LAST_INSERT_ID() MySQL - mysql

Question

I have a MySQL question that I think must be quite easy. I need to return the LAST INSERTED ID from table1 when I run the following MySql query:
INSERT INTO table1 (title,userid) VALUES ('test',1);
INSERT INTO table2 (parentid,otherid,userid) VALUES (LAST_INSERT_ID(),4,1);
SELECT LAST_INSERT_ID();
As you can understand the current code will just return the LAST INSERT ID of table2 instead of table1, how can I get the id from table1 even if I insert into table2 between?

Answer 1

You could store the last insert id in a variable :
INSERT INTO table1 (title,userid) VALUES ('test', 1);
SET #last_id_in_table1 = LAST_INSERT_ID();
INSERT INTO table2 (parentid,otherid,userid) VALUES (#last_id_in_table1, 4, 1);
Or get the max id from table1 (EDIT: Warning. See note in comments from Rob Starling about possible errors from race conditions when using the max id)
INSERT INTO table1 (title,userid) VALUES ('test', 1);
INSERT INTO table2 (parentid,otherid,userid) VALUES (LAST_INSERT_ID(), 4, 1);
SELECT MAX(id) FROM table1;
(Warning: as Rob Starling points out in the comments)

Answer 2

Since you actually stored the previous LAST_INSERT_ID() into the second table, you can get it from there:
INSERT INTO table1 (title,userid) VALUES ('test',1);
INSERT INTO table2 (parentid,otherid,userid) VALUES (LAST_INSERT_ID(),4,1);
SELECT parentid FROM table2 WHERE id = LAST_INSERT_ID();

Answer 3

This enables you to insert a row into 2 different tables and creates a reference to both tables too.
START TRANSACTION;
INSERT INTO accounttable(account_username)
VALUES('AnAccountName');
INSERT INTO profiletable(profile_account_id)
VALUES ((SELECT account_id FROM accounttable WHERE account_username='AnAccountName'));
SET #profile_id = LAST_INSERT_ID();
UPDATE accounttable SET `account_profile_id` = #profile_id;
COMMIT;

Answer 4

I had the same problem in bash and i'm doing something like this:
mysql -D "dbname" -e "insert into table1 (myvalue) values ('${foo}');"
which works fine:-) But
mysql -D "dbname" -e "insert into table1 (myvalue) values ('${foo}');set #last_insert_id = LAST_INSERT_ID();"
mysql -D "dbname" -e "insert into table2 (id_tab1) values (#last_insert_id);"
don't work. Because after the first command, the shell will be logged out from mysql and logged in again for the second command, and then the variable #last_insert_id isn't set anymore.
My solution is:
lastinsertid=$(mysql -B -N -D "dbname" -e "insert into table1 (myvalue) values ('${foo}');select LAST_INSERT_ID();")
mysql -D "dbname" -e "insert into table2 (id_tab1) values (${lastinsertid});"
Maybe someone is searching for a solution an bash :-)

Answer 5

We only have one person entering records, so I execute the following query immediately following the insert:
$result = $conn->query("SELECT * FROM corex ORDER BY id DESC LIMIT 1");
while ($row = $result->fetch_assoc()) {
$id = $row['id'];
}
This retrieves the last id from the database.

Answer 6

It would be possible to save the last_id_in_table1 variable into a php variable to use it later?
With this last_id I need to attach some records in another table with this last_id, so I need:
1) Do an INSERT and get the last_id_in_table1
INSERT into Table1(name) values ("AAA");
SET #last_id_in_table1 = LAST_INSERT_ID();
2) For any indeterminated rows in another table, UPDATING these rows with the last_id_insert generated in the insert.
$element = array(some ids)
foreach ($element as $e){
UPDATE Table2 SET column1 = #last_id_in_table1 WHERE id = $e
}

Answer 7

Instead of this LAST_INSERT_ID()
try to use this one
mysqli_insert_id(connection)

Answer 8

For no InnoDB solution: you can use a procedure
don't forgot to set the delimiter for storing the procedure with ;
CREATE PROCEDURE myproc(OUT id INT, IN otherid INT, IN title VARCHAR(255))
BEGIN
LOCK TABLES `table1` WRITE;
INSERT INTO `table1` ( `title` ) VALUES ( #title );
SET #id = LAST_INSERT_ID();
UNLOCK TABLES;
INSERT INTO `table2` ( `parentid`, `otherid`, `userid` ) VALUES (#id, #otherid, 1);
END
And you can use it...
SET #myid;
CALL myproc( #myid, 1, "my title" );
SELECT #myid;

Answer 9

In trigger BEFORE_INSERT this working for me:
SET #Last_Insrt_Id = (SELECT(AUTO_INCREMENT /*-1*/) /*as Last_Insert_Id*/
FROM information_schema.tables
WHERE table_name = 'tblTableName' AND table_schema = 'schSchemaName');
Or in simple select:
SELECT(AUTO_INCREMENT /*-1*/) as Last_Insert_Id
FROM information_schema.tables
WHERE table_name = 'tblTableName' AND table_schema = 'schSchemaName');
If you want, remove the comment /*-1*/ and test in other cases.
For multiple use, I can write a function. It's easy.

