I try to change my code from MYSQL to SQL and i got an error (SQL Syntax 'Limit').
So i tried to change my query and update with "TOP" but seems to work only with SELECT.
So, how can i change this MYSQL query :
$fct="UPDATE `users` SET `STREAM_TITRE` = '$STREAM_TITRE',`STREAM_URL` = '$STREAM_URL',`STREAM_DESC` = '$STREAM_DESC',`STREAM_GENRE` = '$STREAM_GENRE' WHERE `ID` =$IDSESS LIMIT 1";
Here is my SQL Code without Limit :
$fct="UPDATE users SET STREAM_TITRE = '$STREAM_TITRE', STREAM_URL = '$STREAM_URL', STREAM_DESC = '$STREAM_DESC', STREAM_GENRE = '$STREAM_GENRE' WHERE ID = '$IDSESS'";
Thanks
It's not very clear which version of your query is working and which is not - and in what DBMS.
If ID is of char or varchar type, you are missing some quotes in the LIMIT version. Although MySQL is not very picky and you won't have many issues, with or without quotes:
$fct = "
UPDATE users
SET STREAM_TITRE = '$STREAM_TITRE'
, STREAM_URL = '$STREAM_URL'
, STREAM_DESC = '$STREAM_DESC'
, STREAM_GENRE = '$STREAM_GENRE'
WHERE ID = $IDSESS --<-- this should be '$IDSESS' , right?
----- or $IDSESS , depending on the datatype
LIMIT 1
";
Note: The LIMIT n works in MySQL and PostgreSQL, but not in some other DBMS. Plus, I don't think you really need it anyway, as the ID is probably the Primary Key of the table.
If you are trying to convert the statement from MySQL to SQL-Server, you should not use the backquotes and replace LIMIT 1 with TOP (1):
$fct = "
UPDATE TOP (1) users
SET STREAM_TITRE = '$STREAM_TITRE'
, STREAM_URL = '$STREAM_URL'
, STREAM_DESC = '$STREAM_DESC'
, STREAM_GENRE = '$STREAM_GENRE'
WHERE ID = $IDSESS
";
Related
Previously, this was working:
$patient_story_set_photos = $wpdb->get_results('SELECT * FROM wp_before_after WHERE patientID = '.$post->ID.' AND patient_display = 1');
However, when I try to add another AND condition like this:
$patient_story_set_photos = $wpdb->get_results('SELECT * FROM wp_before_after WHERE patientID = '.$post->ID.' AND patient_display = 1 AND period_taken = '.$set->period_taken);
I get the following error on screen:
WordPress database error: [Unknown column '1hour' in 'where clause']
SELECT * FROM wp_before_after WHERE patientID = 8175 AND patient_display = 1 AND period_taken = 1hour
Can't see why there's a problem, are you not allowed to use multiple AND conditions in SQL?
The problem is not the AND, the problem is your 1hour, 1hour unquoted means a reference to an object (database, table) named 1hour, you need to quote '1hour'.
If you write
SELECT * FROM wp_before_after
WHERE patientID = 8175
AND patient_display = 1
AND period_taken = '1hour'
you will compare the field periodtaken to a string (CHAR,VARCHAR,TEXT) equal to '1hour'.
I assume period_taken is a field typed CHAR,VARCHAR or TEXT
Before anything, DO NOT CONCATENATE SQL STRINGS nowadays it is a MUST (see how to do it properly https://stackoverflow.com/a/60496/3771219)
The problem you are facing is because, I presume, that the period_taken field is some sort of Char/Varchar/String field and when you are filtering by a "Stringy" field you must sorround your literals values with single quotes:
SELECT *
FROM wp_before_after
WHERE patientID = 8175
AND patient_display = 1
AND period_taken = '1hour'
Hope this help
I'm getting an error about my query, and i'm not understanding what the problem might be. The error i get is
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'range = '55', atkspeed = '0.95', m_damage = '0', p_damage = '38', mprotection = ' at line 1
While the code i'm using is this one
$id = mysql_real_escape_string($_POST["id"]);
$value0 = mysql_real_escape_string($_POST["value0"]);
$value1 = mysql_real_escape_string($_POST["value1"]);
$value2 = mysql_real_escape_string($_POST["value2"]);
$value3 = mysql_real_escape_string($_POST["value3"]);
$value4 = mysql_real_escape_string($_POST["value4"]);
$value5 = mysql_real_escape_string($_POST["value5"]);
$value6 = mysql_real_escape_string($_POST["value6"]);
$value7 = mysql_real_escape_string($_POST["value7"]);
$value8 = mysql_real_escape_string($_POST["value8"]);
$value9 = mysql_real_escape_string($_POST["value9"]);
$value10 = mysql_real_escape_string($_POST["value10"]);
$query="UPDATE char_stats SET vita = '$value0', mana = '$value1', speed = '$value2', range = '$value3', atkspeed = '$value4', m_damage = '$value5', p_damage = '$value6', mprotection = '$value7', pprotection = '$value8', hp5 = '$value9', mp5 = '$value10' WHERE id_char_stats='$id'";
I'm using also other very similar queries so i don't get what the problem might be. I was thinking about the underscore on char_stats so i tried using
char\_stats
for escape, but it's not working anyway.
