I have the following query, and would like to list only the first match.
$first = $_GET['category'];
$first = $first[0] . "%";
$query = mysql_query("SELECT * FROM lyrics WHERE authorclean LIKE '".$first."'") or die(mysql_error());
(?category=b)
So DISTINCT could do this right? This is what I tried, but did not work:
$query = mysql_query("SELECT DISTINCT authorclean FROM lyrics WHERE authorclean LIKE '".$first."'") or die(mysql_error());
EDIT: Here is the full code:
function getCategory() {
$first = $_GET['category'];
$first = $first[0] . "%";
$query = mysql_query("SELECT DISTINCT authorclean FROM lyrics WHERE authorclean LIKE 'B%'") or die(mysql_error());
//$query = mysql_query("SELECT * FROM lyrics WHERE authorclean LIKE '".$first."'") or die(mysql_error());
if(mysql_num_rows($query) == 0) {
echo "Geen resultaten gevonden.";
} else {
while ($row = mysql_fetch_assoc($query)) { ?>
<p><?= $row['author']; ?></p>
<?php }
}
}
(B% is just for testing)
If I run this following query in the database directly I get two results. If I run with the code above I just get an empty page (except for the html thats already there).
SELECT DISTINCT authorclean FROM lyrics WHERE authorclean LIKE 'B%'
You should use LIMIT 1 to list only the first match.
If you have a a table "tbl_lyrics" with fields: author lyrics year and is filled for example as follows:
author_A lyrics_A year_A
author_A lyrics_A1 year_A1
author_A1 lyrics_A2 year_A
author_B lyrics_B1 year_B1
if you do
select distinct(author) from tbl_lyrics where author like '%author_A%'
you are going to get: author_A and author_A1. NOT the first one that matches.
If you want the first one that matches you can do:
select author from (select distinct(author) as author from tbl_lyrics where author like '%author_A%') where rownum <2;
this will return author_A only.
Limit is used with MySql but would not work with oracle databases
Related
I have a simple query which works correctly in phpMyadmin, however doesn't when I echo it out on a page:
$query = "SELECT * FROM PEOPLE WHERE MEMBER_TYPE Like 'LFM' ORDER BY LAST_NAME ASC ";
}
$query = mysqli_query($link, $query);
while ($row = mysqli_fetch_array($query)){...`
For unknown reasons it simply will not sort the results by the last name column from within the table. Any ideas why this could be?
Hi gus this is my first question in this coumunity i hope someone answer me
when i want to search from array of mysql_fetch_arrray he give me on error
this is the code
$key = "Meca";
$query = "SELECT * FROM subject WHERE `name` LIKE '%$key%' Or `sale` LIKE '%$key%' Or `Emphet` LIKE '%$key%' ";
$sql = mysql_query($query);
$num = mysql_num_rows($sql);
while ($num >0)
{
$row = mysql_fetch_object($sql);
$num--;
$row = mysql_fetch_object($sql);
in_array($row , "Meca");
}`
You are not clear with your question;
Anyway I give a try:
$key = "Meca";
$query = "SELECT * FROM subject WHERE name LIKE '%$key%' Or sale LIKE '%$key%' Or Emphet LIKE '%$key%'";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result)) {
if(in_array($row , "Meca")){
echo "$key is present this time."
}
}
Note that:
I am not on your requirement. So I just make a rough sketch.
You have not provided your error message.
You may have error in your code(SQl or PHP)[like usage of names
'Emphet'].
Anyway give a try.
after some researching I put this code together to search a mysql table in the db. while it works fine, it limit itself to match the words exactly as the user enters it. anyone know how to make it so that it matches my some sort of relevancy? I have been reading about the full text search but I cant really seem to grasp it.
for example, if you search for 'unanswered questions' in two fields, I want to be able to get result like that include the searched word(s) in any string that it show up in, and list it according to relevancy, like so (search results example output):
- unanswered questions
- answered questions
- answer question
- unanswered questions
- unanswered questions
- questions
- answer
$k = trim ($_GET['search']);
$i = "";
$terms = explode (" ", $k);
$query = "SELECT * FROM table1 WHERE ";
foreach ($terms as $each){
$i++;
if ($i == 1)
$query .= "fld_title LIKE '%$each%' OR fld_keyword LIKE '%$each%' ";
else
$query .= "OR fld_title LIKE '%$each%' OR fld_keyword LIKE '%$each%' ";
}
// connect
include_once "connect.php"; //connect 2 db
$query = mysql_query($query);
$numrows = mysql_num_rows ($query);
if ($numrows > 0){
while ($row = mysql_fetch_assoc ($query)){
//
//
// echo out something here
//
//
}
}else
{
echo "No results found for <b>$k</b>";
}
to do a fulltext search you have to:
Create a Fulltext index in the table (note the fields can't be BLOB)
ALTER TABLE tablename ADD FULLTEXT(field1, field2,...);
in your case:
ALTER TABLE table1 ADD FULLTEXT(fld_title, fld_keyword);
in php change
$k = trim ($_GET['search']);
$i = "";
$terms = explode (" ", $k);
$query = "SELECT * FROM table1 WHERE ";
foreach ($terms as $each){
$i++;
if ($i == 1)
$query .= "fld_title LIKE '%$each%' OR fld_keyword LIKE '%$each%' ";
else
$query .= "OR fld_title LIKE '%$each%' OR fld_keyword LIKE '%$each%' ";
}
for
$k = trim ($_GET['search']);
$query="SELECT * FROM table1 WHERE MATCH(fld_title, fld_keyword) AGAINST ('".$k."')";
if you want to see the relevancy of the results:
$query="SELECT *, MATCH(fld_title, fld_keyword) AGAINST ('".$k."') as relevancy FROM table1 WHERE MATCH(fld_title, fld_keyword) AGAINST ('".$k."')";
The MATCH-AGAINST returns a number: 0 for no match or other depending on matching.
