How string data was loaded with respect to Ghidra? - reverse-engineering

I reverse engineered libil2cpp.so using ghidra. I found these lines of code in a function in the decompiler view:
UnityEngine.PlayerPrefs$$GetInt(*(undefined4 *)(*(int *)(Class$ItemPref + 0x5c) + 8),5,0);
it is apparently getting the value of a shared_preferences. the syntax of when getting a shared_preference in unity games is as follows as described in the documentation:
UnityEngine.PlayerPrefs.GetInt(string key, int defaultValue)
so as apparently the *(undefined4 *)(*(int *)(Class$ItemPref + 0x5c) + 8) in the reversed code is the corresponding string key. while in general I know where the key is in the reversed code which is at this address
010e94b8 undefined4 ?? ; ScoreID
so what I wanted to learn is that how *(undefined4 *)(*(int *)(Class$ItemPref + 0x5c) + 8) is reffering to that address 010e94b8 holding the string key.
what I tried so far?
referring to this answer, I double clicked the value Class$ItemPref in the decompiled code *(undefined4 *)(*(int *)(Class$ItemPref + 0x5c) + 8) and take its memory address 010dd710 and then adding 0x5c yeilds 10DD76C and then adding 8 yeilds 10DD774 so going to this address 10DD774 does not contain the string ScoringID.
also I did this taking memory address of Class$ItemPref which is 010dd710 and then adding 0x5c and the multiply the size of the typecast which is int which is 4 then the result is 4375DB0 then adding 8 equals to 4375DB8 but this is not quite right.
but what I really wanted to learn is that how that string ScoreID is referred in the decompiled code UnityEngine.PlayerPrefs$$GetInt(*(undefined4 *)(*(int *)(Class$ItemPref + 0x5c) + 8),5,0); please help this as my limited knowledge of reversing and ghidra.
if it helps, the corresponding disassembled view of the code is as follows:
003e60f0 5c 00 90 e5 ldr r0, [r0,#0x5c]
003e60f4 05 10 a0 e3 mov r1, #0x5
003e60f8 00 20 a0 e3 mov r2, #0x0
003e60fc 08 00 90 e5 ldr r0, [r0,#0x8]
003e6100 10 4c bd e8 ldmia sp!,{r4 r10 r11 lr}
003e6104 1a 63 14 ea b UnityEngine.PlayerPrefs$$GetInt ; undefined UnityEngine.PlayerPrefs$$GetInt()
-- Flow Override: CALL_RETURN (CALL_TERMIN

Related

arm cortex-m33 (trustzone, silabs efm32pg22) - assembler hardfaults accessing GPIO or almost any peripherals areas, any hint?

I am just lost here with this code trying to configure on baremetal the silicon labs efm32pg22 in theirs devkit accessed through internal J-Link from segger studio (great fast ide) - I have such example blink hello world in C working from theirs simplicity studio, but was trying to achieve the same thing I did on microchip pic32 mc00 or samd21g17d easily in pure assembler, having only clocks and startup configured through gui in mplab x... well, here I tried to go to segger IDE where is NO startup/clocks config easy way, or I didnt found it yet. On hardware level, registers of such cortex beasts are different by manufacturer, in C/C++ there is some not cheap unification over cmsis - but I want only to know what minimal is needed to just have working raw GPIO after clock/startup ... Segger project is generic cortex-m for specific efm32pg22 so cortex-M33 with trust-zone security - I probably dont know what all is locked or switched off or in which state MCU is, if privileged or nonprivileged - there are 2 sets of registers mapping, but nothing works. As far as I try to "store" or even "load" on GPIO config registers (or SMU regs to query someting too) it is throw hardfault exception. All using segger ide debugger over onboard j-link. Kindly please, what I am doing wrong, whats missing here?
in C, I have only this code:
extern void blink(void);
int main ( void )
{
blink();
}
In blink.s I have this:
;#https://github.com/hubmartin/ARM-cortex-M-bare-metal-assembler-examples/blob/master/02%20-%20Bare%20metal%20blinking%20LED/main.S
;#https://sites.google.com/site/hubmartin/arm/arm-cortex-bare-metal-assembly/02---arm-cortex-bare-metal-assembly-blinking-led
;#https://mecrisp-stellaris-folkdoc.sourceforge.io/projects/blink-f0disco-gdbtui/doc/readme.html
;#https://microcontrollerslab.com/use-gpio-pins-tm4c123g-tiva-launchpad/
;#!!! ENABLE GPIO CLOCK SOURCE ON EFM32 !!!
;#https://community.silabs.com/s/share/a5U1M000000knsWUAQ/hello-world-part-2-create-firmware-to-blink-the-led?language=en_US
;#EFM32 GPIO
;#https://www.silabs.com/documents/public/application-notes/an0012-efm32-gpio.pdf
;# ARM thumb2 ISA
;#https://www.engr.scu.edu/~dlewis/book3/docs/ARM_and_Thumb-2_Instruction_Set.pdf
;#https://sciencezero.4hv.org/index.php?title=ARM:_Cortex-M3_Thumb-2_instruction_set
;#!!! https://stackoverflow.com/questions/48561243/gnu-arm-assembler-changes-orr-into-movw
;#segger assembler
;#https://studio.segger.com/segger/UM20006_Assembler.pdf
;#https://www.segger.com/doc/UM20006_Assembler.html
;#!!! unfortunatelly, we dont know here yet how to include ASM SFR defines, nor for MPLAB ARM (Harmony) !!!
;##include <xc.h>
;##include "definitions.h"
.cpu cortex-m33
.thumb
.text
.section .text.startup.main,"ax",%progbits
.balign 2
.p2align 2,,3
.global blink
//.arch armv8-m.base
.arch armv6-m
.syntax unified
.code 16
.thumb_func
.fpu softvfp
.type blink, %function
//!!! here we have manually entered GPIO PORT defines for PIC32CM
.equ SYSCFG_BASE_ADDRESS, 0x50078000
.equ SMU_BASE_ADDRESS, 0x54008000
//.equ SMU_BASE_ADDRESS, 0x5400C000
.equ CMU_BASE_ADDRESS, 0x50008000
.equ GPIO_BASE_ADDRESS, 0x5003C000 // this differs totally from both "special" infineon and microchip "standard?" cortex devices !!!
.equ DELAY, 40000
// Vector table
.word 0x20001000 // Vector #0 - Stack pointer init value (0x20000000 is RAM address and 0x1000 is 4kB size, stack grows "downwards")
.word blink // Vector #1 - Reset vector - where the code begins
// Vector #3..#n - I don't use Systick and another interrupts right now
// so it is not necessary to define them and code can start here
blink:
LDR r0, =(SYSCFG_BASE_ADDRESS + 0x200) // SYSCFG SYSCFG_CTRL
LDR r1, =0 // 0 diable address faults exceptions
ldr r1, [r0] // Store R0 value to r1
LDR r0, =(CMU_BASE_ADDRESS) // CMU CMU_SYSCLKCTRL PCLKPRESC + CLKSEL
LDR r1, =0b10000000001 // FSRCO 20MHz + PCLK = HCLK/2 = 10MHz
STR r1, [r0, 0x70] // Store R0 value to r1
LDR r0, =(CMU_BASE_ADDRESS) // CMU CMU_CLKEN0
LDR r1, [r0, 0x64]
LDR r2, =(1 << 25) // GPIO CLK EN
orrs r1, r2 // !!! HORROR !!! -- orr is not possible in thumb2 ?? only orrs !! (width suffix)
STR r1, [r0, 0x64] // Store R0 value to r1
LDR r1, [r0, 0x68]
LDR r2, =(1 << 14) // SMU CLK EN
orrs r1, r2 // !!! HORROR !!! -- orr is not possible in thumb2 ?? only orrs !! (width suffix)
STR r1, [r0, 0x68] // Store R0 value to r1
//LDR r0, =(SMU_BASE_ADDRESS) // SMU SMU_LOCK
//LDR r1, =11325013 // SMU UNLOCK CODE
//STR r1, [r0, 0x08] //Store R0 value to r1
ldr r0, =(SMU_BASE_ADDRESS) // SMU reading values, detection - AGAIN, HARD FAULTS !!!!!!!
ldr r1, [r0, 0x04]
ldr r1, [r0, 0x20]
ldr r1, [r0, 0x40]
//LDR r0, =(GPIO_BASE_ADDRESS + 0x300) // GPIO UNLOCK
//LDR r1, =0xA534
//STR r1, [r0] // Store R0 value to r1
//!! THIS BELOW IS OLD FOR SAMD , WE STILL SIMPLY CANT ENABLE GPIO !!!!
