I have two tables, 'po' and 'receive'
CREATE TABLE `po` (
`PO_ID` bigint(20) NOT NULL,
`SERVICE_TYPE` bit(1) DEFAULT NULL,
`ENTRY_DATE` date NOT NULL,
`RECEIPT_DATE` date DEFAULT NULL,
`TURNOVER` date DEFAULT NULL,
`MOBILIZATION` date DEFAULT NULL,
`SITE_NAME` varchar(255) NOT NULL,
`SITE_CODE` varchar(45) DEFAULT NULL,
`SITE_TIN` varchar(45) DEFAULT NULL,
`SITE_ADDRESS` varchar(255) NOT NULL,
`COST` decimal(11,2) NOT NULL,
`XML` text,
PRIMARY KEY (`PO_ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8$$
CREATE TABLE `receive` (
`RECEIPT_ID` varchar(100) NOT NULL,
`RECEIPT_DATE` date NOT NULL,
`PO_NUMBER` bigint(20) NOT NULL,
`SUPPLIER_ID` int(11) NOT NULL,
PRIMARY KEY (`RECEIPT_ID`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8$$
I'm trying to connect two tables by defining a foreign key 'fk_po' on the table 'receive'
ALTER TABLE `fourthwave`.`receive`
ADD CONSTRAINT `fk_po`
FOREIGN KEY (`PO_NUMBER` )
REFERENCES `fourthwave`.`po` (`PO_ID` )
ON DELETE SET NULL
ON UPDATE SET NULL
, ADD INDEX `fk_po` (`PO_NUMBER` ASC)
However, the alter query above throws an error :
Error Code: 1005. Can't create table 'fourthwave.#sql-aec_11' (errno:150)
Am i getting this error because the field's names, 'PO_ID' and 'PO_NUMBER' on both tables are different?
Execute SHOW ENGINE INNODB STATUS statement after ALTER TABLE, and you will see the error message - 'You have defined a SET NULL condition though some of the
columns are defined as NOT NULL'.
ALTER TABLE `receive`
ADD CONSTRAINT `fk_po`
FOREIGN KEY (`PO_NUMBER` )
REFERENCES `po` (`PO_ID` )
ON DELETE SET NULL
ON UPDATE SET NULL
, ADD INDEX `fk_po` (`PO_NUMBER` ASC);
SHOW ENGINE INNODB STATUS;
You need an index on PO_NUMBER in the receive table. The field you are referencing in a foreign key always should be indexed.
Related
I´m trying to create Foreign Keys in phpmyadmin, but I get this error:
Error creating foreign key on revision (check data types)
I don´t understand it because the data types are equal. So, what I want is to create a Foreign Key from 'acoustictreatment' to 'filterspecifications' which contains tag, offerid and revision. But I get the error that I mentioned.
This are my tables:
CREATE TABLE `offer` (
`projectid` varchar(20) NOT NULL,
`customer` varchar(255) NOT NULL,
`creator` varchar(255) NOT NULL,
`date` date NOT NULL,
`revision` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
ALTER TABLE `offer`
ADD PRIMARY KEY (`projectid`,`revision`);
CREATE TABLE `filterspecifications` (
`tag` varchar(100) NOT NULL,
`gasFlow` double NOT NULL,
`dustToHandle` double NOT NULL,
`offerid` varchar(20) NOT NULL,
`selectedFilter` varchar(20) NOT NULL,
`revision` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
ALTER TABLE `filterspecifications`
ADD PRIMARY KEY (`tag`,`offerid`,`revision`),
ADD KEY `offerid` (`offerid`,`revision`);
ALTER TABLE `filterspecifications`
ADD CONSTRAINT `filterspecifications_ibfk_1`
FOREIGN KEY (`offerid`,`revision`) REFERENCES `offer` (`projectid`, `revision`) ON DELETE CASCADE ON UPDATE CASCADE;
CREATE TABLE `acoustictreatment` (
`tag` varchar(100) NOT NULL,
`offerid` varchar(20) NOT NULL,
`outputFanSilencer` tinyint(1) NOT NULL,
`fanAcousticInsulation` tinyint(1) NOT NULL,
`revision` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8mb4;
ALTER TABLE `acoustictreatment`
ADD PRIMARY KEY (`tag`,`offerid`,`revision`);
The solution that I found is to delete the 'acoustictreatment' table and create it again with the foreign key from the beginning. Because what I was trying to do was to create all the tables and then create the foreign keys, but that didn´t work for me
I can't figure out why I'm getting an error here.
