I have the following stored proc :-
SELECT Id, Name
FROM FooBars
WHERE CONTAINS(Name, 'FORMSOF(Tesaurus, #query)')
Works fine when there is one word i the query: eg. foo*
But it fails when I want to have more than one word which i'm trying to look for.
eg. foo* bar* (this means any rows that have words that start with foo and start with bar).
What format does my #query argument need to look like, to enable multiple words for a Full Text Search with a Thesaurus?
As far as I know, if you want to search for two or more expressions, you need to concatenate those with either AND, OR or NEAR, something like this (straight from Books Online):
USE AdventureWorks;
GO
SELECT Name
FROM Production.Product
WHERE CONTAINS(Name, '"chain*" OR "full*"');
GO
SELECT Description
FROM Production.ProductDescription
WHERE CONTAINS(Description, 'bike NEAR performance');
GO
SELECT Description
FROM Production.ProductDescription
WHERE ProductDescriptionID <> 5 AND
CONTAINS(Description, ' Aluminum AND spindle');
If and how that would work together with your FORMSOF(...) expression is unclear to me - but I'm sure you could quickly try that, no?
SELECT Id, Name
FROM FooBars
WHERE CONTAINS(Name, 'FORMSOF(THESAURUS, "foo*")'
OR 'FORMSOF(THESAURUS, "bar*")')
Also make sure to spell "thesaurus" correctly in your FORMSOF () expression! :-)
Marc
Related
What is the best way to search a database for a phrase such as "Almond Anise Cookie" and return the result?
If I
SELECT *
FROM recipes
WHERE name LIKE '%".$query."%'
and use the phrase "Almond Cookie", nothing is returned as expected. But if I search for "Anise Cookie" the result above is returned.
I've also tried
SELECT *
FROM recipes
WHERE name LIKE '%".$query."%'
OR name LIKE '".$query."%'
OR name LIKE '%".$query."'
with the same failed result.
Using MATCH AGAINST returns everything that contains "Almond" and everything that contains "Cookie" also not a good result. Is there a happy middle in returned results?
You can try using REPLACE. Something like this should work:
SELECT *
FROM recipes
WHERE NAME LIKE REPLACE(' ".$query." ',' ','%');
Note that I purposely add spaces between .$query. to ensure that the replace operation will make your term filled with the wildcard symbol. In the example above:
If $query='almond cookies' then REPLACE(' ".$query." ',' ','%') will become %almond%cookies%.
You can test the fiddle here : https://www.db-fiddle.com/f/kMzp99S8ENbTkYcW5FVdYN/0
E.g :
I have 1 word for search the data. And the word is 'ayam'.
And this is my query :
select nama_product from product where nama_product like %a%
It works fine. But it show the record that i dont want to be showed.
This is the result :
ayam bakar
daging ayam
bayam hijau
daun bayam
The first and the second result is okay. But the third and the last that i dont want to be showed.
Because i want to show 'ayam' not "b'ayam'"
How do i handle this? I don't know it is duplicate or not. Because i already search it but i didn't find.
If you need to search the word 'ayam' without any prefix and sufix character, you would better use regular expression for that .
e.g.,
SELECT namma_product FROM product WHERE namma_product REGEXP 'ayam'
try this. This will work
Unfortunately this is a limitation of SQL. Some SQL databases have advanced text searching functions such as regular expressions which allow very specific text results.
For your case you will likely have to perform multiple LIKE conditions. For example:
select nama_product
from product
where
nama_product like 'ayam %'
or nama_product like '% ayam %'
or nama_product like '% ayam'
or nama_product = 'ayam'
Please note that if the text fields are very large or if the table is large, queries that rely on LIKE operators can become very slow. LIKE does not scale well with large datasets. If this is a dataset you think will become very large in the future, best to design it in a way where the LIKE operator will not be needed.
You can use regex to match only whole words:
select nama_product
from product
where nama_product regexp '(^| )ayam( |$)';
(^| ) means the word must be the start of the string, or it must be preceded by a space
ayam is the word we're matching
( |$) means the word must be followed by a space, or it must be the end of the string
SQL Fiddle
when u insert '%' before and after it mean All Character before(after) your keyword so just change how u want
for example just keywords start with "ayam":
select nama_product from product where nama_product like 'ayam%'
another example just keywords ended with "ayam":
select nama_product from product where nama_product like '%ayam'
and after that look here ithink your answer is here :
Match only entire words with LIKE?
