I am trying to count the number of dates that occur for a specific mem_id, however, my count output is always "0"... heres my code:
$datechecker = $postdate;
//$postdate is a date variable that is posted via a form into mysql, stored as a DATE
$sql = mysql_query("SELECT * FROM members WHERE mem_id='$id' AND postdate='$datechecker'");
$Counter = mysql_num_rows($sql);
if($Counter >= 0) {
echo "$datechecker $Counter";
exit();
}
This is the output I get: 2011-01-01 0
Even though I have about 10 occurrences of 2011-01-01, so why does my count say "0"? Can anyone help me solve this, or provide an alternate?
echo the string before you mysql_query it, this will validate if the query is what you expect it to be. You can also use count(*) within the query, instead of using php's mysql_num_rows()
I also hope that you're sanitising your input before you're querying that!
1) You didn't clean $postdate, who knows if it conforms to MySQL's definition of DATE?
2) You didn't show us how your members table looks like. Is mem_id primary key? If it is, then of course you're going to get 1 row out of it.
3) You aren't checking whether your query succeeds or not, you immediately pass the resource_id to the mysql_num_rows table - which is a wrong way to perform counting anyway because MySQL (like any other relational database) has inbuilt mechanisms of counting rows based on criteria.
My guess is that your query is failing, seeing there's not $id specified.
Related
hi i am executing nested "select" query in mysql .
the query is
SELECT `btitle` FROM `backlog` WHERE `bid` in (SELECT `abacklog_id` FROM `asprint` WHERE `aid`=184 )
I am not getting expected answer by the above query. If I execute:
SELECT abacklog_id FROM asprint WHERE aid=184
separately
I will get abacklog_id as 42,43,44,45;
So if again I execute:
SELECT `btitle` FROM `backlog` WHERE `bid` in(42,43,44,45)
I will get btitle as scrum1 scrum2 scrum3 msoffice
But if I combine those queries I will get only scrum1 remaining 3 atitle will not get.
You Can Try As Like Following...
SELECT `age_backlog`.`ab_title` FROM `age_backlog` LEFT JOIN `age_sprint` ON `age_backlog`.`ab_id` = `age_sprint`.`as_backlog_id` WHERE `age_sprint`.`as_id` = 184
By using this query you will get result with loop . You will be able to get all result with same by place with comma separated by using IMPLODE function ..
May it will be helpful for you... If you get any error , Please inform me...
What you did is to store comma separated values in age_sprint.as_backlog_id, right?
Your query actually becomes
SELECT `ab_title` FROM `age_backlog` WHERE `ab_id` IN ('42,43,44,45')
Note the ' in the IN() function. You don't get separate numbers, you get one string.
Now, when you do
SELECT CAST('42,43,44,45' AS SIGNED)
which basically is the implicit cast MySQL does, the result is 42. That's why you just get scrum1 as result.
You can search for dozens of answers to this problem here on SO.
You should never ever store comma separated values in a database. It violates the first normal form. In most cases databases are in third normal form or BCNF or even higher. Lower normal forms are just used in some special cases to get the most performance, usually for reporting issues. Not for actually working with data. You want 1 row for every as_backlog_id.
Again, your primary goal should be to get a better database design, not to write some crazy functions to get each comma separated number out of the field.
This is gonna be a dumb question, but I've been working with this code for years and never stopped to understand the what and why....
This is a very typical query I would copy and edit:
mysql_select_db($database_db, $db);
$query_qry_details = sprintf("Select * from table where id = %s", $KTColParam1_qry_details);
$qry_details = mysql_query($query_qry_details, $db) or die(mysql_error());
$row_qry_details = mysql_fetch_assoc($qry_details);
$totalRows_qry_details = mysql_num_rows($qry_details);
What do all these rows mean?
The first I know looks up the correct database. I have this line before each query on the page....do I need this?
The second row ($query_qry_details) is the query itself. I see that.
Rows 3 and 4 - no clue...
Row 5 is obviously a count of the number rows the query returns.
Thanks in advance as always.
EDITED
Shortly:
mysql_select_db(database_name, link_identifier) - Sets the cuurent active database on server that is associated with the specified link identifier.
sprintf - Return formatted string which acts as a query.
mysql_query or die - Sends a unique query to the database previously specified or exit from query.
mysql_fetch_assoc - Returns an associative array that corresponds to the fetched row and moves the internal data pointer ahead.
mysql_num_rows - Retrieves the number of rows from a result set.
I have a query in which the data is lifted from the database.
Eg: I have Category as a field which has values like Doctors, Pathologists etc which is taken from the database.
Category
--------
Doctors
Pathologists
Pediatrics/Child Specialist --->> Unwanted data
The problem is there is a data(value) in 'Category' field which is unexpectedly showing in the list which is not in my database. I even tried to drop the table entirely and reload it but that field is still showing.
Can anyone tell me why is this happening?
Additional Info
function getTierCategory()
{
echo "</br>";
$result = mysql_query("SELECT DISTINCT Category FROM doctors order by Category asc")
or die(mysql_error());
while($tier = mysql_fetch_array( $result ))
{
echo '<option value="'.$tier['Category'].'">'.$tier['Category'].'</option>';
}
}
I have tried renaming the field but how can I if this value is not even in my database.
My Database looks like
Category | Qualification | State | District
--------------------------------------------
and so on
Log in to your database in PHPmyadmin or something like that and check results of your mysql query.
In some complex queries you can receive redundant fields (on example indexes when you have counting variable in PHP) or NULL values.
mysql_fetch_array() returns results in two ways:
number indexed array ($array[0] etc)
associative array ($array['field_name'] etc)
Try with mysql_fetch_assoc or mysql_fetch_row instead. Also PDO_MYSQL API is recommended to use for MySQL querying. It has more convenient form.