// Enable PORTA pin 4 as output
LDR r0, =(GPIO_BASE_ADDRESS) // DIR PORTA
LDR r1, =0b00000000000001000000000000000000
STR r1, [r0, 0x04] // Store R0 value to r1
LDR R2, =1
loop:
// Write high to pin PA04
LDR r0, =GPIO_BASE_ADDRESS // OUT PORTA
LDR r1, =0b10000 // PORT_PA04
STR r1, [r0, 0x10] // Store R1 value to address pointed by R0
// Dummy counter to slow down my loop
LDR R0, =0
LDR R1, =DELAY
loop0:
ADD R0, R2
cmp R0, R1
bne loop0
// Write low to PA04
LDR r0, =GPIO_BASE_ADDRESS // OUT PORTA
LDR r1, =0b00000
STR r1, [r0, 0x10] // Store R1 value to address pointed by R0
// Dummy counter to slow down my loop
LDR R0, =0
LDR R1, =DELAY
loop1:
ADD R0, R2
cmp R0, R1
bne loop1
b loop
UPDATE: well, now I tried it again in SimplicityStudio, placing blink() call after pregenerated system init:
extern void blink(void);
int main(void)
{
// Initialize Silicon Labs device, system, service(s) and protocol stack(s).
// Note that if the kernel is present, processing task(s) will be created by
// this call.
sl_system_init();
blink();
}
having this code in blink.s: - and here it works this way and blinks ...
.cpu cortex-m33
.thumb
.text
.section .text.startup.main,"ax",%progbits
.balign 2
.p2align 2,,3
.global blink
//.arch armv8-m.base
.arch armv6-m
.syntax unified
.code 16
.thumb_func
.fpu softvfp
.type blink, %function
/*
//!!! here we have manually entered GPIO PORT defines for PIC32CM
.equ SYSCFG_BASE_ADDRESS, 0x50078000
.equ SMU_BASE_ADDRESS, 0x54008000
//.equ SMU_BASE_ADDRESS, 0x5400C000
.equ CMU_BASE_ADDRESS, 0x50008000
*/
.equ GPIO_BASE_ADDRESS, 0x5003C000 // this differs totally from both "special" infineon and microchip "standard?" cortex devices !!!
.equ DELAY, 400000
// Vector table
.word 0x20001000 // Vector #0 - Stack pointer init value (0x20000000 is RAM address and 0x1000 is 4kB size, stack grows "downwards")
.word blink // Vector #1 - Reset vector - where the code begins
// Vector #3..#n - I don't use Systick and another interrupts right now
// so it is not necessary to define them and code can start here
blink:
// Enable PORTA pin 4 as output
LDR r0, =(GPIO_BASE_ADDRESS) // DIR PORTA
LDR r1, =0b00000000000001000000000000000000
STR r1, [r0, 0x04]
loop:
// Write high to pin PA04
LDR r0, =GPIO_BASE_ADDRESS // OUT PORTA
LDR r1, =0b10000 // PORT_PA04
STR r1, [r0, 0x10]
// Dummy counter to slow down my loop
LDR R0, =0
LDR R1, =DELAY
loop0:
ADD R0, R2
cmp R0, R1
bne loop0
// Write low to PA04
LDR r0, =GPIO_BASE_ADDRESS // OUT PORTA
LDR r1, =0b00000
STR r1, [r0, 0x10]
// Dummy counter to slow down my loop
LDR R0, =0
LDR R1, =DELAY
loop1:
ADD R0, R2
cmp R0, R1
bne loop1
b loop
... so NOW, I am just curious, what all is missing in pure assembly code to bring that cortex-m33 into some "easy" state, just ignoring trustzone, probably to use it similary as say, plain cortex-m3 ??
can anybody help? I am digging deeply into this datasheet/ref manual, but no luck till now ...
https://www.silabs.com/documents/public/reference-manuals/efm32pg22-rm.pdf
UPDATE AGAIN: umm, will try to figure out ... by traversing system_init C-code its clear whats going on, there are also some chip errata workarounds, but I never touched DCDC while initializing, this may be culprit...
void sl_platform_init(void)
{
CHIP_Init();
sl_device_init_nvic();
sl_board_preinit();
sl_device_init_dcdc();
sl_device_init_hfxo();
sl_device_init_lfxo();
sl_device_init_clocks();
sl_device_init_emu();
sl_board_init();
}
well, okay, manufacturer specific code generation for MCU startup IS really important and useful thing )) ... such MCUs from different manufacturers are really much different at registers level (even that all are "cortex-m" core based), that its worthless to try to configure them manually in assembly if there is enough flash available, and it mostly IS. So, till now, no luck with segger/keil/iar "generic" arm/cortex IDEs to do this properly on specific parts, so using manufacturer specific IDE to (mostly) graphically configure startup clocks and peripherals IS CRUCIAL, or at least, its really easiest way (I know, quite expensive observation after all the assembly tries... )). After then, its easy to make even pure assembly "blink" helloworld test called as extern C-function. You may be asking why I am still considering assembly if there are even CMSIS (on arm) "platform abstraction layer" C-headers at least (no, it doesnt help in abstraction, as the devices are still very different, you only have registers symbols #defines and typedefs and enums to do something in C easily, okay). But I am trying to compare some C-compiled code with handwriten assembly for some specific purpose, which needs forced optimized algorithm from scratch and its often quite easier to think/design it directly in assembly that to rely on very complexly described C-compiler optimisations (each compiler has its own LONG document how his optimisations work and at this level, C is simply still too abstract and moving target, the more, you try to write something for even different MCU architectures (think ARM cortex-m, PIC32/mips, and/or even PIC16/18 + PIC24, AVR , MSP430 ...) - while general algorithm may be described in shared pseudoassenbly to be as near to hardware as possible, withnout knowing all optimization quirks of each architecture C compiler(s) - there are often MORE different C compilers too. So, to compare C-compiler generated code with handwriten assembly you can do it, and I already tried such assembly blink on MANY VERY different architectures, in case I definitelly used mfg specific IDE to genearte startup in C, using all the GUI configurations and code generation down to always compilable empty C project, of course, having very different code size output using such generated startups. Most advanced MCUs are really very complex, mostly in clocks configuration and pins functions config and then different peripheral devices too, sure. Some similarities are possible only at single mfg level, to some extent, so MCU of single manufacturer often share similar approach, obviously. So final solution is to have startup generated and then switch to assembly immediatelly, this is feasible. Sure that in case of small flash, its further possible to optimize even startup code, but its mostly important on smallest 8bit parts, where startup IS quite easy anyway or the generated code is also small, obviously.

How the compiled version of this toy language pseudocode would work in assembly roughly?

I am working on a toy language which is need of some compilation now. So far, I have nested function calls, and I am wondering what the assembly sort of pseudocode would look like. This includes:
Function prologue and epilogue.
Instruction "blocks".
How functions are reused.
Not real assembly code, just pseudocode (though I am sort of coming from x86).
The x86 "block" structure I'm referring to seems to be this:
my_function:
enter N, 0
; ... details
leave
ret
To keep it simple (avoiding async and all that), my toy code looks like this basically:
my_func_a(add(1, my_func_z(2, 3)), sub(my_func_r(4, 5, 6), 7), 8)
Or spread out:
my_func_a(
add(
1,
my_func_z(2, 3)
),
sub(
my_func_r(
4,
5,
6
),
7
),
8
)
When I try to translate this mentally into some sort of corresponding pseudo-assembly, I end up doing this:
u = my_func_r(4, 5, 6)
v = sub(u, 7)
w = my_func_z(2, 3)
x = add(1, w)
y = my_func_a(x, v) ; final result
I'm not sure if I got the order exactly correct, but it's close I think. But this isn't quite low-level enough as x86, so I try lowering it further:
mov r1, 4
mov r2, 5
mov r3, 6
call my_func_r
; how to capture the "u = ..."?
mov r1, u?
mov r2, 7
call sub
; how about capturing "v"?
mov r1, 2
mov r2, 3
call my_func_z
; w = ... somehow
mov r1, 1
mov r2, w
call add
; x = ... somehow
mov r1, x
mov r2, v
call my_func_a
; y...
I would try and use some sort of tool to compile some rough C-like language into LLVM, for example, but it's way over my head to get that all going and working at this stage.
Now let's say we have implementations for some of these functions:
my_func_r(a,b,c):
enter ...
add a, b
sub b, c
leave
ret
my_func_z(a,b):
enter ...
; ...
leave
ret
my_func_a(a,b):
enter ...
; ...
leave
ret
Basically what I'm wondering is, how should the final pseudocode be written? (given I haven't exactly specified here how everything works, just got it at a rough level at this point). What would it roughly look like? I don't see how the values are properly placed and passed around in the lowest-level Assembly version.
Where are the arguments passed into the functions? At what place, before the function call, or inside the function/block?
How do you capture the output variables outside of the function?
Sorry if this pseudocode is prone with errors, I am just beginning to put the pieces together, so please be gentle.

Creating a function in assembly language (TASM)

I wanted to print the first 20 numbers using loop.