My user table has a column "name" which contains information like this:
Joe Lee
Angela White
I want to search for either first name or last name efficiently. First name is easy, I can do
SELECT * FROM user WHERE name LIKE "ABC%"
But for last name, if I do
SELECT * FROM user WHERE name LIKE "%ABC"
That would be extremely slow.
So I am thinking about counting the characters of the input, for example, "ABC" has 3 characters, and if I can search only the last three characters in name column, that would be great. So I want something like
SELECT * FROM user WHERE substring(name, end-3, end) LIKE "ABC%"
Is there anything in MySQL that can do this?
Thanks so much!
PS. I cannot do fulltext because our search engine doesn't support that.
The reason that
WHERE name LIKE '%ith'
is a slow way to look for 'John Smith' by last name is the same reason that
WHERE Right(name, InStr(name, ' ' )) LIKE 'smi%'
or any other expression on the column is slow. It defeats the use of the index for quick lookup and leaves the MySQL server doing a full table scan or full index scan.
If you were using Oracle (that is, if you worked for a formerly wealthy employer) you could use function indexes. As it is you have to add some extra columns or some other helping data to accelerate your search.
Your smartest move is to split your first and last names into separate columns. Several other people have pointed out good reasons for doing that.
If you can't do that you could try creating an extra column which contains the name string reversed, and create an index on that column. That column will have, for example, 'John Smith' stored as 'htimS nhoJ'. Then you can search as follows.
WHERE nameReversed LIKE CONCAT(REVERSE('ith'),'%')
This search will use the index and be decently fast. I've had good success with it.
You're close. In MySQL you should be able to use InStr(str, substr) and Right(str, index) to do the following:
SELECT * FROM user WHERE Right(name, InStr(name, " ")) LIKE "ABC%"
InStr(name, " ") returns the index of the Space character (you may have to play with the " " syntax). This index is then used in the Right() function to search for only the last name (basically; problems arise when you have multiple names, multiple spaces etc). LIKE "ABC%" would then search for a last name starting with ABC.
You cannot use a fixed index as names that are more than 3 or less than 3 characters long would not return properly as you suggest.
However, as Zane said, it's a much better practise to use seperate fields.
If it is a MyIsam table, you may use Free text search to do the same.
You can use the REGEXP operator:
SELECT * FROM user WHERE name REGEXP "ABC$"
http://dev.mysql.com/doc/refman/5.1/en/regexp.html
I have a mysql table with a list of keywords such as:
id | keywords
---+--------------------------------
1 | apple, oranges, pears
2 | peaches, pineapples, tangerines
I'm trying to figure out how to query this table using an input string of:
John liked to eat apples
Is there a mysql query type that can query a field with a sentence and return results (in my example, record #1)?
One way to do it could be to convert apple, oranges, pears to apple|oranges|pears and use RLIKE (ie regular expression) to match against it.
For example, 'John liked to eat apples' matches the regex 'apple|orange|pears'.
First, to convert 'apple, oranges, pears' to the regex form, replace all ', ' by '|' using REPLACE. Then use RLIKE to select the keyword entries that match:
SELECT *
FROM keywords_table
WHERE 'John liked to eat apples' RLIKE REPLACE(keywords,', ','|');
However this does depend on your comma-separation being consistent (i.e. if there is one row that looks like apples,oranges this won't work as the REPLACE replaces a comma followed by a space (as per your example rows).
I also don't think it'll scale up very well.
And, if you have a sentence like 'John liked to eat pineapples', it would match both of the rows above (as it does have 'apple' in it). You could then try to add word boundaries to the regex (i.e. WHERE $sentence RLIKE '[[:<:]](apple|oranges|pears)[[:>:]]'), but this would screw up matching when you have plurals ('apples' wouldn't match '[wordboundary]apple[wordboundary]').
Hopefully this isn't more abstract than what you need but maybe good way of doing it.
I haven't tested this but I think it would work. If you can use PHP you can use str_replace to turn the spaces into keyword LIKE '%apple%'
$sentence = "John liked to eat apples";
$sqlversion = str_replace(" ","%' OR Keyword like '%",$sentence );
$finalsql = "%".$sqlversion."%";
the above will echo:
%John%' OR Keyword like '%liked%' OR Keyword like '%to%' OR Keyword like '%eat%' OR Keyword like '%apples%
Then just combine with your SQl statement
SQL ="SELECT *
FROM keywords_table
WHERE Keyword like" . $finalsql;
Storing comma delimited data is... less than ideal.
