TABLE A, B, C
How can I make a query that joins these three tables. The condition is that Table A must have a record.
I tried like this
select * from a
left join b on a.article_id = b.article_id
left join c on b.file_id = c.submission_id
where c.user_id = 6;
My query doesn't work in the case that Table C is missing a record. In that case, the join doesn't work for the three tables.
Any criteria on the outer tables must be int he relevant ON clause, not the WHERE clause.
For example:
select * from a
left join b on a.article_id = b.article_id
left join c on b.file_id = c.submission_id and c.user_id = 6;
If you use LEFT JOIN, then records from a and b are selected even if there are no corresponding records in table c. Use INNER JOIN instead:
SELECT * FROM a
INNER JOIN b ON a.article_id = b.article_id
INNER JOIN c ON b.file_id = c.submission_id
WHERE c.user_id = 6;
Related
Let's say that I have:
SELECT * FROM a
LEFT OUTER JOIN b ON b.a_id = a.id
LEFT OUTER JOIN c ON b.c_id = c.id
Now what I want to do is to select b's that are assigned to c that is e. g. active (c.active = 1). How can I do that with ON?
Note that I can't use WHERE after the whole query above, because I want a's to be returned even if 0 b's are found.
Just to make sure, I understood the question: You want all rows where either c.active equals 1 or where there is no entry in b or c, right?
It's a bit lengthy but this seems to work:
SELECT * FROM a
LEFT OUTER JOIN b ON a.aid = b.aid
LEFT OUTER JOIN c ON b.bid = c.bid
WHERE a.aid NOT IN (
SELECT a.aid FROM a
INNER JOIN b ON a.aid = b.aid
INNER JOIN c ON b.bid = c.bid
WHERE NOT c.active
);
I could also imagine a solution using UNION
Which rows are returned in each case... Note that one case is different:
FROM b JOIN c ON ... AND c.active=1 -- rows in both tables exist and active
FROM b JOIN c ON ... WHERE c.active=1 -- ditto
FROM b LEFT JOIN c ON ... WHERE c.active=1 -- ditto
FROM b LEFT JOIN c ON ... AND c.active=1 -- all b's, but NULLs for inactive/missing c's
(Caveat: I am not sure I got the cases correct; just keep in mind that ON and WHERE are not always interchangeable.)
When mixing JOIN and LEFT JOIN, you may need to add parentheses:
FROM a JOIN ( b LEFT JOIN c ON... ) ON ... WHERE ...
FROM ( a JOIN b ON ... ) LEFT JOIN c ON... WHERE ...
Can you please help me out. I have this SQL query:
SELECT l.url
FROM (b INNER JOIN links ON b.parent_id = l.id)
INNER JOIN b ON l.id = b.link
WHERE l.url LIKE 'http://domain%' LIMIT 0, 30
And somehow it says
#1066 - Not unique table/alias: b
You seem to be selecting from the same table twice. Each of these occurrences needs its own alias:
SELECT
l.url
FROM
b as b1 /* <-- */
INNER JOIN links as l
ON b1.parent_id = l.id
INNER JOIN b as b2 /* <-- */
ON l.id = b2.link
WHERE l.url LIKE 'http://domain%' LIMIT 0, 30
Please note that I also added the missing alias l for the links table.
SELECT l.url from b inner join links as l on l.id = l.parent_id
inner join b as b1 on b1.link = l.id
where l.url like 'http:domain%' limit 0,30
In this query we r join two table first b and second links and self join b as b1 alias ok
In MySQL, I want to SELECT A.* FROM A where an inner join condition is satisfied whether directly (joining table B) or through another join table (C), WHERE B.field = myvalue. Can anyone point out the proper way to get results?
I have the following tables: A, B, C, which are associated as follows (A joins B, B joins C, A joins C):
B
/ \
A --- C
It looks pretty straightforward, but I get an empty set when I run the following code, even though I get results when I restrict the search to just joining B through C:
SELECT A.* FROM A
INNER JOIN C ON C.id = A.c_id
INNER JOIN B AS B_thru_C ON B_thru_C.id = C.b_id
INNER JOIN B AS B_from_A ON B_from_A.id = A.b_id
WHERE B_thru_C.field = 'myvalue' OR B_from_A.field = 'myvalue';
# yields an empty set
SELECT A.* FROM A
INNER JOIN C ON C.id = A.c_id
INNER JOIN B AS B_thru_C ON B_thru_C.id = C.b_id
WHERE B_thru_C.field = 'myvalue';
# yields results
How about this?
SELECT A.* FROM A
LEFT OUTER JOIN C ON C.id = A.c_id
INNER JOIN B ON B.id = A.b_id OR B.id = C.b_id
WHERE B.field = 'myvalue';
I'm coming across this situation alot, I'll have a query that will have one table needed in a join condition that may have no entries therefore requiring me to use a LEFT JOIN. I can't wrap my head around the syntax when it's used with more than 1 join.