Printing the first nine numbers is absolutely fine as the hexadecimal and decimal codes are the same, but from the 10th number I had to convert each number into its appropriate code and then convert it and store it to string and eventually display it
That is,
If (NUMBER > 9)
ADD 6D
;10d = 0ah --(+6)--> 16d = 10h
IF NUMBER IS > 19
ADD 12D
;20d = 14h --(+12)--> 32d = 20h
Then rotating and shifting each number to get the desired output number, that is,
DAA # let al = 74h = 0111.0100
XOR AH,AH # ah = 0 (Just in case it wasn't)
# ax = 0000.0000.0111.0100
ROR AX,4 # ax = 0100.0000.0000.0111 = 4007h
SHR AH,4 # ax = 0000.0100.0000.0111 = 0407h
ADD AX,3030h # ax = 0011.0100.0011.0111 = 3437h = ASCII "74" (Reversed due to little endian)
And then storing the result in to the string and displaying it, that is,
MOV BX,OFFSET Result ;Let Result is an empty string
MOV byte ptr[BX],5 ;Size of the string
MOV byte ptr[BX+4],'$' ;String terminator
MOV byte ptr[BX+3],AH ;storing number
MOV byte ptr[BX+2],AL
MOV DX,BX
ADD DX,02 ;Displaying the result
MOV AH,09H ;Interrupt 21 service to display string
INT 21H
And here is the complete code with proper commenting,
MOV CX,20 ;Number of iterations
MOV DX,0 ;First value of the sequence
L1:
PUSH DX
ADD DX,30H ; 30H is equal to 0 in hexadecimal , 31H = 1 and so on
MOV AH,02H ; INTERRUPT Service to print the DX content
INT 21H
POP DX
ADD DX,1
CMP DX,09 ; if number is > 9 i.e 0A then go to L2
JA L2
LOOP L1
L2:
PUSH DX
MOV AX,DX
CMP AX,14H ;If number is equal to 14H(20) then Jump to L3
JE L3
ADD AX,6D ;If less than 20 then add 6D
XOR AH,AH ;Clear the content of AH
ROR AX,4 ;Rotating and Shifting for to properly store
SHR AH,4
ADC AX,3030h
MOV BX,OFFSET Result
MOV byte ptr[BX],5
MOV byte ptr[BX+4],'$'
MOV byte ptr[BX+3],AH
MOV byte ptr[BX+2],AL
MOV DX,BX
ADD DX,02
MOV AH,09H
INT 21H
POP DX
ADD DX,1
LOOP L2
;If the number is equal to 20 come here, ->
; Every step is repeated here just to change 6D to 12D
L3:
ADD AX,12D
XOR AH,AH
ROR AX,1
ROR AX,1
ROR AX,1
ROR AX,1
SHR AH,1
SHR AH,1
SHR AH,1
SHR AH,1
ADC AX,3030h
MOV BX,OFFSET Result
MOV byte ptr[BX],5
MOV byte ptr[BX+4],'$'
MOV byte ptr[BX+3],AH
MOV byte ptr[BX+2],AL
MOV DX,BX
ADD DX,02
MOV AH,09H
INT 21H
Is there any proper way to do it, creating a function and using if/else (jumps) to get the desired output rather than repeating the code again and again?
PSEUDO CODE:
VAR = 6
IF Number is > 9
ADD AX,VAR
Else IF Number is > 19
ADD AX,(VAR*2)
ELSE IF NUMBER is > 29
ADD AX,(VAR*3)
So you just want to print 0 ... 20 as ASCII characters? It looks like you understand that the numerals are identified as 0x30 ... 0x39 for '0' to '9', so you could use integer division to generate the character for the tens digit:
I usually work with C but conversion to assembler shouldn't be too complicated since these are all fundamental operations and there are no function calls.
int i_value = 29;
int i_tens = i_value/10; //Integer division! 29/10 = 2, save for later use
char c_tens = '0' + i_tens;
char c_ones = '0' + i_value-(10*i_tens); // Subtract N*10 from value
The output will be c_tens = 0x32, c_ones = 0x39. You should be able to wrap this inside of a loop pretty easily using a pair of registers.
Pseudocode
regA <- num_iterations //For example, 20
regB <- 0 //Initialize counter register
LOOP:
//Do conversion for the current iteration.
//Manipulate bytes for output as necessary.
regB <- regB +1
branch not equal regA, regB LOOP
The following code counts from 0 up to 99 (ax contains the ASCII number):
count proc
mov cx, 100 ; loop runs the times specified in the cx register
xor bx, bx ; set counter to zero
print:
mov ax, bx
aam ; Converts binary to unpacked BCD
xor ax, 3030h ; Converts upacked BCD to ASCII
; Print here (ax now contains the numer in ASCII representation)
inc bx ; Increase counter
loop print
ret
count endp

Code Golf: Conway's Game of Life

Locked. This question and its answers are locked because the question is off-topic but has historical significance. It is not currently accepting new answers or interactions.
The Challenge: Write the shortest program that implements John H. Conway's Game of Life cellular automaton. [link]
EDIT: After about a week of competition, I have selected a victor: pdehaan, for managing to beat the Matlab solution by one character with perl.
For those who haven't heard of Game of Life, you take a grid (ideally infinite) of square cells. Cells can be alive (filled) or dead (empty). We determine which cells are alive in the next step of time by applying the following rules:
Any live cell with fewer than two live neighbours dies, as if caused by under-population.
Any live cell with more than three live neighbours dies, as if by overcrowding.
Any live cell with two or three live neighbours lives on to the next generation.
Any dead cell with exactly three live neighbours becomes a live cell, as if by reproduction.
Your program will read in a 40x80 character ASCII text file specified as a command-line argument, as well as the number of iterations (N) to perform. Finally, it will output to an ASCII file out.txt the state of the system after N iterations.
Here is an example run with relevant files:
in.txt:
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
..................................XX............................................
..................................X.............................................
.......................................X........................................
................................XXXXXX.X........................................
................................X...............................................
.................................XX.XX...XX.....................................
..................................X.X....X.X....................................
..................................X.X......X....................................
...................................X.......XX...................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
Iterate 100 times:
Q:\>life in.txt 100
Resultant Output (out.txt)
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
..................................XX............................................
..................................X.X...........................................
....................................X...........................................
................................XXXXX.XX........................................
................................X.....X.........................................
.................................XX.XX...XX.....................................
..................................X.X....X.X....................................
..................................X.X......X....................................
...................................X.......XX...................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
................................................................................
The Rules:
You need to use file I/O to read/write the files.
You need to accept an input file and the number of iterations as arguments
You need to generate out.txt (overwrite if it exists) in the specified format
You don't need to deal with the edges of the board (wraparound, infinite grids .etc)
EDIT: You do need to have newlines in your output file.
The winner will be determined by character count.
Good luck!
Mathematica - 179 163 154 151 chars
a = {2, 2, 2};
s = Export["out.txt",
CellularAutomaton[{224, {2, {a, {2, 1, 2}, a}}, {1,1}},
(ReadList[#1, Byte, RecordLists → 2>1] - 46)/ 42, #2]〚#2〛
/. {0 → ".", 1 → "X"}, "Table"] &
Spaces added for readability
Invoke with
s["c:\life.txt", 100]
Animation:
You can also get a graph of the mean population over time:
A nice pattern for generating gliders from Wikipedia
AFAIK Mathematica uses a Cellular Automaton to generate random numbers using Rule 30.
MATLAB 7.8.0 (R2009a) - 174 171 161 150 138 131 128 124 characters
Function syntax: (124 characters)
Here's the easier-to-read version (with unnecessary newlines and whitespace added for better formatting):
function l(f,N),
b=char(importdata(f))>46;
for c=1:N,
b=~fix(filter2(ones(3),b)-b/2-3);
end;
dlmwrite('out.txt',char(b*42+46),'')
And here's how the program is run from the MATLAB Command Window:
l('in.txt',100)
Command syntax: (130 characters)
After a comment about calling functions with a command syntax, I dug a little deeper and found out that MATLAB functions can in fact be invoked with a command-line format (with some restrictions). You learn something new every day!
function l(f,N),
b=char(importdata(f))>46;
for c=1:eval(N),
b=~fix(filter2(ones(3),b)-b/2-3);
end;
dlmwrite('out.txt',char(b*42+46),'')
And here's how the program is run from the MATLAB Command Window:
l in.txt 100
Additional Challenge: Tweetable GIF maker - 136 characters
I thought for fun I'd see if I could dump the output to a GIF file instead of a text file, while still keeping the character count below 140 (i.e. "tweetable"). Here's the nicely-formatted code:
function l(f,N),
b=char(importdata(f))>46;
k=ones(3);
for c=1:N+1,
a(:,:,:,c)=kron(b,k);
b=~fix(filter2(k,b)-b/2-3);
end;
imwrite(~a,'out.gif')
Although IMWRITE is supposed to create a GIF that loops infinitely by default, my GIF is only looping once. Perhaps this is a bug that has been fixed in newer versions of MATLAB. So, to make the animation last longer and make the evolution steps easier to see, I left the frame delay at the default value (which seems to be around half a second). Here's the GIF output using the Gosper Glider Gun pattern:
Improvements
Update 1: Changed the matrix b from a logical (i.e. "boolean") type to a numerical one to get rid of a few conversions.
Update 2: Shortened the code for loading the file and used the function MAGIC as a trick to create the convolution kernel in fewer characters.
