Getting total value from each field? - mysql

Question

How do I get the Total value of Yes, No, Other fields of each username?
I like to add Total field.
SELECT Username,
SUM(CASE WHEN type = 'Yes' THEN 1 ELSE NULL END) as Yes,
SUM(CASE WHEN type = 'No' THEN 1 ELSE NULL END) as No,
SUM(CASE WHEN type = '' THEN 1 ELSE NULL END) as Other
//How to get total of Yes/No/Other
FROM table
WHERE source = 'CompanyName' ";
Also the highest Total goes at the top order.

Answer 1

use 0 instead of NULL, add the missing group by and use COUNT(*) to get the total of each group and order the result:
SELECT Username,
SUM(CASE WHEN type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN type = '' THEN 1 ELSE 0 END) as Other,
COUNT(*) as TOTAL
FROM table
WHERE source = 'CompanyName'
group by Username
order by TOTAL desc;
This assumes that type can only be 'Yes', 'No' or ''.

Answer 2

Use a sub query to sum up your results and add a sort:
select yes, no, other, yes + no + other as Total
from (
SELECT Username,
SUM(CASE WHEN type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN type = '' THEN 1 ELSE 0 END) as Other
FROM table
WHERE source = 'CompanyName'
)
order by (yes + no + other) desc

Answer 3

Don't use SUM(null), the SUM of (1,1,1,null) = null, not 3.
SELECT s.*, s.yes+s.no+s.other as all FROM (
SELECT Username,
SUM(CASE WHEN type = 'Yes' THEN 1 ELSE 0 END) as Yes,
SUM(CASE WHEN type = 'No' THEN 1 ELSE 0 END) as No,
SUM(CASE WHEN type = '' THEN 1 ELSE 0 END) as Other
FROM table
WHERE source = 'CompanyName'
GROUP BY Username
) s
ORDER BY all DESC