Let's assume that I have OuterDiv of unknown size and InnerDiv 10px x 10px within the OuterDiv. What I want to achieve is absolute positioning of InnerDiv within OuterDiv (the easy part), so that position (0,0) means top left corner of OuterDiv and (the hard part) position (-5, 0) means that only right half of InnerDiv is visible (the overflowed part is hidden). Any ideas?
You have to use the overflow: hidden css attribute.
Is the following piece of code working for you?
<div id="outer" style="position: relative; overflow: hidden;">
<div id="inner" style="height: 10px; width: 10px; display: block; position: absolute; top: 0; left: -5px; background: #f00;">
</div>
</div>
You simply need to apply overflow: hidden on the outer element and position the inner element with left: -5px like so:
#outer {
height: 200px; /* Must give explicit height since contents are absolute */
position: relative;
overflow: hidden;
}
#inner {
height: 10px;
width: 10px;
position: absolute;
top: 0;
left: -5px;
}
Here's a gist of a working example.
Related
I have 3 divs on top of each other having following css.
.d1 {
position: relative;
background-color: yellow;
height: 50px;
width: 100px;
overflow: hidden;
}
.d2 {
position: absolute;
background-color: green;
height: 25px;
width: 50px;
}
.d3 {
position: absolute;
left: 83px;
}
and the divs that have classes are as follows:
<div class="d1">
<div class="d2">
<div class="d3">text</div>
</div>
</div>
and as a result I see content of d3 cut off because of overflow:hidden in d1.
How can I avoid cut off content of d3 without modifying d1?
Getting around the overflow..
An element can overflow from a relative or absolute positioned parent by setting its position to fixed. An element that has position: fixed will have the default left,right,top, and bottom styles set as auto. This will position .d3 to the top-left of .d2, and then the left: 83px style will push it to the left from there.
Making up the additional space..
However, to get that additional movement to the right as the original markup, you will need to add margin-left: 8px, which will make-up the additional ~8px needed to replicate the original. Further adjustments to the position of .d3 will need to be done by setting the margin style (see below).
Your updated code should look like this..
.d1 {
position: relative;
background-color: yellow;
height: 50px;
width: 100px;
overflow: hidden;
}
.d2 {
position: absolute;
background-color: green;
height: 25px;
width: 50px;
}
.d3 {
position: fixed;
margin-left: 8px;
left: 83px;
}
Some considerations and caveats..
As a previous commenter mentioned, best practice would be to fix your html markup because this solution could cause issues if you ever need to move the position of .d3. For example, setting left,right,top, or bottom will cause the default setting of this style, auto, from being unset, and the element will be positioned relative to the viewport rather than the parent relative or absolute element.
Here is the HTML I am working with.
<div id="outer" style="min-width: 2000px; min-height: 1000px; background: #3e3e3e;">
<div id="inner" style="left: 1%; top: 45px; width: 50%; height: auto; position: absolute; z-index: 1;">
<div style="background: #efffef; position: absolute; height: 400px; right: 0px; left: 0px;"></div>
</div>
</div>
What I would like to happen is for the inner div to occupy 50% of the space given to its parent div(outer). Instead, is is getting 50% of the space available to the viewport, which means that as the browser/viewport shrinks in size, so does it.
Given that the outer div has min-width of 2000px, I would expect the inner div to be at least 1000px wide.
Specifying a non-static position, e.g., position: absolute/relative on a node means that it will be used as the reference for absolutely positioned elements within it http://jsfiddle.net/E5eEk/1/
See https://developer.mozilla.org/en-US/docs/Learn/CSS/CSS_layout/Positioning#Positioning_contexts
We can change the positioning context — which element the absolutely positioned element is positioned relative to. This is done by setting positioning on one of the element's ancestors.
#outer {
min-width: 2000px;
min-height: 1000px;
background: #3e3e3e;
position:relative
}
#inner {
left: 1%;
top: 45px;
width: 50%;
height: auto;
position: absolute;
z-index: 1;
}
#inner-inner {
background: #efffef;
position: absolute;
height: 400px;
right: 0px;
left: 0px;
}
<div id="outer">
<div id="inner">
<div id="inner-inner"></div>
</div>
</div>
Use position: relative on the parent element.