Update 3: Simplified the indexing logic, replaced ~~b+0 with b/42, and replaced 'same' with 's' as an argument to CONV2 (and it surprisingly still worked!).
Update 4: I guess I should have searched online first, since Loren from The MathWorks blogged about golfing and the Game of Life earlier this year. I incorporated some of the techniques discussed there, which required me to change b back to a logical matrix.
Update 5: A comment from Aslak Grinsted on the above mentioned blog post suggests an even shorter algorithm for both the logic and performing the convolution (using the function FILTER2), so I "incorporated" (read "copied") his suggestions. ;)
Update 6: Trimmed two characters from the initialization of b and reworked the logic in the loop to save 1 additional character.
Update 7: Eric Sampson pointed out in an e-mail that I could replace cell2mat with char, saving 4 characters. Thanks Eric!
Ruby 1.9 - 189 178 159 155 153 chars
f,n=$*
c=IO.read f
n.to_i.times{i=0;c=c.chars.map{|v|i+=1
v<?.?v:('...X'+v)[[83,2,-79].map{|j|c[i-j,3]}.to_s.count ?X]||?.}*''}
File.new('out.txt',?w)<<c
Edit:
Handles newlines with 4 chars less.
Can remove 7 more (v<?.?v:) if you allow it to clobber newlines when the live cells reach the edges.
perl, 127 129 135 chars
Managed to strip off a couple more characters...
$/=pop;#b=split'',<>;map{$n=-1;#b=map{++$n;/
/?$_:($t=grep/X/,#b[map{$n+$_,$n-$_}1,80..82])==3|$t+/X/==3?X:'.'}#b}1..$/;print#b
Python - 282 chars
might as well get the ball rolling...
import sys
_,I,N=sys.argv;R=range(3e3);B=open(I).read();B=set(k for k in R if'A'<B[k])
for k in R*int(N):
if k<1:b,B=B,set()
c=sum(len(set((k+o,k-o))&b)for o in(1,80,81,82))
if(c==3)+(c==2)*(k in b):B.add(k)
open('out.txt','w').write(''.join('.X\n'[(k in B)-(k%81<1)]for k in R))
Python 2.x - 210/234 characters
Okay, the 210-character code is kind of cheating.
#coding:l1
exec'xÚ=ŽA\nÂ#E÷sŠº1­ƒÆscS‰ØL™Æª··­âî¿GÈÿÜ´1iÖ½;Sçu.~H®J×Þ-‰­Ñ%ª.wê,šÖ§J®d꘲>cÉZË¢V䀻Eîa¿,vKAËÀå̃<»Gce‚ÿ‡ábUt¹)G%£êŠ…óbÒüíÚ¯GÔ/n×Xši&ć:})äðtÏÄJÎòDˆÐÿG¶'.decode('zip')
You probably won't be able to copy and paste this code and get it to work. It's supposed to be Latin-1 (ISO-8859-1), but I think it got perverted into Windows-1252 somewhere along the way. Additionally, your browser may swallow some of the non-ASCII characters.
So if it doesn't work, you can generate the file from plain-old 7-bit characters:
s = """
23 63 6F 64 69 6E 67 3A 6C 31 0A 65 78 65 63 27 78 DA 3D 8E 41 5C 6E C2
40 0C 45 F7 73 8A BA 31 13 AD 83 15 11 11 C6 73 08 63 17 05 53 89 D8 4C
99 C6 AA B7 B7 AD E2 EE BF 47 C8 FF DC B4 31 69 D6 BD 3B 53 E7 75 2E 7E
48 AE 4A D7 DE 90 8F 2D 89 AD D1 25 AA 2E 77 16 EA 2C 9A D6 A7 4A AE 64
EA 98 B2 3E 63 C9 5A CB A2 56 10 0F E4 03 80 BB 45 16 0B EE 04 61 BF 2C
76 0B 4B 41 CB C0 E5 CC 83 03 3C 1E BB 47 63 65 82 FF 87 E1 62 55 1C 74
B9 29 47 25 A3 EA 03 0F 8A 07 85 F3 62 D2 FC ED DA AF 11 47 D4 2F 6E D7
58 9A 69 26 C4 87 3A 7D 29 E4 F0 04 74 CF C4 4A 16 CE F2 1B 44 88 1F D0
FF 47 B6 27 2E 64 65 63 6F 64 65 28 27 7A 69 70 27 29
"""
with open('life.py', 'wb') as f:
f.write(''.join(chr(int(i, 16)) for i in s.split()))
The result of this is a valid 210-character Python source file. All I've done here is used zip compression on the original Python source code. The real cheat is that I'm using non-ASCII characters in the resultant string. It's still valid code, it's just cumbersome.
The noncompressed version weighs in at 234 characters, which is still respectable, I think.
import sys
f,f,n=sys.argv
e=open(f).readlines()
p=range
for v in p(int(n)):e=[''.join('.X'[8+16*(e[t][i]!='.')>>sum(n!='.'for v in e[t-1:t+2]for n in v[i-1:i+2])&1]for i in p(80))for t in p(40)]
open('out.txt','w').write('\n'.join(e))
Sorry about the horizontal scroll, but all newlines in the above are required, and I've counted them as one character each.
I wouldn't try to read the golfed code. The variable names are chosen randomly to achieve the best compression. Yes, I'm serious. A better-formatted and commented version follows:
# get command-line arguments: infile and count
import sys
ignored, infile, count = sys.argv
# read the input into a list (each input line is a string in the list)
data = open(infile).readlines()
# loop the number of times requested on the command line
for loop in range(int(count)):
# this monstrosity applies the rules for each iteration, replacing
# the cell data with the next generation
data = [''.join(
# choose the next generation's cell from '.' for
# dead, or 'X' for alive
'.X'[
# here, we build a simple bitmask that implements
# the generational rules. A bit from this integer
# will be chosen by the count of live cells in
# the 3x3 grid surrounding the current cell.
#
# if the current cell is dead, this bitmask will
# be 8 (0b0000001000). Since only bit 3 is set,
# the next-generation cell will only be alive if
# there are exactly 3 living neighbors in this
# generation.
#
# if the current cell is alive, the bitmask will
# be 24 (8 + 16, 0b0000011000). Since both bits
# 3 and 4 are set, this cell will survive if there
# are either 3 or 4 living cells in its neighborhood,
# including itself
8 + 16 * (data[y][x] != '.')
# shift the relevant bit into position
>>
# by the count of living cells in the 3x3 grid
sum(character != '.' # booleans will convert to 0 or 1
for row in data[y - 1 : y + 2]
for character in row[x - 1 : x + 2]
)
# select the relevant bit
& 1
]
# for each column and row
for x in range(80)
)
for y in range(40)
]
# write the results out
open('out.txt','w').write('\n'.join(data))
Sorry, Pythonistas, for the C-ish bracket formatting, but I was trying to make it clear what each bracket was closing.
Haskell - 284 272 232 chars
import System
main=do f:n:_<-getArgs;s<-readFile f;writeFile"out.txt"$t s$read n
p '\n'_='\n'
p 'X'2='X'
p _ 3='X'
p _ _='.'
t r 0=r
t r n=t[p(r!!m)$sum[1|d<-1:[80..82],s<-[1,-1],-m<=d*s,m+d*s<3240,'X'==r!!(m+d*s)]|m<-[0..3239]]$n-1
F#, 496
I could reduce this a lot, but I like this as it's still in the ballpark and pretty readable.
open System.IO
let mutable a:_[,]=null
let N y x=
[-1,-1;-1,0;-1,1;0,-1;0,1;1,-1;1,0;1,1]
|>Seq.sumBy(fun(i,j)->try if a.[y+i,x+j]='X' then 1 else 0 with _->0)
[<EntryPoint>]
let M(r)=
let b=File.ReadAllLines(r.[0])
a<-Array2D.init 40 80(fun y x->b.[y].[x])
for i=1 to int r.[1] do
a<-Array2D.init 40 80(fun y x->
match N y x with|3->'X'|2 when a.[y,x]='X'->'X'|_->'.')
File.WriteAllLines("out.txt",Array.init 40(fun y->
System.String(Array.init 80(fun x->a.[y,x]))))
0
EDIT
428
By request, here's my next stab:
open System
let mutable a,k=null,Array2D.init 40 80
[<EntryPoint>]
let M r=
a<-k(fun y x->IO.File.ReadAllLines(r.[0]).[y].[x])
for i=1 to int r.[1] do a<-k(fun y x->match Seq.sumBy(fun(i,j)->try if a.[y+i,x+j]='X'then 1 else 0 with _->0)[-1,-1;-1,0;-1,1;0,-1;0,1;1,-1;1,0;1,1]with|3->'X'|2 when a.[y,x]='X'->'X'|_->'.')
