Update table mysql and if value is 10 update another table - mysql

Question

I've following sql to update results table:
$mysqli->query("UPDATE results
SET result_value = IF('$logo_value' - result_tries < 0 OR '$logo_value' - result_tries = 0, 1, '$logo_value' - result_tries)
WHERE logo_id = '$logo_id'
AND user_id = '$user_id'
AND result_value = 0");
In the same sql command is it possible to update another table based on result_value?
if result_value = 10
Update users SET user_hints = user_hints +1 WHERE user_id = '$user_id'
How would I incorporate this into sql syntax above?
Long way I can think of is to select this value get it into php variable. And than do another update based on php variable value... But this seems long and tedious

Answer 1

This is a long shot (not tested) but how about:
$mysqli->query("UPDATE results, users
SET result_value =
IF('$logo_value' - results.result_tries < 0 OR
'$logo_value' - results.result_tries = 0,
1, '$logo_value' - result_tries),
users.user_hints =
IF(results.result_value >= 10,
users.user_hints + 1, users.user_hints)
WHERE results.logo_id = '$logo_id'
AND results.user_id = '$user_id'
AND results.user_id = users.user_id
AND results.result_value = 0");
If both tables have some of the same column names, of course, youll have to specify which table (like results.user_id -or- users.user_id)