I am trying to fetch the top 3 scores of unique players in the last n months. While I try to execute the query I am getting an error:
Unknown column 'f.SC_Date' in 'where clause'
Below is my query
SELECT * from scores f
WHERE
SC_Id IN (
SELECT SC_Id FROM (
SELECT SC_Id from scores where DATE_FORMAT( SC_Date, "%Y%m" ) = DATE_FORMAT( f.SC_Date, "%Y%m" ) AND US_Id != 0 ORDER BY SC_Score DESC
LIMIT 3
) AS u )ORDER BY DATE_FORMAT( SC_Date, "%Y%m" ) DESC, SC_Score DESC
You can't use f.SC_Date in the inner query like that - remember the bit in brackets will be run first, and then the bit outside will be run on the result.
You'd need to declare scores f inside that select statement for this to work.
I expect you don't need it at all though - something like:
SELECT * from scores f
WHERE
SC_Id IN (
SELECT SC_Id FROM (
SELECT SC_Id from scores where DATE_FORMAT( SC_Date, "%Y%m" ) = DATE_FORMAT( SC_Date, "%Y%m" ) AND US_Id != 0 ORDER BY SC_Score DESC
LIMIT 3
) AS u )ORDER BY DATE_FORMAT( SC_Date, "%Y%m" ) DESC, SC_Score DESC
Should work, unless I'm mistaken as to your intentions here.
Related
SELECT * FROM (
SELECT * FROM cars WHERE site = '5'
ORDER BY cost DESC LIMIT 0 , 10
)
ORDER BY time
How would I execute a sql query like this? So first it selects the 10 cars with the highest cost, THEN it reorders those 10 cars by what time they were added to the DB.
I tried to figure it out but I just cannot get a grip on the syntax :P
Just give an alias to the sub-query.
SELECT * FROM (
SELECT * FROM `cars` WHERE `site` = '5'
ORDER BY `cost` DESC LIMIT 0 , 10
)t
ORDER BY `time`;
This query will give you the desired results
SELECT * FROM ( SELECT * FROM cars WHERE site = 5
ORDER BY cost DESC LIMIT 0 , 10 ) as t ORDER BY time
I would like to get values without the smallest and the biggest ones, so without entry with 2 and 29 in column NumberOfRepeating.
My query is:
SELECT Note, COUNT(*) as 'NumberOfRepeating'
WHERE COUNT(*) <> MAX(COUNT(*))AND COUNT(*) <> MIN(COUNT(*))
FROM Note GROUP BY Note;
SELECT Note, COUNT(*) as 'NumberOfRepeating'
FROM Notes
GROUP BY Note
HAVING count(*) <
(
SELECT max(t.maxi)
FROM (select
Note, COUNT(Note) maxi FROM Notes
GROUP BY Note
) as t
)
AND
count(*) >
(
SELECT min(t.min)
FROM (select
Note, COUNT(Note) min FROM Notes
GROUP BY Note
) as t
)
try this code.
One method would use order by and limit, twice:
select t.*
from (select t.*
from t
order by NumberOfRepeating asc
limit 99999999 offset 1
) t
order by NumberOfRepeating desc
limit 99999999 offset 1;
Try this code,
Select * from Note where NumberOfRepeating < (select MAX(NumberOfRepeating) from Note ) AND NumberOfRepeating > (select MIN(NumberOfRepeating) from Note );
Here in the code, as in your table Note is the name of the table, and NumberOfRepeating is the column name, as in your table.
Try this. It should work
SELECT *
FROM ( SELECT Note, COUNT(*) as 'NumberOfRepeating'
FROM Notes
GROUP BY Note
ORDER BY NumberOfRepeating DESC
LIMIT 1, 2147483647
) T1
ORDER BY T1.NumberOfRepeating
LIMIT 1, 2147483647
Ok, so I have the following query:
SELECT MIN(`date`), `player_name`
FROM `player_playtime`
GROUP BY `player_name`
I then need to use this result inside the following query:
SELECT DATE(`date`) , COUNT(DISTINCT `player_name`)
FROM `player_playtime /*Use previous query result here*/`
GROUP BY DATE( `date`) DESC LIMIT 60
How would I go about doing this?
You just need to write the first query as a subquery (derived table), inside parentheses, pick an alias for it (t below) and alias the columns as well.