IO.File.WriteAllLines("out.txt",Array.init 40(fun y->String(Array.init 80(fun x->a.[y,x]))))
0
That's a 14% reduction with some basic golfing. I can't help but feel that I'm losing by using a 2D-array/array-of-strings rather than a 1D array, but don't feel like doing that transform now. Note how I elegantly read the file 3200 times to initialize my array :)
Ruby 1.8: 178 175 chars
f,n=$*;b=IO.read f
n.to_i.times{s=b.dup
s.size.times{|i|t=([82,1,-80].map{|o|b[i-o,3]||''}*'').count 'X'
s[i]=t==3||b[i]-t==?T??X:?.if s[i]>13};b=s}
File.new('out.txt','w')<<b
Newlines are significant (although all can be replaced w/ semicolons.)
Edit: fixed the newline issue, and trimmed 3 chars.
Java, 441... 346
Update 1 Removed inner if and more ugliness
Update 2 Fixed a bug and gained a character
Update 3 Using lots more memory and arrays while ignoring some boundaries issues. Probably a few chars could be saved.
Update 4 Saved a few chars. Thanks to BalusC.
Update 5 A few minor changes to go below 400 and make it just that extra bit uglier.
Update 6 Now things are so hardcoded may as well read in the exact amount in one go. Plus a few more savings.
Update 7 Chain the writing to the file to save a char. Plus a few odd bits.
Just playing around with BalusC's solution. Limited reputation means I couldnt add anything as a comment to his.
class M{public static void main(String[]a)throws Exception{int t=3240,j=t,i=new Integer(a[1])*t+t;char[]b=new char[i+t],p={1,80,81,82};for(new java.io.FileReader(a[0]).read(b,t,t);j<i;){char c=b[j],l=0;for(int n:p)l+=b[j+n]/88+b[j-n]/88;b[j+++t]=c>10?(l==3|l+c==90?88:'.'):c;}new java.io.FileWriter("out.txt").append(new String(b,j,t)).close();}}
More readable(?) version:
class M{
public static void main(String[]a)throws Exception{
int t=3240,j=t,i=new Integer(a[1])*t+t;
char[]b=new char[i+t],p={1,80,81,82};
for(new java.io.FileReader(a[0]).read(b,t,t);j<i;){
char c=b[j],l=0;
for(int n:p)l+=b[j+n]/88+b[j-n]/88;
b[j+++t]=c>10?(l==3|l+c==90?88:'.'):c;
}
new java.io.FileWriter("out.txt").append(new String(b,j,t)).close();
}
}
Scala - 467 364 339 chars
object G{def main(a:Array[String]){val l=io.Source.fromFile(new java.io.File(a(0)))getLines("\n")map(_.toSeq)toSeq
val f=new java.io.FileWriter("out.txt")
f.write((1 to a(1).toInt).foldLeft(l){(t,_)=>(for(y<-0 to 39)yield(for(x<-0 to 79)yield{if(x%79==0|y%39==0)'.'else{val m=t(y-1)
val p=t(y+1);val s=Seq(m(x-1),m(x),m(x+1),t(y)(x-1),t(y)(x+1),p(x-1),p(x),p(x+1)).count('X'==_)
if(s==3|(s==2&t(y)(x)=='X'))'X'else'.'}})toSeq)toSeq}map(_.mkString)mkString("\n"))
f.close}}
I think there is much room for improvement...
[Edit] Yes, it is:
object G{def main(a:Array[String]){var l=io.Source.fromFile(new java.io.File(a(0))).mkString
val f=new java.io.FileWriter("out.txt")
var i=a(1).toInt
while(i>0){l=l.zipWithIndex.map{case(c,n)=>if(c=='\n')'\n'else{val s=Seq(-83,-82,-81,-1,1,81,82,83).map(_+n).filter(k=>k>=0&k<l.size).count(l(_)=='X')
if(s==3|(s==2&c=='X'))'X'else'.'}}.mkString
i-=1}
f.write(l)
f.close}}
[Edit] And I have the feeling there is still more to squeeze out...
object G{def main(a:Array[String]){val f=new java.io.FileWriter("out.txt")
f.write(((1 to a(1).toInt):\(io.Source.fromFile(new java.io.File(a(0))).mkString)){(_,m)=>m.zipWithIndex.map{case(c,n)=>
val s=Seq(-83,-82,-81,-1,1,81,82,83)count(k=>k+n>=0&k+n<m.size&&m(k+n)=='X')
if(c=='\n')c else if(s==3|s==2&c=='X')'X'else'.'}.mkString})
f.close}}
The following solution uses my own custom domain-specific programming language which I have called NULL:
3499538
In case you are wondering how this works: My language consists of only of one statment per program. The statement represents a StackOverflow thread ID belonging to a code golf thread. My compiler compiles this into a program that looks for the best javascript solution (with the SO API), downloads it and runs it in a web browser.
Runtime could be better for new threads (it may take some time for the first upvoted Javascript answer to appear), but on the upside it requires only very little coding skills.
Javascript/Node.js - 233 236 characters
a=process.argv
f=require('fs')
m=46
t=f.readFileSync(a[2])
while(a[3]--)t=[].map.call(t,function(c,i){for(n=g=0;e=[-82,-81,-80,-1,1,80,81,82][g++];)t[i+e]>m&&n++
return c<m?c:c==m&&n==3||c>m&&n>1&&n<4?88:m})
f.writeFile('out.txt',t)
C - 300
Just wondered how much smaller and uglier my java solution could go in C. Reduces to 300 including the newlines for the preprocessor bits. Leaves freeing the memory to the OS! Could save ~20 by assuming the OS will close and flush the file too.
#include<stdio.h>
#include<stdlib.h>
#define A(N)j[-N]/88+j[N]/88
int main(int l,char**a){
int t=3240,i=atoi(a[2])*t+t;
char*b=malloc(i+t),*j;
FILE*f;
fread(j=b+t,1,t,fopen(a[1],"r"));
for(;j-b-i;j++[t]=*j>10?l==3|l+*j==90?88:46:10)
l=A(1)+A(80)+A(81)+A(82);
fwrite(j,1,t,f=fopen("out.txt","w"));
fclose(f);
}
MUMPS: 314 chars
L(F,N,R=40,C=80)
N (F,N,R,C)
O F:"RS" U F D C F
.F I=1:1:R R L F J=1:1:C S G(0,I,J)=($E(L,J)="X")
F A=0:1:N-1 F I=1:1:R F J=1:1:C D S G(A+1,I,J)=$S(X=2:G(A,I,J),X=3:1,1:0)
.S X=0 F i=-1:1:1 F j=-1:1:1 I i!j S X=X+$G(G(A,I+i,J+j))
S F="OUT.TXT" O F:"WNS" U F D C F
.F I=1:1:R F J=1:1:C W $S(G(N,I,J):"X",1:".") W:J=C !
Q
Java, 556 532 517 496 472 433 428 420 418 381 chars
Update 1: replaced 1st StringBuffer by Appendable and 2nd by char[]. Saved 24 chars.
Update 2: found a shorter way to read file into char[]. Saved 15 chars.
Update 3: replaced one if/else by ?: and merged char[] and int declarations. Saved 21 chars.
Update 4: replaced (int)f.length() and c.length by s. Saved 24 chars.
Update 5: made improvements as per hints of Molehill. Major one was hardcoding the char length so that I could get rid of File. Saved 39 chars.
Update 6: minor refactoring. Saved 6 chars.
Update 7: replaced Integer#valueOf() by new Integer() and refactored for loop. Saved 8 chars.
Update 8: Improved neighbour calculation. Saved 2 chars.
Update 9: Optimized file reading since file length is already hardcoded. Saved 37 chars.
import java.io.*;class L{public static void main(String[]a)throws Exception{int i=new Integer(a[1]),j,l,s=3240;int[]p={-82,-81,-80,-1,1,80,81,82};char[]o,c=new char[s];for(new FileReader(a[0]).read(c);i-->0;c=o)for(o=new char[j=s];j-->0;){l=0;for(int n:p)l+=n+j>-1&n+j<s?c[n+j]/88:0;o[j]=c[j]>13?l==3|l+c[j]==90?88:'.':10;}Writer w=new FileWriter("out.txt");w.write(c);w.close();}}
More readable version:
import java.io.*;
class L{
public static void main(String[]a)throws Exception{
int i=new Integer(a[1]),j,l,s=3240;
int[]p={-82,-81,-80,-1,1,80,81,82};
char[]o,c=new char[s];
for(new FileReader(a[0]).read(c);i-->0;c=o)for(o=new char[j=s];j-->0;){
l=0;for(int n:p)l+=n+j>-1&n+j<s?c[n+j]/88:0;
o[j]=c[j]>10?l==3|l+c[j]==90?88:'.':10;
}
Writer w=new FileWriter("out.txt");w.write(c);w.close();
}
}
Closing after writing is absoletely mandatory, else the file is left empty. It would otherwise have saved another 21 chars.
Further I could also save one more char when I use 46 instead of '.', but both javac and Eclipse jerks with a compilation error Possible loss of precision. Weird stuff.
Note: this expects an input file with \n newlines, not \r\n as Windows by default uses!
