select p.partnerid,
sum(case when c.amount is not null then c.amount else 0 end) as amount,
sum(case when c.netamt is not null then c.netamt else 0 end) as total,
sum(case when (c.netamt - d.paidamount) is not null then (c.netamt - d.paidamount) else 0 end) as remainingamount,
sum(case when d.paidamount is not null then d.paidamount else 0 end) as paidamt
from customerinfo c
left join dailypayments d on c.accno = d.accno
right join partnerinfo p on c.partnerid = p.partnerid
where (d.paiddate is null or (d.paiddate >= '2011-3-15' and d.paiddate <= '2012-6-13')) and p.manager = 7 group by p.partnerid
from athe above query i need to subtract two values from two tables where there is no value in second table.
for better understanding see below image.
Use the IFNULL() function to remove the case and simplify your calculation:
sum(c.netamt - ifnull(d.paidamount, 0)) as remainingamount,
Related
SELECT PatchPhase.PhaseName, MAX(PatchPhase.Sequence) AS seq,
PatchState.Application, PatchState.Objectname, PatchState.Jobname,
PatchState.Streamname, COUNT(*) AS Total,
PatchState.Jobdescription,
PatchState.Status, PatchState.Timestamp
FROM PatchState
INNER JOIN PatchPhase ON PatchState.Phase = PatchPhase.PhaseTech
WHERE (PatchPhase.PhaseName IN (#Phase))
AND (PatchState.Application IN (#Application)) AND (PatchState.Timestamp >= #StartDate)
AND (PatchState.Timestamp <= #EndDate)
GROUP BY PatchPhase.PhaseName, PatchState.Application, PatchState.Objectname,
PatchState.Jobname, PatchState.Streamname, PatchState.Jobdescription, PatchState.Status,
PatchState.Timestamp
ORDER BY PatchState.Application
I am working on matrix and I have column group of status which contains 3 columns (planned, running,completed). I want to sum planned+completed and divide by total column.
Total column is outside the column group.
I do find some answers but I did not get how should I use in my code
can someone please help?
Try using this to aggregate, and then use a table instead of a matrix. You will not need a column group now. As I cannot run the sql I can't promise it is perfect but perhaps you could have a little play with it if not. It should offer a guide if nothing else.
SELECT
PatchPhase.PhaseName,
MAX(PatchPhase.Sequence) AS seq,
PatchState.Application,
PatchState.Objectname,
PatchState.Jobname,
PatchState.Streamname,
PatchState.Jobdescription,
SUM(case when PatchState.Status = 'Planned' then 1 else 0 end) as 'Planned',
SUM(case when PatchState.Status = 'Running' then 1 else 0 end) as 'Running',
SUM(case when PatchState.Status = 'Completed' then 1 else 0 end) as 'Completed',
(SUM(case when PatchState.Status = 'Planned' then 1 else 0 end) + SUM(case when PatchState.Status = 'Running' then 1 else 0 end)) /
(SUM(case when PatchState.Status = 'Planned' then 1 else 0 end) + SUM(case when PatchState.Status = 'Running' then 1 else 0 end) + SUM(case when PatchState.Status = 'Completed' then 1 else 0 end)) as totalPercentage
PatchState.Timestamp
FROM
PatchState
INNER JOIN PatchPhase
ON PatchState.Phase = PatchPhase.PhaseTech
WHERE
(PatchPhase.PhaseName IN (#Phase))
AND (PatchState.Application IN (#Application))
AND (PatchState.Timestamp >= #StartDate)
AND (PatchState.Timestamp <= #EndDate)
GROUP BY
PatchPhase.PhaseName,
PatchState.Application,
PatchState.Objectname,
PatchState.Jobname,
PatchState.Streamname,
PatchState.Jobdescription,
PatchState.Status,
PatchState.Timestamp
ORDER BY
PatchState.Application
You can get a value displayed in a text box from expression =Reportitems!Textbox133.Value
instead of textbox133 in the above expression you have to give the textbox name of the textbox from which you want the value. In your case the total column
I would like to join 3 tables.
The result is one of the field - SUM from the other table like this image, please help
You don't need to join tblwork as you can get all required fields from other 2 tables.
Following query should work:
select t1.nmstudent,
sum(case when t2.idwork = 'w001' then t2.trprice else 0 end) as w001,
sum(case when t2.idwork = 'w002' then t2.trprice else 0 end) as w002,
sum(case when t2.idwork = 'w003' then t2.trprice else 0 end) as w003,
sum(case when t2.idwork = 'w004' then t2.trprice else 0 end) as w004
from tblstudent t1
inner join tblTrans t2
on t1.idstudent = t2.idstudent
group by t1.idstudent;
Hope it helps!
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else 0 end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else 0 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
FROM mohon
LEFT JOIN dun ON dun.KOD_DUN=mohon.dun_nama
WHERE status_proses = 'diproses'
AND concat('20', substr(noMyKid, 1, 2)) = '2008'
AND status_mohon = 'Layak'
AND status_semak = '1'
AND (
status_bayar = ''
OR status_bayar = 'Belum'
OR status_bayar = 'Sudah')
AND (
status_terima = ''
OR status_terima = 'Terima'
) GROUP BY dun_nama
ORDER BY NAMA_DUN
This is my mysql code. why is my 'COUNT CASE WHEN' give the same output for female and male column.
