
v.id = tmp.id
GROUP BY
choice;
Something like this (if you really need count only last vote of person)
SELECT
sum(case when vote='A' then cnt else 0 end) voteA,
sum(case when vote='B' then cnt else 0 end) voteB
FROM
(SELECT vote,count(distinct name) cnt
FROM (
SELECT name,vote,date,max(date) over (partition by name) maxd
FROM votes
)
WHERE date=maxd
GROUP BY vote
)
PS. MySQL v 8
select
name,
sum( case when choice = 'A' then 1 else 0 end) voteA,
sum( case when choice = 'B' then 1 else 0 end) voteB
from
(
select id, name, choice
from votes
where date = (select max(date) from votes t2
where t2.name = votes.name )
) t
group by name
Or output just one row for the total counts of VoteA and VoteB:
select
sum( case when choice = 'A' then 1 else 0 end) voteA,
sum( case when choice = 'B' then 1 else 0 end) voteB
from
(
select id, name, choice
from votes
where date = (select max(date) from votes t2
where t2.name = votes.name )
) t
Based on #d-shish solution, and since introduction (in MySQL 5.7) of ONLY_FULL_GROUP_BY, the GROUP BY statement must be placed in subquery like this :
SELECT v.`name`,
SUM(v.`choice` = 'A') as `votesA`,
SUM(v.`choice` = 'B') as `votesB`
FROM `votes` v
WHERE (
SELECT MAX(v2.`date`)
FROM `votes` v2
WHERE v2.`name` = v.`name`
GROUP BY v.`name` # << after
) = v.`date`
# GROUP BY v.`name` << before
Otherwise, it won't work anymore !
I have this two MySQL statements from same table :
SELECT
`table1`.`product_id` As product_id,
COUNT(DISTINCT(table1.user_id)) AS NonebuyersNumber
FROM table1
WHERE status = 1 AND `ispaid` != 2
GROUP BY `table1`.`product_id`
The second statement is :
SELECT l
`table1`.`product_id` As product_id,
COUNT(DISTINCT(table1.user_id)) AS BuyersNumber
FROM table1
WHERE `ispaid` = 1
GROUP BY `table1`.`product_id`
The result that I want is a table like this one :
I tried to use Union but doesn't work because I have two different columns
Any idea how I can get this 3rd table?
Use conditional aggregation:
SELECT
product_id,
COUNT(DISTINCT CASE WHEN status = 1 AND ispaid != 2
THEN user_id ELSE NULL END) AS NonebuyersNumber
COUNT(DISTINCT CASE WHEN ispaid = 1 THEN user_id ELSE NULL END) AS BuyersNumber
FROM table1
WHERE
(status = 1 AND ispaid != 2) OR
ispaid = 1
GROUP BY
product_id;
This should work because both of your queries aggregate over the product_id and the only differences are the WHERE clauses. We can combine the records from both queries and then use CASE expressions to target records intended for each original query.
SELECT t1.product_id AS product_id
SELECT CASE WHEN t1.NonebuyersNumber IS NULL
THEN 0
ELSE t1.NonebuyersNumber
END
AS NonebuyersNumber,
SELECT CASE WHEN t2.BuyersNumber IS NULL
THEN 0
ELSE t2.BuyersNumber
END
AS BuyersNumber
FROM
(SELECT
`table1`.`product_id` As product_id ,
COUNT(DISTINCT(table1.user_id)) AS NonebuyersNumber
FROM table1 WHERE status =1
AND `ispaid` != 2
GROUP BY `table1`.`product_id`)
AS t1
INNER JOIN
(SELECT
`table1`.`product_id` As product_id ,
COUNT(DISTINCT(table1.user_id)) AS BuyersNumber
FROM table1 WHERE `ispaid` = 1
GROUP BY `table1`.`product_id`)
AS t2
ON t1.product_id = t2.product_id
Basically, you need following
Join both the views on product_id
Use CASE statements in select in case one of the buyers numbers is NULL
I want to count the distinct occurrences of some column grouped and non-grouped by two boolean columns
select count(Distinct some_column) as Uniques, sum(some_other_col)
from myTable T
where T.created_at>'2016-09-15'
group by T.col1, T.col2
This query gives four values
uniques when col1=true and col2=true
uniques when col1=true and col2=false
uniques when col1=false and col2=true
uniques when col1=false and col2=false
Is it possible to change the same query and to get these three values?
I can't get that info combining the first 4 values
uniques (all)
uniques when col1=true
uniques when col2=true
UPDATE
Actually I want to keep the group by because there are some other values that I get the sum.
Use conditional aggregation:
select count(Distinct some_column) as Uniques,
count(distinct case when t.col1 then some_column end) as Uniques_col1_true,
count(distinct case when t.col2 then some_column end) as Uniques_col2_true
from myTable t
where t.created_at > '2016-09-15';
Try this
SELECT SUM(CASE WHEN col1 = TRUE
AND col2 = TRUE THEN 1 ELSE 0 END) AS opt1,
SUM(CASE WHEN col1 = TRUE
AND col2 = FALSE THEN 1 ELSE 0 END) AS opt2,
FROM
(SELECT DISTINCT col1,
col2,
somecolumn
FROM TABLE T
WHERE ...) AS TB
I'm trying to do multiple selects from one table but it only shown the last select statement.