Answer 10

For last and second last:
INSERT INTO `t_parent_user`(`u_id`, `p_id`) VALUES ((SELECT MAX(u_id-1) FROM user) ,(SELECT MAX(u_id) FROM user ) );

Answer 11

We could also use $conn->insert_id;
// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
$sql = "INSERT INTO MyGuests (firstname, lastname, email)
VALUES ('John', 'Doe', 'john#example.com')";
if ($conn->query($sql) === TRUE) {
$last_id = $conn->insert_id;
echo "New record created successfully. Last inserted ID is: " . $last_id;
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}

Answer 12

My code does not work for me. Any idea to recover the id of my last insert this is my code I am new developing and I do not know much
I GOT ERROR IN THE QUERY AND I DON'T KNOW HOW TO SEND PRINT IN THE LINE OF $ session-> msg ('s', "Product added successfully. Make cost configuration". LAST_INSERT_ID ());
ALREADY VERIFY AND IT IS CORRECT THE CONNECTION AND THE FIELDS OF THE DATABASE.
<?php
if(isset($_POST['add_producto'])){
$req_fields = array( 'nombre', 'categoria', 'proveedor');
validate_fields($req_fields);
if(empty($errors)){
$codigobarras = remove_junk($db->escape($_POST['codigobarras']));
$identificador = remove_junk($db->escape($_POST['identificador']));
$nombre = remove_junk($db->escape($_POST['nombre']));
$categoria = (int)$db->escape($_POST['categoria']);
$etiquetas = remove_junk($db->escape($_POST['etiquetas']));
$unidadmedida = remove_junk($db->escape($_POST['unidadmedida']));
$proveedor = remove_junk($db->escape($_POST['proveedor']));
$fabricante = remove_junk($db->escape($_POST['idfabricante']));
$maximo = remove_junk($db->escape($_POST['maximo']));
$minimo = remove_junk($db->escape($_POST['minimo']));
$descripcion = remove_junk($db->escape($_POST['descripcion']));
$dias_vencimiento = remove_junk($db->escape($_POST['dias_vencimiento']));
$servicio = "0";
if (isset($_POST['servicio'])){
$servicio =implode($_POST['servicio']);
}
$numeroserie = "0";
if (isset($_POST['numeroserie'])){
$numeroserie =implode($_POST['numeroserie']);
}
$ingrediente = "0";
if (isset($_POST['ingrediente'])){
$ingrediente =implode($_POST['ingrediente']);
}
$date = make_date();
$query = "INSERT INTO productos (";
$query .=" codigo_barras,identificador_producto,nombre,idcategoria,idetiquetas,unidad_medida,idproveedor,idfabricante,max_productos,min_productos,descripcion,dias_vencimiento,servicio,numero_serie,ingrediente,activo";
$query .=") VALUES (";
$query .=" '{$codigobarras}', '{$identificador}', '{$nombre}', '{$categoria}', '{$etiquetas}', '{$unidadmedida}', '{$proveedor}', '{$fabricante}', '{$maximo}', '{$minimo}', '{$descripcion}', '{$dias_vencimiento}', '{$servicio}', '{$numeroserie}', '{$ingrediente}', '1'";
$query .=");";
$query .="SELECT LAST_INSERT_ID();";
if($db->query($query)){
$session->msg('s',"Producto agregado exitosamente. Realizar configuracion de costos" . LAST_INSERT_ID());
redirect('precio_producto.php', false);
} else {
$session->msg('d',' Lo siento, registro falló.');
redirect('informacion_producto.php', false);
}
} else{
$session->msg("d", $errors);
redirect('informacion_producto.php',false);
}
}
?>

Answer 13

Just to add for Rodrigo post, instead of LAST_INSERT_ID() in query you can use SELECT MAX(id) FROM table1;, but you must use (),
INSERT INTO table1 (title,userid) VALUES ('test', 1)
INSERT INTO table2 (parentid,otherid,userid) VALUES ( (SELECT MAX(id) FROM table1), 4, 1)

Answer 14

If you need to have from mysql, after your query, the last auto-incremental id without another query, put in your code:
mysql_insert_id();