CURRENT TABLES:
CREATE TABLE `Clients` (
`ClientID` varchar(8) NOT NULL,
`Age` varchar(20) NOT NULL,
`Postcode` varchar(6) NOT NULL,
PRIMARY KEY (`ClientID`,`Age`,`Postcode`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
CREATE TABLE `Disclosure` (
`ClientID` varchar(8) NOT NULL,
`Fname` varchar(100) DEFAULT NULL,
`Lname` varchar(100) DEFAULT NULL,
`Email` varchar(100) DEFAULT NULL,
`Postcode` varchar(6) NOT NULL,
`Offender` varchar(45) DEFAULT NULL,
`Location` varchar(100) DEFAULT NULL,
`Age` varchar(20) NOT NULL,
`Support` varchar(45) DEFAULT NULL,
`Disclosure` varchar(1000) DEFAULT NULL,
PRIMARY KEY (`ClientID`,`Postcode`,`Age`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
trying to add foreign key
ALTER TABLE `FYP`.`Disclosure`
ADD CONSTRAINT `client`
FOREIGN KEY (`ClientID` , `Postcode` , `Age`)
REFERENCES `FYP`.`Clients` (`ClientID` , `Postcode` , `Age`)
ON DELETE NO ACTION
ON UPDATE CASCADE;
I've tried using show status to see what the error is but I still cant figure it out.
SHOW ENGINE INNODB STATUS
returns:
------------------------ LATEST FOREIGN KEY ERROR
------------------------ 171102 11:35:10 Error in foreign key constraint of table FYP/#sql-266_33b:
FOREIGN KEY (ClientID , Postcode , Age) REFERENCES
FYP.Clients (ClientID , Postcode , Age) ON DELETE NO
ACTION ON UPDATE CASCADE: Cannot find an index in the referenced
table where the referenced columns appear as the first columns, or
column types in the table and the referenced table do not match for
constraint. Note that the internal storage type of ENUM and SET
changed in tables created with >= InnoDB-4.1.12, and such columns in
old tables cannot be referenced by such columns in new tables. See
http://dev.mysql.com/doc/refman/5.5/en/innodb-foreign-key-constraints.html
for correct foreign key definition.
You need an index on the referenced columns. The order of the columns in an index matter. In the clients table change the primary key to
(`ClientID`,`Postcode`,`Age`)
This should do it
ALTER TABLE clients DROP PRIMARY KEY, ADD PRIMARY KEY (`ClientID`,`Postcode`,`Age`);
I have the followiing tables:
CREATE TABLE `Atletica` (
`Universidade` varchar(100) NOT NULL,
`Nome` varchar(100) NOT NULL,
`Logo` varchar(100) NOT NULL,
`GritoDeGuerra` varchar(100) NOT NULL,
`EnderecoCEP` int(11) NOT NULL,
`EnderecoNumero` int(11) NOT NULL,
`MedalhaOuro` int(6) NOT NULL,
`MedalhaPrata` int(6) NOT NULL,
`MedalhaBronze` int(6) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
-- --------------------------------------------------------
--
-- Table structure for table `Endereco`
--
CREATE TABLE `Endereco` (
`Rua` varchar(50) NOT NULL,
`Numero` int(11) NOT NULL,
`Bairro` varchar(50) DEFAULT NULL,
`CEP` int(11) NOT NULL,
`Cidade` varchar(50) NOT NULL,
`Estado` varchar(50) NOT NULL,
`Complemento` varchar(50) DEFAULT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
--
-- Indexes for dumped tables
--
--
-- Indexes for table `Atletica`
--
ALTER TABLE `Atletica`
ADD PRIMARY KEY (`Universidade`,`Nome`),
ADD KEY `EnderecoCEP` (`EnderecoCEP`),
ADD KEY `EnderecoNumero` (`EnderecoNumero`);
--
-- Indexes for table `Endereco`
--
ALTER TABLE `Endereco`
ADD PRIMARY KEY (`Numero`,`CEP`);
And I keep getting the error:
Error creating foreign key on EnderecoCEP, EnderecoNumero (check data types)
when I try to execute the following command:
ALTER TABLE `Atletica`
ADD FOREIGN KEY (`EnderecoCEP`, `EnderecoNumero`)
REFERENCES `proj3`.`Endereco`(`CEP`, `Numero`)
ON DELETE RESTRICT ON UPDATE RESTRICT;
Ive read tons of similar questions here but all of them the error was an obvious data type mismatch. I only have those two table on my database. Please help.
Thank you very much for your time.
As it turns out, when you create a foreign key with multiple columns, it should be in the same order ar the primary key in the referencing table.
