I need a PHP regular expression that will compare stings similar to mysql Match Against behaviour.
e.g:
string = "findmatches";
$pattern = 'fildcatches';
this pattern is supposed to match the string
Thanks a lot
Regular expression may not be the best solution for your needs, try instead the PHP construct similar_text() :
http://php.net/manual/en/function.similar-text.php
The function returns the similarity between two strings in percentage and the number of matching chars.
Related
I try get name of city's from string '{"travelzoo_hotel_name":"Graduate Minneapolis","travelzoo_hotel_id":"223","city":"Minneapolis","country":"USA","sales_manager":"Stephen Conti"}'
I try this regexp:
SELECT REGEXP_SUBSTR('{\"travelzoo_hotel_name\":\"Graduate Minneapolis\",\"travelzoo_hotel_id\":\"223\",\"city\":\"Minneapolis\",\"country\":\"USA\",\"sales_manager\":\"Stephen Conti\"}'
,'(?:.city...)([[:alnum:]]+)');
I have: '"city":"Minneapolis'
Me need only name of city:Minneapolis.
How to use groups in queries?
My example in regex101
Help me Please
I assume you are using MySQL 8.x that uses ICU regex expressions.
It looks like the string you want to process is JSON. You may use JSON_EXTRACT with JSON_UNQUOTE and a '$.city' as JSON path then:
JSON_UNQUOTE(JSON_EXTRACT('{"travelzoo_hotel_name":"Graduate Minneapolis","travelzoo_hotel_id":"223","city":"Minneapolis","country":"USA","sales_manager":"Stephen Conti"}', '$.city'))
will return Minneapolis.
In your regex, the non-capturing group pattern is still matched and appended to the match value. "Non-capturing" only means no separate memory buffer is alotted to the text captured with a grouping construct. So, you may fix it with '(?<="city":")[^"]+' pattern where (?<="city":") is a positive lookbehind that matches "city":" but does not put it into the match value. The only text you will have in the output is the one matched with [^"]+, 1+ chars other than ".
I have to find how many numbers in the following String,
'~1~~2~~123~~~~12~~1~~~~' and the output should be 5.
Any help?
MySQL cannot do that directly. You would have to dig into UDF (User defined functions). It would allow you to create a function that returns the number of number substrings in a string.
Regular expression need pattern to match and there no pattern to use regular expression in provided example. You can go here to see regular expression in mysql.
One column returns such values:
Something";s:5:"value";s:3:"900";s:11:"print_
I want to extract all numbers that are at least 3 digits long, in the above case thats 900. How can I do that in MySQL? Maybe using a regex? I cant use any index, the length of the string and the number in the string can be different.
Thanks!
Try unserialize() it if you are using PHP! And then var_dump it to see the strings and arrays
You can't extract them using MySQL, use any other language for that.
What you can do is include a Where Clause, that will make the work easier for your script.
Assuming your column is called "serialized" in the table "example"
SELECT serialized FROM example WHERE serialized REGEXP '[0-9]{3,}'
Please note that REGEXP is just outputting 1 or 0
After you did the query, use the regex functions of your language do extract the numbers like so:
([0-9]{3,})*
My database contains a string pattern that is used to allow for easy user editing via a JS-script.
The string is basicly formatted like so:
aaa[bbb#ccc]ddd[eee#fff]ggg
the result I am looking for is
aaacccdddfffggg
I'd like to do this when selecting the string from the database. I'm guessing a regex should do the trick. But my knowledge in the subject of regex's is rather limited. However, this is not a requirement, if there exist a more elegant solution to the problem.
Unfortunately, you can only use a MySQL REGEXP in a WHERE clause, to match against values. You can't use them to transform Strings.
You'll either need to do it clientside, or work with the other String Functions. A MID() would do the trick, if the lengths and positions of the substrings are fixed. If not, use POSITION() (or LOCATE()) to find the special characters []#.
Is it possible to get the (first?) match of a regex and output it within a select? It looks like the REGEXP function only return whether there has been a match or not. I want to be able to extract information out of a varchar column without having to use complex SUBSTRING-LOCATION nestings.
Any ideas?
http://dev.mysql.com/doc/refman/5.1/en/regexp.html that's all there is. You can't do more than pattern comparison.