Also note that had you not added any position attributes to any of the divs you wouldn't have seen this behavior. Juan explains further.
it's a known 'bug' that elements with fixed position loose their position if the container is translated. For example, if i've got a structure like this:
<div class="container">
<div class="fixed"></div>
</div>
and, say, the container is scrolled, when the conteiner gets transformed (say, translate(x,y), rotate(), or so..), then the fixed element behaves like it was positioned relative and it scrolls with the container. I can see it on the latest firefox, for example.
How can one fix this kind of problem? Is there any way?
This behaviour is not a bug. It's actually the specs recommended behaviour.
(See this post by Eric Meyer, or this question here on SO which accepted solution only provides a link to the same meyer's post)
For those who don't know this issue, and because you didn't provide a snippet into your question, here's one.
document.addEventListener('click', function() {
document.getElementById('container').classList.toggle('transformed')
}, false);
#bg {
border: 1px solid #AFA;
height: 100%;
width: 100%;
position: fixed;
top: 0;
left: 0;
}
#container {
border: 1px solid #FAF;
height: 50%;
width: 75%;
position: relative;
margin: 0 auto;
overflow: auto;
}
#content {
background: rgba(125, 175, 0, .7);
position: fixed;
width: 100%;
top: 0;
left: 0;
}
.transformed {
transform: translate(0, 5em);
}
<div id="bg">
<div id="container" class="transformed">
.<br>.<br>.<br>.<br>.<br>.<br>.
this is a scrollable paragraph
<br>.<br>the "fixed" content does scroll with the paragraph
<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.
you can click to toggle the transformation On/Off
<br>.<br>.<br>.<br>.<br>.
<span id="content">relatively fixed content</span>
</div>
</div>
However, I did find something that may help others facing the same issue.
It's not really a solution, since the "fixed" element will be only inside the container, (except for IE browsers where it will really be fixed to the document). But in my case, it's actually what I wanted and maybe it'll be fine for others too.
If you add a wrapper, set its height:100%; width:100%; and overflow:auto, then your "fixed" content won't scroll with the container.
Actually it's not you container which scrolls anymore, but the wrapper. So you might want to set the container's overflow:visible or hidden to avoid unwanted scrolling of the not so well "fixed" element.
Also, note that you need your wrapper be a block or inline-block element.
#bg {
border: 1px solid #AFA;
height: 100%;
width: 100%;
position: fixed;
top: 0;
left: 0;
}
#container {
border: 1px solid #FAF;
height: 50%;
width: 75%;
position: relative;
margin: 0 auto;
overflow: visible;
}
#wrapper {
height: 100%;
width: 100%;
overflow: auto;
}
#content {
background: rgba(125, 175, 0, .7);
position: fixed;
width: 100%;
top: 0;
left: 0;
}
.transformed {
transform: translate(0, 50%);
}
<div id="bg">
<div id="container" class="transformed">
<div id="wrapper">
.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.<br>.
<span id="content">relatively fixed content</span>
</div>
</div>
</div>
I am not familiar with this bug, but when you use positioned: fixed; the element is positioned relative to the browser window, so it doesn't really make any sense to put it inside a container.
This markup would be my recommendation:
<div class="fixed"></div>
<div class="container"></div>
Once you use position: fixed; on any element it is positioned relative to the view-port. Directly from page in MDN about position property.
fixed
Do not leave space for the element. Instead, position it at a specified position relative to the screen's viewport and don't move it when scrolled.
So what you are experiencing is a what it is actually supposed to work like and not a 'bug'.
Now if what you want is something that is positioned with relation to the .container div and translate with it than you will have to use absolute positioning here. Take a look at this fiddle. The important CSS is-
.container {
width: 200px;
height: 100px;
position: relative;
}
.absolute {
position: absolute;
width: 20px;
height: 10px;
top: 50px;
left: 50px;
}
Notice that with positioning the inner div as absolute I have also positioned the outer div as relative as the inner div takes its position in reference to the closest parent div positioned as anything different from static.
let's say I have to place an image RIGHT in a proper spot, but I need its CENTER to be in that spot. I wanted to place an image in the top-left corner of a div, so I placed the image in the div, gave position: relative to the div and position: absolute to the image then set its top and left values to 0. It quite worked but I'd need the CENTER of that image to be right over the top left corner. I'd do it manually setting top: -xpx, left: -ypx BUT I don't have any specific value for the image size (which could vary a lot).
