I want to use Case When with AND condition and it is not calculating the sum properly.
For example:
SELECT DATE(`SubmitDate`),
SUM(CASE status WHEN 'New' AND `Type` = 'consumer' THEN 1 ELSE 0 END) as new_consumer,
SUM(CASE status WHEN 'New' AND `Type` = 'business' THEN 1 ELSE 0 END) as new_business
FROM report
WHERE `source` = 'net'
group by DATE(`SubmitDate`) Order by `SubmitDate` DESC
You need to use CASE WHEN [Condition] THEN... rather than a simple case expression:
SELECT DATE(`SubmitDate`),
SUM(CASE WHEN status = 'New' AND `Type` = 'consumer' THEN 1 ELSE 0 END) as new_consumer,
SUM(CASE WHEN status = 'New' AND `Type` = 'business' THEN 1 ELSE 0 END) as new_business
FROM report
WHERE `source` = 'net'
group by DATE(`SubmitDate`) Order by `SubmitDate` DESC
You should write
CASE WHEN status='New' AND `Type` = 'consumer' THEN 1 ELSE 0 END
Check the syntax of CASE WHEN
Related
I want to display a table with SQL query like this:
I have run my query:
select
tb_r_orderdata.finishtime as date ,
count(*)sum all,
sum(when status = 'SUCCESS' and issync = '1' then 1 else 0 end) sumpaid,
sum(when status = 'SUCCESS' and issync in ('3', '4') then 1 else 0 end) sumfail,
sum(when status = 'CLOSED' then 1 else 0 end) sumclose,
sum(when status = 'Null' then 1 else 0 end) sumunflag
from
tb_r_orderdata;
But when I execute it, the result is different than what I expected. The result is like this:
Thank you for any help
You are missing the GROUP BY and the CASE:
select tb_r_orderdata.finishtime as date ,
COUNT(*) as sumall,
SUM(CASE WHEN status='SUCCESS' AND issync='1' then 1 ELSE 0 END) as sumpaid,
SUM(CASE WHEN status='SUCCESS' AND issync in ('3','4') then 1 ELSE 0 END) as sumfail,
SUM(CASE WHEN status='CLOSED' then 1 ELSE 0 END) as sumclose,
SUM(CASE WHEN status is null then 1 ELSE 0 END) as sumunflag
from tb_r_orderdata
group by tb_r_orderdata.finishtime ;
MySQL treats booleans as integers in a numeric context, with "1" for true and "0" for false. You can simplify your query to:
select o.finishtime as date ,
COUNT(*) as sumall,
SUM(status = 'SUCCESS' AND issync = '1') as sumpaid,
SUM(status = 'SUCCESS' AND issync in ('3', '4')) as sumfail,
SUM(status = 'CLOSED') as sumclose,
SUM(status is null) as sumunflag
from tb_r_orderdata o
where tb_r_orderdata.finishtime is not NULL
group by o.finishtime ;
This also removes NULL finish times.
Explanation in comment for Gordon Linoff
i have try your answer but there is record NULL in the top of table, i dont know why, can you explain it
with little bit change from Gordon Linoff answer
select tb_r_orderdata.finishtime as date ,
SUM(CASE WHEN status='SUCCESS' AND issync='1' then 1 ELSE 0 END) as sumpaid,
SUM(CASE WHEN status='SUCCESS' AND issync in ('3','4') then 1 ELSE 0 END) as sumfail,
SUM(CASE WHEN status='CLOSED' then 1 ELSE 0 END) as sumclose,
SUM(CASE WHEN status='NULL' then 1 ELSE 0 END) as sumunflag
from tb_r_orderdata
group by tb_r_orderdata.finishtime
-------------------------------------------------
SELECT trtm,
COUNT(CASE WHEN trtm= 'TM' THEN 1 ELSE NULL END) AS Transmission,
COUNT(CASE WHEN trtm= 'TR' THEN 1 ELSE NULL END) AS Transfer,
COUNT(CASE WHEN trtm= 'DL' THEN 1 ELSE NULL END) AS Deletion
(SELECT
(SUM( tshares ) AS total WHERE trtm = 'TM'),
(SUM( tshares ) AS total1 WHERE trtm = 'TR'))
FROM transfer_file
where t_date between '10/1/1992' and '10/2/1992'
-----------------------------------------------
How to get the sum of values for specific fields,i am getting the count of value but not getting the sum of value,what to do? help me if any body knows
You should use conditional aggregation inside the SUM too:
SELECT trtm,
COUNT(CASE WHEN trtm= 'TM' THEN 1 ELSE NULL END) AS Transmission,
COUNT(CASE WHEN trtm= 'TR' THEN 1 ELSE NULL END) AS Transfer,
COUNT(CASE WHEN trtm= 'DL' THEN 1 ELSE NULL END) AS Deletion
SUM(CASE WHEN trtm = 'TM' THEN tshares END) AS Total_Transmission,
SUM(CASE WHEN trtm = 'TR' THEN tshares END) AS Total_Transfer
FROM transfer_file
WHERE t_date between '10/1/1992' and '10/2/1992'
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else 0 end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else 0 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
FROM mohon
LEFT JOIN dun ON dun.KOD_DUN=mohon.dun_nama
WHERE status_proses = 'diproses'
AND concat('20', substr(noMyKid, 1, 2)) = '2008'
AND status_mohon = 'Layak'
AND status_semak = '1'
AND (
status_bayar = ''
OR status_bayar = 'Belum'
OR status_bayar = 'Sudah')
AND (
status_terima = ''
OR status_terima = 'Terima'
) GROUP BY dun_nama
ORDER BY NAMA_DUN
This is my mysql code. why is my 'COUNT CASE WHEN' give the same output for female and male column.
