I have an HTML page with a section across the middle of it. This horizontal section uses a <table> and has a custom background image that needs to repeat horizontally across the entire section. This table has 5 elements in it. These elements are statically sized to 140px.
My problem is, I can't get the image to repeat across the remaining space. It's as if the table doesn't stretch the entire width. However, if I set the table width to 100%, the table cells grow beyond 140px.
What do I do? I want the table to fill the entire space. But I want my cells to remain a constant size, and I want the background image to be used.
Thank you!
A <table> is only as big as the cells inside it. So, if you’ve got 5 cells, each 140 pixels wide, the table will only be 700 pixels wide: it won’t stretch across the full width available to it.
You could wrap the <table> in a <div> and put the repeating background image on the <div>, if the 6th cell solution doesn’t work or isn’t preferable.
The sizes of background images are irrelevant to CSS, no help there. Maybe you can hack something in JavaScript, otherwise you will have to know how large your background image is.
Consider wrapping the middle section in a div and applying the background image to the div. Then set the width of your td elements in the table to 140px.
Here is an example. Clearly, you will need to reference your image instead of flurries.png (which is not part of the fiddle so it does not show).
Add a 6th cell and don't specify any width. This will keep the 5 cells at 140px and the 6th cell will be stretched to the end when table width is set to 100%.
Related
I need to have 2 equal width divs side by side, the left column contains an image and the right column will contain dynamic text where the height of the text div can vary somewhere between 400px - 550px depending on how much text the site owner inputs.
I need the image to line up flush at the top and bottom with the end of the text box. The container element is fluid to be responsive.
Desired Effect
What I have at the moment is using floats to line the elements up together and responding fine, but the image falls short, like so:
I tried setting the image as a background-image on the left column with...
.column-image{
padding-bottom:100%;
margin-bottom:-100%;
background-size:contain;
}
But this still falls short a little unless i tweak the padding-bottom amount. This is then rendered useless when I re-size my browser as the aspect ratio changes.
I am trying to avoid using Javascript to solve this.
Use display:table for the container and display:table-cell for the inner divs. Also make sure to remove the float
Fiddle: http://jsfiddle.net/afelixj/26b3vtfx/2/
So my problem is this - I have a div with fixed size of 970px. Inside it I want to create a horizontal menu where the first element will be a link to the home page with the logo of the company and the others will be standard links to different parts of the page.
What I want is to make the link with the logo wider than the other links and let the other links occupy the space left equally. Due to the fact that in near future the width of the container div may be changed even though I know the number of links I would like to use percentages to determine their width so the width of one link will be = (width of the div - width of the logo link)/5 (the number of link I'll have.
I tried with something like this
<div id="main-container">
<div id="logo-container">
</div>
<div id="standard-menu-container">
</div>
</div>
But I couldn't make it work (In fact all this is wrapped in one other div that I haven't shown here). So googling about this I get to the understanding that maybe using some sort of table may solve my problem. To be honest I have never used table this way but I followed an example and I got this result : JSFiddle Example where the red rectangle is meant to be my Logo link and the problem is that everything else is stacking under. In this particular example the logo link is excluded from the <ul> but I played around with that case too and simply trying to set one width in pixels and other - in percentage seems to be not what I need to do.
I would appreciate any help, just bare in mind that I tried a lot of styling with divs and display: inline-block and it breaks other parts of my structure so I would prefer a solution where the normal flow is not disturbed (like using a table for example)
You're on the right lines with the display: table-cell. I've made a few changes where you had extra code that wasn't needed, and set the <ul> to display: table, rather than the container. Adding table-layout: fixed will make items in the list (the cells) occupy an equal width.
Then, float the logo left, don't specify a width for #main-menu-navigation because then it will fill remaining space, and give it margin-left: 150px to cater for width of logo.
So that won't make much sense when read. Take a look here:
http://jsfiddle.net/LREbC/1/
Try resizing, the cells will adapt to the width.
