I want a query that would order them by this kind of results :
column = 1
column = 2
column = 1
column = 2
and repeat
you see what i mean is, i want it to list results of two values of the same column value by value
EDIT :
ill make it more simple, column name has two values to verify something of 1 and 0
i want to use php to sort them down eachother but 1 follows it 0 and again 1 follows it 0, keeps going on this
table has other info that i want to extract but sorted by how its written aboce ^
Here's my overly complicated code.
select bar
from (select bar, (#t := #t + 2) t
from foo, (select #t := 0) dummy
where bar = 1
union all
select bar, (#t2 := #t2 + 2) t
from foo, (select #t2 := 1) dummy
where bar = 2) temp
order by t;
Live demo: http://sqlfiddle.com/#!2/5d5f0/19
Try below code:
$sqlQuery1 = "SELECT distinct grade FROM loglists where
speciesNo='".$speciesData['speciesNo']."' and voyageNo='".$_REQUEST[voyageNo]."' order by
grade ASC, combinedgrade DESC";
I think this is the best solution for arrange order by multiple value.
select * from hotel where confId=13 group by hotelName ORDER BY CASE WHEN rating = '5 Star'
THEN 1
WHEN rating = '4 Star'
THEN 2
WHEN rating = '3 Star'
THEN 3
WHEN rating = 'BUDGET & EQUIVALENT HOTELS'
THEN 4
END
"select * from table order by field2,field3,field4";
the above sytnax is to order by multiple fields
use a foreach statement and check if its column1 and column 2 and display them
Related
i have a table named cq500_all(to record diffrent doctor feedback)
now i want know counts when condition status is
field dr_1_finish and field dr_2_finish value is all fill 1
and
when field dr_1 different dr_2 (like dr_1=1 and dr_2=0,or dr_1=0 and dr_2=1 )
cause i want to know two doctors feedback counts (when different doctor's feedback on jpg)
for example image show CQ500-CT-1_36_08.jpg and CQ500-CT-1_36_09.jpg is match my select counts
it will be two (select counts result)
how to make the query on mysql?
You can count as
select count(*) as total
from cq500_all
where dr_1_finish = 1 and dr_2_finish = 1 and dr_1 != dr_2
You will got result in total
Pretty much just the way you've described it:
select *
from cq500_all
where dr_1_finish = 1 and dr_2_finish = 1
and dr_1 != dr_2
or (if dr_1 or dr_2 might not be just 0 and 1):
select *
from cq500_all
where dr_1_finish = 1 and dr_2_finish = 1
and ((dr_1 = 1 and dr_2 = 0) or (dr_1 = 0 and dr_2 = 1))
Hi this maybe a simple one but I need help specifically for MYsql
I have the data in one column lets call the column WORK 1,2,3,5,2 (these values are sometimes longer and shorter or more values are present e.g 12,15,11,15,16,143)
I need these to be put into 1 new column for each delimiter and have an ID for the order presented. e.g output
SELECT
*
FROM (SELECT
ROW_NUMBER()
OVER (ORDER BY WORK) AS Row,
RIGHT(LEFT(T.WORK, Number - 1),
CHARINDEX(',', REVERSE(LEFT(',' + T.WORK, Number - 1)))) AS a
FROM master..spt_values,
<YOUR_TABLENAME> T
WHERE Type = 'P'
AND Number BETWEEN 1 AND LEN(T.WORK) + 1
AND (SUBSTRING(T.WORK, Number, 1) = ','
OR SUBSTRING(T.WORK, Number, 1) = '')) AS A
I am trying to get the max + 1 value from one column, and all of the values from another column. However, my query does not give any results.
For example,
SectionItemID SectionItem
1 blue
2 red
The query should return
SectionItemID SectionItem
3 blue
red
Heres what I have
SELECT SectionItem,MAX(SectionItemID) + 1 AS SectionItemID FROM Core.SectionItem_Lkup
SELECT SectionItem,
(select MAX(SectionItemID)+1 FROM Core.SectionItem_Lkup) AS SectionItemID
FROM Core.SectionItem_Lkup
Whenever you GROUP BY, you should aggregate the other columns involved.
Mysql does allow to omit aggregation on other colums
MsSQL does not, cause the result is undefined for columns without Aggregation.
Best way is to aggregate other columns. For your szenario, you could use group_concat
SELECT MAX(SectionItemID)+1, Group_concat(SectionItem) FROM tbl
Note: The query does not contain any Group By, because you dont want to group on SectionItemId nor SectionItem. Omiting the Group By and using aggregate-functions will use them on the whole table.
