Here is an example of my table.
int_id ranking prize
1 1 120
1 2 60
1 3 30
2 1 40
2 2 25
3 1 500
I'm trying to figure out how to take this table sum the prize monies of each event and list the int_id and total money. So it will look like this
int_id total_money
1 210
2 65
3 500
Thank you for any help provided.
For something like this, you need to use the aggregate function SUM, grouping by the int_id:
SELECT int_id, sum(prize) as total_money
from tablename
GROUP BY int_id
Related
Please help me with writing a query for the following condition. I have a table which I have listed below
ID Wt1 Wt1_Type Wt2 Wt2_Type Wt3 Wt3_Type Wt4 Wt4_Type
--------------------------------------------------------------
1 200 1 220 1 300 2 400 3
2 100 4 150 3 100 5 120 1
3 100 3 110 1 200 5 100 4
I want a query to sum all the the weights (wt1, wt2, wt3, wt4) grouped on the weight type (wt1_type, wt2_type, wt3_type, wt4_type).
The output should look like
Wt_type Total
1 650
2 300
3 650
4 200
5 300
Can someone please help me draft a mysql query to get this result ?
Thanks
You can try below - using union all and subquery
select Wt_Type,sum(Wt) as total from
(
select Wt1_Type as Wt_Type,Wt1 as Wt from tablename
union all
select Wt2_Type ,Wt2 from tablename
union all
select Wt3_Type ,Wt3 from tablename
union all
select Wt4_Type ,Wt4 from tablename
)A group by Wt_Type
Rather than giving the answer by #fa06, which should work for you, I am going to suggest using a better table design. Here is how you should be storing your data:
ID Type Wt
-------------
1 1 200
2 4 100
3 3 100
4 1 220
5 3 150
6 1 110
7 2 300
8 5 100
9 5 200
10 3 400
11 1 120
12 4 100
Note that there is a single column which stores the type and a single column for that type's weight. Now your expected output just requires a very simple query:
SELECT Type, SUM(Wt) AS Total
FROM yourTableUpdated
GROUP BY Type;
Databases are really good at performing operations across rows, much less so across columns.
Use this it should be work
select Wt_Type,sum(Wt) as total from ( select Wt1_Type as Wt_Type,Wt1 as Wt from tablename union all select Wt2_Type ,Wt2 from tablename union all select Wt3_Type ,Wt3 from tablename union all select Wt4_Type ,Wt4 from tablename )A group by Wt_Type
Need MySQL query for below problem
Consider a table having student and their marks in a particular subject
Schema
std_id int(11)
marks int(11)
Sample data
std_id marks
1 10
2 15
3 90
4 120
5 25
6 29
7 121
8 122
Now I have an web app in which a form will take a input (int) from user.
For eg 12
then I am required to show total number of student ids (std_id) and their corresponding marks group.
Eg
std_total (tot no of students) group (marks range we got from form)
1 0-11
1 12-23
2 24-35
1 84-95
3 120-131
#Barmar Your answer was almost correct, I made few changes to clean the output. Your query gives output as below :
0-11 2
1-12 2
2-13 1
3-14 1
4-15 1
6-17 1
7-18 2
My query return Outout as
0-11 2
12-23 2
24-35 1
36-47 1
48-59 1
72-83 1
84-95 2
SELECT CONCAT(FLOOR(marks/12)*12, '-', FLOOR(marks/12)+11*(FLOOR(marks/12))+11) AS `group`, COUNT(*) as `std_total`
FROM yourTable
GROUP BY `group`
Use division and FLOOR() to get the beginning of each range.
SELECT CONCAT(FLOOR(marks/12), '-', FLOOR(marks/12)+11) AS `group`, COUNT(*) as `std_total`
FROM yourTable
GROUP BY `group`
I have my data base like this
id project_id client_id price
1 1 1 200
2 2 1 123
3 2 1 100
4 1 1 87
5 1 1 143
6 1 1 100
7 3 3 123
8 3 3 99
9 4 3 86
10 4 3 43
11 4 3 145
12 4 3 155
Now here I want that it will sum the price columns with the same client_id.
For that I just made my query like this
Select `project_id`, SUM(`price`) FROM `table-name` GROUP BY `client_id`
This one is doing sum the price but I am getting only two project_id in the result. I want the result should be all the distinct project for the client id and the price will be summed for the group clients.
So can someone tell me how to do this? Any help and suggestions will be really appreciable. Thanks
You should not have "bare" column in a group by query that are not in the group by statement.
If you want the list of projects, you can get them in a list like this:
SELECT client_id, GROUP_CONCAT(project_id), SUM(price)
FROM table-name
GROUP BY client_id;
you only have two client that why you are getting only two record , you can group by two column,
Select `project_id`, SUM(`price`) FROM `table-name` GROUP BY `client_id`, `project_id`
I want to SUM two columns from two different database and output the highest value.
trying to figure it out since last 1day but no luck. can anyone please help?
Table 1
mid points
1 20
2 10
1 10
1 30
3 10
Table 2
mid points
1 20
2 10
1 10
2 20
1 10
3 10
so the total should be
mid points
1 100
2 40
3 20
output that i want highest total mid is 1 = 100
Try this untested query:
select mid , sum(points) from (
select mid,points from table1
union all
select mid,points from table2
) as table3
group by mid
order by sum(points) DESC
limit 1
I want to find number of repeated value in group using single select query.
I can't use the column in group by for which I want to find number of occurrence in some group.
e.g.
obsid Name Value
1 Ronak 120
2 Ronak 125
3 Ronak 120
4 Pankti 130
5 Pankti 130
6 Sanket 140
7 Aakash 140
8 Unnat 120
Now I want to develop select query in mysql that give me below result
obsid Name Value Value_occurrence
1 Ronak 120 2
2 Ronak 125 1
4 Pankti 130 2
6 Sanket 140 1
7 Aakash 140 1
8 Unnat 120 1
SELECT min(obsid) AS obsid, Name, Value, COUNT(*) AS Value_occurence
FROM yourTable
GROUP BY Name, Value
Group by the desired columns and use COUNT to count the rows in each group:
SELECT MIN(`obsid`) AS `obsid`, `Name`, `Value`, COUNT(*) AS Value_occurrence
FROM yourtable
GROUP BY `Name`, `Value`
Try this online demo which shows your example data and the results for the above query.