I have a table within mysql with orders stored in it. I have figured out how to pull everything I need with my SELECT statment. However, I was wondering, does anyone know how to grab orders only from today or even for the week using mysql? The table does contain an "order_date" field which is populated.
You can use this:
... WHERE order_date = CURDATE(); // today
... WHERE order_date BETWEEN CURDATE() - INTERVAL 7 DAY AND CURDATE(); // in the week
Generally speaking (not knowing your schema):
SELECT * FROM orders WHERE order_date >= $start_date AND order_date <= $end_date
You need to define $start_date and $end_date
SELECT * FROM `orders` WHERE DATE(`order_date`) = DATE(NOW())
If the order_date is in datetime
EDIT
For a week
SELECT * FROM `orders` WHERE DATE(`order_date`) >= DATE_SUB(DATE(NOW()),INTERVAL 7 DAY)
Related
I am trying to figure out how to select results based on the current date. The script will be ran daily but I am unsure of how to do it automatically.
SELECT * FROM Orders WHERE OrderDate='2008-11-11'
What I am trying now
SELECT * FROM Orders WHERE OrderDate=NOW() - INTERVAL 1 DAY
SELECT *
FROM Orders
WHERE OrderDate >= DATE(NOW())
AND OrderDate < DATE(NOW()) + INTERVAL 1 DAY
EDIT
I always tend to write the above style of query when I expect the column that I am checking against to have a time component as well.
If your OrderDate column does not have a time component, then as Lennart pointed out, you can simply do:
SELECT *
FROM Orders
WHERE OrderDate = DATE(NOW())
EDIT 2: Mihai's comment on your question is also relevant. You can simply use CURDATE() instead of DATE(NOW()).
You could do
SELECT * FROM Orders WHERE (OrderDate > DATE_SUB(NOW(),INTERVAL 1 DAY))
What is the proper way to query all data on current date? a function in mysql that will get the current date in 12:01 am and current date 11:59 pm
select * from tb_data where date between currentdate_starts and currentdate_ends
Without using DATE(column) = CURDATE()
SELECT * FROM tb_data WHERE date between concat(curdate(),' ','00:00:00') AND concat(curdate(),' ','23:59:59')
more info
Try using CURDATE()
SELECT field FROM table WHERE DATE(column) = CURDATE()
select * from tb_data where DATE(date) = CURDATE()
Documentation: CURDATE
CURDATE() returns the current date.
SELECT * from FROM tb_data WHERE DATE(column) = CURDATE()
Use CURRENT_DATE() or CURDATE() function.
Try this:
SELECT * FROM tb_data WHERE DATE(dateCol) = CURRENT_DATE();
OR
SELECT * FROM tb_data WHERE DATE(dateCol) = CURDATE()
well since there are so many answers. Try this one too and see if it's faster
SELECT * FROM tb_data WHERE date BETWEEN CURDATE() AND (CURDATE()+INTERVAL 1 DAY-INTERVAL 1 SECOND)
I have tried to filter records but with the use of now function as given below
select * from table where date>= DATE_SUB( NOW( ) ,INTERVAL 90 DAY )
What I need is a select statement that can filter its records for a week or month from the current date but without using NOW() function
if you are using java you could make use of the following code
String timeStamp = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss").format(Calendar.getInstance().getTime());
or you could use curdate() of mysql
Since I found it hard to understand the question I provide the following possibilities:
Try for all dates in a week from now:
SELECT * FROM table
WHERE date BETWEEN CURDATE() AND DATE_ADD(CURDATE() ,INTERVAL 1 WEEK)
and for all dates in a month from now:
SELECT * FROM table
WHERE date BETWEEN CURDATE() AND DATE_ADD(CURDATE() ,INTERVAL 1 MONTH)
If you are looking for all dates of the current month use
SELECT * FROM table
WHERE MONTH(date)=MONTH(CURDATE()) AND YEAR(date)=YEAR(CURDATE())
or for all dates of the current week use
SELECT * FROM table
WHERE WEEK(date)=WEEK(CURDATE()) AND YEAR(date)=YEAR(CURDATE())
How can I select the amount of rows from a database if the type is a varchar?
SELECT * FROM `orders` WHERE DATE(`order_date`) = DATE(NOW())
would not work as it is not stored in datetime is there any other way?
2011-10-30 19:14:32
Is what is stored
You can use
SELECT * FROM `orders` WHERE DATE(`order_date`) = CURDATE()
Since order_date is a VARCHAR, try with:
WHERE LEFT(order_date, 10) = CURDATE()
Best would be to change the order_date to date type and use this:
SELECT *
FROM orders
WHERE order_date >= CURDATE()
AND order_date < CURDATE() + INTERVAL 1 DAY
If you keep it as VARCHAR, you can use this variation:
SELECT *
FROM orders
WHERE order_date >= CAST( CURDATE() AS CHAR)
AND order_date < CAST( (CURDATE() + INTERVAL 1 DAY) AS CHAR)
Both of these, may use an index of order_date, if there is one.
Use datediff function in sql....
Something like
SELECT * FROM table WHERE DATEDIFF(day, StartDate, GETDATE()) <= 0
I have a table filled with a lot of rows and I need to select all the rows that are less than a year old till now.
The table (called orders) has a DateTime column named order_date, that's the field that determines when the order was placed.
How can I select all the records that have an order_date between now and a full year ago?
select *
from orders
where order_date >= DATE_SUB(NOW(),INTERVAL 1 YEAR);
SELECT * FROM order WHERE order_date >= curdate() - interval 1 year;
To first of month a year ago
SELECT DATE_SUB(DATE_FORMAT(CURRENT_DATE,'%Y-%m-01'),INTERVAL 1 YEAR);
I hope it helps you:
select *
from table
where (order_date BETWEEN '2/15/2011 3:36:18 PM' AND '2/17/2011 9:00:00 PM')