Output:
MAX(SECTIONITEMID)+1 GROUP_CONCAT(SECTIONITEM)
3 blue,red
http://sqlfiddle.com/#!2/353bf3/6
select case when t2.SectionItem = 'blue'
then cast(max(t1.SectionItemID) + 1 as varchar(1))
else '' end
as SectionItemID
, t2.SectionItem
from Core.SectionItem_Lkup t1
full outer join Core.SectionItem_Lkup t2 on 1 = 1
group by t2.SectionItem
order by
case when t2.SectionItem = 'blue'
then cast(max(t1.SectionItemID) + 1 as varchar(1))
else '' end
desc
I have a table with 5 fields. Each field can store a number from 1 - 59.
Similar to countif in Excel, how do I count the number of times a number from 1 - 59 shows up in all 5 fields?
Here's an example for the count of occurances for the number 1 in all five fields:
SELECT SUM(pick_1 = 1 OR pick_2 = 1 OR pick_3 = 1 OR pick_4 = 1 OR pick_5 = 1) AS total_count_1
FROM tbldraw
Hopefully I made sense.
There was an answer here that had a solution. I think this is just a variation.
Step1: Create a numbers table (1 field, called id, 59 records (values 1 -59))
Step2:
SELECT numbers_table.number as number
, COUNT(tbldraw.pk_record)
FROM numbers_table
LEFT JOIN tbldraw
ON numbers_table.number = tbldraw.pick_1
OR numbers_table.number = tbldraw.pick_2
OR numbers_table.number = tbldraw.pick_3
OR numbers_table.number = tbldraw.pick_4
OR numbers_table.number = tbldraw.pick_5
GROUP BY number
ORDER BY number
How about a two step process? Assuming a table called summary_table ( int id, int ttl), for each number you care about...
insert into summary_table values (1,
(select count(*)
from table
where field1 = 1 or field2 = 1 or field3 = 1 or field4 = 1 or field5 = 1))
do that 59 times, once for each value. You can use a loop in most cases. Then you can select from the summary_table
select *
from summary_table
order by id
That will do it. I leave the coversion of this SQL into a stored procedure for those that know what database is in use.
The ALL() function, which returns true if the preceding operator is true for all parameters, makes the query particularly elegant and succinct.
To find the count a particular number (eg 3):
select count(*)
from tbldraw
where 3 = all (pick_1, pick_2, pick_3, pick_4, pick_5)
To find the count of all such numbers:
select pick_1, count(*)
from tbldraw
where pick_1 = all (pick_2, pick_3, pick_4, pick_5)
group by pick_1
I am dealing with an issue and need some expert advice on to achieve the problem, my sql query generates output with two columns, 1st column displays id (for e.g. abc-123 in following table) and next column displays corresponding result to the id stored in db which is pass or fail.
I need to implement, when resolution is pass it should display success attempt, in following example, abc-123 failed 1st time however def-456 passed in next attempt thus success rate is 50%, now counter should reset and go to next row where there is pass thus it should show 100%, again when code hits pass counter resets then goes next and displays 33% bec there are two fail and one pass at the end, how it can be achieved in sql? (id and resolution are column names)
**date** **id resolution**
6/6/2012 abc-123 fail 50%
6/7/2012 abc-456 pass
6/8/2012 abc-789 pass 100%
6/9/2012 abc-799 fail 33%
6/10/2012 abc-800 fail
6/1/2012 abc-900 pass
Thanks
SELECT
*
FROM
table
INNER JOIN
(
SELECT
MIN(g.id) AS first_id,
MAX(g.id) AS last_id,
COUNT(*) AS group_size
FROM
table AS p
INNER JOIN
table AS g
ON g.id > COALESCE(
(SELECT MAX(id) FROM table WHERE id < p.id AND resolution = 'pass'),
''
)
AND g.id <= p.id
WHERE
p.resolution = 'pass'
GROUP BY
p.id
)
AS groups
ON table.id >= groups.first_id
AND table.id <= groups.last_id
There's more than one way to do it:
SELECT st.*,
#prev:=#counter + 1,
#counter:= CASE
WHEN st.resolution = 'pass'
THEN 0
ELSE #counter + 1
END c,
CASE WHEN #counter = 0
THEN CONCAT(FORMAT(100/#prev, 2), '%')
ELSE '-'
END res
FROM so_test st, (SELECT #counter:=0) sc
Here's proof of concept.