On special:preferences mediawiki users are given a choice between two genders. For my wiki I'd like to add more options. For example: 'transgendered', or 'none of your damn business'. Is this doable?
No, because it makes no sense. MediaWiki only deals with grammatical gender. If your language has multiple grammatical genders which could/should be used for users in the interface, more than the currently supported male/female/generic, please tell us because we've never heard of any such language (there's someone requesting neuter gender for bots and so, though).
It can be done. All the method described below was done working with Mediawiki 1.17.0.
I'm asumming you're authenticated at least as a sysop of the wiki and that you have full access to the FTP folder and are able to modify the wiki files.
You will need to modify the /includes/Preferences.php file.
Go around line 200 and you'll find the following code:
$defaultPreferences['gender'] = array(
'type' => 'select',
'section' => 'personal/info',
'options' => array(
wfMsg( 'gender-male' ) => 'male',
wfMsg( 'gender-female' ) => 'female',
wfMsg( 'gender-unknown' ) => 'unknown',
),
'label-message' => 'yourgender',
'help-message' => 'prefs-help-gender',
);
Add the new genders you'll need:
$defaultPreferences['gender'] = array(
'type' => 'select',
'section' => 'personal/info',
'options' => array(
wfMsg( 'gender-male' ) => 'male',
wfMsg( 'gender-female' ) => 'female',
wfMsg( 'gender-transgender' ) => 'transgender',
wfMsg( 'gender-noneofyourbusiness' ) => 'noneofyourbusiness',
),
'label-message' => 'yourgender',
'help-message' => 'prefs-help-gender',
);
Finally, you'll need to go to the MediaWiki:gender-transgender and MediaWiki:gender-noneofyourbusiness (assumming you added those two new genders) pages of your wiki and edit them with the text you'd like to see when selecting a gender option.
That should be all. Enjoy!
Related
I have two custom post types, playlists and games. Playlists have a ACF repeater field, that contain games.
My goal: I am trying to build a simple query, that gets all playlists that DO NOT have this game listed in the repeater field AND alll playlists that are empty (do not have any repeater fields / database entries at all). I want to use the get_posts() function to achieve my goal, if possible.
My problem: I can only get the query to show ONLY the playlists that HAVE the game by using the = operator in the "game_filter" meta query compare field (but I want the opposite). If I choose the != or <> or IS NOT operator, it spits out all available posts. And if I also include my "empty_playlists" meta query, it ALWAYS shows me all playlists, no matter what operators I use, even tho it is a OR and the listed posts do have entrys.
I tried a lot but just cant get it to work. All exmaples I found were about different things, mostly about the % problem with the repeater field names and its solution. I hope someone can help me with this real quick. What am I doing wrong? Please help fellow and better coders! :-)
This is my code
$excluded_playlists_game_id = 274;
$user_id = 1;
$args = array(
'post_type' => PSiCorePostTypes::PLAYLISTS,
'author' => $user_id,
'order_by' => 'title',
'order' => 'ASC',
'suppress_filters' => false,
'meta_query' => array(
'relation' => 'OR',
'game_filter' => array(
'type' => 'NUMERIC',
'key' => 'psi_playlist_games_%_item',
'compare' => '!=',
'value' => $excluded_playlists_game_id,
),
'empty_playlists' => array(
'key' => 'psi_playlist_games_%_item',
'compare' => 'NOT EXISTS',
),
),
);
$user_playlists = get_posts( $args );
and this function for the % problem.
add_filter( 'posts_where', 'get_user_playlists_query_allow_wildcard' );
function get_user_playlists_query_allow_wildcard( $where ) {
global $wpdb;
$where = str_replace(
"meta_key = 'psi_playlist_games_%_item",
"meta_key LIKE 'psi_playlist_games_%_item",
$wpdb->remove_placeholder_escape( $where )
);
return $where;
}
If I were using a SQL statement, this is what it would look like:
select * from courses where active = 1 AND (title = $string OR description = $string)
'courses' is a custom post type
'active' is a custom field created with ACF
'description' is a custom field created with ACF
'title' is the standard WP title for posts
This is what I have so far:
$args_courses = array(
'post_type' => 'courses',
'posts_per_page' => 9999,
'meta_query' => array(
array(
'key' => 'active',
'value' => 1,
'compare' => '='
),
'relation' => 'AND',
array(
'key' => 'description',
'value' => $string,
'compare' => '='
),
'relation' => 'OR',
array(
'key' => 'title',
'value' => $string,
'compare' => '='
)
),
);
It seems as though I can't access the WP title through a meta_query, but can't figure out how to turn my query around so 'active' remains the first column to check on.
Thanks in advance for any help!
What you are trying to do is not supported by the default WP_Query functionality, however you can extend it as described in the following answer from the WordPress Stackexchange site. Note that you you may need to alter it further for your specific use case.
https://wordpress.stackexchange.com/questions/178484/wp-query-args-title-or-meta-value
A few notes on your current query.
relation should only be used once in your meta_query. WordPress uses arrays to do the grouping, and wouldn't know to use "AND" or "OR" in your example.
It looks like you want "all" posts, not really 9999 posts, so you should use -1 to fetch everything in one result set.
I have a custom Post Type called cptMovie which has two Custom Field (Metadata) "Language" and "Box office" assigned to it.
I also have a Custom Taxonomy called movieTax with 4 tax Terms "Action", "Comedy", "Family" ,and "Horror" .
In a WordPress File structe like below:
index.php
page.php
page-movie.php
taxonomy.php
taxonomy-movieTax.php
I am able to list and display all the Custom Post Types (movie) under Taxonomy (movieTax) using indexed page page-movie.php and custom wp-query and eventually link them to the taxonomy-movieTax.php to have all Post under each tax terms.