The DISTINCT can also be safely removed as the internal GROUP BY makes it redundant:
SELECT DATE(`date`) AS `date` , COUNT(`player_name`) AS `player_count`
FROM (
SELECT MIN(`date`) AS `date`, `player_name`
FROM `player_playtime`
GROUP BY `player_name`
) AS t
GROUP BY DATE( `date`) DESC LIMIT 60 ;
Since the COUNT is now obvious that is only counting rows of the derived table, you can replace it with COUNT(*) and further simplify the query:
SELECT t.date , COUNT(*) AS player_count
FROM (
SELECT DATE(MIN(`date`)) AS date
FROM player_playtime
GROUP BY player_name
) AS t
GROUP BY t.date DESC LIMIT 60 ;
I have the following query which queries a table of sports results for the last 20 matches that involved a teams, returning goals conceeded in each of these matches.
SELECT *, `against` AS `goalsF` , `for` AS `goalsA`
FROM `matches` , `teams` , `outcomes`
WHERE (
`home_team_id`=7 AND `matches`.away_team_id = `teams`.team_id
OR
`away_team_id`=7 AND `matches`.home_team_id = `teams`.team_id
)
AND `matches`.score_id = `outcomes`.outcome_id
ORDER BY `against', `date` DESC
LIMIT 0 , 20
I want sort the results by goals conceeded and then within each group of goals conceeded by date so for example.
the first 4 results where goals conceded=1 in date order
then the next 3 might be results where conceded=2 in date order
I have tried ORDER by date,against - this gives me a strict date order
I have tried ORDER by against,date - this gives me matches beyond the last 20
Is it possible to do what I want to do?
Thanks everyone, I found this worked. This solution was posted by another user but then was removed, not sure why?
SELECT * FROM (
SELECT *, `against` AS `goalsF` , `for` AS `goalsA`
FROM `matches` , `teams` , `outcomes`
WHERE (
`home_team_id`=7 AND `matches`.away_team_id = `teams`.team_id
OR
`away_team_id`=7 AND `matches`.home_team_id = `teams`.team_id
)
AND `matches`.score_id = `outcomes`.outcome_id
ORDER by `goalsF`
LIMIT 0 , 20
) res
ORDER BY `date` DESC
If you want to limit by date, add the date range you are looking for into your WHERE clause and then order by the number of goals conceded.
Im trying to calculate the amount of money won by all the offspring of a male race horse (Sire) over a time period. Listed by the Sire with the most amount of money won.
I run the query and get the result Im after with one problem, I cant display the sires name, only their ID.
SELECT `horses`.`SireID` AS `SireID` , `horses`.`HorseName` AS `Sire Name`,
COUNT( `runs`.`HorsesID` ) AS `Runs` ,
COUNT(
CASE WHEN `runs`.`Finish` =1
THEN 1
ELSE NULL
END ) AS `Wins` ,
CONCAT( FORMAT( (
COUNT(
CASE WHEN `runs`.`Finish` =1
THEN 1
ELSE NULL
END ) / COUNT
( `runs`.`TrainersID` ) ) *100, 0 ) , '%'
) AS `Percent` ,
FORMAT( SUM( `runs`.`StakeWon` ) , 0 ) AS `Stakes`
FROM runs
INNER JOIN horses ON runs.HorsesID = horses.HorsesID
INNER JOIN races ON runs.RacesID = races.RacesID
WHERE `races`.`RaceDate` >= STR_TO_DATE( '2012,07,01', '%Y,%m,%d' )
AND `races`.`RaceDate` < STR_TO_DATE( '2012,07,01', '%Y,%m,%d' ) + INTERVAL 1
MONTH
AND `horses`.`SireID` <> `horses`.`HorsesID`
GROUP BY `horses`.`SireID`, `horses`.`HorseName`
ORDER BY SUM( `runs`.`StakeWon` ) DESC
Take a record in the horse table for example, a horse has a horsesID and they also have a sireID (their father). The sireID has an equivalent horsesID in another record in the same table as it is also a horse
Basically I need to map the horseName to the sireID.
I thought a self join would work.
`AND `horses`.`SireID` <> `horses`.`HorsesID``
but it doesn't return the correct Sire name corresponding to the SireID.
You can do a JOIN on the table itself. Here's a simpler example:
SELECT Horses.HorseID, Horses.HorseName, Horses.SireID, b.HorseName as SireName
FROM Horses
LEFT JOIN Horses b ON (Horses.SireID = b.HorseID)
You can probably figure out how to add the conditions from here.
join horses sires on sires.HorsesID = horses.SireID