I'll have:
SELECT A.*, B.*, C.*
FROM A, B, C
WHERE A.id = C.id
AND C.aid = A.id
AND B.cid = C.id
Along comes D with the possibility of being empty and I have to rewrite the query and run into problems.
How can I simply join D to any one of these tables?
You're much better off explicitly specifying all of your JOINs. That should make things much clearer.
SELECT A.*, B.*, C.*, D.*
FROM A
INNER JOIN C
ON C.aid = A.id
INNER JOIN B
ON B.cid = C.id
LEFT JOIN D
ON C.did = d.id
My advice is to never specify more than one column on FROM clause.
For clarity, it's better to always:
Use JOIN clause
Use aliases
Specify columns of joined tables on left side of equal sign
Example:
SELECT a.*, b.*, c.*
FROM ATable a
INNER JOIN BTable b
ON b.id = a.id
INNER JOIN CTable c
ON c.id = a.id
WHERE a.someColumn = 'something'
Not sure about MySQL, but in some other SQL flavors, you can use the same on UPDATES and DELETES, like:
DELETE FROM a
FROM ATable a
INNER JOIN BTable b
ON b.id = a.id
INNER JOIN CTable c
ON c.id = a.id
WHERE a.someColumn = 'something'
or
UPDATE a
SET something = newValue
FROM ATable a
INNER JOIN BTable b
ON b.id = a.id
INNER JOIN CTable c
ON c.id = a.id
WHERE a.someColumn = 'something'
The syntax below should help you. The basic premise is whatever table is listed LEFT is the required.. the table (or alias) on the right is optional. I understand you don't quite get it, and your syntax sample shows that (not meant to criticize) as you are joining from A -> C and C back to A on a different field. If this is the case where two fields are in the "C" table that BOTH point to A, you would re-join to A as a second alias...
select
Want.*,
Maybe.*,
SecondA.*,
B.*
From
A as Want
LEFT JOIN C as Maybe
on Want.ID = Maybe.ID
JOIN A as SecondA
on Maybe.AID = SecondA.ID
JOIN B
on Maybe.ID = B.cID
So, this query is stating I want everything from Table A (alias Want -- left side/first table in the list) Regardless of there being a match in Table C (alias Maybe) where the ID keys match.
Notice the next joins going down from "C" back to the second instance of "A" and table B. I have those as just joins... So the relationship between the "Maybe" alias, and that of second instance of "A" and "B" are JOIN (required).
Hopefully this gives some better clarification on HOW it works.
Now, for your real-life query. If you can describe what you are looking for, and your sample table structures / result expections, listing that could offer more explicit solution to your needs.
Hope this will help
SELECT
A.*, B.*, C.*
FROM A
inner join C on(A.id = C.id)
inner join B on(B.cid = C.id)
This is the query I'm performing (without some Joins that are not relevant):
SELECT a.*, c.id
FROM a
LEFT OUTER JOIN b ON a.id = b.id_anunciante
LEFT OUTER JOIN c ON c.id = b.id_rubro
GROUP BY a.id
Each row of "a" is linked with 1 to 5 rows in "b".
The problem is that GROUP BY has performance issues (it takes 10x or more using GROUP BY than not using it). I need to retrieve only one row of each member in "a".
How can I make this faster?
edit: I need to be able to filter by a.id AND/OR c.id. The resultset I should be getting is only 1 row per "valid" member of "a", meaning the rows that match the constraints. Rows that don't match the filters shouldn't be returned.
In my original query, this would be done this way:
SELECT a.*, c.id
FROM a
LEFT OUTER JOIN b ON a.id = b.id_anunciante
LEFT OUTER JOIN c ON c.id = b.id_rubro
WHERE c.id = 1
OR a.id = 1
GROUP BY a.id
a.id, b.id_anunciante, b.id_rubro, c.id are all indexes.
SELECT a.*,
(
SELECT c.id
FROM b
JOIN с
ON c.id = b.id_rubro
WHERE b.id_anunciante = a.id
-- add the ORDER BY condition to define which row will be selected.
LIMIT 1
)
FROM a
Create the index on b (id_anunciante) for this to work faster.
Update:
You don't need the OUTER JOINs here.
Rewrite your query as this:
SELECT a.*, c.id
FROM a
JOIN b
ON b.id_anunciante = a.id
JOIN c
ON c.id = b.id_rubro
WHERE a.id = 1
UNION ALL
SELECT a.*, 1
FROM a
WHERE EXISTS
(
SELECT NULL
FROM c
JOIN b
ON b.id_rubro = c.id
WHERE c.id = 1
AND b.id_anunciante = a.id
)
Add ORDER BY NULL to avoid the implicit sorting MySQL does when doing a group by.
I suppose you have indexes/PKs on a.id, b.id_anunciante, b.id_rubro and c.id ? I guess you could try adding a composite index on (b.id_anunciante, b.id_rubro) if your mysql version is not able to do an index merge.