Thanks in advance
create table t11
(
id int not null,
`range` int not null,
speed int not null
);
update t11 set range='11', speed=1; -- blows up
update t11 set `range`='11', speed=1; -- fine
update t11 set `range`=11, speed=1; -- fine
Moral of the store: back-tick range. Even the create table blows up without it.
see mysql keywords and reserved words here. Range is one of them.
So your query would become:
$query="UPDATE char_stats SET vita = '$value0', mana = '$value1', speed = '$value2', `range` = '$value3', atkspeed = '$value4', m_damage = '$value5', p_damage = '$value6', mprotection = '$value7', pprotection = '$value8', hp5 = '$value9', mp5 = '$value10' WHERE id_char_stats='$id'";
I've got two Queries to Update two tables:
First Table
UPDATE user_info SET `location` = ".$locationid.", `looking_for` = ".$lookingfor." WHERE `user_info`.`user_id` = ".$infoid.";
Second Table
UPDATE user_personality SET `personality` = '".$changedescription."' WHERE `user_personality`.`user_info_id` = ".$infoid.";
And I'm trying to merge those two Queries, using the same statement.
UPDATE user_info, user_personality
SET user_info.location = ".$locationid.", user_info.`looking_for` = ".$lookingfor.", user_personality.personality = '".$changedescription."'
WHERE `user_info`.`user_id` = ".$infoid."
AND `user_personality`.`user_info_id` = ".$infoid."
I'm not receiving any error message, but is not updating.
What am I doing wrong?
Thanks.
Just a guess...
"
UPDATE user_info i
JOIN user_personality p
ON p.user_info_id = i.user_id
SET i.location = $locationid
, i.looking_for = '$lookingfor'
, p.personality = '$changedescription'
WHERE i.user_id = $infoid;
";
If you set the 2 table fields equal to each other in the where clause it should work, so I believe you'd change your where clause to:
WHERE `user_info`.`user_id` = `user_personality`.`user_info_id`
AND `user_info`.`user_id` = ".$infoid."
MySQL definitely supports updating multiple tables, so the where clause that works for a multi table select statement should also work for an update.
I've following sql to update results table:
$mysqli->query("UPDATE results
SET result_value = IF('$logo_value' - result_tries < 0 OR '$logo_value' - result_tries = 0, 1, '$logo_value' - result_tries)
WHERE logo_id = '$logo_id'
AND user_id = '$user_id'
AND result_value = 0");
In the same sql command is it possible to update another table based on result_value?
if result_value = 10
Update users SET user_hints = user_hints +1 WHERE user_id = '$user_id'
How would I incorporate this into sql syntax above?
Long way I can think of is to select this value get it into php variable. And than do another update based on php variable value... But this seems long and tedious
This is a long shot (not tested) but how about:
$mysqli->query("UPDATE results, users
SET result_value =
IF('$logo_value' - results.result_tries < 0 OR
'$logo_value' - results.result_tries = 0,
1, '$logo_value' - result_tries),
users.user_hints =
IF(results.result_value >= 10,
users.user_hints + 1, users.user_hints)
WHERE results.logo_id = '$logo_id'
AND results.user_id = '$user_id'
AND results.user_id = users.user_id
AND results.result_value = 0");
If both tables have some of the same column names, of course, youll have to specify which table (like results.user_id -or- users.user_id)
I can't figure out the syntax for Mysql update with multiple concatinations. I want to be able to append a string to the end of the string stored in the database but do it to multiple columns all at once. I can do one column at a time just fine with this
UPDATE `table1`.`column1` SET `category1` = CONCAT(category1,'$value[0]',) WHERE `id`='$id';
But when I try to do it to multiple columns in the same table I get a syntax error.
UPDATE `table1`.`column1`
SET `category1` = CONCAT(category1,'5'),
`category2` = CONCAT(category2,'5'),
`category3` = CONCAT(category3,'5'),
`category4` = CONCAT(category4,'5'),
`category5` = CONCAT(category5,'5'),
`comments` = CONCAT(comments, 'jfsaklfsad')
WHERE `for_student_id`='46';
"You have an error in your SQL syntax;"
I can't find the syntax for separating each concat.
According to MySQL docs, UPDATE does not support such syntax. You must reference the table name, without the column, before the SET:
UPDATE `table1`
SET `category1` = CONCAT(category1,'5'),
`category2` = CONCAT(category2,'5'),
`category3` = CONCAT(category3,'5'),
`category4` = CONCAT(category4,'5'),
`category5` = CONCAT(category5,'5'),
`comments` = CONCAT(comments, 'jfsaklfsad')
WHERE `for_student_id`='46';