I have complicated query over very big table.
Long story short, when I use convert time to select period of day (let's say 12-13h, converting it from datetime row) query takes few minutes, instead of few seconds without convert!
So, I tried datepart, and it works well, almost instant, but, problem is, how to point to hours and minutes in same time?
Any other fast solution is more than welcome.
Thanks.
Meanwhile I came up with this:
DATEPART(HOUR, datetimecolumn)*100 + DATEPART(MINUTE, datetimecolumn)) between 1210 and 1540
You can use datePart if you are willing to do a bit of math, as shown below:
12:10 = 12 * 60 + 10 = 730 minutes
15:40 = 15 * 60 + 40 = 940 minutes
select * .....
where datepart(mi, datefield) between (12*60+10) and (15*60+40)
If you have a constant periods - i.e. - always hourly and no any floating periods - you may introduce something like "ordinal number of period" calculated field, index on it and query of it with precalculated period value
OR
is there are no any constant periods - try to calculate proper begin and end values prior to SELECT statement and use them in the query.
Keep in mind that using functions in where clause of query - sometimes is a bad idea. Using functions in ORDER BY clause - always bad
You can get GETTIME from following Function
alter function GetTimeOnly(#_DateTime DateTime)
returns datetime
as
begin
return dateadd(day, -datediff(day, 0, #_datetime), #_datetime)
end
go
OR YOU CAN HAVE THE TIME FROM CONVERT FUNCTION.
SELECT
CONVERT(VARCHAR(8),GETDATE(),108) AS HourMinuteSecond,
CONVERT(VARCHAR(8),GETDATE(),101) AS DateOnly
Related
I have take time (datatype) in mysql. In this column I want to use as a minutes. How to solve
when I use as a minutes(etr) then only take minutes value. I want to take minutes and hours both in one function
etr
01:00:00
00:30:00
00:15:00
I want to use minutes(etr) because this column subtract from another column.
The simplest method is probably time_to_sec():
select floor(time_to_sec(etr) / 60) as minutes
To be honest, it is not much more complicated to do:
select hour(etr) * 60 + minute(etr)
You can use hour() and minute() function
select hour(etr)*60 + minute(etr) from your_table
I'm new for mysql, Already value in time field, I want to update extra 5 minutes in time field using query. I tried so many things but not working.
Here my query:
UPDATE STUDENT SET START_TIME = ADDTIME(START_TIME, 500) WHERE ID = 1;
Above query working but one issue is there that is, If my field having 23:55:00.
I want result after executing query 00:00:00 but it updates 24:00:00.
Anyone help me!
Thanks in advance!!
This is bit tricky, because you only have the time, and you want it to wrap around to 0 after hitting 24 hours. My approach is to extract the number of seconds from START_DATE, add 5 minutes, then take the mod of this by 24 hours to wrap around to zero if it exceeds one day's worth of seconds.
UPDATE STUDENT
SET START_TIME = CAST(STR_TO_DATE(CAST(MOD((TIME_TO_SEC(START_TIME) + 300), 86400) AS CHAR(5)), '%s') AS TIME)
WHERE ID = 1
In the demo below, you can see the logic in action which correctly converts 23:55:00 with five minutes added to become 00:00:00.
SQLFiddle
However, the easiest solution in your case might be to just use a DATETIME and ignore the date component. Then the time should wrap automatically to a new day.
select addtime('23:55:00', '00:06:00');
output - 24:01:00 (Ideally it is right, because time datatype represents only time, if it converts to 00:01:00 then time component looses 24hr, which is wrong)
select addtime('2016-09-01 23:55:00', '00:06:00');
output - 2016-09-02 00:01:00 (In this case, 24hr gets added in date so time component is represented as 00:01:00)
If the requirement is to get it as 00:01:00 then here is the workaround -
SELECT TIME((ADDTIME(TIME('23:59:59'), TIME('02:00:00')))%(TIME('24:00:00')));
reference -
ADDTIME() return 24 hour time
I am looking for a way to be able to grab rows from a database from a time.
Two columns exist:
Time - scheduled Time
Delay - +seconds that time is delayed.
Let's say:
ID,time,delay
1,18:23,360
2,18:25,0
3,17:15,-60
Now, let's say I am searching for buses after actually arriving at/after 18:25, how would i do it to include these two results:
2,18:25,0
1,18:23,360 (note: 18:23 + 360 seconds = 18:29)
in a query like
where `time` >= '18:23'
Thanks
SELECT * FROM [TABLE] WHERE DATE_ADD(Time,INTERVAL TimeDelay SECOND) >= '18:25:00'
MySql Date_Add Function
I have a table.
And it has two fields id and datetime.
What I need to do is, for any two given datetimes, I need to divide the time range into 10 equal intervals and give row count of each interval.
Please let me know whether this is possible without using any external support from languages like java or php.
select ((UNIX_TIMESTAMP(date_col) / CAST((time2 - time1)/10) AS INT) + time1), count(id) from my_table where date_col >= time1 AND date_col <= time2 GROUP BY ((UNIX_TIMESTAMP(date_col) / CAST((time2 - time1)/10) AS INT) + time1)
I haven't tested it. But something like this should work.
The easiest way to divide date intervals is if you store them as longs (ie #of ticks from the "beginning of time"). As far as I know, there is no way to do it using MySQL's datetime.
How you decide to do it ultimately depends on your application. I would store them as longs and have whatever front end you are using handle to conversion to a more readable format.
What exactly do you mean by giving the row count of each interval? That part doesn't make sense to me.
In MySQL I can create a table with a time field, and the value can be as high as 838:59:59 (839 hours - 1 second). I just read that in PostgreSQL, the hour field cannot exceed 23:00:00 (24 hours). Is there a way around this? I'm trying to make a simple DB that keeps track of how many hours & minutes were spent doing something, so it'll need to go higher than 23 hours & some minutes. I can do this in MySQL, but I need to use PostgreSQL for this. I Googled, but didn't find what I'm looking for, so I'm hoping I just didn't use the right keywords.
Postgres has no "hour field" - it has a few date/time types which serve different needs. The type I believe best fits your needs is INTERVAL.
Although they use the same notation, there's a difference between time of day and elapsed time. Some of their values overlap, but they're different domains. 838 isn't a valid value for an hour if you're talking about a time of day. 838 is a valid value for an hour if you're talking about elapsed time.
This distinction leads to two different data types: timestamp and interval.
create table intervals (
ts timestamp primary key,
ti interval not null
);
insert into intervals values (current_timestamp, '145:23:12');
select *
from intervals;
2011-08-03 21:51:16.837 145:23:12
select extract(hour from ti)
from intervals
145
I believe you are right, but It should not be an issue to work around. Would suggest storing the UNIX time integers for when you "punch in" and out again, and then adding the delta to an int field.
This will yield the number of seconds spent, which can be translated trivially into an hours:minutes:seconds format.
The delta (difference) can be calculated by subtracting the start timestamp from the end timestamp.
you could use a datetime field... 839 hours being something on the order 34.9 days...