So is there any way to say something like: position: absolute-but-i'm-talking-about-the-center; top: 0px; left: 0px;?
Thank you very much indeed!
Matteo
You could use javascript yo get the size of the image and then set the css left value needed.
Be mindful of the way images are loaded though as they are asynchronous so will not necesserily be available when the document is ready. This means that unless you handle the images correctly you will end up with width and height dimensions of 0.
You should wrap the image in another block element and put a negative left position to the image.
Something like this:
<div id="something">
<div class="imagewrap">
<img>
</div>
</div>
Then give #something a relative position, .imagewrap an absolute, etc... And img should have a relative position with left:-50%. Same for the top.
have you tried;
name_of_div_with_image {
display: block;
margin-left: auto;
margin-right: auto }
give that a go.
No need to use Javascript, this can be done in CSS.
The required HTML: (you must change the div to an img obviously)
<div id="container">
<div id="imgwrapper">
<div id="img">Change this div-tag to an img-tag</div>
</div>
</div>
The required CSS:
#container
{
position: absolute;
left: 200px;
top: 100px;
height: auto;
overflow: visible;
border: 2px dashed green;
}
#imgwrapper
{
position: relative;
margin-left: -50%;
margin-top: -50%;
padding-top: 25%;
border: 2px dashed blue;
}
#img
{
display: block;
width: 200px;
height: 100px;
border: 2px solid red;
}
Click here for a jsFiddle link
The margin-left: 50%; obviously works when using the container div, because the width of the container will be exactly that of the content. (You might need to add width: auto;)
But margin-top: -50%; will not work because the height of the container div will change with it, thus you need yet another wrapper div in which you use this margin-top: -50%; and then you need to fix this error it makes by using a positive percentage based padding. Obviously there may be other solutions to fix this, but the solution should be something like this.
Probably one of the simplest solutions is to place the image in the upper left corner at position
left: 0px; top: 0px; and then use translate to move its center to this position. Here's a working snippet for that:
#theDiv {
position: absolute;
left: 100px;
top: 100px;
background: yellow;
width: 200px;
height: 200px;
}
#theImage {
background: green;
position: absolute;
left: 0px;
top: 0px;
transform: translate(-50%, -50%);
}
<div id="theDiv">
<image width=31.41 height=41.31 id="theImage"></image>
</div>
Here is the HTML I am working with.
<div id="outer" style="min-width: 2000px; min-height: 1000px; background: #3e3e3e;">
<div id="inner" style="left: 1%; top: 45px; width: 50%; height: auto; position: absolute; z-index: 1;">
<div style="background: #efffef; position: absolute; height: 400px; right: 0px; left: 0px;"></div>
</div>
</div>
What I would like to happen is for the inner div to occupy 50% of the space given to its parent div(outer). Instead, is is getting 50% of the space available to the viewport, which means that as the browser/viewport shrinks in size, so does it.
Given that the outer div has min-width of 2000px, I would expect the inner div to be at least 1000px wide.
Specifying a non-static position, e.g., position: absolute/relative on a node means that it will be used as the reference for absolutely positioned elements within it http://jsfiddle.net/E5eEk/1/
See https://developer.mozilla.org/en-US/docs/Learn/CSS/CSS_layout/Positioning#Positioning_contexts
We can change the positioning context — which element the absolutely positioned element is positioned relative to. This is done by setting positioning on one of the element's ancestors.
#outer {
min-width: 2000px;
min-height: 1000px;
background: #3e3e3e;
position:relative
}
#inner {
left: 1%;
top: 45px;
width: 50%;
height: auto;
position: absolute;
z-index: 1;
}
#inner-inner {
background: #efffef;
position: absolute;
height: 400px;
right: 0px;
left: 0px;
}
<div id="outer">
<div id="inner">
<div id="inner-inner"></div>
</div>
</div>
Use position: relative on the parent element.
Also note that had you not added any position attributes to any of the divs you wouldn't have seen this behavior. Juan explains further.