I would like to use iMacros to check a html site if it contains certain numbers. if it does, then I would like to assign a variable according to a number that has been found.
Like if the html contains 112233 then I woul like to assing Var1 to be 123
if the html contains 223344 then I want Var1 to be 645
What would be the way to do this?
Thanks!
Wow! That is a typical case for iMacros EVAL!
Extract the element's text with TAG and assign the value to !VAR1, using EVAL for the conditional.
If the text is not inside an html element (it could be in a comment, for instance) and so, not reachable by the TAG command, sou can try with SEARCH, which does offer some regular expression facility as well.
Related
I have a bunch of records in a QuickBase table that contain a rich text field. In other words, they each contain some paragraphs of text intermingled with HTML tags like <p>, <strong>, etc.
I need to migrate the records to a new table where the corresponding field is a plain text field. For this, I would like to strip out all HTML tags and leave only the text in the field values.
For example, from the below input, I would expect to extract just a small example link to a webpage:
<p>just a small <a href="#">
example</a> link</p><p>to a webpage</p>
As I am trying to get this done quickly and without coding or using an external tool, I am constrained to using Quickbase Pipelines' Text channel tool. The way it works is that I define a regex pattern and it outputs only the bits that match the pattern.
So far I've been able to come up with this regular expression (Python-flavored as QB's backend is written in Python) that correctly does the exact opposite of what I need. I.e. it matches only the HTML tags:
/(<[^>]*>)/
In a sense, I need the negative image of this expression but have not be able to build it myself.
Your help in "negating" the above expression is most appreciated.
Assuming there are no < or > elsewhere or entity-encoded, an idea using a lookbehind.
(?:(?<=>)|^)[^<]+
See this demo at regex101
(?:(?<=>)|^) is an alternation between either ^ start of the string or looking behind for any >. From there [^<]+ matches one or more characters that are not < (negated character class).
Using regular expressions, I need to extract a multiline content of a tag, which has specific id value. How can I do this?
This is what I currently have:
<div(.|\n)*?id="${value}"(.|\n)*?>(.|\n)*?<\/div>
The problem with this is this sample:
<div id="1">test</div><div id="2">test</div>
If I want to replace id="2" using this regexp (with ${value} = 2), the whole string would get matched. This is because from the tag opening to closing I match everything until id is found, which is wrong.
How can I do this?
A fairly simple way is to use
Raw: <div(?=\s)[^>]*?\sid="2"[^>]*?>([\S\s]*?)</div>
Delimited: /<div(?=\s)[^>]*?\sid="2"[^>]*?>([\S\s]*?)<\/div>/
Use the variable in place of 2.
The content will be in group 1.
Change (.|\n) to [^>] so it won't match the > that ends the tag. Then it can't match across different divs.
<div\b[^>]*\bid="${value}"[^>]*>.*?<\/div>
Also, instead of using (.|\n)* to match across multiple lines, use the s modifier to the regexp. This makes . match any character, including newlines.
However, using regular expressions to parse HTML is not very robust. You should use a DOM parser.
I have an XPath
//*[#class]
I would like to make an XPath to select the content inside this attribute.
<li class="tab-off" id="navList0">
So in this case I would like to extract the text "tab-off", is this possible with XPath?
Your original //*[#class] XPath query returns all elements which have a class attribute. What you want is //*[#class]/#class to retrieve the attribute itself.
In case you just want the value and not the attribute name try string(//*[#class]/#class) instead.
If you are specifically grabbing the data from an tag, you can do this:
//li[#class]
and loop through the result set to find a class with attribute "tab-off". Or
//li[#class='tab-off']
If you're in a position to hard code.
I assume you have already put your file through an XML parser like a DOMParser. This will make it much easier to extract any other values you may need on a specific tag.
I want to replace <whatever>Some Title</whatever> with <something>Some Title</something> using the Find and Replace tool inside of Dreamweaver. How do I perform?
Not a Dreamweaver user, but this simple approach works in my editor (Emacs):
Replace:
<whatever>\(.*\)</whatever>
With:
<something>\1</something>
This is a pretty straightforward approach but it may fall short of your needs. Do some or all of your <whatever> element pairs occupy more than one line of text? Or do you have more than one <whatever> pair on a single line?
i guess what you want is to change all your <whatever> tag with an <something> tag whitout changing your text, right?
If it is so, you want to use find and replace with regular expression. Find (in source code) <whatever>(.*)</whatever> and replace it with <something>$1</something>. The $1 is used as a variable for anything fits the (.*) part DW finds for each instance.
For example, you you want to comment all instances of an
document.NAMEOFANYFORMONTHEPAGE.WHATEVERNAME.focus();
in a JavaScript file, you would use find:
document\.(.*)\.focus\(\);
and replace it with:
// document.$1.focus();
Don't forget to escape special characters and, please, try a few instances before using Replace All
I'm using TextMate to edit a project that I'm doing(HTML files) and I have some <div> tags assigned with the class=navigation property, but I need to change this <div>'s for a new design that I'm planning, but they are much(about 47 results if I search for class=navigation).
So I need a regular expression to match the entire line that this property is found, but which is it?
I'm not a regex expert, but I would think that ^.*class=navigation.*$ would work.