I have a school project where I have to make a small database application using Oracle Forms.
I have 4 forms in my application:
A login form
A main form
A form that is displayed after the new button is pressed on the main form
Another form that is displayed after the edit button is pressed on the main form.
I've created the forms in the mentioned way.
When I start the application, I want the login form to be the starting form. Now what starts first is the edit form (the last one created).
How can I manage that?
Thank you.
The form loads that canvas first which holds the first data block in the Object Navigator. So make sure that your login form block is first on the list.
You can also set the "First Navigation Data Block" in the Property Palette for the form to the desired block on the login form and it will display that first, overriding the first block in the other answer.
Related
I have a MS Access form that is bound to a query in the database. I added a textbox and added a row source to a Hyperlink datafield in the query. When I open the form, it won't allow me to drop a file into the textbox.
Here's the deal. When I follow this EXACT same process on a new form, it works perfectly. That is, I open a blank form and I bind the form to some new query, let's say qryNewIdeas. Then on the blank form i add a textbox, let's say Text0. Then, when I select Text0, I go to the data tab - row source and choose the dropdown arrow to select the hyperlink field, lets say NewIdeasAddress. I click SAVE and open the form. It works PERFECTLY.
BUT, when I repeat this on an existing form (the one where I need the thing to actually work), it does nothing. It adds and changes the textbox to a hyperlink box (I note this because of the blue underlined word that appears in the box). But it won't allow me to drop files to this location.
I tried commenting out ALL of my VBA code to try to make sure that something wasn't hindering it (say in an OnLoad event) AND I've checked all of the form and control box properties and they seem to be the same in both the existing form and the test form.
I can't determine why it works on one form and not the other; Solution needed.
If you have access to "the data tab - row source ..", you are in design view.
When you later open the form, you are in form view, a completely different animal which specifically prohibits design changes.
It sounds like you will have to rethink your concept.
I have a form in which the attribute action is set to go to a page but whenever i press the submit button its taking the data to another page.
while writing your form use post method if you are using get method or use get if using post. one of them uses to carry data while navigating to target.. so just change your form method..
Assume that you want to display two separate forms on one page, but only one at a time.
One form acts as a gate for the other form, and would disappear upon submission, being replaced by the second form.
Is it possible to display a second form on POST on the same page without having to reload the page?
Not without using Javascript in some method or other. Best bet would be to post the first form via AJAX and in the response delivery the second form.
I've build a JSP page that contains a form with two multiple select objects and several buttons to send the elements from one to other. When the user has finished choosing the elements, clicks on a button to submit the form.
The form data is encapsulated through commandName="mainForm" in the JSP to a java POJO class MainForm that represents that form.
The problem here is that the POSTed elements from the multiselect objects are only those who remain "selected" (in blue) when the user submits the form. Is there any clean way (without JQuery) to send all the options?
Thanks in advance!!
You should write a JS code on "onsubmit" event of form to programatically select all the options of multiselect. (Thus, making all options blue)
Like in jQuery,
$('#form #selectId option').attr('selected', 'selected');
I don't see better way of doing it.
I have two forms, a login form and a register form on the same page and each has its own submit button. If I fill in bad data and click on submit button on register form, I get the form back with errors ( expected). If I now enter sign in details on signin form and click on signin form's submit button, the register form gets submitted.
This is strange behaviour. I am not sure where to start search for this. I am using firefox to test this.
Thanks
Well, you will need to debug it step by step.
Check your form nesting and follow good structure, make sure both form are not overlapping with each other or not being closed properly.
Give you form a proper ID and NAME. Be careful when two forms have the same name From Name Attr.
Based on your structure and your question, make sure you have a different submit buttons for each form and that button is placed within the form nesting.
Same as for the forms, give your submit button a proper unique ID and NAME .
Choose whether you want to submit by your using submit in html, or having JS to submit the form for you JS submit form.
If you are using HTML5, you can separate the button from the FORM. They can run separately. Means dynamic association between the form and it's submit button by having submit button placed anywhere and can submit a form located in different place. Check Association of Controls and Forms & HTML5′s New “form” Attribute.
Please post some code in order for us to have a better understanding of your issue.
Good luck.