Usually COUNT() is used to count rows and is therefore very often used in the form COUNT(*). When you use a field (or anything else) as a parameter into the COUNT() it counts 1 for every no NULL value.
In your case all your values are not NULL (they are either 1 or 0) and consequently you end up with the same results.
So Abhik Chakraborty is right, use SUM() and everything should be fine.
The COUNT() function does only recognize non-null values, so when using case expressions such as you have here, you can explicitly return NULL where needed
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else NULL end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else NULL end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
OR, implicitly return NULL by ignoring the else condition
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
OR, mimic the effect of count by using SUM() provided you do use 1 and 0 (or 1 and NULL)
SELECT NAMA_DUN,
SUM(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else 0 end) AS FEMALE,
SUM(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else 0 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
In SQL how do you show 0 if record is null?
select sales_id, totalbuy, totalsell, totalbuy + totalsell as total from
(select sales_id, SUM(CASE WHEN side= 'buy' THEN 1 ELSE 0 END) AS totalbuy,
SUM(CASE WHEN side= 'sell' THEN 1 ELSE 0 END) AS totalsell
from car_orders
where sales_id in ('sales1', 'sales2', 'sales3', 'sales4')only
GROUP BY sales_id)q
order by total desc
limit 0, 10;
After car_orders I have tried inserting*(car_orders+ISNULL(car_orders,0)) but get an error.
Building from Sohnee's answer, here is the SQL I think you want to use:
SELECT
sales_id,
IFNULL(totalbuy, 0),
IFNULL(totalsell, 0),
IFNULL(totalbuy, 0) + IFNULL(totalsell, 0) as total
FROM
(
SELECT
sid as sales_id,
SUM(CASE WHEN side = 'buy' THEN 1 ELSE 0 END) AS totalbuy,
SUM(CASE WHEN side = 'sell' THEN 1 ELSE 0 END) AS totalsell
FROM
( SELECT 'sales1' as sid UNION SELECT 'sales2' UNION SELECT 'sales3' UNION SELECT 'sales4' ) mysalesids
LEFT OUTER JOIN car_orders
ON sales_id = sid
GROUP BY
sales_id
) q
ORDER BY total DESC
LIMIT 0, 10;
The key to the above is the "LEFT OUTER JOIN". If you can have the 'sales1', 'sales2', 'sales3' values in their own table, that would be preferable rather than having a sub-select.
Hope this helps,
john...
When you use +, both arguments must be of the same type. I can't tell from your question what car is, but I assume it isn't compatible with a 0.
It is better to use CONCAT in these cases.
CONCAT(car, IFNULL(car_orders, 0))
If car_orders is a table, it isn't valid here - you must use a column, i.e. car_orders.MyColumn
How To Use IFNULL
I don't think you can end up with a null here, given your query, buy you would use IFNULL like this:
SELECT
sales_id,
IFNULL(totalbuy, 0),
IFNULL(totalsell, 0),
IFNULL(totalbuy, 0) + IFNULL(totalsell, 0) as total
FROM
(
SELECT
sales_id,
SUM(CASE WHEN side = 'buy' THEN 1 ELSE 0 END) AS totalbuy,
SUM(CASE WHEN side = 'sell' THEN 1 ELSE 0 END) AS totalsell
FROM
car_orders
WHERE
sales_id in ('sales1', 'sales2', 'sales3', 'sales4')
GROUP BY
sales_id
) q
ORDER BY total DESC
LIMIT 0, 10;
I am using SUM ( CASE WHEN ) to count number of Yes and No, it work fine.
I am havin problem counting number of matching mobile number from two tables. It dont seem to be counting correctly.
There is a MobileNO field in dairy table and mobile field in the sales table
SELECT
D.Username,
SUM(CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN D.type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN D.type = '' THEN 1 ELSE 0 END) as Other,
(SELECT SUM(CASE WHEN D.MobileNo = S.mobile THEN 1 ELSE 0 END) from sales as S) as Sales,
COUNT(*) as TOTAL FROM dairy as D
WHERE source = 'Company' AND UNIX_TIMESTAMP(CheckDate) >= 1293840000 AND UNIX_TIMESTAMP(CheckDate) <= 1322697600
group by D.Username order by TOTAL DESC
SELECT
D.Username,
SUM(CASE WHEN D.type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN D.type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN D.type = '' THEN 1 ELSE 0 END) as Other,
SUM(CASE WHEN S.mobile IS NULL THEN 0 ELSE 1 END) as Sales,
COUNT(*) as TOTAL
FROM dairy as D
LEFT JOIN (SELECT DISTINCT mobile FROM sales) as S ON D.MobileNo = S.mobile
WHERE source = 'Company' AND UNIX_TIMESTAMP(CheckDate) >= 1293840000 AND UNIX_TIMESTAMP(CheckDate) <= 1322697600
group by D.Username order by TOTAL DESC