You can "order by relevancy", change the query for make more relevant the search... MATCH(fld_title, fld_keyword) AGAINST ('".$k."') > 0.5
Only one problem: the AGAINST part ($k for you) must be greater than 3 characters.
What's the best way to check whether the value is in the database?
Am I doing it correct?
$result = mysql_query("SELECT COUNT(*) FROM table WHERE name = 'John'");
$count = count($result);
you could use straight forward ,
mysql_num_rows() ;
eg :
$con = mysql_connect($host,$uname,$passwd)
mysql_select_db($dbase,$con);
$result = mysql_query($query,$con);// query : SELECT * FROM table WHERE name='jhon';
if( ! mysql_num_rows($result)) {
echo " Sorry no such value ";
}
Yes you are doing it right, if you are only concerned with checking if there are any records where name='john'
SELECT COUNT(*) FROM table WHERE name = 'John'
will return the no. of records where name field is 'John'. if there are no records then it will return 0, and if there are any records it will return the number of records.
But the above query will miss the entries where name is 'John Abraham' or 'V john', to include even these
you can modify your query like this.
SELECT COUNT(*) FROM table WHERE name like '%John%'
I'd say yes.
$result = mysql_query("SELECT COUNT(*) AS 'nb' FROM table WHERE name = 'John'");
$line = mysql_fetch_array($result, MYSQL_ASSOC);
$count = $line['nb'];
Will give you the number of matching rows.
$result = mysql_query("SELECT COUNT(*) as user FROM table WHERE name = 'John'");
$line = mysql_fetch_array($result, MYSQL_ASSOC);
$count = $line['user'];
if($count!=0)
{
echo "user exists";
}
else
{
echo "There is no such user";
}
I want to display four (4) items'name from these id:
Can I do like this?
SELECT item_name from items WHERE item_id IN ('001', '012', '103', '500')
or
SELECT item_name from items WHERE item_id = '001' or item_id = '012' or item_id = '103' or item_id = '500'
IN RESPONSE TO ALL ANSWERS
Well, most of the answers said it works, but it does not really work. Here is my code:
$query = "SELECT `item_name` from items WHERE item_id IN('s001','a012','t103','p500')";
$result = mysql_query($query, $conn) or die (mysql_error());
$fetch = mysql_fetch_assoc($result) or die (mysql_error());
$itemsCollected = $fetch['item_name'];
echo $itemsCollected;
The item_id is alphanumeric.
You can do either one, but the IN query is much more efficient for this purpose for any large queries. I did some simple testing long ago that revealed it's about 10 times faster to use the IN construct for this. If you're asking if the syntax is correct then yes, it looks fine, other than missing semi-colons to complete the statement.
EDIT: It looks like the actual question you were asking was "why do these queries only return one value". Well, looking at the sample code you posted, the problem is here:
$fetch = mysql_fetch_assoc($result) or die (mysql_error());
$itemsCollected = $fetch['item_name'];
echo $itemsCollected;
You need to loop through and iterate until there are no more results to be fetched, as Pax pointed out. See the PHP manual page for mysql_fetch_assoc:
$sql = "SELECT item_name from items WHERE item_id IN('s001','a012')";
$result = mysql_query($sql);
if (!$result) {
echo "Could not successfully run query ($sql) from DB: " . mysql_error();
exit;
}
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
// While a row of data exists, put that row in $row as an associative array
// Note: If you're expecting just one row, no need to use a loop
// Note: If you put extract($row); inside the following loop, you'll
// then create $userid, $fullname, and $userstatus
while ($row = mysql_fetch_assoc($result)) {
echo $row["userid"];
echo $row["fullname"];
echo $row["userstatus"];
}
mysql_free_result($result);
Yes, both those should work fine. What's the actual problem you're seeing?
If, as you say, only one record is being returned, try:
select item_name from items order by item_id
and check the full output to ensure you have entries for 001, 012, 103 and 500.
If both those queries only return one row, I would suspect not.
If they all do exist, check the table definitions, it may be that the column is CHAR(4) and contains spaces for the others. You may have genuinely found a bug in MySQL but I doubt it.
After EDIT:
This is a perl/mysql problem, not an SQL one: mysql_fetch_array() returns only one row of the dataset at a time and advances a pointer to the next.
You need to do something like:
$query = "SELECT item_name from items WHERE item_id IN('s001','a012')";
$result = mysql_query($query, $conn) or die (mysql_error());
if (mysql_num_rows($result) == 0) {
echo "No rows found, nothing to print so am exiting";
exit;
}
while ($row = mysql_fetch_assoc($result)) {
echo $row["item_name"];
}
Your ID field must be set to auto increment, i guess. i had problems with that once and i changed the auto increment to int. in the IN field if you pass the parameters to match against the auto increment variable you get back only the first parameter, the remaining generates an error.
Use mysql_fetch_assoc to get the query and assign the values from mysql_fetch_assoc query into a an array. Simple as that
$i=0;
$fullArray = array();
$query = mysql_query("SELECT name FROM users WHERE id='111' OR id='112' OR id='113' ")or die(mysql_error());
while($row = mysql_fetch_assoc($query)){
foreach ($row as $value) {
$fullArray[$i] = $value;
}
$i++;
}
var_dump($fullArray);
echo $fullArray[0]."<br/>".$fullArray[1]."<br/>".$fullArray[2];`
You could also use the mysql_num_rows function to tell you how many rows your query retrieved and then use that result to increment a for loop. An example.
$num_rows=mysql_num_rows($query_results);
for ($i=0; $i <$num_rows ; $i++) {
$query_array[]=mysql_fetch_assoc($query_results);
}