PHP - 365 328 322 Characters.
list(,$n,$l) = $_SERVER["argv"];
$f = file( $n );
for($j=0;$j<$l;$j++){
foreach($f as $k=>$v){
$a[$k]="";
for($i=0;$i < strlen( $v );$i++ ){
$t = 0;
for($m=-1;$m<2;$m++){
for($h=-1;$h<2;$h++){
$t+=ord($f[$k + $m][$i + $h]);
}
}
$t-=ord($v[$i]);
$a[$k] .= ( $t == 494 || ($t == 452 && ord($v[$i])==88)) ? "X" : "." ;
}
}
$f = $a;
}
file_put_contents("out.txt", implode("\n", $a ));
I'm sure this can be improved upon but I was curious what it would look like in PHP. Maybe this will inspire someone who has a little more code-golf experience.
Updated use list() instead of $var = $_SERVER["argv"] for both args. Nice one Don
Updated += and -= this one made me /facepalm heh cant believe i missed it
Updated file output to use file_put_contents() another good catch by Don
Updated removed initialization of vars $q and $w they were not being used
R 340 chars
cgc<-function(i="in.txt",x=100){
require(simecol)
z<-file("in.txt", "rb")
y<-matrix(data=NA,nrow=40,ncol=80)
for(i in seq(40)){
for(j in seq(80)){
y[i,j]<-ifelse(readChar(z,1) == "X",1,0)
}
readChar(z,3)
}
close(z)
init(conway) <- y
times(conway)<-1:x
o<-as.data.frame(out(sim(conway))[[100]])
write.table(o, "out.txt", sep="", row.names=FALSE, col.names=FALSE)
}
cgc()
I feel it's slightly cheating to have an add in package that does the actual automata for you, but I'm going with it cos I still had to thrash around with matricies and stuff to read in the file with 'X' instead of 1.
This is my first 'code golf', interesting....
c++ - 492 454 386
my first code golf ;)
#include<fstream>
#define B(i,j)(b[i][j]=='X')
int main(int i,char**v){for(int n=0;n<atoi(v[2]);++n){std::ifstream f(v[1]);v[1]="out.txt";char b[40][83];for(i=0;i<40;++i)f.getline(b[i],83);std::ofstream g("out.txt");g<<b[0]<<'\n';for(i=1;i<39;++i){g<<'.';for(int j=1;j<79;++j){int k=B(i-1,j)+B(i+1,j)+B(i,j-1)+B(i,j+1)+B(i-1,j-1)+B(i+1,j+1)+B(i+1,j-1)+B(i-1,j+1);(B(i,j)&&(k<2||k>3))?g<<'.':(!B(i,j)&&k==3)?g<<'X':g<<b[i][j];}g<<".\n";}g<<b[0]<<'\n';}}
A somewhat revised version, replacing some of the logic with a table lookup+a few other minor tricks:
#include<fstream>
#define B(x,y)(b[i+x][j+y]=='X')
int main(int i,char**v){for(int n=0;n<atoi(v[2]);++n){std::ifstream f(v[1]);*v="out.txt";char b[40][83], O[]="...X.....";for(i=0;i<40;++i)f>>b[i];std::ofstream g(*v);g<<b[0]<<'\n';for(i=1;i<39;++i){g<<'.';for(int j=1;j<79;++j){O[2]=b[i][j];g<<O[B(-1,0)+B(1,0)+B(0,-1)+B(0,1)+B(-1,-1)+B(1,1)+B(1,-1)+B(-1,1)];}g<<".\n";}g<<b[0]<<'\n';}}
Perl – 214 chars
What, no perl entries yet?
$i=pop;#c=<>;#c=map{$r=$_;$u='';for(0..79)
{$K=$_-1;$R=$r-1;$u.=((&N.(&N^"\0\W\0").&N)=~y/X//
|(substr$c[$r],$_,1)eq'X')==3?'X':'.';}$u}keys#c for(1..$i);
sub N{substr$c[$R++],$K,3}open P,'>','out.txt';$,=$/;print P#c
Run with: conway.pl infile #times
Another Java attempt, 361 chars
class L{public static void main(final String[]a)throws Exception{new java.io.RandomAccessFile("out.txt","rw"){{int e=88,p[]={-1,1,-80,80,-81,81,-82,82},s=3240,l=0,i=new Byte(a[1])*s+s,c;char[]b=new char[s];for(new java.io.FileReader(a[0]).read(b);i>0;seek(l=++l%s),i--){c=b[l];for(int n:p)c+=l+n>=0&l+n<s?b[l+n]/e:0;write(c>13?(c==49|(c|1)==91?e:46):10);}}};}}
And a little more readable
class L {
public static void main(final String[]a) throws Exception {
new java.io.RandomAccessFile("out.txt","rw"){{
int e=88, p[]={-1,1,-80,80,-81,81,-82,82},s=3240,l=0,i=new Byte(a[1])*s+s,c;
char[] b = new char[s];
for (new java.io.FileReader(a[0]).read(b);i>0;seek(l=++l%s),i--) {
c=b[l];
for (int n:p)
c+=l+n>=0&l+n<s?b[l+n]/e:0;
write(c>13?(c==49|(c|1)==91?e:46):10);
}
}};
}
}
Very similar to Molehill’s version. I've tried to use a different FileWriter and to count the cell's neighbors without an additional variable.
Unfortunately, RandomAccessFile is a pretty long name and it is required that you pass an file access mode.
RUST - 469 characters
Don't know if I should post this here, (this post is 3 years old) but anyway, my try on this, in rust (0.9):
use std::io::fs::File;fn main(){
let mut c=File::open(&Path::new(std::os::args()[1])).read_to_end();
for _ in range(0,from_str::<int>(std::os::args()[2]).unwrap()){
let mut b=c.clone();for y in range(0,40){for x in range(0,80){let mut s=0;
for z in range(x-1,x+2){for t in range(y-1,y+2){
if z>=0&&t>=0&&z<80&&t<40&&(x !=z||y !=t)&&c[t*81+z]==88u8{s +=1;}}}
b[y*81+x]=if s==3||(s==2&&c[y*81+x]==88u8){88u8} else {46u8};}}c = b;}
File::create(&Path::new("out.txt")).write(c);}
For people interested, here is the code before some agressive golfing:
use std::io::fs::File;
fn main() {
let f = std::os::args()[1];
let mut c = File::open(&Path::new(f)).read_to_end();
let n = from_str::<int>(std::os::args()[2]).unwrap();
for _ in range(0,n)
{
let mut new = c.clone();
for y in range(0,40) {
for x in range(0,80) {
let mut sum = 0;
for xx in range(x-1,x+2){
for yy in range(y-1,y+2) {
if xx >= 0 && yy >= 0 && xx <80 && yy <40 && (x != xx || y != yy) && c[yy*81+xx] == 88u8
{ sum = sum + 1; }
}
}
new[y*81+x] = if sum == 3 || (sum == 2 && c[y*81+x] == 88u8) {88u8} else {46u8};
}
}
c = new;
}
File::create(&Path::new("out.txt")).write(c);
}
ét voilà
you may want to use this html file. no file input, but a textarea that does the job!
there is also some html and initiation and vars. the main routine has only 235 characters.
It's hand-minified JS.
<!DOCTYPE html>
<html><body><textarea id="t" style="width:600px;height:600px;font-family:Courier">
</textarea></body><script type="text/javascript">var o,c,m=new Array(3200),
k=new Array(3200),y,v,l,p;o=document.getElementById("t");for(y=0;y<3200;y++)
{m[y]=Math.random()<0.5;}setInterval(function(){p="";for(y=0;y<3200;y++){c=0;
for(v=-1;v<2;v+=2){c+=m[y-1*v]?1:0;for(l=79;l<82;l++)c+=m[y-l*v]?1:0;}
k[y]=c==3||m[y]&&c==2;}p="";for(y=0;y<3200;y++){p+=(y>0&&y%80==0)?"\n":"";
m[y]=k[y];p+=(m[y]?"O":"-");}o.innerHTML=p;},100);</script></html>
One of the classic patterns
***
..*
.*
My avatar was created using my version of the Game of Life using this pattern and rule(note that it is not 23/3):
#D Thanks to my daughter Natalie
#D Try at cell size of 1
#R 8/1
#P -29 -29
.*********************************************************
*.*******************************************************.*
**.*****************************************************.**
***********************************************************
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***********************************************************
***********************************************************
***********************************************************
***********************************************************
***********************************************************
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***********************************************************
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***********************************************************
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***********************************************************
***********************************************************
***********************************************************
****************************.*.****************************
***********************************************************
****************************.*.****************************
***********************************************************
***********************************************************
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**.*****************************************************.**
*.*******************************************************.*
.*********************************************************
IMHO - as I learned Conway's Game of Life the trick wasn't writing short code, but code that could do complex life forms quickly. Using the classic pattern above and a wrapped world of 594,441 cells the best I could ever do was around 1,000 generations / sec.
Another simple pattern
**********
.
................*
.................**
................**.......**********
And gliders
........................*...........
......................*.*...........
............**......**............**
...........*...*....**............**
**........*.....*...**..............
**........*...*.**....*.*...........
..........*.....*.......*...........
...........*...*....................
............**......................