I have the following codes..
echo "<form><center><input type=submit name=subs value='Submit'></center></form>";
$val=$_POST['resulta']; //this is from a textarea name='resulta'
if (isset($_POST['subs'])) //from submit name='subs'
{
$aa=mysql_query("select max(reservno) as 'maxr' from reservation") or die(mysql_error()); //select maximum reservno
$bb=mysql_fetch_array($aa);
$cc=$bb['maxr'];
$lines = explode("\n", $val);
foreach ($lines as $line) {
mysql_query("insert into location_list (reservno, location) values ('$cc', '$line')")
or die(mysql_error()); //insert value of textarea then save it separately in location_list if \n is found
}
If I input the following data on the textarea (assume that I have maximum reservno '00014' from reservation table),
Davao - Cebu
Cebu - Davao
then submit it, I'll have these data in my location_list table:
loc_id || reservno || location
00001 || 00014 || Davao - Cebu
00002 || 00014 || Cebu - Davao
Then this code:
$gg=mysql_query("SELECT GROUP_CONCAT(IF((#var_ctr := #var_ctr + 1) = #cnt,
location,
SUBSTRING_INDEX(location,' - ', 1)
)
ORDER BY loc_id ASC
SEPARATOR ' - ') AS locations
FROM location_list,
(SELECT #cnt := COUNT(1), #var_ctr := 0
FROM location_list
WHERE reservno='$cc'
) dummy
WHERE reservno='$cc'") or die(mysql_error()); //QUERY IN QUESTION
$hh=mysql_fetch_array($gg);
$ii=$hh['locations'];
mysql_query("update reservation set itinerary = '$ii' where reservno = '$cc'")
or die(mysql_error());
is supposed to update reservation table with 'Davao - Cebu - Davao' but it's returning this instead, 'Davao - Cebu - Cebu'. I was previously helped by this forum to have this code working but now I'm facing another difficulty. Just can't get it to work. Please help me. Thanks in advance!
I got it working (without ORDER BY loc_id ASC) as long as I set phpMyAdmin operations loc_id ascending. But whenever I delete all data, it goes back as loc_id descending so I have to reset it. It doesn't entirely solve the problem but I guess this is as far as I can go. :)) I just have to make sure that the table column loc_id is always in ascending order. Thank you everyone for your help! I really appreciate it! But if you have any better answer, like how to set the table column always in ascending order or better query, etc, feel free to post it here. May God bless you all!
The database server is allowed to rewrite your query to optimize its execution. This might affect the order of the individual parts, in particular the order in which the various assignments are executed. I assume that some such reodering causes the result of the query to become undefined, in such a way that it works on sqlfiddle but not on your actual production system.
I can't put my finger on the exact location where things go wrong, but I believe that the core of the problem is the fact that SQL is intended to work on relations, but you try to abuse it for sequential programming. I suggest you retrieve the data from the database using portable SQL without any variable hackery, and then use PHP to perform any post-processing you might need. PHP is much better suited to express the ideas you're formulating, and no optimization or reordering of statements will get in your way there. And as your query currently only results in a single value, fetching multiple rows and combining them into a single value in the PHP code shouldn't increase complexety too much.
Edit:
While discussing another answer using a similar technique (by Omesh as well, just as the answer your code is based upon), I found this in the MySQL manual:
As a general rule, you should never assign a value to a user variable
and read the value within the same statement. You might get the
results you expect, but this is not guaranteed. The order of
evaluation for expressions involving user variables is undefined and
may change based on the elements contained within a given statement;
in addition, this order is not guaranteed to be the same between
releases of the MySQL Server.
So there are no guarantees about the order these variable assignments are evaluated, therefore no guarantees that the query does what you expect. It might work, but it might fail suddenly and unexpectedly. Therefore I strongly suggest you avoid this approach unless you have some relaibale mechanism to check the validity of the results, or really don't care about whether they are valid.
This is a request from my client to tweak an existing Perl script. However, it is the actual database structure on their end that confuses me.
The requirement looks pretty simple:
only pull records where _X begins with 1, 2, or 9.
However, the underlying database is not that simple, here is the guideline from their DBA:
"_X is a custom metadata field. The database stores this data in rows, not columns, within the customData table. In order to query the custom data table in an efficient manner you need to know the Field_ID for the custom field you get that from the fielddef table:
SELECT Field_ID FROM FieldDef WHERE Name = "_X";
This returns:
10012
"Now you can query CustomData. For example:
SELECT Record_ID FROM CustomData where Field_ID="10012" AND StringValue="2012-04";
He also suggests that in my case, probably it would be:
"SELECT Record_ID FROM CustomData where Field_ID="10012" AND (StringValue LIKE '1%' || StringValue LIKE '2%' || StringValue LIKE '9%')
The weird thing is that the existing Perl script doesn't contain anything like "Select Record_ID FROM" but all like "SELECT StringValue FROM".
So that is why I am very confused here: What is "store in rows, not in columns"? Why first query the Field_ID table then CustomData? I would not be able to communicate with any of them during this weekend but really wish to get some idea on the whole thing, hope experts can help me a little on sorting out the whole structure.
More info(Table schema):
http://pastebin.com/ZiDTCCC0
The existing perl script:(focus on lines 72-136)
http://pastebin.com/JHpikTeZ
Thanks in advance.
What they seem to be using is some kind of Entity-Attribute-Value model, with the entities stored as ints and explained in another table (FieldDef).
You explained pretty well how you queried it (although you can do it in one query, with a join or a subquery), and your problem seems to be that you don't know how the Perl script does it. Unfortunately, without us seeing the Perl script, we can't either :]