Up to here I am Ok and getting the resut BUT I need to add some Filters for users like Filtering the result by Language or Boc office Metadata,
Now my question is Which Part of the WP Template Hierarchy is in charge of displaying the result? Do I have to create the search.php if so how a query like this:
$arg = array(
'meta_query' => array(
array(
'key' => 'language',
'value' => 'english'
)
)
);
$filter-lang = new WP_Query( $arg );
in page-movie.php will end up in search.php?
Thanks,
You don't need to create a "search.php" file.
You can add the below code in "page-movie.php" or "taxonomy-movieTax.php" file, as per your requirement.
$arg = array(
'meta_query' => array(
'relation' => 'OR',
array(
'key' => 'language',
'value' => $lang_val,
'compare' => '='
),
array(
'key' => 'box_office',
'value' => $box_office_val,
'compare' => '='
)
)
);
$filter-lang = new WP_Query( $arg );
Here, $lang_val & $box_office_val are values to search for language key & box office key respectively. However, if you want to create separate search file, you also need to specify post type in arguments.
I've been trying to find an answer to my problem for hours. I am currently working with cakePHP 2.4.
I have two models, Users and Groups. I have created the following associations for each:
(User.php)
public $hasAndBelongsToMany = array(
'Group' =>
array(
'className' => 'Group',
'joinTable' => 'groups_users',
'foreignKey' => 'user_id',
'associationForeignKey' => 'group_id',
'unique' => true,
)
);
and (Group.php):
public $hasAndBelongsToMany = array(
'GroupUser' =>
array(
'className' => 'User',
'joinTable' => 'groups_users',
'foreignKey' => 'group_id',
'associationForeignKey' => 'user_id',
'unique' => true,
)
);
The reason I use GroupUser and not "User" is I get an error because I have already used "User for some other relation.
My form looks like this:
echo $this->Form->create('Group', array('controller' => 'group','action' => 'add'));
echo $this->Form->input('User.id', array('type' => 'hidden', 'value' => $authUser['id']);
echo $this->Form->input('Group.address');
echo $this->Form->end(__('Save', true));
I also have a table called groups_users with "id", "user_id" and "group_id"
When I submit the form, it created the new Group and saves the data, but the association is not created.
I tried manually filling a groups_users record with an existing user_id and group_id but still, when I use find(All), it doesn't find the expected association like it should according to the books.
I debugged the array that is being saved and it looks like this:
Array
(
[User] => Array
(
[user_id] => 39
)
[Group] => Array
(
[address] => asdasd, San Antonio, Texas 78233, EE. UU.
)
)
This is the code in my GroupsController add function:
if ($this->Group->save($this->request->data)) {
// redirect or do something
}
I have tried changing the array to work with saveAll like in the books, still only created new record but no association. And as I said, I mannually created a record and tried finding it and it wouldn't find it anyway.
I solved it apparently, I think it was because I hadn't created the GroupsUser.php model file. Not rreally sure because I changed a bunch of stuff! But maybe it helps someone.
I have made a site that uses custom posts types for a projects section.
I need to change the post type from 'projects' to 'galleries' but as I have already uploaded a bunch of projects was wondering how I would do this with as little as possible hassle (I do not want to have to re-upload all the images and text etc)
I found a few articles that tell me to do a SQL query to rename the posts
UPDATE `wp_posts`
SET `post_type` = '<new post type name>'
WHERE `post_type` = '<old post type name>';
And this one for the taxonomy
UPDATE `wp_term_taxonomy`
SET `taxonomy` = '<new taxonomy name>'
WHERE `taxonomy` = '<old taxonomy name>';
I just have no idea what I am supposed to do with this code. If it is SQL do I run it in a php file or is there some sort of 'terminal' that can be found in the WP dashboard or cPanel of my site?
Below is how I created my post type (Not sure if this helps)
function create_my_post_types() {
//projects
register_post_type(
'Projects', array('label' => 'Projects','description' => '','public' => true,'show_ui' => true,'show_in_menu' => true, 'menu_position' => 8,'capability_type' => 'post','hierarchical' => false,'rewrite' => array('slug' => '','with_front' => '0'),'query_var' => true,'exclude_from_search' => false,'supports' => array('title','editor','thumbnail'),'taxonomies' => array('category',),'labels' => array (
'name' => 'Projects',
'singular_name' => 'Project',
'menu_name' => 'Projects',
'add_new' => 'Add New Project',
'add_new_item' => 'Add New Project',
'edit' => 'Edit',
'edit_item' => 'Edit Project',
'new_item' => 'New Project',
'view' => 'View Project',
'view_item' => 'View Project',
'search_items' => 'Search Projects',
'not_found' => 'No Projects Found',
'not_found_in_trash' => 'No Projects Found in Trash',
'parent' => 'Parent Projects',
),) );
} // end create_my_post_types
If you have CPanel access, you can look for PHPMyAdmin and run the SQL code there.
Go to PHPMyAdmin.
Select your wordpress database from the left.
RECOMMENDED: Backup your database first, by going to the export tab at the top and doing a quick export.
Select "SQL" from the top tabs.
Copy your SQL queries in the huge textarea, and click Go.
Hope it works!
It's better to go directly with a plugin:
Convert Post Types
This is a utility for converting lots of posts or pages to a custom post type (or vice versa). You can limit the conversion to posts in a single category or children of specific page. You can also assign new taxonomy terms, which will be added to the posts' existing terms.
All the conversion process happens in the function bulk_convert_posts(), using the core functions wp_update_post and wp_set_post_terms. IMO, you should use WordPress functions to do the conversion, there are quite some steps happening in the terms function before the MySQL command.
Do a database backup before proceeding with this kind of operations.