If you broke up the string "John liked to eat apples" into individual words, you could use the FIND_IN_SET operator:
WHERE FIND_IN_SET('apple', t.keywords) > 0
The performance wouldn't be great - this operation is better suited to Full Text Search.
I'm not aware of any direct solution to that type of query. But Full Text Search is a possibility. If you have a full-text index on the field of interest then a search with OR between each word in the sentence (although I think the OR operator is implied) would find that record ... but it might also find more than you want too.
I really don't think what you are looking for is completely possible but you can look into Full Text Search or SOUNDEX. SOUNDEX, for example, can do something like:
WHERE SOUNDEX(sentence) = SOUNDEX('%'+keywords+'%');
I have never tried it in this context but you should and let me know how it works out.
I am new to SQL and I have several large database with upper case first and last names that I need to convert to proper case in SQL sever 2008.
I am using the following to do this:
update database
Set FirstNames = upper(substring(FirstNames, 1, 1))
+ lower(substring(FirstNames, 2, (len(FirstNames) - 1) ))
I was wondering if there was any way to adapt this so that a field with two first names is also updated (currently I make the change and then go through and manually change the second name).
I have looked over the other answers in this field and they all seem quit long, compared to the query above.
Also is there any way to assist with converting the Mc suranmes ( I will manually change the others)? MCDONALD to McDonald, again I am just using the about query but replacing the FirstNames with LastName.
This is probably best done outside of SQL. However, if there is a requirement to do it on the server or if speed isn't an issue (because it will be an issue so you need to figure out if you care), the way you are going about it is probably the best way of doing so. If you want, you could create a UDF that puts all of the logic in one area.
Here is some code I came across (with attribution and more information below it):
CREATE FUNCTION dbo.fCapFirst(#input NVARCHAR(4000)) RETURNS NVARCHAR(4000)
AS
BEGIN
DECLARE #position INT
WHILE IsNull(#position,Len(#input)) > 1
SELECT #input = Stuff(#input,IsNull(#position,1),1,upper(substring(#input,IsNull(#position,1),1))),
#position = charindex(' ',#input,IsNull(#position,1)) + 1
RETURN (#input)
END
--Call it like so
select dbo.fCapFirst(Lower(Column)) From MyTable
I got this code from http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=37760 There is more information and other suggestions in this forum as well.
As for dealing with cases like the McDonald, I would suggest one of two ways to handle this. One would be to put a search in the above UDF for key names ('McDonald', 'McGrew', etc.) or for patterns (the first two letters are Mc then make the next one capital, etc.) The second way would be to put these cases (the full names) in a table and have their replacement value in a second column. Then simply do a replace. Most likely, however, it will be easiest to identify rules like Mc then capitalize instead of trying to list every last-name possibility.
Don't forget you may want to modify the above UDF to include dashes, not just spaces.
Maybe this is too long but it is very easy and can be adapted for -, ', etc:
UPDATE tbl SET LastName = Case when (CharIndex(' ',lastname,1)<>0) then (Upper(Substring(lastname,1,1))+Lower(Substring(lastname,2,CharIndex(' ',lastname,1)-1)))+
(Upper(Substring(lastname,CharIndex(' ',lastname,1)+1,1))+
Lower(Substring(lastname,CharIndex(' ',lastname,1)+2,Len(lastname)-(CharIndex(' ',lastname,1)-1))))
else (Upper(Substring(lastname,1,1))+Lower(Substring(lastname,2,Len(lastname)-1))) end,
FirstName = Case when (CharIndex(' ',firstname,1)<>0) then (Upper(Substring(firstname,1,1))+Lower(Substring(firstname,2,CharIndex(' ',firstname,1)-1)))+
(Upper(Substring(firstname,CharIndex(' ',firstname,1)+1,1))+
Lower(Substring(firstname,CharIndex(' ',firstname,1)+2,Len(firstname)-(CharIndex(' ',firstname,1)-1))))
else (Upper(Substring(firstname,1,1))+Lower(Substring(firstname,2,Len(firstname)-1))) end;
Tony Rogerson has code that deals with:
double barrelled names eg Arthur Bentley-Smythe
Control characters
I haven't used it myself though...