Code Golf: Triforce

Locked. This question and its answers are locked because the question is off-topic but has historical significance. It is not currently accepting new answers or interactions.
This is inspired by/taken from this thread: http://www.allegro.cc/forums/thread/603383
The Problem
Assume the user gives you a numeric input ranging from 1 to 7. Input should be taken from the console, arguments are less desirable.
When the input is 1, print the following:
***********
*********
*******
*****
***
*
Values greater than one should generate multiples of the pattern, ending with the one above, but stacked symmetrically. For example, 3 should print the following:
*********** *********** ***********
********* ********* *********
******* ******* *******
***** ***** *****
*** *** ***
* * *
*********** ***********
********* *********
******* *******
***** *****
*** ***
* *
***********
*********
*******
*****
***
*
Bonus points if you print the reverse as well.
*********** ***********
********* *********
******* *******
***** *****
*** ***
* *
***********
*********
*******
*****
***
*
*
***
*****
*******
*********
***********
* *
*** ***
***** *****
******* *******
********* *********
*********** ***********
Can we try and keep it to one answer per language, that we all improve on?
Assembler, 165 bytes assembled
Build Instructions
Download A86 from here
Add a reference to the A86 executable into your DOS search path
Paste the code below into a text file (example: triforce.asm)
Invoke the assembler: a86 triforce.asm
This will create a .COM file called triforce.com
Type triforce to run
This was developed using the standard WinXP DOS box (Start->Programs->Accessories->Command Prompt). It should work with other DOS emulators.
Assemble using A86 and requires WinXP DOS box to run the .COM file it produces. Press 'q' to exit, keys 1-7 to draw the output.
l20:mov ah,7
int 21h
cmp al,'q'
je ret
sub al,'0'
cmp al,1
jb l20
cmp al,7
ja l20
mov [l0-1],al
mov byte ptr [l7+2],6
jmp $+2
mov ah,2
mov ch,0
mov bh,3
l0:mov bl,1
l1:mov dh,0
l3:cmp dh,ch
je l2
mov dl,32
int 21h
inc dh
jmp l3
ret
l2:mov dh,bh
l6:mov cl,12
l5:mov dl,42
cmp cl,bl
ja l4
mov dl,32
cmp dh,1
je l21
l4:int 21h
dec cl
jnz l5
l21:dec dh
jnz l6
mov dl,10
int 21h
mov dl,13
int 21h
l10:inc ch
l9:add bl,2
l7:cmp ch,6
jne l1
l13:add byte ptr [l7+2],6
l11:dec bh
l12:cmp bh,0
jne l0
xor byte ptr [l0+1],10
xor byte ptr [l9+1],40
xor byte ptr [l10+1],8
xor byte ptr [l13+1],40
sub byte ptr [l7+2],12
mov dh,[l0-1]
inc dh
xor [l12+2],dh
xor byte ptr [l11+1],8
xor byte ptr [l1+1],1
inc bh
cmp byte ptr [l0+1],11
je l0
jmp l20
It uses lots of self-modifying code to do the triforce and its mirror, it even modifies the self-modifying code.
GolfScript - 43 chars
~:!6*,{:^' '
*'*'12*' '
^6%.+)*+
-12>!^
6/-*
n}
/
~:!6*,{:^' '*'*'12*' '^6%.+)*+-12>!^6/-*n}/
48 Chars for the bonus
~:!6*,.-1%+{
:^' '*'*'12
*' '^6%.+
)*+-12>
!^6/-
*n}
/
~:!6*,.-1%+{:^' '*'*'12*' '^6%.+)*+-12>!^6/-*n}/
Python - 77 Chars
n=input()
for k in range(6*n):print' '*k+('*'*12+' '*(k%6*2+1))[-12:]*(n-k/6)
n=input()
for k in range(6*n):j=1+k%6*2;print' '*k+('*'*(12-j)+' '*j)*(n-k/6)
89 Chars for the bonus
n=input();R=range(6*n)
for k in R+R[::-1]:print' '*k+('*'*11+' '*11)[k%6*2:][:12]*(n-k/6)
114 Chars Version just using string replacements
u,v=' *';s=(v*11+u)*input()
while s.strip():print s;s=u+s.replace(*((v*2+u,u*3),(v*1+u*10,v*11))[' * 'in s])[:-2]
Unk Chars all in one statement, should work w/ 2.x and 3.x. The enumerate() is to allow the single input() to work for both places you need to use it.
print ('\n'.join('\n'.join(((' '*(6*n))+' '.join(('%s%s%s'%(' '*(5-x),'*'*(2*x+1),' '*(5-x)) for m in range(i + 1)))) for x in range(5,-1,-1)) for n, i in enumerate(range(int(input())-1,-1,-1))))
Yet Another Method
def f(n): print '\n'.join(' '*6*(n-r)+(' '*(5-l)+'*'*(l*2+1)+' '*(5-l)+' ')*r for r in xrange(1, n+1) for l in xrange(6))
f(input())
Ruby - 74 Chars
(6*n=gets.to_i).times{|k|puts' '*k+('*'*(11-(j=k%6*2))+' '*(j+1))*(n-k/6)}
COBOL - 385 Chars
$ cobc -free -x triforce.cob && echo 7| ./triforce
PROGRAM-ID.P.DATA DIVISION.WORKING-STORAGE SECTION.
1 N PIC 9.
1 M PIC 99.
1 value '0100***********'.
2 I PIC 99.
2 K PIC 99.
2 V PIC X(22).
2 W PIC X(99).
PROCEDURE DIVISION.ACCEPT N
COMPUTE M=N*6
PERFORM M TIMES
DISPLAY W(1:K)NO ADVANCING
PERFORM N TIMES
DISPLAY V(I:12)NO ADVANCING
END-PERFORM
DISPLAY ''
ADD 2 TO I
IF I = 13 MOVE 1 TO I ADD -1 TO N END-IF
ADD 1 TO K
END-PERFORM.
K could be returned to outside the group level. An initial value of zero for a numeric with no VALUE clause is compiler-implementation dependent, as is an initial value of space for an alpha-numeric field (W has been cured of this, at no extra character cost). Moving K back would save two characters. -free is compiler-dependant as well, so I'm probably being over-picky.
sed, 117 chars
s/$/76543210/
s/(.).*\1//
s/./*********** /gp
:
s/\*(\**)\*/ \1 /gp
t
:c
s/\* {11}\*/ ************/
tc
s/\* / /p
t
Usage: $ echo 7 | sed -rf this.sed
First attempt; improvements could probably be made...
Ruby 1.9 - 84 characters :
v=gets.to_i
v.times{|x|6.times{|i|puts' '*6*x+(' '*i+'*'*(11-2*i)+' '*i+' ')*(v-x)}}
Perl - 72 chars
die map$"x$_.("*"x(12-($l=1+$_%6*2)).$"x$l)x($n-int$_/6).$/,0..6*($n=<>)
78 chars
map{$l=$_%6*2;print$"x$_,("*"x(11-$l).$"x$l.$")x($n-int$_/6),$/}0..6*($n=<>)-1
87 chars
$n=<>;map{$i=int$_/6;$l=$_%6*2;print$"x$_,("*"x(11-$l).$"x$l.$")x($n-$i),$/}(0..6*$n-1)
97 chars
$n=<>;map{$i=int$_/6;$l=$_%6;print$"x(6*$i),($"x$l."*"x(11-2*$l).$"x$l.$")x($n-$i),$/}(0..6*$n-1)
108 chars
$n=<>;map{$i=int$_/6;$l=$_%6;print ""." "x(6*$i),(" "x$l."*"x(11-2*$l)." "x$l." ")x($n-$i),"\n";}(0..6*$n-1)
Powershell, 78 characters
0..(6*($n=read-host)-1)|%{" "*$_+("*"*(12-($k=1+$_%6*2))+" "*$k)*(.4+$n-$_/6)}
Bonus, 92 characters
$a=0..(6*($n=read-host)-1)|%{" "*$_+("*"*(12-($k=1+$_%6*2))+" "*$k)*(.4+$n-$_/6)}
$a
$a|sort
The output is stored in an array of strings, $a, and the reverse is created by sorting the array. We could, of course, just reverse the array, but it would be more characters to type :)
Haskell - 131 138 142 143 Chars
(⊗)=replicate
z o=[concat$(6*n+m)⊗' ':(o-n)⊗((11-m-m)⊗'*'++(1+m+m)⊗' ')|n<-[0..o-1],m<-[0..5]]
main=getLine>>=mapM_ putStrLn.z.read
This one is longer (146 148 chars) at present, but an interesting, alternate line of attack:
(⊗)=replicate
a↑b|a>b=' ';_↑_='*'
z o=[map(k↑)$concat$(6*n)⊗' ':(o-n)⊗"abcdefedcba "|n<-[0..o-1],k<-"abcdef"]
main=getLine>>=mapM_ putStrLn.z.read
FORTRAN - 97 Chars
Got rid of the #define and saved 8 bytes thanks to implict loops!
