Know which condition didn't match in mysql consult - mysql

Question

Into a very high selective MySQL query, is there a way to know which condition did not match?
Eg.: If I'm looking for 12 conditions and my MySQL returns 0, wich one of these 12 conditions did not match?
SELECT
article.id,
article.name,
GROUP_CONCAT(tags.name order by tags.name) AS nameTags,
GROUP_CONCAT(tags.id order by tags.id) AS idTags,
MAX(IF(article.name LIKE '%var1%',1,0)) AS var1match,
MAX(IF(article.name LIKE '%var2%',1,0)) AS var2match,
and more 10 conditions.
FROM
article
LEFT JOIN ....
LEFT JOIN ....
GROUP BY id
HAVING
(nameTags LIKE '%var1%' OR var1match=1)
AND (nameTags LIKE '%var2%' OR var2match=1)
AND more 10 conditions.
I mean, do it without make 12 single consults to see which one results nothing.
Update: Got some evolution
If I do this:
SELECT
article.id,
MAX(IF(article.name LIKE '%var1%',1,0) AS var1,
MAX(IF(article.name LIKE '%var2%',1,0) AS var2,
MAX(IF(article.name LIKE '%var3%',1,0) AS var3,
FROM
article
LEFT JOIN ....
LEFT JOIN ....
GROUP BY article.id
I'll get an aliased table like this
|id|var1|var2|var3|
| 1| 0| 0| 1|
| 2| 0| 1| 0|
| 3| 0| 0| 0|
| 4| 0| 1| 1|
So I know that 'var 1' doesn't match with the condition because all column value is equal 0. How I get the return of that column name?
Tried to sum value and get columns that sum = 0. Don't know how to do.
Update:
Found to do that is using temporary tables.
1) Create tmp table:
CREATE TEMPORARY TABLE tmp_tagReport AS
SELECT
article.id,
MAX(IF(article.name LIKE '%var1%',1,0) AS l_var1,
MAX(IF(article.name LIKE '%var2%',1,0) AS l_var2,
MAX(IF(article.name LIKE '%var3%',1,0) AS l_var3,
FROM
article
LEFT JOIN ....
LEFT JOIN ....
GROUP BY article.id
You'll have something like this:
|id|l_var1|l_var2|l_var3|
| 1| 0| 0| 1|
| 2| 0| 1| 0|
| 3| 0| 0| 0|
| 4| 0| 1| 1|
2) Sum values and you will know that column with 0 has no match
SELECT
SUM(l_var1) as l_var1,
SUM(l_var2) as l_var2,
SUM(l_var3) as l_var3
You'll get something like this:
|l_var1|l_var2|l_var3|
| 0| 2| 2|
3) Get name of columns with value = 0 in PHP
$querySelect = "SELECT
SUM(l_var1) as l_var1,
SUM(l_var2) as l_var2,
SUM(l_var3) as l_var3
";
$result = mysql_query($querySelect);
$arrayUnfound = array_keys(#mysql_fetch_assoc($result), "0");
print_r($arrayUnfound)
4) It is a temporary table, but I added a drop table just to make sure and try to free memory:
mysql_query("DROP TABLE tmp_tagReport; ");
I found myself a way to do it, but it still has to make 2 or more queries. However I hope it could be helpful.
sorry my english
Thanks