Note: When using table-cell you don't need to define a width, the behaviour is the same as actual table cells.
I have a list of div with each div having a image inside.
The width of the images is not known before loading the page.
I have a container div with width 960px. How can i arrange the images in rows with each row having as much images as the row width permits? So for example if i have 4 images (300px, 400px, 200px, 250px) i would need to have first 3 of them on a row and the 4-th one on second row as having all 4 of them in a single row will get a width larger then 960. And on each row the images should be centered.
I've tried all i could think of using css, and did not found a way that works.
Any ideea?
Something like THIS?
Ok, I worked with simply divs, because I didn't want to search for images but the main pont is: the elements which need to be both aligned and fitted, make them inline-block. Inline to be made multiline, box to be able to set both width and height. After that, you only need to set on the parent: text-align: center
EDIT
Oups, I've put spaces between the divs (like real space characters) and they appear as spaces between the divs, since they are inline. make sure not tu put any whitespace between the containers, like THIS
If you lose the containers, you don't even need to use inline-block.
http://jsfiddle.net/bryandowning/ghcmM/
However, since this is a list of images, you probably should use inline-block on the li elements of an unordered list.
See here: http://jsfiddle.net/KDfTN/
I have a table for which one column will sometimes contain extra-long content. Normally I want the table to stay at its natural width (i.e. not filling its container). However, if the natural width would be larger than the container, I want to cut off the extra-long content with an ellipsis. As shown in the link, I've tried what I think is the correct way of doing this, but it doesn't work: The table just keeps growing past the width of its container. Any ideas or suggestions?
Edit: The width of the table's container is not fixed, just as it is in the JSFiddle interface.
Set max-width:300px; on td.long (or whatever width you want)
I really hope that you can help me.
I created this fiddle to show what I'm trying to do.
My question is: How do I stretch two div-elements to fill available horizontal space?
As you can see there are 5 div-elements strung together, wrapped by a div-element where I set the background-color and width with 100%.
There are three div-elements with a width of 50px.
The width of the other two div-elements should fill up to the rest availiable space, they should have the same width, too ->50% for each of both divs.
My problem is that the 50% for those both div-elements amount to a 100% total-width. And not to a availiable space width.
I'm trying not to use tables, etc.
Let me know if there is something unclear.
EDIT:
I'd like to hear your comments about this way.
One way to solve this is to treat your divs like the cells of a table. A unique property of tables is that the cells will fill the width of the table no matter what widths you give them. By giving some cells a width the other cells will fill the remaining space. By using display:table and display:table-cell you can take advantage of this without changing your html. Have a look at this example:
http://jsfiddle.net/GyxWm/
I've not tested this but it should work in all "current" browsers. It should work in IE8+ but probably doesn't work in IE7 and certainly won't work in IE6.
You can do it with help of javascript. Change div tags like this:
<div id="part1" class="sectionFillUp">section2</div>
<div id="part2" class="sectionFillUp">section4</div>
And add this javascript somehwere after those tags:
var elem1 = document.getElementById("part1");
elem1.style.width = (screen.width - 150)/2;
var elem2 = document.getElementById("part2");
elem2.style.width = (screen.width - 150)/2;
And remove width:50%; from sectionFillUp in css
Afraid I dont think you can.
The float:left; removes your code from the containing div and all the elements end up next to each other, once an element leaves the screen to the right, it wraps underneath leaving a space (a bit like relative positioning does).
Also, you are attempting to compare a fixed width with a variable width, which is close to impossible.
If you take a look here: http://jsfiddle.net/P5Kjh/5/
First I reduced your code back to 2 divs and got that working.
I've added overflow:hidden to the backgroundG class to make sure there is a grey background and floated both divs left.
Then I set the widths, the cumulative total has to be around 100%, if you add a border to each element you need to work to a smaller percentage.
Then I added back the other 3 in a new backgroundG element and created a separte class for the fillup element so it would be 80% (without a border).
Probably doesnt help you a lot. sorry if not.
Cheers