mysql ORDER BY MIN() not matching up with id - mysql

Question

I have a database that has the following columns:
-------------------
id|domain|hit_count
-------------------
And I would like to perform this query on it:
SELECT id,MIN(hit_count)
FROM table WHERE domain='$domain'
GROUP BY domain ORDER BY MIN(hit_count)
I would like this query to give me the id of the row that had the smallest hit_count for $domain. The only problem is that if I have two rows that have the same domain, say www.bestbuy.com, the query will just group by whichever one came first, and then although I will get the correct lowest hit_count, the id may or may not be the id of the row that has the lowest hit_count.
Does anyone know of a way for me to perform this query and to get the id that matches up with MIN(hit_count)? Thanks!

Answer 1

Try this:
SELECT id,MIN(hit_count),domain FROM table GROUP BY domain HAVING domain='$domain'

Answer 2

See, when you're using aggregates, either via aggregate functions (and min() is such a function) or via GROUP BY or HAVING operators, your data is being grouped. In your case it is grouped by domain. You have 2 fields in your select list, id and min(hit_count).
Now, for each group database knows which hit_count to pick, as you've specified this explicitly via the aggregate function. But what about id — which one should be included?
MySQL internally wraps such fields into max() aggregate function, which I find an error prone approach. In all other RDBMSes you will get an error for such a query.
The rule is: if you use aggregates, then all columns should be either arguments of aggregate functions or arguments of GROUP BY operator.
To achieve the desired result, you need a subquery:
SELECT id, domain, hit_count
FROM `table`
WHERE domain = '$domain'
AND hit_count = (SELECT min(hit_count) FROM `table` WHERE domain = '$domain');
I've used backticks, as table is a reserved word in SQL.

Answer 3

SELECT
id,
hit_count
FROM
table
WHERE
domain='$domain'
AND hit_count = (SELECT MIN(hit_count) FROM table WHERE domain='$domain')

Answer 4

Try this:
SELECT id,hit_count
FROM table WHERE domain='$domain'
GROUP BY domain ORDER BY hit_count ASC;
This should also work:
select id, MIN(hit_count) from table where domain="$domain";

Answer 5

I had same question. Please see that question below.
min(column) is not returning me correct data of other columns
You are using a GROPU BY. Which means each row in result represents a group of values.
One of those values is the group name (the value of the field you grouped by). The rest are arbitrary values from within that group.
For example the following table:
F1 | F2
1 aa
1 bb
1 cc
2 gg
2 hh
If u will group by F1: SELECT F1,F2 from T GROUP BY F1
You will get two rows:
1 and one value from (aa,bb,cc)
2 and one value from (gg,hh)
If u want a deterministic result set, you need to tell the software what algorithem to apply to the group. Several for example:
MIN
MAX
COUNT
SUM
etc etc

Answer 6

There is a most simplist way your query is OK just modify it with DESC keyword after GROUP BY domain
SELECT
id,
MIN(hit_count)
FROM table
WHERE domain = '$domain'
GROUP BY domain DESC
ORDER BY MIN(hit_count)
Explanation:
When you use group by with aggregate function it always selects the first record but if you restrict it with desc keyword it will select the lowest or last record of that group.
For testing puspose use this query that has only group_concat added.
SELECT
group_concat(id),
MIN(hit_count)
FROM table
WHERE domain = '$domain'
GROUP BY domain DESC
ORDER BY MIN(hit_count)

Answer 7

If you can have duplicated domains group by id:
SELECT id,MIN(hit_count)
FROM domain WHERE domain='$domain'
GROUP BY id ORDER BY MIN(hit_count)