CREATE PROCEDURE `usp_GetStockCard` (IN Matecode varchar(10))
BEGIN
(select tran_date as tran_date
from TM_matbalance
where Mate_code=Matecode);
(select Mate_code as Mate_code
from TM_matbalance
where Mate_code=Matecode);
(select tran_qtyx as Qty_in
from TM_matbalance
where tran_type='IN'
and mate_code=matecode);
(select tran_qtyx as Qty_out
from TM_matbalance
where tran_type='OUT'
and mate_code=matecode);
END
I've tried to change semicolon to comma after each select statement but it said that syntax error: missing 'semicolon'.
please help.
I look at your problem and I think I solve it.
Basically there is two problems here first one is to pivot your table where your Tran_Qtyx column become Qty_In and Qty_Out based on value in Tran_Type column (IN or OUT)... That part of problem you solve with this query
SELECT Tran_Date, Mate_Code,
SUM(CASE WHEN Tran_Type = 'IN' THEN Tran_Qtyx ELSE 0 END) Qty_In,
SUM(CASE WHEN Tran_Type = 'OUT' THEN Tran_Qtyx ELSE 0 END) Qty_Out
FROM myTable
WHERE Mate_Code = 'MAT001'
GROUP BY DATE(Tran_Date)
NOTE: In your desired result I only see 'MAT001'as Mate_Code so I stick with that in this solution and exclude MAT002 from result.
More about pivot table you can read here, there you can find a link, which is good to take a look, and where you can find a lot of stuff about mysql query's.
The second part of your problem is to get Qty_Balance column. Similar problem is solved here. It's how to calculate row value based on the value in previous row.
So your complete query could look like this:
SELECT t1.Tran_Date, t1.Mate_Code, t1.Qty_In, t1.Qty_Out,
#b := #b + t1.Qty_In - t1.Qty_Out AS Qty_Balance
FROM
(SELECT #b := 0) AS dummy
CROSS JOIN
(SELECT Tran_Date, Mate_Code,
SUM(CASE WHEN Tran_Type = 'IN' THEN Tran_Qtyx ELSE 0 END) Qty_In,
SUM(CASE WHEN Tran_Type = 'OUT' THEN Tran_Qtyx ELSE 0 END) Qty_Out
FROM myTable
WHERE Mate_Code = 'MAT001'
GROUP BY DATE(Tran_Date)) AS t1
ORDER BY t1.Tran_Date;
NOTE: probably only think you should change here is table name and it's should work.
Here is SQL Fiddle so you can see how that's work!
GL!
You will need to structure your query into one, or pass in a parameter to the stored procedure to select which output/query you want, to restructure your query you will need something like:
`CREATE PROCEDURE `usp_GetStockCard` (IN Matecode varchar(10))
BEGIN
(select tran_date as tran_date, Mate_code as Mate_code, tran_qtyx as Qty
from TM_matbalance
where Mate_code=Matecode
and (tran_type='IN' or tran_type='OUT');
END`
Or try this if you have an ID column:
SELECT coalesce(ta.id, tb.id) as tran_id, coalesce(ta.tran_date, tb.tran_date) as tran_date, coalesce(ta.Mate_code, tb.Mate_code) as Mate_code, ta.tran_type as Qty_In, tb.tran_type as Qty_Out
from (select ta.*
from TM_matbalance ta
where ta.tran_type = 'IN'
and Mate_code=Matecode
) ta full outer join
(select tb.*
from TM_matbalance tb
where tb.tran_type = 'OUT'
and Mate_code=Matecode
) tb
on ta.id = tb.id ;
just replace "id" with the name of your ID column if you don't need to return the id column then remove coalesce(ta.id, tb.id) as tran_id
How to check whether all rows in a table have unique values for a column
having char datatype in a table in MySQL and return the value as yes or no ?
You can try something like this, where ? is the column you want to check :
SELECT IF(t.total = t.total_distinct, 'YES', 'NO') AS result
FROM ( SELECT COUNT(*) AS total
, COUNT(DISTINCT ?) AS total_distinct
FROM tbl
) t
If you ignore NULL values, you can just compare count() and count(distinct):
select (case when count(col) = count(distinct col) then 'All Unique' else 'Duplicates' end)
from table t;
If NULL values are a concern (so NULL would be allowed at most one time), then you can aggregate and look at the maximum count:
select (case when max(cnt) = 1 then 'All Unique' else 'Duplicates' end)
from (select col, count(*) as cnt
from table t
group by col
) col
I would go with the first version of Gordon's answer, but grouped by the Primary key of the table. In other words :
select primary_key_field, (case when count(col) = count(distinct col) then 'All Unique' else 'Duplicates' end)
from table t
group by primary_key_field.