Usually COUNT() is used to count rows and is therefore very often used in the form COUNT(*). When you use a field (or anything else) as a parameter into the COUNT() it counts 1 for every no NULL value.
In your case all your values are not NULL (they are either 1 or 0) and consequently you end up with the same results.
So Abhik Chakraborty is right, use SUM() and everything should be fine.
The COUNT() function does only recognize non-null values, so when using case expressions such as you have here, you can explicitly return NULL where needed
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else NULL end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else NULL end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
OR, implicitly return NULL by ignoring the else condition
SELECT NAMA_DUN,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 end) AS FEMALE,
COUNT(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
OR, mimic the effect of count by using SUM() provided you do use 1 and 0 (or 1 and NULL)
SELECT NAMA_DUN,
SUM(case when ((RIGHT(noMyKid, 1))% 2) = 0 then 1 else 0 end) AS FEMALE,
SUM(case when ((RIGHT(noMyKid, 1))% 2) = 1 then 1 else 0 end) AS MALE,
COUNT(DISTINCT(noMyKid)) as jumlah
I'm trying to add a column named Ready to my query that checks if the sum of Complete is = to the sum of Total and places 'Y' if True and 'N' if FALSE.
Here is my query that works producing 4 columns
SELECT pc.Sub,
SUM(CASE WHEN `SheetStatus` LIKE 'Complete' THEN 1 ELSE 0 END) AS 'Complete',
SUM(CASE WHEN `SheetStatus` LIKE 'Not started' THEN 1 ELSE 0 END) AS 'Not Started',
SUM(CASE WHEN `CheckSheet` LIKE '%' THEN 1 ELSE 0 END) AS 'Total'
FROM `pc`
Group By pc.Sub WITH ROLLUP
I just cant figure out how to create the extra column if it is possible at all.
Regards
Try outer SELECT
SELECT `Complete`,
`Not Started`,
`Total`,
CASE WHEN `Complete` = `Total` THEN 'Y' ELSE 'N' END `Ready`
FROM (
SELECT pc.Sub,
SUM(CASE WHEN `SheetStatus` LIKE 'Complete' THEN 1 ELSE 0 END) AS `Complete`,
SUM(CASE WHEN `SheetStatus` LIKE 'Not started' THEN 1 ELSE 0 END) AS `Not Started`,
SUM(CASE WHEN `CheckSheet` LIKE '%' THEN 1 ELSE 0 END) AS `Total`
FROM `pc`
GROUP BY pc.Sub WITH ROLLUP) t
Try this:
SELECT pc.Sub,
SUM(IF(`SheetStatus`='Complete',1,0) AS 'Complete',
SUM(IF(`SheetStatus`='Not started',1,0) AS 'Not Started',
SUM(IF(`CheckSheet` LIKE '%',1,0) AS 'Total'
IF(SUM(IF(`CheckSheet` LIKE '%',1,0) = SUM(IF(`SheetStatus`='Complete',1,0),"Y","N") AS Ready
FROM `pc`
Group By pc.Sub WITH ROLLUP
How do I get the Total value of Yes, No, Other fields of each username?
I like to add Total field.
SELECT Username,
SUM(CASE WHEN type = 'Yes' THEN 1 ELSE NULL END) as Yes,
SUM(CASE WHEN type = 'No' THEN 1 ELSE NULL END) as No,
SUM(CASE WHEN type = '' THEN 1 ELSE NULL END) as Other
//How to get total of Yes/No/Other
FROM table
WHERE source = 'CompanyName' ";
Also the highest Total goes at the top order.
use 0 instead of NULL, add the missing group by and use COUNT(*) to get the total of each group and order the result:
SELECT Username,
SUM(CASE WHEN type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN type = '' THEN 1 ELSE 0 END) as Other,
COUNT(*) as TOTAL
FROM table
WHERE source = 'CompanyName'
group by Username
order by TOTAL desc;
This assumes that type can only be 'Yes', 'No' or ''.
Use a sub query to sum up your results and add a sort:
select yes, no, other, yes + no + other as Total
from (
SELECT Username,
SUM(CASE WHEN type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN type = '' THEN 1 ELSE 0 END) as Other
FROM table
WHERE source = 'CompanyName'
)
order by (yes + no + other) desc
Don't use SUM(null), the SUM of (1,1,1,null) = null, not 3.
SELECT s.*, s.yes+s.no+s.other as all FROM (
SELECT Username,
SUM(CASE WHEN type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN type = '' THEN 1 ELSE 0 END) as Other
FROM table
WHERE source = 'CompanyName'
GROUP BY Username
) s
ORDER BY all DESC