I am attempting to create a data model. It's fairly complicated, but I'm trying to link the Splits table to the Trials table. A screenshot of the model is below:
I'm attempting to make Splits.protocol + Splits.resultID + Splits.trialNumber a foreign key to Trials. Those three relations are the primary key of Trials. I'm doing this with MySQL Workbench and it throws an Error #150. Does anyone know what the problem is?
Here is the SQL statement and the error that it throws when attempting to execute it:
ERROR 1005: Can't create table '403898_BAMNormalized.#sql-7285_6c29081' (errno: 150)
SQL Statement:
ALTER TABLE `403898_BAMNormalized`.`Splits`
ADD CONSTRAINT `FK_FromTrial`
FOREIGN KEY (`protocol` , `resultID` , `trialNumber`)
REFERENCES `403898_BAMNormalized`.`Trials` (`protocol` , `resultID` , `trialNumber`)
ON DELETE NO ACTION
ON UPDATE NO ACTION
ERROR: Error when running failback script. Details follow.
ERROR 1050: Table 'Splits' already exists
SQL Statement:
CREATE TABLE `Splits` (
`protocol` varchar(255) NOT NULL,
`resultID` int(11) NOT NULL,
`trialNumber` int(11) NOT NULL,
`splitNumber` int(11) NOT NULL,
`splitScore` decimal(10,0) NOT NULL,
PRIMARY KEY (`protocol`,`resultID`,`trialNumber`,`splitNumber`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1
Here are the create table statements:
CREATE TABLE `Trials` (
`resultID` int(11) NOT NULL,
`protocol` varchar(255) NOT NULL,
`trialNumber` int(11) NOT NULL,
`trialScore` decimal(10,0) NOT NULL,
`best` char(1) DEFAULT NULL,
`DQFlag` varchar(45) DEFAULT NULL,
PRIMARY KEY (`resultID`,`protocol`,`trialNumber`),
CONSTRAINT `FK_trialID` FOREIGN KEY (`resultID`, `protocol`) REFERENCES `ResultsDetails` (`resultID`, `protocol`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
CREATE TABLE `Splits` (
`protocol` varchar(255) NOT NULL,
`resultID` int(11) NOT NULL,
`trialNumber` int(11) NOT NULL,
`splitNumber` int(11) NOT NULL,
`splitScore` decimal(10,0) NOT NULL,
PRIMARY KEY (`protocol`,`resultID`,`trialNumber`,`splitNumber`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
Indexes of Trials table:
Reordering the index to represent the same order as the foreign key was the solution. See comments appended to original post for detailed information.
So I have 2 tables.
subject_schedule:
CREATE TABLE IF NOT EXISTS `subject_schedule` (
`subject` varchar(10) NOT NULL,
`schedule_id` int(11) NOT NULL,
`id` int(11) NOT NULL,
PRIMARY KEY (`subject`,`schedule_id`),
KEY `schedule_id` (`schedule_id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
and appointment:
CREATE TABLE IF NOT EXISTS `appointment` (
`work_plan` varchar(1000) DEFAULT NULL,
`date` date DEFAULT NULL,
`homework_given` varchar(1000) DEFAULT NULL,
`tutor_comments` varchar(1000) DEFAULT NULL,
`admin_comments` varchar(1000) DEFAULT NULL,
`id` int(11) NOT NULL AUTO_INCREMENT,
`schedule_id` int(11) NOT NULL,
`attended` tinyint(1) NOT NULL DEFAULT '1',
`arrival_time` time DEFAULT NULL,
`departure_time` time DEFAULT NULL,
`homework_completed` tinyint(1) NOT NULL DEFAULT '0',
`subject` varchar(10) NOT NULL,
PRIMARY KEY (`id`),
KEY `schedule_id` (`schedule_id`),
KEY `subject` (`subject`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=10004 ;
I want to create a foreign key which references the composite key in appointment. I have tried:
ALTER TABLE 'appointment'
ADD CONSTRAINT 'appointment_fk' FOREIGN KEY (`schedule_id`, `subject`)
REFERENCES 'subject_schedule' ('schedule_id', 'subject');
but it returns an error in PhpMyAdmin:
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use
near ''appointment' ADD CONSTRAINT 'appointment_fk' FOREIGN KEY
(schedule_id, `su' at line 1
What am I doing wrong?
Is it better to just have an id as a primary key and reference that instead of using a composite key?
the columnNames shouldn't be wrap with single quotes because it will be converted to a string (not a column anymore)
ALTER TABLE appointment
ADD CONSTRAINT appointment_fk FOREIGN KEY (`schedule_id`, `subject`)
REFERENCES subject_schedule (schedule_id, subject);
SQLFiddle Demo