$ f95 triforce.f95 -o triforce && echo 7 | ./triforce
READ*,N
DO K=0,N*6
M=2*MOD(K,6)
PRINT*,(' ',I=1,K),(('*',I=M,10),(' ',I=0,M),J=K/6+1,N)
ENDDO
END
125 bytes for the bonus
READ*,N
DO L=1,N*12
K=L+5
If(L>N*6)K=N*12-L+6
M=2*MOD(K,6)
PRINT"(99A)",(32,I=7,K),((42,I=M,10),(32,I=0,M),J=K/6,N)
ENDDO
END
FORTRAN - 108 Chars
#define R REPEAT
READ*,N
DO I=0,6*N
J=MOD(I,6)*2
PRINT*,R(' ',I)//R(R('*',11-J)//R(' ',J+1),N-I/6)
ENDDO
END
JavaScript 1.8 - SpiderMonkey - 118 chars
N=readline()
function f(n,c)n>0?(c||' ')+f(n-1,c):''
for(i=0;i<N*6;i++)print(f(i)+f(N-i/6,f(11-(z=i%6*2),'*')+f(z+1)))
w/ bonus - 151 chars
N=readline()
function f(n,c)n>0?(c||' ')+f(n-1,c):''
function l(i)print(f(i)+f(N-i/6,f(11-(z=i%6*2),'*')+f(z+1)))
for(i=0;i<N*6;i++)l(i)
for(;i--;)l(i)
Usage: js thisfile.js
JavaScript - In Browser - 154 characters
N=prompt()
function f(n,c){return n>0?(c||' ')+f(n-1,c):''}
s='<pre>'
for(i=0;i<N*6;i++)s+=f(i)+f(N-i/6,f(11-(z=i%6*2),'*')+f(z+1))+'\n'
document.write(s)
The non-obfuscated version (before optimizations by gnarf):
var N = prompt();
var S = ' ';
function fill(c, n) {
for (ret=''; n--;)
ret += c;
return ret;
}
var str = '<pre>';
for (i=0; i<N*6; i++) {
str += fill(S, i);
for (j=0; j<N-i/6; j++)
str += fill('*', 11-i%6*2) + fill(S, i%6*2+1);
str += '\n';
}
document.write(str);
Here's a different algorithm that uses replace() to go from one line to the next of each line of a triangle row:
161 characters
N=readline()
function f(n,c){return n>0?(c||' ')+f(n-1,c):''}l=0
for(i=N;i>0;){r=f(i--,f(11,'*')+' ');for(j=6;j--;){print(f(l++)+r)
r=r.replace(/\*\* /g,' ')}}
F#, 184 181 167 151 147 143 142 133 chars
let N,r=int(stdin.ReadLine()),String.replicate
for l in[0..N*6-1]do printfn"%s%s"(r l" ")(r(N-l/6)((r(11-l%6*2)"*")+(r(l%6*2+1)" ")))
Bonus, 215 212 198 166 162 158 157 148 chars
let N,r=int(stdin.ReadLine()),String.replicate
for l in[0..N*6-1]#[N*6-1..-1..0]do printfn"%s%s"(r l" ")(r(N-l/6)((r(11-l%6*2)"*")+(r(l%6*2+1)" ")))
C - 120 Chars
main(w,i,x,y){w=getchar()%8*12;for(i=0;i<w*w/2;)y=i/w,x=i++%w,putchar(x>w-2?10:x<y|w-x-1<y|(x-y)%12>=11-2*(y%6)?32:42);}
Note that this solution prints some trailing spaces (which is okay, right?). It also relies on relational operators having higher precedence than bitwise OR, saving two characters.
124 Chars
main(n,i,k){n=getchar()&7;for(k=0;k<6*n;k++,putchar(10))for(i=-k-1;++i<12*n-2*k-1;putchar(32+10*(i>=0&&(11-i%12>2*k%12))));}
C - 177 183 Chars
#define P(I,C)for(m=0;m<I;m++)putchar(C)
main(t,c,r,o,m){scanf("%d",&t);for(c=t;c>0;c--)for(r=6;r>0;r--){P((t-c)*6+6-r,32);for(o=0;o<c;o++){P(r*2-1,42);P(13-r*2,32);}puts("");}}
C - 222 243 Chars (With Bonus Points)
#define P(I,C)for(m=0;m<I;m++)putchar(C)
main(t,c,r,o,m){scanf("%d",&t);for(c=t-1;-c<2+t;c-=1+!c)for(r=c<0?1:6;c<0?r<7:r>0;r+=c<0?1:-1){P((t-abs(c+1))*6+6-r,32);for(o=0;o<abs(c+1);o++){P(r*2-1,42);P(13-r*2,32);}puts("");}}
This is my first Code Golf submission as well!
Written in C
Bonus points (492 chars):
p(char *t, int c, int s){int i=0;for(;i<s;i++)printf(" ");for(i=0;i<c;i++)printf("%s",t);printf("\n");}main(int a, char **v){int i=0;int k;int c=atoi(v[1]);for(;i<c;i++){p("*********** ",c-i,i);p(" ********* ",c-i,i);p(" ******* ",c-i,i);p(" ***** ",c-i,i);p(" *** ",c-i,i);p(" * ",c-i,i);}for(i=0;i<c;i++){k=c-i-1;p(" * ",1+i,k);p(" *** ",1+i,k);p(" ***** ",1+i,k);p(" ******* ",1+i,k);p(" ********* ",1+i,k);p("*********** ",i+1,k);}}
Without bonus points (322 chars):
p(char *t, int c, int s){int i=0;for(;i<s;i++)printf(" ");for(i=0;i<c;i++)printf("%s",t);printf("\n");}main(int a, char **v){int i=0;int k;int c=atoi(v[1]);for(;i<c;i++){p("*********** ",c-i,i);p(" ********* ",c-i,i);p(" ******* ",c-i,i);p(" ***** ",c-i,i);p(" *** ",c-i,i);p(" * ",c-i,i);}}
First time posting, too!
Lua, 121 chars
R,N,S=string.rep,io.read'*n',' 'for i=0,N-1 do for j=0,5 do X=R(S,j)print(R(S,6*i)..R(X..R('*',11-2*j)..X..S,N-i))end end
123
R,N,S=string.rep,io.read'*n',' 'for i=0,N-1 do for j=0,5 do print(R(S,6*i)..R(R(S,j)..R('*',11-2*j)..R(S,j)..S,N-i))end end
PHP, 153
<?php $i=fgets(STDIN);function r($n,$c=' '){return$n>0?$c.r($n-1,$c):'';}for($l=0;$l<$i*6;){$z=$l%6*2;echo r($l).r($i-$l++/6,r(11-$z,'*').r($z+1))."\n";}
with Bonus, 210
<?php $i=fgets(STDIN);function r($n,$c=' '){return$n>0?$c.r($n-1,$c):'';}$o=array();for($l=0;$l<$i*6;){$z=$l%6*2;$o[]=r($l).r($i-$l++/6,r(11-$z,'*').r($z+1));}print join("\n",array_merge($o,array_reverse($o)));
dc 105 chars
123 129 132 139 141
[rdPr1-d0<P]sP?sn
0sk[1lk6%2*+sj32lkd0<Plnlk6/-si
[[*]12lj-d0<P32ljd0<Pli1-dsi0<I]dsIx
10Plk1+dskln6*>K]dsKx
Mathematica, 46 characters
The answer prints sideways.
TableForm#{Table["*",{l,#},{l},{j,6},{2j-1}]}&
HyperTalk - 272 chars
function triforce n
put"******" into a
put n*6 into h
repeat with y=0 to h-1
put" " after s
put char 1 to y of s after t
repeat n-y div 6
get y mod 6*2
put char 1 to 11-it of (a&a)&&char 1 to it of s after t
end repeat
put return after t
end repeat
return t
end triforce
Indentation is neither needed nor counted (HyperCard automatically adds it).
Miscellanea:
Since there is no notion of console or way to access console arguments in HyperCard 2.2 (that I know of), a function is given instead. It can be invoked with:
on mouseUp
ask "Triforce: "
put triforce(it) into card field 1
end mouseUp
To use this, a card field would be created and set to a fixed-width font. Using HyperCard's answer command would display a dialog with the text, but it doesn't work because:
The answer dialog font (Chicago) is not fixed-width.
The answer command refuses to display long text (even triforce(2) is too long).
Common Lisp, 150 characters:
(defun f(n o)(unless(= n 0)(dotimes(x 6)(format t"~v#{~a~:*~}~-1:*~v#{~?~2:*~}~%"
o" "n"~11#: "(list(- 11(* 2 x))#\*)))(f(1- n)(+ 6 o))))
77 char alternative python solution based on gnibbler's:
n=input()
k=0
exec"print' '*k+('*'*12+' '*(k%6*2+1))[-12:]*(n-k/6);k+=1;"*6*n
Amazingly the bonus came out exactly the same also (101 chars, oh well)
n=input()
l=1
k=0
s="print' '*k+('*'*12+' '*(k%6*2+1))[-12:]*(n-k/6);k+=l;"*6*n
exec s+'l=-1;k-=1;'+s