if statement not running in the while loop in python - tic-tac-toe

Question

I encountered a problem while running some code for taking input in the TicTacToe game. The code is written as below:
def player_input():
marker = " "
while marker != "X" and marker != "O":
marker = input("Player 1: Do you want me to play X or O? ").upper()
if marker == "X":
return ("X", "O")
else:
return ("O", "X")
player_input()
After calling the function, the 'if loop' does not run here in the text editor, whereas in the Jupyter notebook, the code returns the tuple, I can't understand why! Need help. I am a beginner.

Answer 1

You have missed the line indentations..And you didnt mention the method outside the code..
Line Indentations:
In simple terms indentation refers to adding white space before a statement. But the question arises is it even necessary?
To understand this consider a situation where you are reading a book and all of a sudden all the page numbers from the book went missing. So you don’t know, where to continue reading and you will get confused. This situation is similar with Python. Without indentation, Python does not know which statement to execute next or which statement belongs to which block.
Revised version of code....
def player_input():
marker = " "
while marker != "X" and marker != "O":
marker = input("Player do you want to play X or O").upper()
if marker == "X":
print("You have chosen X and if statement works...Insert your command here")
else:
print("You have chosen O and else statement works...Insert your command here")
player_input()

Answer 2

Give the proper spacing for the code. Like this
while <condition>:
//Code block
if <condition>:
//<statement 1>
else:
//<statement 2>

Answer 3

I think you are missing indentations, after adding proper indentations the following code returns a touple :
def player_input():
marker = " "
while marker != "X" and marker != "O":
marker = input("Player 1: Do you want me to play X or O? ").upper()
if marker == "X":
return ("X", "O")
else:
return ("O", "X")