Select fields which contain only numeric values ACCESS - ms-access

Can you please help me with these two points? :
(1) I working on Access and would like to wirte a query that returns those fields that contain only numberic values. e.g., 12, 45, 67. It shoud exclude any fields such as 12T, abc, TT34 because they contain characters in addition to the numbers.
(2) will it be possible to write a query to return data from fields with the following format: Num Num Char. such as : 19K or 30H or 22U
Thanks a lot!

You can use an expression such as:
WHERE Field Like "[0-9][0-9][a-z]"
Which will return two numbers followed by a letter, or
WHERE IsNumeric([Field])=True
Which will return numeric fields.

Related

Select from a field containing spaces using MySQL

I'm attempting to query on a field/column/table in a MySQL DB where the field type is varchar, but some values contains spaces. In my query, I tried to put the exact string to match on in single quotes in a where clause. However, the only rows that are returned are the strings that do not contain spaces.
Here are the values stored in the table/column:
Here is the query and the result that is only returning fields without spaces:
I expected to find a row for "New Business", a row for "Monetary Endorsement", etc. Any idea on how I can modify my query to return the desired fields? Thanks for your help in advance!
Maybe the other values have leading or trailing spaces. You can either use one of the suggestion below:
1.) Use TRIM()
WHERE TRIM(PTD_TRANS_TYPE) = 'NEW BUSINESS'
2.) Use LIKE
WHERE PTD_TRANS_TYPE LIKE '%NEW BUSINESS%'
Here's a Demo.

How to get intersect value of two comma seperated string in stored procedure?

I need to find intersect value from two comma separated string in stored procedure.
String 1: 40,31,42,23,45 => System generated numbers
String 2: 30,23,24,31,25,32 => User selected numbers
I want to check that, do any of my numbers are present in system generated numbers.
Above value should return 23,31.
I have solution that, i will loop through system generated numbers and will check one by one with my numbers using FIND_IN_SET, if present i will CONCATE that and will get required output.
But is there any shorter and optimized way to do this?

Hive: Count non zero characters in substrings of a string

I have a string like the following in the column of a hive external table
<id>^<count>^<distinct_count>|<id>^<count>^<distinct_count>|...
There are two delimiters. | on an entity level and ^ on sub-entity level
I have a metric which is defined by the sum of counts of non-zero distinct_counts or counts, which means given a string I have check whether the distinct count (or the count - I can check either) is non zero and if it mark a flag as 1. Then the metric would be sum(flags). I have to store this metric in an aggregated table in the next step.
Please suggest a way for me to do this in Hive
I think it's not possible. Ended up using an external python mapper for the same.
If you want to count number of non-zero count in a string s, it seems to be solved by
length(
regexp_replace(
regexp_replace(s, "[^^|]*\\^0\\^[^^|]*\\|?", ""),
"[^^|]*\\^[^^|]*\\^[^^|]*\\|?",
"1"
)
)
First regexp_replace removes parts with zero count, second regexp_replace replaces remaining parts with single symbols (it should not necessarily be "1", any symbol would suffice), and hence length returns number of parts with non-zero count.

MySQL REPLACE string with regex

I have a table with about 50,000 records. One of the fields is a "imploaded" field consisting of variable number of parameters from 1 to 800. I need to replace all parameters to 0.
Example:
1 parameter 3.45 should become 0.00
2 parameters 2.27^11.03 should become 0.00^0.00
3 parameters 809.11^0.12^3334.25 should become 0.00^0.00^0.00
and so on.
Really I need to replace anything between ^ with 0.00 ( for 1 parameter it should be just 0.00 without ^).
Or I need somehow count number of ^, generate string like 0.00^0.00^0.00 ... and replace it. The only tool available is MySqlWorkbench.
I would appreciate any help.
There is no regex replace capability built in to MySQL.
You can, however, accomplish your purpose by doing what you suggested -- counting the number of ^ and crafting a string of replacement values, with this:
TRIM(TRAILING '^' FROM REPEAT('0.00^',(LENGTH(column) - LENGTH(REPLACE(column,'^','')) + 1)));
From inside to outside, we calculate the number of values by counting the number of delimiters, and adding 1 to that count. We count the delimiters by comparing the length of the original string, against the length of the same string with the delimiters stripped out using REPLACE(...,'^','') to replace every ^ with nothing.
The REPEAT() function builds a string by repeating a string expression n number of times.
This results in a spurious ^ at the end of the string, which we remove easily enough with TRIM(TRAILING '^' FROM ...).
SELECT t1.*, ... the expression above ... FROM table_name t1, from your table to verify the results of this logic (replacing column with the actual name of the column), then you can UPDATE table SET column = ... to modify the values. once you are confident in the logic.
Note, of course, that this is indicative of a problematic database design. Each column should contain a single atomic value, not a "list" of values, as this question seems to suggest.

Finding number of occurence of a specific string in MYSQL

Consider the string "55,33,255,66,55"
I am finding ways to count number of occurence of a specific characters ("55" in this case) in this string using mysql select query.
Currently i am using the below logic to count
select CAST((LENGTH("55,33,255,66,55") - LENGTH(REPLACE("55,33,255,66,55", "55", ""))) / LENGTH("55") AS UNSIGNED)
But the issue with this one is, it counts all occurence of 55 and the result is = 3,
but the desired output is = 2.
Is there any way i can make this work correct? please suggest.
NOTE : "55" is the input we are giving and consider the value "55,33,255,66,55" is from a database field.
Regards,
Balan
You want to match on ',55,', but there's the first and last position to worry about. You can use the trick of adding commas to the frot and back of the input to get around that:
select LENGTH('55,33,255,66,55') + 2 -
LENGTH(REPLACE(CONCAT(',', '55,33,255,66,55', ','), ',55,', 'xxx'))
Returns 2
I've used CONCAT to pre- and post-pend the commas (rather than adding a literal into the text) because I assume you'll be using this on a column not a literal.
Note also these improvements:
Removal of the cast - it is already numeric
By replacing with a string one less in length (ie ',55,' length 4 to 'xxx' length 3), the result doesn't need to be divided - it's already the correct result
2 is added to the length because of the two commas added front and back (no need to use CONCAT to calculate the pre-replace length)
Try this:
select CAST((LENGTH("55,33,255,66,55") + 2 - LENGTH(REPLACE(concat(",","55,33,255,66,55",","), ",55,", ",,"))) / LENGTH("55") AS UNSIGNED)
I would do an sub select in this sub select I would replace every 255 with some other unique signs and them count the new signs and the standing 55's.
If(row = '255') then '1337'
for example.